Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Chemical formula of Freon 12 is

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`CH_2F_2`
`CH_2CL_2`
`C``CLF_3`
`C``CL_2F_2`

ANSWER :D
2.

Chemical formula of cuprite is……..

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SOLUTION :`Cu_(2)O`
3.

Chemical formula for the phosphorous molecule is

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P
`P_(4)`
`P_(2)`
`P_(5)`

ANSWER :B
4.

Chemical equilibrium is a dynamic equilibrium because

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EQULIBRIUM is maintained RAPIDLY
The concentraion of reactants and PRODUCTS become some at equlibrium
The concentration of reactants and products are constant but DIFFERENT
Both forward and BACKWARD reaction occur at all time which same speed

Answer :D
5.

Chemical equilibrium is:

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STATIONARY
DYNAMIC
interness
STATE of rest

Answer :B
6.

Chemical equations convey quantivaive information on the

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Type of atoms/molecules taking PART in the reaction
NUMBER of atoms/molecules of the reactants and products INVOLVED in the reaction
RELATIVE number of moles of reactants and products involved in the reaction
QUANTITY of reactant consumed and quantity of product formed

Solution :Chemical reaction quantiatively depend on the reactant and product molecule.
7.

Chemical equation is balanced according to the law of:

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MULTIPLE proportion
reciprocal proportion
Conservation of mass
Definite proportion

Answer :C
8.

Chemical composition of malachite is 'X'. Then the composition of azurite is

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`CuCO_3+X`
`CU(OH)_2 +X`
`X-CuCO_3`
`X-Cu(OH)_2`

ANSWER :A
9.

Chemical bonding between two atoms is necessarily with an electrical moment arising out of the difference in electronegativity of two atoms. This means that every bond carries with it an electrical moment called the bond moment.The dipole moment of a molecule is really the vectorial sum of the individual bond moment present in it. To compute the dipole moment it is necessary to find out the values of various bond moment in the moment of different bonds are as given. {:("Bond",oversetto(H-C), " ",oversetto(C-Cl)," ",oversetto(C=O)),("Bond moments",0.4 D ," ", 1.5 D, " ", 2.5D):} The group moments of few groups as given {:("Group",NO_2,OH,CN,CH_3),("direction of dipole","toward N","towards O","towards N","away from" CH_2),("Dipole moment",4D,1.6D,3.8 D,0.4D):} In the acetone molecule considering the normal planar structure, the observed dipole moment of acetone molecule is -

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2.9 D
2.75 D
3 D
None of these

Solution :
`mu_("net")=2.5+mu_(CH_3)=2.5+0.4=2.9 D`
10.

Chemical bonding between two atoms is necessarily with an electrical moment arising out of the difference in electronegativity of two atoms. This means that every bond carries with it an electrical moment called the bond moment.The dipole moment of a molecule is really the vectorial sum of the individual bond moment present in it. To compute the dipole moment it is necessary to find out the values of various bond moment in the moment of different bonds are as given. {:("Bond",oversetto(H-C), " ",oversetto(C-Cl)," ",oversetto(C=O)),("Bond moments",0.4 D ," ", 1.5 D, " ", 2.5D):} The group moments of few groups as given {:("Group",NO_2,OH,CN,CH_3),("direction of dipole","toward N","towards O","towards N","away from" CH_2),("Dipole moment",4D,1.6D,3.8 D,0.4D):} In CH_3C Cl_3 (I), CHCl_3 (II) and CH_3Cl (III) the normal tetrahedral bond angle is maintained.Also give cos 70.5^@=1/3 Therefore dipole moments of the given compounds are (given due to -I effect of Cl, the Bond moment of H-C bond directedtoward the H in CHCl_3)

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I=1.9 D, II-1.9 D, III=1.7 D
I=1.9 D, II-1.7 D, III=1.9 D
I=1.9 D, II-1.7 D, III=1.7 D
I=1.9 D, II-1.1 D, III=1.9 D

Solution :`mu_I=3mu_(C-Cl)xxcos70.5+mu_(CH_3)=1.5+0.4=1.9 D`
`mu_(II)=3mu_(C-Cl)xxcos70.5mu_(C-H)=1.5-0.4=1.1 D`
`mu_(III)=3mu_(C-H)xxcos70.5+mu_(C-Cl)=1.9 D`
11.

Chemical bonding between two atoms is necessarily with an electrical moment arising out of the difference in electronegativity of two atoms. This means that every bond carries with it an electrical moment called the bond moment.The dipole moment of a molecule is really the vectorial sum of the individual bond moment present in it. To compute the dipole moment it is necessary to find out the values of various bond moment in the moment of different bonds are as given. {:("Bond",oversetto(H-C), " ",oversetto(C-Cl)," ",oversetto(C=O)),("Bond moments",0.4 D ," ", 1.5 D, " ", 2.5D):} The group moments of few groups as given {:("Group",NO_2,OH,CN,CH_3),("direction of dipole","toward N","towards O","towards N","away from" CH_2),("Dipole moment",4D,1.6D,3.8 D,0.4D):} The bond angle in H_2S is 97^@ and its dipole moments is 1.5 D.The S-H bond distance is 0.15 nm.There fore approximate percentage ionic character of S-H bond is (neglect the effect of dipole moment of lone pair on sulphur atom in H_2S).(Given [cos 97^@=-0.12] and sqrt0.88=0.94)

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`32 %`
`16 %`
`84 %`
`10 %`

SOLUTION :
`mu_R=sqrt(2mu_(S-H)^2+2mu_(S-H)^2xxcos97^@)`
`mu_R=sqrt2xxmu_(S-H)xxsqrt(1-0.12)`
`mu_R=sqrt2xxmu_(S-H)xxsqrt(0.88)`
`mu_(S-H)=1.5/(sqrt2xx0.94)D`
`(mu_(S-H))_(Cal)=(0.15xx10^(-9)xx1.6xx10^(-19))/(10/3xx10^(-30))`
`(mu_(S-H))_(Cal)=3xx0.15xx1.6xx10D`
So % Ionic character
`=15/(sqrt2xx0.94)XX[1/(0.15xx16xx3)]xx100=16%`
12.

Chemical bonding between two atoms is necessarily associated with an electrical moment arising out of the difference in electroegativity of two atoms. This means that every bond carries with it an electricalmoment called the ''bond moment''. The dipole moment of a molecule is really the vectorial sum of the individual bond moment present in it. To compute the dipole moment it is necessary to find out the values of various bond moment. In the following table, dipole moment of different bonds are as given. {:(,rarr,rarr,rarr),("Bond",H-C,C-Cl,C=0),("Bond moments",0.4 D,1.5 D,2.5 D):} The group moments of few groups as given {:("Group",NO_(2),OH,CN,CH_(3)),("Direction of dipole","Towards N","Towards O","Towards N","Away from "CH_(3)),("Dipole moment",4D,1.6D,3.8D,0.4D):} In CH_(3)"CCl"_(3)" (I)", CHCl_(3) (II) and CH_(3)Cl (III) the normal tetragedral bond angle is maintained. Also given cos70.5^(@)=(1)/(3). Therefore dipole moments of the given compounds are : (given due to -I effect of Cl. The bond moment of H-C bond directed towards the H in CHCl_(3))

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I = 1.9D, II = 1.9 D, III = 1.7 D
I = 1.9 D, II = 1.7D, III = 1.9D
I = 1.9 D, II = 1.7 D, III = 1.7 D
I = 1.9 D, II = 1.1D, III = 1.9 D

Solution : `mu_(CHCl_(3)ltCH_(3)Cl`
`Irarr1.9D"(LEAST)"`
(given in options)
Hence, no CALCULATIONS required.
13.

Chemical bond implies

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attraction and repulsion
attraction and repulsion balanced at a particular distance
attraction
repulsion

Solution :A chemical bond may be regarded as a force which holds the atoms together in a molecule. When two ISOLATED atoms get very close to each other besides force of attraction, there also develop force of repulsion between the two nuclei and ELECTRONS of like charge. at a short internuclear distance the ATTRACTIVE force due to sharing, gaininig or losing electrons just BALANCE the repulsive forces between particles of like charge, at which the MOLECULES attain maximum stability.
14.

Chemical adsorption is an exothermic process. Justify this statement.

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Solution :In chemical adsorption, GAS molecules are held to the surface by the formation of STRONG bond. Due to this 400kJ/mole is GIVEN out as heat of adsorption. Since heat is evolved, it is an exothermic PROCESS.
15.

Chemical adsorption :

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Is exothermic
Irreversible
Unilayer
All

Answer :D
16.

Chemical A is used for water softening to remove temporary hardness. A reacts with sodium carbonate to generate caustic soda. When CO_2 is bubbled through A, it turns cloudy. What is the chemical formula of A ?

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`CaCO_3`
CaO
`Ca(OH)_2`
`Ca(HCO_3)_2`

ANSWER :C
17.

Cheilosis is caused due to deficiency of ………………….

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VITAMIN `B_(12)`
Vitamin `B_(2)`
Vitamin K
Vitamin E

SOLUTION :Vitamin `B_(2)`
18.

Cheilosis and digestive disorders are due to the deficiency of

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ASCORBIC ACID
pyridoxine
thiamine
RIBOFLAVIN

Solution :Deficiency of riboflavin (VITAMIN `B_2`)causes CHEILOSIS and digestive disorders.
19.

Checking of radiating heat by atmospheric dust, water vapour, ozone, CO_(2) etc., is known as:

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GREENHOUSE EFFECT
OZONE LAYER effect
RADIOACTIVE effect
Solar effect

Answer :A
20.

Cheese is a colloidal:

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GAS in liquid
Liquid in SOLID
Gas in solid
Solid in gas.

Answer :D
21.

Check, which of the following statements is false ?

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A catalyst does not DIFFERENTIATE between forward and backward reaction
Large activation energy is ASSOCIATED with low reaction rate
Maxwell's distribution of velocities remains- unaltered under all conditions of temperature and PRESSURE
A catalyst does not affect the equilibrium state of reaction

Answer :C
22.

CH,COOH -overset(Cl_2.P)(rarr)A underset(C_2H_5OH//H^+)overset("esterification")(rarr)B overset(alc. KCN)(rarr)C underset(H_2O//H^(+))overset(hydrolysis)(rarr)D underset(-CO_2)overset("heat" 150^@C)(rarr)E.Name the functional isomer of compound E in the above sequence.

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ANSWER :METHYL FORMATE
23.

CHCl_(3)+Cl_(2) to CCl_(4)+HCl Rate law for above reactionl will be Rate=K[CHCl_(3)][Cl_(2)]^(1)/(2) On the basis of information provided which of the following option will be correct?

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RATE law for any chemical REACTION can be PREDICTED accurately by LOOKING at balanced chemical equation.
Rate law for a chemical reaction has to DETERMINE experimentally.
Either determine experimentally or obtained from balanced reactionrate will besame.
None of the above is correct

Solution :Rate law has to be determined experimentally as `Cl_(2)` is raised to power `(1)/(2)` in rate law whereas its stichiometric coefficient in balanced chemical equation is 1.
24.

CHCl_3 can be obtained from:

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METHANOL
Methanal
Prooanol-1
Propanol-2

Answer :D
25.

CHCl_(3) and HF lead to the formation of a compound of fluorine of molecular weight 70. the compound is

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Fluoroform
Fluorine monoxide
Fluorine dioxide
Fluoromethanol

Solution :We KNOW that `CHCl_(3)+HFtoCFH_(3)+3HCL`. Thus in this reaction the compound obtained in fluoroform `(CHF_(3))`. As we know MOLECULAR weight of `CHF_(3)=70`
26.

Chargoff's rule states that in an organism :

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amount of ADENINE (A) is equal to that of thymine (T) and the amount of GUANINE is equal to that of cytosine (C ).
Amount of adenine (A) is equal to that of guanine (G) and the amount of thymine (T) is equal to that of cytosine ( C).
Amount of adenine (A) is equal to that of guanine (G) and the amount of thymine (T) is equal to that of guanine (G).
Amount of all BASES are equal.

ANSWER :A
27.

Charle's law is applicable under

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ISOBARIC process
Isochoric process
Isothermal process
Adiabatic process

Answer :A
28.

Charge to mass ratio of electron was determined by

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JAMES Chadwick
J.J. Thomson
Goldstein
Ernest Rutherford

Answer :B
29.

Charge on one mole of electron is _______

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SOLUTION :ONE FARADAY or 96500C
30.

Charge of 6.24xx10^(18) electrons will be (in coulomb) :

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ANSWER :1
31.

Charge on cation in product formed when BeCl_2 reacts with concentrated diethyl ether solution.

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Solution :`BeCl_2` being electron DEFICIENT FORMS complex with electron RICH ETHERS.
32.

Charge distribution in iodine monochloride is best represented as :

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`I^(+)Cl^(-)`
`I^(delta)+Cl^(delta+)`
`I^(-) Cl^(+)`
`I^(delta-) Cl^(delta+)`

Solution :The bond is POLAR covalent with IODINE having partial positive `(delta+)` and CHLORINE partial negative charge `(delta-)`.
33.

Charge distribution in iodine monochloride is best represented as

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`I^+CL^-`
`I^(DELTA+)Cl^(delta-)`
`I^(-)Cl^+`
`I^(delta-)Cl^(delta+)`

ANSWER :B
34.

Charge carried by 1 mole of electrons is ________.

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SOLUTION :`1.6 xx 10^(-19) C xx6.023 xx 10^(23) =9.65 xx10^4C =96500C`
35.

Chargaff's rule states that in an organism.

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AMOUNT of adenine (A) is equal to that of THYMINE (T) and the amount of thymine (T) is equal to that of cytosine (C).
Amount of adenine (A) is equal to that of GUANINE (G) and the amount of thymine (T) is equal to that of cytosine (C).
Amount of adenine (A) is equal to that of cytosine(C) and the amount of thymine (T) is equal to that of guanine (G).

Answer :A
36.

Charcoal is activated

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by COOLING it from `623^@C` to `127^@C` in vacuum
by cooling it to 23K in vacuum
by HEATING it from 573K to 1273K in vacuum
by heating UPTO 300K 

Answer :C
37.

Chargaff's rule states that in an organism

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amount of adenine (A) is EQUAL to that of thymine (T) and amount of guanine (G) is equal to that of CYTOSINE (C)
amount of adenine (A) is equal to that of guanine (G) and the amount of thymine (T) is equal to that of cytosine (C)
amount of adenine (A) is equal to that of cytosine (C) and the amount of thymine (T) is equal to that of guanine (G)
AMOUNTS of all BASES are equal.

Solution :Amount of A = Tand thatofG = C .
38.

Characterstic feature of alkali metals is

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GOOD conductor of heat and electricity
High melting point
LOW OXIDATION potentials
High IONIZATION potentials

Solution :Alkali metals are good conductor of heat and electricity.
39.

Characters are transferred from parents to offspring through :

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gametes
genes
mutants
enzymes

Solution :Gene is a HEREDITARY UNIT consisting of a sequence of DNA, and OCCUPYING a SPECIFIC position or locus within the genome .
40.

Characteristic group of aldehyde is_____.

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SOLUTION :ALDEHYDIC (-CHO) GROUP.
41.

Characteristicreaction of aldehydes and ketonesis oneof nuclephilicadditionwhile Acyl comppoundyield Nucelophilicsubstitiution product . Explain.

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SOLUTION :
42.

Characteristic of transition element is that its …….. Is in complete :

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d' orbital
p' orbital
f' orbital
s' orbital

Answer :A
43.

Changes in a system from an initital state to the final state were made by a different manner that DeltaH remains same but q changes because

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`DELTAH` is a path FUNCTION and q is a state function
`DeltaH` is a state function and q is a path function
Both `DeltaH` and q are state functions
Both `DeltaH` and q are path functions

Answer :B
44.

Changes in enthalpy for the reaction : 2H_(2)O_(2)(g) rarr 2H_(2)O (l) + O_(2)(g) if heat of formation of H_(2)O_(2)(l) and H_(2)O(l) are -188 kJ mol^(-1) and -286 kJ mol^(-1) respectively is

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`-196 KJ MOL^(-1)`
`+196 kJ mol^(-1)`
`+948 kJ mol^(-1)`
`-948 kJ mol^(-1)`

ANSWER :A
45.

Change of catalyst changed products CO + 3H_2 overset(N i)(rarr) X + H_2O CO + 2H_2 underset(Cr_2O_3)overset(Cu//ZnO)(rarr)Y CO + H_2 overset(Cu)(rarr)Z. The magnitude of the algebraic sum of the oxidation state of carbon in X, Y and Z is _____

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Solution :`CO + 3H_2 overset(N i)(RARR) overset(-4)(CH_4) + H_2O , CO + 2H_2 + underset(Cr_2O_3)overset(Cu//Zn)(rarr) overset(-2)(CH_3)OH`
`CO + H_2 overset(Cu)(rarr)Hoverset(0)(C)HO ,` total OXIDATION no - 4 - 2 = -6
46.

Changing the volume of the system does not after the number of moles in which of the following equilibrium.

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`N_(2(g))+O_(2(g))hArr2NO_((g))`
`PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g))`
`N_(2(g))+3H_(2(g))hArr2NH_(3(g))`
`SO_(2)Cl_(2(g))hArrSO_(2(g))+Cl_(2(g))`

SOLUTION :`N_(2(g))+O_(2(g))hArr2NO_((g)),""Deltan=2-2=0`
47.

Change in optical rotation of sucrose solution due to hydrolysis is called

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SPECIFIC ROTATION
INVERSION
ROTATORY motion
Mutarotation

Answer :B
48.

Change in internal energy, when 4 kJ of work is done on the system and 1 kJ of heat is given out by the system, is

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`+1 kJ`
`-5 kJ`
`+5 kJ`
`+3 kJ`

SOLUTION :CHANGE in internal ENERGY is given by the relation,
`DeltaE=q+w`
`DeltaE=-q+w` (as heat is given out by the system)
`DeltaE=-1+4`
`DeltaE=+3kJ`.
49.

Change in entropy is negative for:

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`Bromine(l)rarrBromine(G)`
`C(s)+H_2O(g)rarrCO(g)+H_2(g)`
`N_2(g, 10 atm)rarrN_2(g, 1 atm)`
`Fe(1 mol, 400K)rarrFe(1 mol, 300K)`

Answer :D
50.

Change in entropy for a reaction is given by:

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2.303 NR `log_10(v_2)/(v_1)`
nR `log_e(v_2)/(v_1)`
nR `log_e(P_1)/(P_2)`
All

Answer :D