CH_(4) (g) and O_(2) (g) react according to the given equation: CH_(4) (g) + 2O_(2) (g) rarr CO_(2) (g) + 2H_(2) O (l) Assuming that reaction take placed and goes to completion.If valve is opened then [Assume temperature remains constant 300 K throughout ]

CH_(4) (g) and O_(2) (g) react according to the given equation: CH_(4

1.	CH_(4) (g) and O_(2) (g) react according to the given equation: CH_(4) (g) + 2O_(2) (g) rarr CO_(2) (g) + 2H_(2) O (l) Assuming that reaction take placed and goes to completion.If valve is opened then [Assume temperature remains constant 300 K throughout ]
Answer» `CH_(4)` gas is left after the reaction `O_(2)` gas is left the reaction. Total pressure is `(1)/(3)` atm after the reaction . After the reaction pressure in both the vessels will REMAIN same Solution :`n_(CH_(4)) = (0.5 xx 2)/(R xx 300) = (1)/(300 R)` `n_(O_(2)) = (1 xx 1)/(R xx 300) = (1)/(300 R)` `{:(,CH_(4) (g),+,2O_(2) (g),RARR,CO_(2) (g),+,2H_(2) o (l),),("Mole initially",(1)/(300R),,(1)/(300 R),,-,,-,):}` `O_(2)` is LR `CH_(2)` will be left after the reaction `{:("Mole at",(1)/(600 R),0,(1)/(600 R),-,),("Completion",,,,,):}` Total moles after completion `= n_(CH_(4) + n_(CO_(2))` `= (1)/(600 R) + (1)/(600 R)` `(1)/(300 R)` `P = (nRT)/(V) = (1)/(300 R) xx (R xx 300)/(3) = (1)/(3)` atm