Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

An organic compound taken in a test tube and acetyl chloride is added to it. White fumes appeared when a glass rod dipped NH_(3) is placed at the mouth of test tube. This indicates that organic compound may contain.

Answer»

-CL
-COOH
-OH
double bond

Answer :C
Discussion
2.

An organic compound reacts with Cu_2Cl_2 and also decolourise Br_2 water is

Answer»

`CH_3-C-=C-CH_3`
`CH_2=CH-CH_3`
`CH_3-C-=CH`
`CH_3-CH_3`

Solution :Alkenes and alkynes both decolourise bromine water, but only alkynes , containing TERMINAL H atom reacts with ammonical cuprous CHLORIDE solution.
`CH_3-C-=Chunderset(H_2O)overset(Br_2)to CH_3-undersetunderset(Br)(|)C=CHBr UNDERSET(H_2O)overset(Br_2)to CH_3-undersetunderset(Br)(|)oversetoverset(Br)(|)C-undersetunderset(Br)(|)overset(Br)overset(|)C`
`CH_3-C-=underset(Cu_2Cl_2)overset"ammonical"toCH_3-C-=C Cu`
Discussion
3.

An organic compound reacts with metallic sodium to liberate hydrogen and with Na_2 CO_3 solution to liberate CO_2. The compound is

Answer»

ALCOHOL
CARBOXYLIC acid
ETHER
ESTER

Answer :B
Discussion
4.

An organic compound (P) of molecular formula C_(5)H_(10)O is treeted with dil. H_(2)SO_(4) t give compounds (Q) and ( R ) both of which responds iodoform test The rate c reaction of (P) with dil. H_(2)SO_(4) is 10^(10) faster than the reaction of ethylene with di H_(2)SO_(4). Identify the organic compounds (P), (Q) and ( R ) and explain the extr reactivity of (P).

Answer»

SOLUTION :
Discussion
5.

An organic compound 'P (mol mass -75) on reduction gives compound 'Q' which yields compound 'R' when treated with nitrous acid. Compound R responds to iodofonn reaction. Compound Q is

Answer»

ETHYL a lcohol
nitroethanc
ethanamine
propanol

Solution :Compound Q is ethanaminc.
`CH_(3)underset((P))(CH_(2))NO_(2)overset([H])underset(-H_(2)O)(rarr)CH_(3)underset((Q))(CH_(2))NH_(2)overset(HNO_(2))underset(-H_(2)O)(rarr)CH_(3)underset((R))(CH_(2))OH`
The product (R ) ethyl alcoholn gives IODOFORM reaction.
Discussion
6.

An organic compound P having molecular formula C_(6)H_(4)N_(2)O_(4) is insoluble in both dilute acid and base and its dipole moment is zero. Its structure is :

Answer»




Solution :The compound is insoluble in both ACID and base. This indicates that it does not contain acidic or basic groups. Since its dipole moment is ZERO, it should have symmetrical structure i.e. a benzene derivative having same group in ORTHO and para POSITIONS.
Discussion
7.

An organic compound (P) C_(4)H_(6) formsa precipitate with Tolles regent. (P) has an isomer (Q) which on Reductive ozonolysis forms only one product. (P) and (Q) are :

Answer»




Solution :An ORGANIC COMPOUND …………….
TERMINAL alkayne gives white ppt with TOLLEN's reagent.
Discussion
8.

An organic compound P exists in two enantiomeric forms, which have specific optical rotation values [alpha] = +-100^(@). The optical rotation of a mixture of these two enantiomers is -50^(@). Calculate the percentage of that enantiomer which is in lower concentration in the mixture.

Answer»


Solution :`"Enatiomeirc excess" = ("observed rotation")/("specific rotation of pure ENANTIOMER")= (-50^(@))/(-100^(@)) XX 100 = 50%`
`% " of LAEVOROTATORY isomer " = 50+25%`
`% " of DEXTROROTATORY isomer " = 25%`
Discussion
9.

An organic compound on treatment with conc. Sulphuricacid, gives an intermediate compound, which on furtherhydrolysis givesisopropanol. The organic compound is __________ and the process is called _____

Answer»

`CH_3CH_2CH_3`, ELIMINATION
`CH_3CH_2CH_3`, DEHYDRATION
`CH_3CH=CH_2`, SUBSTITUTION
`CH_2=CHCH_3`, HYDRATION

ANSWER :D
Discussion
10.

An organic compound on qualitative analysis was found to contain C, H, N and O. 1.0g of it on oxidation with CuO and oxygen gave 1.239g of CO_(2) and 0.1269g of H_(2)O. 2g of the sample was digested with concentrated sulphuric acid and the residue was distilled after the addition of excess solution of sodium hydroxide. The ammonia evolved was absorbed in 50mL of 1.0N sulphuric acid. The resulting solution was diluted to 500mL in a measuring flask. 25mL of this solution required 21.8mL of 0.05N NaOH for complete neutralisation. Calculate the empirical formula of the compound.

Answer»

SOLUTION :`(C_(2)HNO_(2))`
Discussion
11.

An organic compound on heating with CuO produces CO_(2) but not water. The organic compound may be

Answer»

Chloroform
Methane
Ethyl iodide
Carbon tetrachloride

Solution :Since the COMPOUND on heating produces only `CO_(2)` and no water, thus the compound does not contain any HYDROGEN, hecne it is `"CC"l_(4)`.
Discussion
12.

An organic compound on analysis gave the following results : C = 54.5% , O = 36.4 %, H = 9.1% . The Empirical formula of the compound is

Answer»

`C_(2)H_(4)`
`C_(3)H_(4)O`
`C_(3)H_(4)O`
`C_(4)H_(8)O`

SOLUTION :`{:("ELEMENT"," No. of moles"," Simple RATIO"),(C=54.5,54.5//12=4.54,=2(2.2)),(H=9.1,9.1//1=9.1,=4(4.5)),(O=36.4,36.4//16=2.27,=1(1)):}`
Hence `C_(2)H_(4)O`.
Discussion
13.

An organic compound on analysis gave the following composition : C = 57.8% H = 3.6% and rest is oxygen. Its empirical formula is :

Answer»

`C_(4) H_(2)O_(3)`
`C_(4)H_(3)O_(2)`
`C_(2)H_(4)O_(6)`
`C_(3)H_(4)O_(2)`

ANSWER :B
Discussion
14.

An organic compound of two gases are in the ratio of 1:3 Their molecular masses are in the ratio is:

Answer»

200
2000
20000
200000

Answer :D
Discussion
15.

An organic compound on analysis gaveC=48 g,H=8g and N=56 g. Volume of 1.0 g of the compound was foud to be 200ml at NTP. Molecular formula of the compound is

Answer»

`C_(4)H_(8)N_(4)`
`C_(2)H_(4)N_(2)`
`C_(12)H_(24)N_(12)`
`C_(16)H_(32)N_(16)`

Solution :`{:("Element",%," NO. of moles"," Simple ratio"),(C,48,48//12=4,1),(H,8,8//1=8,2),(N,56,56//14=4,1):}`
Empirical FORMULA ` = CH_(2)N`
Empirical formula MASS `= 28`
Now, `200ml` of compound `= 1 gm`
`22400 ml` of compound `1/200 XX 22400 = 112`
`n '(" Mol.mass")/(" Emp.formula mass") = 112/28 = 4`
Therefore, molecularformula `= (CH_(2)N)_(4) = C_(4)H_(8)N_(4)`.
Discussion
16.

An organic compound of structure CH_(3)CH_(2)CH_(2)CH_(2)Cl shows chain isomer of compound of structural formula,

Answer»

`(CH_(3))_(3)C Cl`
`CH_(3)CH_(2)CHClCH_(3)`
`(CH_(3))_(2)CHCH_(2)Cl`
NONE of these

Solution :`(CH_(3))_(2)CHCH_(2)Cl` is a isobutly CHLORIDE shows isomereism with n-butyl chloride, because in those compounds arrangnements carbon chain is differenct but chlorine atom is at same POSITION
Discussion
17.

An organic compound of moleular formula C_4H_10Odoes not react with sodium. With excess of HI, it gives only one type of alkyl halide. The compound is.

Answer»

ETHOXYETHANE
2-Methoxypropane
1-Methoxypropane
1-Butanol

SOLUTION :
Discussion
18.

An organic compound of moleuular formula C_3H_6O dones not prduce any precipitate with 2,3- dinitrophenyl hydrazine and does not react with sodium metal. This compound is

Answer»

`CH_3COCH_3`
`CH_2=CH-OCH_3`
`CH_3CH_2CHO`
`CH_2=CHCH_2OH`

SOLUTION :
Discussion
19.

An organic compound of molecular formula C_(3)H_(7)N was analysed for nitrogen by Dumas method. Find the volume (in mL) of nitrogen evolved at NTP from 2g of the substance.

Answer»


ANSWER :393mL
Discussion
20.

An organic compound of molecular formula, C_3H_6O , forms 2,4 - dinitrophenylhydrazone, but gives negative Tollen's test . The compound is

Answer»

`CH_2=CH - CH_2-OH`
`CH_3CH_2CHO`
`CH_3COCH_3`
`CH_2=CH-OCH_3`

ANSWER :C
Discussion
21.

An organic compound of molecular formula C_(3)H_(6)O did not give a silver mirror with with Tollens' reagent but give an oxime with hydroxylamine. It may be

Answer»

`CH_(2)=CH-CH_(2)-OH`
`CH_(3)COCH_(3)`
`CH_(3)CH_(2)CHO`
`CH_(2)=CH-OCH_(3)`

Answer :B
Discussion
22.

An organic compound of molecula formula C_(6)H_(5)O"Na" is heated with CO_(2) at 400 K gives compound (A) of molecular formula C_(7)H_(5)O_(3)Na. Compound (A) on treating with HCl gives (B). B on further reactions wiith NaOH / CaO gives compound (C ) of molecular formula C_(6)H_(6)O which on treatment with nitrous acid at 200 K gives compound (D ). Identify (A), (B) , ( C) and (D) are explain the reactions.

Answer»

Solution :(i) When a sodium phenoxide is HEATED with carbon dioxide at 400 K under PRESSURE, sodium salicylate is formed.

(ii) Sodium salicylate is decomposed hydilute hydrochloric acid, when salicylic acid is formed.

(iii) On TREATMENT with NaOH/ CaO sodium salicyalte gives phenol.

(IV) Phenol reacts with nitrous acid to give p-nitrosophenol.
Discussion
23.

An organic compound of formula, C_(3)H_(6)O forms phenyl hydrazone, but gives negative Tollen's test . The compound is

Answer»

`CH_(2) = CHOCH_(3)`
`CH_(3)CH_(2)CHO`
`CH_(3)COCH_(3)`
`CH_(2) = CHCH_(2)OH`

Solution :Ketones do not respound to TOLLEN's test ALDEHYDES respond to Tollen's test.
Discussion
24.

An organic compound of carbon, hydrogen and nitrogen contains these elements having mass percentage 66.67%, 7.41% and 25.92% respectively. Calculate empirical formula

Answer»

`C_3H_4N`
`C_2H_6N`
`C_4H_4N`
`C_4H_9N`

ANSWER :`A`
Discussion
25.

An organic compound must contain:

Answer»

Oxygen
Carbon
Hydrogen
Nitrogen

Answer :B
Discussion
26.

An organic compound (mol. Wt =44) (X) contains 54.54% of C and 9.09% of H. With PCl_(5), (X) gives a compound of molecular weight 99. On oxidation it gives an acid of molecular weight 60. What is (X)?

Answer»

SOLUTION :`(CH_(3)CHO)`
Discussion
27.

An organic compound % of C and % of H in the ratio 6 : 1 and % of Cand % of O in the ratio 3 : 4. The compound is

Answer»

`HCHO`
`CH_(3)OH`
`CH_(3)CH_(2)OH`
`(COOH)_(2)`

Solution :Let `%` of hydrogen is X then `%` of carbon is `6x` and `%` of OXYGEN is `8x`
i.e., `x+6x+8x=100 rArr x = (100)/(15)`
`C 600//15% rArr 40//12 = 3.3333 rArr 1`
`H 100//15% rArr 100//15 = 6.6667 rArr 2`
`O 800//15% rArr 50//15 = 3.333 rArr 1`
`CH_(2)O` is the empirical formula.
Discussion
28.

An organic compound made of C,H and N contain20% nitrogen.Its molecular weightI

Answer»

70
140
100
65

Solution :MINIMUM MOL. WT. of the COMPOUND is `= (100)/(20) xx 14 = 70`.
Discussion
29.

An organic compound made of C , H and N contains 20% nitrogen. What will be its molecular mass if it contains only one nitrogen atom in it?

Answer»

70
140
100
65

Solution :`%N=("Mass of NITROGEN")/("Molecular mass")XX100`
`20=(14)/(m)xx100`
m=70
Discussion
30.

An organic compound made of C, H and N contain 20%nitrogen. Its minimum molecular weight is

Answer»

70
140
100
65

Solution :`%" of N"=("Mass of N")/("Molecular mass of compound")xx100`
the compound MUST CONTAIN at LEAST one N-atom.
Hence, `20=(14)/("Molecular mass")xx100`
`"or Molecular mass"=(14)/(20)xx100=70`
Note. If two N atoms are present in the molecule, molecular mass would be 140.
Discussion
31.

An organic compound is heated with HNO_(2) at 0^(@)C and then the resulting solution is added to a solution of beta-naphthol whereby a brilliant red dye is produced. The observations indicate that the compound possesses.

Answer»

`-NO_(2)` group
`-CONH_(2)` group
Aromatic `NH_(2)` group
Aliphatic `NH_(2)` group.

Solution :
Hence choice (c ) is correct(a) is incorrect.
Aliphatic p-and `s-NO_(2)` groups react with `HNO_(2)` but not with `BETA`-napththol.
`-UNDERSET(O)underset(||)C-NH_(2)`group react with `HNO_(2)` and produces `N_(2)` gas and does not react with `beta`-naphthol. Hence choice(b) is incorrect An aliphatic amine reacts with `HNO_(2)` and produces alcohol. Here first an aliphatic diazonium SALT is formed which being unstable immediately reacts with `H_(2)O` to form alcohol. While aromatic amines when they form diazonium salts are highly STABLE and hence can be used to diazonium salts are highly stable and hence can be used to take part in dizonium caupling reactions. Hence choice (d) is incorrect.
Discussion
32.

An organic compound is fused with sodium metal and crushed in water. The solution thus obtained when treated with freshly prepared ferric chloride solution gives blood red color solution. The test confirms

Answer»

Presence of `S` in the organic COMPOUND.
Presence of `O` in the organic compound
Presence of `N` and `O` in the organic compound
Presence of `N` and `S` in the organic compound

Solution :If organic compound has both `N` and `S`, then the LASSAIGNE's extract has `SCN^(-)` ION which form blood red color solution with `FE^(3+)` ion.
`Fe^(3+) + SCN^(-) rarr [Fe(SCN)]^(2+)`
Discussion
33.

An organic compound is fused with fusion mixture and extracted with HNO_3.The extract gives yellow precipitate with ammonium molybdate. It shows the presence of which element :

Answer»

<P>P
As
Both P and As
MAY be p or As or both

ANSWER :D
Discussion
34.

An organic compound is boiled with alcoholic potash. The product is cooled and acidified with HCI. A white solid separates out. The starting compound may be

Answer»

ETHYL benzoate
ethyl FORMATE
 ethyl ACETATE
 METHYL acetate,

ANSWER :A
Discussion
35.

An organic compound is adsorbed on the surface of silica gel. Name the process of removing the organic compound from silica gel.

Answer»

SOLUTION :DESORPTION.
Discussion
36.

An organic compound having the molecular formula C_5H_(10)O_3 on hydrolysis in the presence of Zn, gives acetone and acetaldehyde. Write the structure of the organic compound.

Answer»

Solution :The molecular formula of the compound is `C_(5)H_(10)O_(3) = C_(n)H_(2n) O_(3) (n=5)`, l.e., the compound is an addition compound of an ALKENE and `O_(3)`. The compound, on reductive hydrolysis, produces acetone and acetaldehyde. Hence, the compound must be an alkene ozonide. The STRUCTURE of the alkene obtained by writing the carbonyl compound side by side FACING carbonyl groups with RESPECT to each other followed by removing the two oxygen atoms and joining the two carbonyl CARBONS by a double bond. So the compound is 2-methylbut-2-ene.
`underset("Acetone")(CH_(3) - overset(overset(CH_(3))(|))(C) = O) + underset("Acetaldehyde")(O = overset(overset(H)(|))(C) - CH_(3)) rArr underset("2-methylbut-2-ene")(CH_(3) - overset(overset(CH_(3))(|))(C) = CHCH_(3))`
Discussion
37.

An organic compound having molecular mass 60 is found to be contain C=20%., H=6.67 % and N=46.67% while rest is oxygen. On heating it gives NH_(3) along with a solid residue. The solid residue give violet colour with alkaline copper sulphate solution. the compound is

Answer»

`CH_(3)CH_(2)CONH_(2)`
`(NH_(2))_(2)CO`
`CH_(3)CONH_(2)`
`CH_(3)NCO`

Answer :B
Discussion
38.

An organic compound having the molecular formula C_(2)H_(4)O_(2) is

Answer»

formic ACID
acetic acid
ethyl acetate
propionic acid

SOLUTION :`C_(2)H_(4)O_(2)`have two isomers,
`(i) CH_(3)COOH,""(ii) HCOOCH_(3)`
Discussion
39.

An organic compound having molecular mass 60 is fond to contain C=20%, H=6.67% and N=46.67% while rest is oxygen. On heating it gives NH_(3) alongwith a solid residue. The solid residue gives violet colour with alkaline copper sulphate solution. the compound is

Answer»

`CH_(3)NCO`
`CH_(3)CONH_(2)`
`(NH_(2))_(2)CO`
`CH_(3)CH_(2)CONH_(2)`

Solution :`{:("Element","Percentage","Mole","Mole RATIO"),(C,20,20//12=1.66,1),(H,6.67,6.67//1=6.67,4),(N,46.67,(46.67)/(14)=3.33,2),(O,26.66,26.6//16=1.66,1):}`
Empirical FORMULA `=CH_(4)N_(2)O`
Out of these urea on heating gives a solid residue called biuret which gives violet colour with alkaline `CuSO_(4)` solution.
`underset("Urea")(NH_(2)CONH_(2)+H)NHCONH_(2) to underset("Biuret")(NH_(2)CONHCONH_(2))+NH_(3)`
Discussion
40.

An organic compound having molecular formula C_(5)H_(10)O exixts in two chain ismors. (A) and (B). Iosomer (A) undergoes the Cannizzaro's reaction to give 2,2dimethyl propanic acid and 2,2dimethyl propan-1-ol. Compound (B) in the presence of dilute alkali undergoes aldol condensation to from 3-hydroxy-2-proplheptanal. Give graphi representation of (A) and (B)

Answer»

Solution :ISOMER have formula `C_(4)H_(9)CHO`.
(A) undegoes Cannizaro' reaction, thus it does not have `alpha` hydrogen. The rstructure of f(A) is `(CH_(3))_(3)C CHO`
`(CH_(3))_(3)underset((A))(C)-CHOoverset(NaOH)rarrunderset(2,2-"Dinethylpropanoic acid")((CH_(3))_(3)C-COOH)+underset(2,2-"Dimethylpropan-1-ol")((CH_(3))_(3)-CH_(2)OH)`
(B) undergoes ALDOL CONDENSATION, it possesses `alpha`- hydrogen atom. The structure of (B) is `CH_(3)CH_(2)CH_(2)CHO`
`CH_(3)CH_(2)underset((B))(CH_(2))CH_(2)CHO+H-underset(CHO)underset(|)(CH)CH_(2)CH_(2)CH_(3)rarrCH_(3)CH_(2)CH_(2)CH_(2)underset(3-"Hydroxy-2-propylheptanal")underset(OH)underset(|)(CH)-underset(CHO)underset(|)(CHCH_(2))CH_(2)CH_(3)`
Discussion
41.

An organic compound having molecular formula C_5H_(10) O exists in two chain isomers, (A) and (B).Isomer (A) undergoes Cannizzaro reaction to give 2, 2- dimethyl propanoic acid 2,2- dimethyl propanol - 1. Compound (B) in the presecne of dilute alkali undergeos aldol condensation to form 3 - hydroxy -2- propyl heptanal. Give the structures of (A) and (B).

Answer»

Solution :ISOMERS have the FORMULA, `C_(4)H_(9)CHO`. Isomer (A) undergoes Cannizzaro reaction, thus it does not have `alpha`-hydrogen. The structure of (A) is `(CH_(3))_(3)C CHO`.
`(CH_(3))_(3)C CHO overset(NaOH)RARR (CH_(3))_(3)C COOH+ (CH_(3))_(3)C CH_(2)OH`
Isomer (B) undergoes aldol condensation as it possesses `alpha`-hydrogen ATOM. The structure of (B) is `CH_(3)CH_(2)CH_(2)CH_(2)CHO`.
Discussion
42.

An organic compound having molecular, C_(4)H_(10)Odoes not react with metallic sodium. On heating this compound with excess of constant boiling HI (density 1.7 g/mL) in a sealed tube, yields ethyl iodide as the only organic compound. What is the organic compound?

Answer»

SOLUTION :(i) Since the compound with M.F. `C_(4)H_(10)O` does not REACT with metallic solution, it cannot be an alcohol
(ii) Since on heating with excess of HI in a sealed TUBE, it gives ETHYL iodide as the only organic compound, therefore, it must be diethyl ether.
`underset("Diethyl ether")(CH_(3)CH_(2)-O-CH_(2)CH_(3))+2HI overset(Delta)to underset("Ethyl iodide")(2CH_(3)CH_(2)-I)+H_(2)O`
Discussion
43.

An organic compound having C,H and sulphur contains 4% of sulphur. The minimum molecular weight of compound is

Answer»

200
400
600
800

Solution :`%` of `S = ("WT. of 1 sulphur atom")/(" Minimum mol. Wt.") xx 100`
`4 = (32)/(" Minimum mol.wt.") xx 100`
Minimum mol. Wt =` 800 g mol^(-1)`
(a) , (B) and (c ) are not POSSIBLE.
Alternate Method: A compound MUST have at leat one atom of S i.e, `32g` of S.
4gof sulphur is PRESENT in 100 g of compound.
`32g` of sulphur will be present in `(100)/(4) xx 32 = 800 g mol^(-1)`.
Discussion
44.

An organic compound has the formula C4H10O. It reacts with metallic sodium liberating hydrogen. (i) Write down the formula of three possible isomers of the compound which are similar and react with sodium. (ii) What will be the product if any one of the isomers reacts with acetic acid ?

Answer»

Solution :The three ISOMERS are
(i) `CH_(3)CH_(2)CH_(2)CH_(2)OH`
`CH_(3)CH(OH)CH_(2)CH_(3)`
`CH_(3)-underset(CH_(3))underset("|")"CH"-CH_(2)OH`
(II) `CH_(3)CH_(2)CH_(2)CH_(2)OH +CH_(3)COOH rarr CH_(3)CH_(2)CH_(2)CH_(2)OOC CH_(3)`
Discussion
45.

An organic compound has C and H percenatage in the ratio 6 : 1 and C and O percentage in the ratio 3 : 4 .The compound is :

Answer»

HCHO
`CH_3OH`
`CH_3CH_2OH`
`(COOH)_2`

ANSWER :A
Discussion
46.

An organic compound does not reacts with Tollen's reagent but undergoes Baeyer Villiger oxidation. The compound is

Answer»

`CH-=C-CH_(2)COCH_(3)`

`CH_(3)CHO`
`CH_(3)-underset(O)underset(||)(C)-CH_(3)`

Answer :D
Discussion
47.

An organic compound does not give a precipitate with 2,4 - DNP and does not react with sodium metal . It could be

Answer»

`CH_(3) - CH_(2) - CHO`
`CH_(3) COCH_(3)`
`CH_(3) - CHO`
`CH_(3) OC_(2)H_(5)`

ANSWER :D
Discussion
48.

An organic compound dissolved in dry benzene evolved hydrogen on treatment with sodium .It is

Answer»

A ketone
An aldehyde
A TERTIARY amine
An ALCOHOL

Solution :Alcohol + `underset("(dry)")("Benzene")to` SOLUBLE
(Alcohol) `R-OH+Na to R -O"N"a + H_(2)`
Discussion
49.

An organic compound dissolved in dry benzene evolved hydrogen on treatment with sodium. It is :

Answer»

A ketone
An aldehyde
A TERTIARY amine
An alcohol

Answer :D
Discussion
50.

An organic compound crystallises in an orthorhombic cell in the ratio of 2 : 1. The dimensions of cell are 12.05, 15.05 and 2.69Å and density is 1.419g//cm^(3). Molar mass of the compound is-

Answer»

`207g*MOL^(-1)`
`209g*mol^(-1)`
`308g*mol^(-1)`
`317g*mol^(-1)`

ANSWER :B
Discussion