1.

An organic compound % of C and % of H in the ratio 6 : 1 and % of Cand % of O in the ratio 3 : 4. The compound is

Answer»

`HCHO`
`CH_(3)OH`
`CH_(3)CH_(2)OH`
`(COOH)_(2)`

Solution :Let `%` of hydrogen is X then `%` of carbon is `6x` and `%` of OXYGEN is `8x`
i.e., `x+6x+8x=100 rArr x = (100)/(15)`
`C 600//15% rArr 40//12 = 3.3333 rArr 1`
`H 100//15% rArr 100//15 = 6.6667 rArr 2`
`O 800//15% rArr 50//15 = 3.333 rArr 1`
`CH_(2)O` is the empirical formula.


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