1.

An organic compound on analysis gave the following composition : C = 57.8% H = 3.6% and rest is oxygen. Its empirical formula is :

Answer»

`C_(4) H_(2)O_(3)`
`C_(4)H_(3)O_(2)`
`C_(2)H_(4)O_(6)`
`C_(3)H_(4)O_(2)`

ANSWER :B


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