Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

By which reaction phenol can be converted to O-hydroxy benzaldehyde ?

Answer»

Kolbe-Schmitt
Reimer-Tiemann
Wurtz
Cannizaro

Solution :Reimer-Tiemann
2.

By which reaction haxane can be prepared from 1 - chloropropane ?

Answer»

Wurtz reaction
Wurtz - FITTING reaction
FINKELSTEIN reaction
Swartz reaction

Answer :A
3.

By which reaction between monomer, the polymers are obtained ?

Answer»

Condensation
INTERNAL REACTION
HYDROLYSIS
By JOINING with EACHOTHER

Solution :By joining with eachother
4.

By which reaction. Best yield of H_(2) gas forms : Temperature of container is more than 100^(@)C

Answer»

By C only
By A, B only
By A, B, C only
None of these

Answer :D
5.

By which reaction best yield of H_(2) gas forms: temperature of all flask More then 100^(@)C

Answer»

Only By D
Only By A & B
Only By A, B & C
In all process

Solution :SN react with WATER to PRODUCE hydrogen gas.
6.

By which reaction formation of hard water takes place : (a) Ca(CH)_(2)+2HCl (b) NaOH+HCl (c) KOH+HCl (d) NaOH+H_(2)CO_(3)

Answer»

By only d
By only a
By a, B, C
By all process

Solution :Hardness of WATER ARISES due to presence of `CaCl_(2),CaSO_(4),MgCl_(2),MgSO_(4),CA(HCO_(3))_(2)Mg(HCO_(3))_(2)" only "Ca(OH)_(2)+2HClrarr CaCl_(2)+H_(2)O`
7.

By which process phenyl acetate can be converted in to hydroxy acetophenone ?

Answer»

FRIES REARRANGMENT
Reimer-Tiemann process
Kolbe-Schmitt reaction
Acetylation

Solution :Fries rearrangment
8.

By which of the following reactions, chlorine gas will not be obtained as the product ?

Answer»

Oxidation of HCl by `MnO_(2)`
Oxidation of HCl by `KMnO_4`
Oxidation of `KClO_3` by `KMnO_4`
By electrolysis of CONCENTRATED AQUEOUS SOLUTION of NaCl.

Answer :C
9.

By which one among the following mechanism , soap removes dirt (soil) from cloth ?

Answer»

Soap dissolves the soil as such
Soan reacts with soil and converts them into SOLUBLE silicates
Soap TAKES away the oily part of the soil and thus separates the soil from the cloth
The soap MOLECULES bind with the soil, lift the the soil and keep it suspended which can then be RINSED away

Solution :The soap molecules form micelle arround the dirt particles prevents them from coming together and form AGGREGATES, which form emulsion in water. The hand rubbing or the agitation cause dispersion of the dirt particles throughout the soapy water. These are washed away with water along the with dust particles. in this way dirt are removed from the surface of the cloth.
10.

Bywhichof thefollowingreagents , butanoicacidcan beconvertedintobutane ?

Answer»

RED p/HI
NaOh/CaO
`CH_(3)MGBR`
All of these

ANSWER :A
11.

By which of the following reactions, ether compound will be obtained easily ?

Answer»

`(CH_(3))_(3)CONA+CH_(3)CL to`
`(CH_(3))_(3)CONa+ (CH_(3))_(3)C-Cl to`
`(CH_(3))_(3)CONa+(CH_(3))_(2)CHCl to`
`(CH_(3))_(3)CHONa+ (CH_(3))_(2)CHCl to`

Solution :`(CH_(3))_(3)CONa+CH_(3)Cl to`
12.

By which of the following reactions can MIC (methyl isocyante) be obtained?

Answer»

`CH_(3)-OVERSET(o+)(N)-= overset(ɵ)C + HGO rarr`
`CH_(3)-overset(o+)(N)-= overset(ɵ)C + O_(3) rarr`
`CH_(3)-overset(o+)(N)-= overset(ɵ)C + S rarr`
`CH_(3)-overset(o+)(N)-= overset(ɵ)C + DMSO rarr`

ANSWER :A::C::D
13.

By which of the following reaction seequence can nylon-5be prepared?

Answer»




All

Answer :A::C
14.

By which of the following methods, sulphur sol can be prepared ?

Answer»

Oxidation 
DISSOLUTION 
EXCHANGE of solvent
All the GIVEN THREE OPTIONS 

Solution :All the given three options
15.

By which of the following methods, H_(2)O_(2) can't be synthesised?

Answer»

LEWIS ADDITION of ice cold `H_(2)SO_(4)` on `BaO_(2)`
Addition of ice cold `H_(2)SO_(4)` on `PbO_(2)`
Aerial oxidation of 2-ethyl anthraquinol
Electrolysis of `(NH_(4))_(2)SO_(4)` at a high current density

Solution :`H_(2)SO_(4)+PbO_(2) to PbSO_(4) DARR+(1)/(2)O_(2)+H_(2)O` (`PbO_(2)` is not peroxy compound)
`H_(2)SO_(4)+BaO_(2) to BaSO_(4) darr+H_(2)O_(2)`

`(NH_(4))_(2)SO_(4) hArr 2NH_(4)^(+)+SO_(4)^(2-)`
At anode: `2SO_(4)^(2-) overset("Electrolysis")toS_(2)O_(8)^(2-)+2e^(-)`
Peroxo SULPHATE hydrolysis, produces `H_(2)O_(2)`
16.

By which of the following PHBV will degrade ?

Answer»

ENZYMES
BACTERIA
OXIDATION
HYDROLYSIS

SOLUTION :Bacteria
17.

By which of the following method, H_2O_2 cannot be synthesised?

Answer»

ADDITION of `H_2SO_4` on `BaO_2`
Addition of `H_2SO_4` on `PbO_2`
Aerial oxidation of 2-ethyl anthraquinol
Electrolysis of `(NH_4)_2SO_4` at a HIGH CURRENT density.

Answer :B
18.

By which of the following blue colour is obtained while adding hydrogen paroxide (H_(2)O_(2)) in acidic potassium dichromate?

Answer»

`CrO_(3)`
`Cr_(2)O_(3)`
`CrO_(5)`
`CrO_(4)^(2-)`

ANSWER :C
19.

By which method oxygen and nitrogen present in the form of impurities in Zirconium are removed ?

Answer»

VAN Arkel 
ROASTING 
LIQUATION 
DISTILLATION 

ANSWER :A
20.

By which method phosphorous colloid can be prepared?

Answer»

DECOMPOSITION
EXCHANGE of SOLVENT
Hydrolysis
Reduction

Solution :Exchange of solvent
21.

By which law, energy produced in nuclear reaction is given

Answer»

GRAHAM's law
Charle's law
Gas Lussac's Law
Einstein's law

Solution :Einstein's law is `E = MC^(2)`
22.

By which mechanism (C_(6)H_(5))_(2) CHCl will undergo hydrolysis?

Answer»

Solution :Since `(C_(6)H_(5))_(2)CHCL` can form were stable carboncation, it will UNDERGO hydrolysis by `SN^(1)` mechanism.
23.

By which enzyme, the lactose is hydrolysed ?

Answer»

INVERTASE
Emulsin
MALTASE
Zymase

Solution :Emulsin
24.

By which bond, the polypeptide chains are joined in tertiary structure of protein ? [P] Van der Waal's attraction [QI H-bond [R] Ionic bond [S] Disulphide bond

Answer»

<P>P and Q
P, Q and S
Only Q
P, Q, R and S

SOLUTION :P, Q, R and S
25.

By what type of reaction do the common antacids destroy the excess acid of the stomach ?

Answer»

SOLUTION :By acid-base NEUTRALISATION REACTION.
26.

By what fraction the Ea should be decreased in orderto increase the rate by 10 times at 300 K (initial Ea=8.314kJ/mol) by use of a catalyst?

Answer»

0.79
0.84
0.76
0.69

Solution :`(r_(2))/(r_(1))=(K_(2))/(K_(1))=(a.E^(-EPSILON a_(2)//RT_(2)))/(A.e^(Ea_(1)//RT_(1)))to` cat
`to` Not cat: ` (10r)/r=(A.e^(epsilona_(2)//RT))/(A.e^(-epsilona_(1)//RT)),2.303xxlog_(10)^(10)=In[e^(((-epsilona_(2)+epsilona_(1))/(RT)))]`
`2.303xx1=(-epsilon_(a_(2))+epsilon_(a_(1)))/(RT),(DeltaE_(a))/(epsilon_(a_(1)))=(2.303xx8.314xx300)/(8.314xx1000)=0.6909,(DeltaE_(a))/(epsilon_(a_(1)))=0.6909`
`25^(@)Cto35^(@)Cto45^(@)Cto55^(@)C`
27.

By using the following data draw an appropriate enthalpy cycle & Calculate the enthalpy change of hydration of (i) the chloride ion , (ii) the iodide ion. Comment on the difference in their values. {:(**,,"enthalpy change of solution of "NaCl(s)=-2" kJ/mol."),(**,,"enthalpy change of solution of "NaI(s)=+2" kJ/mol."),(**,,"enthalpy change of hydration of "Na^(+)(g)=-390" kJ/mol."),(**,,"lattice anthalpy of "NaCl=-772" kJ/mol."),(**,,"lattice enthalpy of "NaI=-699" kJ/mol."):}

Answer»


SOLUTION :(i) `-2=722-390+x` [Where x= Ethalpy change of hydration of IODINE ion]
`x=-384" KJ MOL"^(-1)`
(ii) `2=699-390+x""`[x= Ethalpy change of hydration of iodide ion]
`x=-307" kJ mol"^(-1)`
28.

By using the following data draw an appropriate energy cycle & calculate the enthalpy change of hydration of (i) the chloride ion , (ii) the iodide ion. comment on the difference in their values. M enthalpy change of solution of NaCl(s) = – 2 kJ/ mol enthalpy change of solution of Nal (s) = +2 kJ/mol enthalpy change of hydration of Na+(g) = –390 kJ/mol lattice energy of NaCl = – 772 kJ/mol lattice energy of NaI = –699 kJ/mol.

Answer»

SOLUTION :for `CL^(-) - 384 KJ mol^(-1)` , for `I^(-) - 307 kJ mol^(-1)`
29.

By warming a paste of bleaching powder with a solution of ammonia we get:

Answer»

`H_2`
`N_2`
`N_2O_3`
`N_2O_4`

ANSWER :B
30.

By treating acetic acid with an etheral solution of diazomethane, it forms

Answer»

methyl acetate
ETHYL acetate
acetamide
ACETIC ANHYDRIDE

ANSWER :A
31.

By use of which free radical reactive intermediate, emulsion type SBR is obtained ?

Answer»

Alkyl MERCAPTAN and water
Alkyl LITHIUM
Ziegler NATTA
Peroxideahetal

SOLUTION :Alkyl mercaptan and water
32.

By the reaction of carbon and oxygen , a mixture of CO and CO_(2) is obtained . What is the composition (% by mass)of the mixture obtained when 20 gm of O_(2) reacts with 12 gm of carbon ?

Answer»


ANSWER :`%CO=65.625;%CO_(2)=34.375`
33.

By the overall order of a reaction , we mean

Answer»

The number of concentration terms in the equation for the reaction
The SUM of powers to which the concentration terms are RAISED in the velocity equation
The least number of MOLECULES of the reactants needed for the reaction
The number of reactants which take PART in the reaction

Solution :The overall order of a reaction is sum of powers raised on concentration terms in order to write RATE expression.
34.

By the reaction between 3 mole ethanol and 1 mole PBr_(3) the product obtained are 3 mole bromo ethane and 1 mole X, What is X ?

Answer»

`H_(3)PO_(4)`<BR>`H_(3)PO_(2)`
`H_(3)PO_(3)`
`HPO_(3)`

SOLUTION :`underset("Ethanol")(3CH_(3).CH_(2).OH )OVERSET(PBr_(3))to underset("Bromo ethane")(3CH_(3)CH_(2) .Br+ H_(3)PO_(3))`
35.

By the order of reaction we mean __________

Answer»

the sum of powers to which the concentration terms are raised in the rate equation
the number of reactants take part in the reaction
the number of concentration terms in the VELOCITY equation for the reaction
the LEAST number of PRODUCT MOLECULE NEEDED for the reaction

Answer :A
36.

By the catalytic combination of ammonia and carbon monoxide under high pressure, it forms:

Answer»

`CH_(3)CONH_(2)`
`CO_(2) + NH_(3)`
`HCONH_(2)`
`CH_(3)COOH+NH_(3)`

Answer :A
37.

By the additionof 3% to 10% sulphurin rubber

Answer»

SOFT rubber is OBTAINED
hard rubberis obtained
no changetakes place
solublerubberis obtained.

Solution :Addition of 3-10% SULPHUR to rubber , MAKES it hard.
38.

By the action of enzymes, the rate of biochemical reaction

Answer»

Decreases
Increases
Does not CHANGE
Either (a) or (C)

ANSWER :B
39.

By the action of malonic acid in ethanolic ammonia on benzaldehyde in the presence of pyridine, it forms :

Answer»

BENZOIC acid
PHENYL acetic acid
cinnamic acid
phthalic acid

Answer :C
40.

By the action of concentrated hydrochloric acid on potassium chlorate we get this mixture of gases:

Answer»

`CO_2 + Cl_2`
`O_2 + ClO_2`
`Cl_2 + ClO_2`
`O_2 + Cl_2 + ClO_2`

ANSWER :C
41.

By the action of concentrated sodium hydroxide on benzaldehyde, the benzyl alcohol and sodium benzoate is obtained. The reaction is knownas

Answer»

Perkin's reaction
CANNIZZARO's reaction
Sandmeyer's reaction
Clasien CONDENSATION

ANSWER :B
42.

By the action of CH_3I on sodium ethoxide, we get

Answer»

`CH_3COOCH_3`
`CH_3COC_2H_5`
`CH_3OC_2H_5`
ETHYL acetate

Answer :C
43.

By the action of bromine and caustic potash on propionamide we get:

Answer»

METHYL amine
ETHYL amine
Propyl amine
Methyl ethyl amine

Answer :B
44.

By reaction with which reagent phenol will convert into salicyldehyde ?

Answer»

`CHCl_(3)+ NaOH`
`SiO_(2)+ NaOH`
`CHBr_(3)+ KBrO_(3)`
`KCIO+ HCIO_(4)`

Solution :`CHCl_(3)+ NaOH`
45.

By reaction of propene with which of the following, propane 1-ol can be obtained ?

Answer»

`H_(3)BO_(3)`
`B_(2)H_(6)//NaOH, H_(2)O_(2)`
`H_(2)SO_(4)//H_(2)O`
`CH_(3)-underset(O)underset(||)-O-O-H`

SOLUTION :`underset("PROPENE ")(CH_(3)-CH=CH_(2)) underset(NaOH)overset(OH^(-))to (CH_(3)CH_(2)CH_(2))_(3) B underset(H_(2)O_(2))overset(OH^(-))to underset("Propane-1-ol")(3CH_(3)CH_(2)CH_(2)OH)`
46.

By passing X-rays through copper sulphate crystals diffraction band is obtained. It was first observed by

Answer»

MAX VAN Laue
W.L Bragg
W.H. Bragg
W.L.Bragg & W.H.Bragg 

ANSWER :A
47.

By passing water gas (CO + H_2) through an electric discharge at low pressure, we get :

Answer»

HCHO
HCOOH
`CH_3CHO`
`CO_2` and `H_2O`

ANSWER :A
48.

By passing H_(2)S gas in acidified KMnO_(4) solution, we get

Answer»

`K_(2)S`
`S`
`K_(2)SO_(3)`
`MnO_(2)`

SOLUTION :`2KMnO_(4)+3H_(2)SO_(4) to K_(2)SO_(4)+2MnSO_(4)+5S+8H_(2)O`
49.

By passing SO_2 in solution of K_2Cr_2O_7. It turns green due to the formation of:

Answer»

`K_2CrO_4`
CHROMIUM sulphate
Chromic sulphate
None of these

Answer :C
50.

Only which one of the following compounds is obtained whwn excess of Cl_2(g) is passes through boiling toluene

Answer»




SOLUTION :