1.

By what fraction the Ea should be decreased in orderto increase the rate by 10 times at 300 K (initial Ea=8.314kJ/mol) by use of a catalyst?

Answer»

0.79
0.84
0.76
0.69

Solution :`(r_(2))/(r_(1))=(K_(2))/(K_(1))=(a.E^(-EPSILON a_(2)//RT_(2)))/(A.e^(Ea_(1)//RT_(1)))to` cat
`to` Not cat: ` (10r)/r=(A.e^(epsilona_(2)//RT))/(A.e^(-epsilona_(1)//RT)),2.303xxlog_(10)^(10)=In[e^(((-epsilona_(2)+epsilona_(1))/(RT)))]`
`2.303xx1=(-epsilon_(a_(2))+epsilon_(a_(1)))/(RT),(DeltaE_(a))/(epsilon_(a_(1)))=(2.303xx8.314xx300)/(8.314xx1000)=0.6909,(DeltaE_(a))/(epsilon_(a_(1)))=0.6909`
`25^(@)Cto35^(@)Cto45^(@)Cto55^(@)C`


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