1.

By using the following data draw an appropriate enthalpy cycle & Calculate the enthalpy change of hydration of (i) the chloride ion , (ii) the iodide ion. Comment on the difference in their values. {:(**,,"enthalpy change of solution of "NaCl(s)=-2" kJ/mol."),(**,,"enthalpy change of solution of "NaI(s)=+2" kJ/mol."),(**,,"enthalpy change of hydration of "Na^(+)(g)=-390" kJ/mol."),(**,,"lattice anthalpy of "NaCl=-772" kJ/mol."),(**,,"lattice enthalpy of "NaI=-699" kJ/mol."):}

Answer»


SOLUTION :(i) `-2=722-390+x` [Where x= Ethalpy change of hydration of IODINE ion]
`x=-384" KJ MOL"^(-1)`
(ii) `2=699-390+x""`[x= Ethalpy change of hydration of iodide ion]
`x=-307" kJ mol"^(-1)`


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