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सिद्ध कीजिए कि `"cosec "10^(@)-sqrt3. sec10^(@)=4` |
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Answer» बायाँ पक्ष `="cosec 10"^(@)-sqrt3.sec 10^(@)` `=(1)/(sin 10^(@))-sqrt3.(1)/(cos 10^(@))` `=(cos 10^(@)-sqrt3 sin 10^(@))/(sin 10^(@).cos10^(@))=(2((1)/(2)cos 10^(@)-(sqrt3)/(2)sin10^(@)))/(2sin10^(@)cos10^(@))` `=2xx2((sin 30^(@)cos10^(@)-cos 30^(@)sin10^(@))/(2sin10^(@)cos10^(@)))` `=(4sin(30^(@)-10^(@)))/(sin 20^(@))` `=(4sin 20^(@))/(sin 20^(@))=4=` दायाँ पक्ष |
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