67486 + Interview Questions in Secondary School in Physics

1.	Annemalies of modern periodic table
Answer» Hey there! Here is the answer for your question! ≫ ──── ≪•◦ ❈ ◦•≫ ──── ≪ Q) Anomalies of MODERN PERIODIC table ≫ ──── ≪•◦ ❈ ◦•≫ ──── ≪ Answer:- # In the modern periodic table there are two anomalies that stand out these are: The position of the element HYDROGEN is not fixed in the modern periodic table. Lanthanoids and Actinoids are placed outside the periodic table in two SEPARATE columns. ≫ ──── ≪•◦ ❈ ◦•≫ ──── ≪ Hope this helped with your DOUBT :)

1.

Annemalies of modern periodic table

Answer»

Hey there!

Here is the answer for your question!

≫ ──── ≪•◦ ❈ ◦•≫ ──── ≪

Q) Anomalies of MODERN PERIODIC table

≫ ──── ≪•◦ ❈ ◦•≫ ──── ≪

Answer:-

# In the modern periodic table there are two anomalies that stand out these are:

The position of the element HYDROGEN is not fixed in the modern periodic table.
Lanthanoids and Actinoids are placed outside the periodic table in two SEPARATE columns.

≫ ──── ≪•◦ ❈ ◦•≫ ──── ≪

Hope this helped with your DOUBT :)

Discussion

2.	Write 4 differences between Momentum and Impulse.no spam plzzzzzz _/\_no faltu answers....xD xD explanation bhi aacha hona chahiye xD
Answer» Answer: $\huge \underline{ \rm \red{hello}}$ QUESTION:- Write 4 differences between MOMENTUM and Impulse. __________________________________ Answer:- $\: \: \: \: \: \: \: \: \boxed{ \fcolorbox{blue}{yellow}{momentum}}$ the product of the mass of a body and its velocity is called the momentum of the body. Momentum = Mass × velocity. SI unit of momentum is kilogram meter per second kg⋅m/s. Momentum is a VECTOR quantity. $\: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \fcolorbox{blue}{yellow}{impulse}}$ The Impulse of a force ACTING on a body is equal to the product of the force and the time for which it acts on the body. Impulse = Force × Time. SI unit of impulse is kilogram meter per second. Impulse is a scalar quantity.

2.

Write 4 differences between Momentum and Impulse.no spam plzzzzzz _/\_no faltu answers....xD xD explanation bhi aacha hona chahiye xD

Answer»

Answer:

$\huge \underline{ \rm \red{hello}}$

QUESTION:-

Write 4 differences between MOMENTUM and Impulse.

__________________________________

Answer:-

$\: \: \: \: \: \: \: \: \boxed{ \fcolorbox{blue}{yellow}{momentum}}$

the product of the mass of a body and its velocity is called the momentum of the body.

Momentum = Mass × velocity.
SI unit of momentum is kilogram meter per second kg⋅m/s.
Momentum is a VECTOR quantity.

$\: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ \fcolorbox{blue}{yellow}{impulse}}$

The Impulse of a force ACTING on a body is equal to the product of the force and the time for which it acts on the body.

Impulse = Force × Time.
SI unit of impulse is kilogram meter per second.
Impulse is a scalar quantity.

Discussion

3.	Designing a system of fixed pulleys combined with levers for liftingAn object rises in two cases:a) Links with the pulley. b) an object connected to the lever.
Answer» Answer: a Explanation: OBJECT has to be linked with PULLEYS as livers are used to pull the OBJECTS

3.

Designing a system of fixed pulleys combined with levers for liftingAn object rises in two cases:a) Links with the pulley. b) an object connected to the lever.

Answer»

Answer:

a

Explanation:

OBJECT has to be linked with PULLEYS as livers are used to pull the OBJECTS

Discussion

4.	See the given pic and solve it
Answer» Answer: 1 MSD = 0.5 mm N ( VSD ) = ( N - 1 ) MSD 50 VSD = 49 MSD 1 VSD = 49 / 50 MSD = 49 / 50 × 0.5 :. Least count = 1 MSD - 1 VSD = 0.5 - 49 / 50 × 0.5 → ( 1 - 49 / 50 ) 0.5 Least count = 1 / 50 × 0.5 = 0.01 mm The minimum inaccuracy in the MEASUREMENT of DISTANCE = 0.01 mm

4.

See the given pic and solve it

Answer»

Answer:

1 MSD = 0.5 mm

N ( VSD ) = ( N - 1 ) MSD

50 VSD = 49 MSD

1 VSD = 49 / 50 MSD = 49 / 50 × 0.5

:. Least count = 1 MSD - 1 VSD = 0.5 - 49 / 50 × 0.5

→ ( 1 - 49 / 50 ) 0.5

Least count = 1 / 50 × 0.5 = 0.01 mm

The minimum inaccuracy in the MEASUREMENT of DISTANCE = 0.01 mm

Discussion

5.	if a freely falling body covers 36% of the total height in the last second then what is the total height covered by the body
Answer» ANSWER: 125m Explanation: PLEASE MARK my answer as BRAINLIEST and FOLLOW me

5.

if a freely falling body covers 36% of the total height in the last second then what is the total height covered by the body

Answer»

ANSWER:

125m

Explanation:

PLEASE MARK my answer as BRAINLIEST and FOLLOW me

Discussion

6.	Help me with this..
Answer» ANSWER: this is your CORRECT answer

6.

Help me with this..

Answer»

ANSWER:

this is your CORRECT answer

Discussion

7.	Can u help me find this answer?1)Velocity of sound in the atmosphere of a planet is 500ms^-1.The minimum distance between the source and sound and the obstate to hear the echo,should bea)17mb)20mc)25md)50m
Answer» Answer: EXPLANATION: Given, SPEED of sound = 500m/s Therefore the distance transversed by sound wave in one SECOND = 500m So, the distnace transversed by the sound wave in 1/10 sec =50.0m Since the sound wave has to travel the distance between source nd reflector twice to produce ECHO. So the minimum distance between source nd reflector required to produce echo = 50.0/2 = 25m

7.

Can u help me find this answer?1)Velocity of sound in the atmosphere of a planet is 500ms^-1.The minimum distance between the source and sound and the obstate to hear the echo,should bea)17mb)20mc)25md)50m

Answer»

Answer:

EXPLANATION:

Given,

SPEED of sound = 500m/s

Therefore the distance transversed by sound wave in one SECOND = 500m

So, the distnace transversed by the sound wave in 1/10 sec =50.0m

Since the sound wave has to travel the distance between source nd reflector twice to produce ECHO. So the minimum distance between source nd reflector required to produce echo = 50.0/2 = 25m

Discussion

8.	In which medium speed of sound is maximuma air b vaccume c water d solid
Answer» Answer: ď) in *SOLIDS* *the* *sound* *TRAVELS* *the* *fastest. HOPE it HELPS.....*

8.

In which medium speed of sound is maximuma air b vaccume c water d solid

Answer»

Answer:

ď) in SOLIDS the sound TRAVELS the fastest.

HOPE it HELPS.....

Discussion

9.	A vehicle with heavy load and a vehicle with less load are travelling in a road. when sudden brake is applied simultaneously for both the vehicles, which will come to rest first?
Answer» Answer: heavy load vehicle COMES to REST FIRST

9.

A vehicle with heavy load and a vehicle with less load are travelling in a road. when sudden brake is applied simultaneously for both the vehicles, which will come to rest first?

Answer»

Answer:

heavy load vehicle COMES to REST FIRST

Discussion

10.	The troops soldiers equipped to be dropped parachutes from an aircraft are called paratroopers. Why do paratroopers roll on landing
Answer» ANSWER: to DECREASE the FORCE of LANDING

10.

The troops soldiers equipped to be dropped parachutes from an aircraft are called paratroopers. Why do paratroopers roll on landing

Answer»

ANSWER:

to DECREASE the FORCE of LANDING

Discussion

11.	Our earth is moving in which motion is it
Answer» ANSWER: CIRCULAR motion.jdjdjdjjdjdhdhdhd

11.

Our earth is moving in which motion is it

Answer»

ANSWER:

CIRCULAR motion.jdjdjdjjdjdhdhdhd

Discussion

12.	In the wilfley table method the particles of gangue are separated by ____ separation method
Answer» ANSWER: gravitational separation method Explanation: It is USED to separate the PARTICLES of gangue. Please don't forget to MARK me as the brainliest

12.

In the wilfley table method the particles of gangue are separated by ____ separation method

Answer»

ANSWER:

gravitational separation method

Explanation:

It is USED to separate the PARTICLES of gangue.

Please don't forget to MARK me as the brainliest

Discussion

13.	Write the four factors affecting the resistance of a conductor
Answer» ANSWER:Thickness(CROSS sectional AREA), LENGTH, temperature, material Explanation:

13.

Write the four factors affecting the resistance of a conductor

Answer»

ANSWER:Thickness(CROSS sectional AREA), LENGTH, temperature, material

Explanation:

Discussion

14.	How kinetic energy (E) of an electron is related to its De Broglie wavelength ?
Answer» Answer: K= PLANCKS CONSTANT* FREQUENCY + WORK function

14.

How kinetic energy (E) of an electron is related to its De Broglie wavelength ?

Answer»

Answer:

K= PLANCKS CONSTANT* FREQUENCY + WORK function

Discussion

15.	A physical quantity a is related to four observable x y z and m as follows A equal to xy/mz the percentage errors of measures in x y z and m are 4 % 3% 2% and 1% respectively what is the percentage error in the quantity A
Answer» Answer: Given: A RELATIONSHIP has been provided as follows : $\boxed{ \huge{ \sf{a = \dfrac{xy}{mz}}}}$ To find: Max error in "a" when error of each quantity has been given. Concept: Max error can be found by adding the error of each quantity MULTIPLIED with the respective exponential in the given Equation. Calculation: $\boxed{ \sf{ \red{ \frac{ \Delta a}{a} = \dfrac{ \Delta x}{x} + \dfrac{ \Delta y}{y} + \dfrac{ \Delta m}{m} + \dfrac{ \Delta z}{z}}}}$ $\sf{ \implies \dfrac{ \Delta a}{a} = 4 + 3 + <klux>1</klux> + 2}$ $\sf{ \implies \dfrac{ \Delta a}{a} = 10\%}$ So final answer : $\boxed{ \sf{max \: error = 10\%}}$ Additional information: For max error , always ADD the individual errors. Remember to MULTIPLY each term with exponential (here exponential was 1) Express the final answer in percentage.

15.

A physical quantity a is related to four observable x y z and m as follows A equal to xy/mz the percentage errors of measures in x y z and m are 4 % 3% 2% and 1% respectively what is the percentage error in the quantity A

Answer»

Answer:

Given:

A RELATIONSHIP has been provided as follows :

$\boxed{ \huge{ \sf{a = \dfrac{xy}{mz}}}}$

To find:

Max error in "a" when error of each quantity has been given.

Concept:

Max error can be found by adding the error of each quantity MULTIPLIED with the respective exponential in the given Equation.

Calculation:

$\boxed{ \sf{ \red{ \frac{ \Delta a}{a} = \dfrac{ \Delta x}{x} + \dfrac{ \Delta y}{y} + \dfrac{ \Delta m}{m} + \dfrac{ \Delta z}{z}}}}$

$\sf{ \implies \dfrac{ \Delta a}{a} = 4 + 3 + <klux>1</klux> + 2}$

$\sf{ \implies \dfrac{ \Delta a}{a} = 10\%}$

So final answer :

$\boxed{ \sf{max \: error = 10\%}}$

Additional information:

For max error , always ADD the individual errors.
Remember to MULTIPLY each term with exponential (here exponential was 1)
Express the final answer in percentage.

Discussion

16.	Complete the path A and B
Answer» Answer: [I HAVE ATTACHED PIC] The blue arrow and line SHOWS the REFLECTED part and direction. Explanation: In path A, the incident ray is PARALLEL to principal axis, hence after reflection it will pass through Focus (F). In path B, as the ray is passing through center of curvature , hence after reflection it will follow the same path from which it came. Hence it will pass through Center of Curvature (C).

16.

Complete the path A and B

Answer»

Answer:

[I HAVE ATTACHED PIC]

The blue arrow and line SHOWS the REFLECTED part and direction.

Explanation:

In path A, the incident ray is PARALLEL to principal axis, hence after reflection it will pass through Focus (F).

In path B, as the ray is passing through center of curvature , hence after reflection it will follow the same path from which it came. Hence it will pass through Center of Curvature (C).

Discussion

17.	Various layer in the soil ate called
Answer» ANSWER: SOIL PROFILE THANKYOU...........

17.

Various layer in the soil ate called

Answer»

ANSWER:

SOIL PROFILE

THANKYOU...........

Discussion

18.	Trees covered with many leaves are natural
Answer» Answer: yes not only TREES covered with LEAVES Explanation: everythin is natural.. even the the trees without leaves... treat them with CARE ND love theyll give U back care nd lovr

18.

Trees covered with many leaves are natural

Answer»

Answer:

yes not only TREES covered with LEAVES

Explanation:

everythin is natural.. even the the trees without leaves...

treat them with CARE ND love theyll give U back care nd lovr

Discussion

19.	Using calcus method prove that v²-u²=2as
Answer» We know that, acceleration, $\displaystyle\longrightarrow\sf{a=\dfrac{dv}{dt}}$ $\displaystyle\longrightarrow\sf{a=\dfrac{dv}{dx}\cdot\dfrac{dx}{dt}}$ $\displaystyle\longrightarrow\sf{a=\dfrac{dv}{dx}\cdot v}$ $\displaystyle\longrightarrow\sf{a\ dx=v\ dv}$ Now, before integration, integration is done for displacement from x = 0 to x = s. integration is done for velocity from u to v. Then, $\displaystyle\longrightarrow\sf{\int\limits_0^sa\ dx=\int\limits_u^vv\ dv}$ SINCE acceleration is independent of displacement (MOTION is not SIMPLE HARMONIC), $\displaystyle\longrightarrow\sf{a\big[x\big]_0^s=\left[\dfrac{v^2}{2}\right]_u^v}$ $\displaystyle\longrightarrow\sf{a(s-0)=\dfrac{v^2-u^2}{2}}$ $\displaystyle\longrightarrow\sf{as=\dfrac{v^2-u^2}{2}}$ $\displaystyle\longrightarrow\sf{\underline{\underline{v^2-u^2=2as}}}$ HENCE the Proof!

19.

Using calcus method prove that v²-u²=2as

Answer»

We know that, acceleration,

$\displaystyle\longrightarrow\sf{a=\dfrac{dv}{dt}}$

$\displaystyle\longrightarrow\sf{a=\dfrac{dv}{dx}\cdot\dfrac{dx}{dt}}$

$\displaystyle\longrightarrow\sf{a=\dfrac{dv}{dx}\cdot v}$

$\displaystyle\longrightarrow\sf{a\ dx=v\ dv}$

Now, before integration,

integration is done for displacement from x = 0 to x = s.

integration is done for velocity from u to v.

Then,

$\displaystyle\longrightarrow\sf{\int\limits_0^sa\ dx=\int\limits_u^vv\ dv}$

SINCE acceleration is independent of displacement (MOTION is not SIMPLE HARMONIC),

$\displaystyle\longrightarrow\sf{a\big[x\big]_0^s=\left[\dfrac{v^2}{2}\right]_u^v}$

$\displaystyle\longrightarrow\sf{a(s-0)=\dfrac{v^2-u^2}{2}}$

$\displaystyle\longrightarrow\sf{as=\dfrac{v^2-u^2}{2}}$

$\displaystyle\longrightarrow\sf{\underline{\underline{v^2-u^2=2as}}}$

HENCE the Proof!

Discussion

20.	The displacement of a particle having S.H.M.is x= 10 Sin 10ltfind:(i)Amplitude(ii) Angular Frequency(iii) Time Period(iv) Frequency(v) Maximum Velocity
Answer» ANSWER: TIME PERIOD..............

20.

The displacement of a particle having S.H.M.is x= 10 Sin 10ltfind:(i)Amplitude(ii) Angular Frequency(iii) Time Period(iv) Frequency(v) Maximum Velocity

Answer»

ANSWER:

TIME PERIOD..............

Discussion

21.	Find the value of acceleration due to gravity at a depth R/2 below the earths surface ?Answer = g/4But how ????Pls show the calculation too..
Answer» here is your ANSWER HOPE it HELPED !

21.

Find the value of acceleration due to gravity at a depth R/2 below the earths surface ?Answer = g/4But how ????Pls show the calculation too..

Answer»

here is your ANSWER

HOPE it HELPED !

Discussion

22.	Emission test for vehicle is made mandatory.Why?
Answer» Answer: In the year 2017, the Supreme Court of India mandated a PUC certificate for the renewal of a car INSURANCE policy. In order to make SURE that the vehicle owners undergo an EMISSION TEST to CHECK the emissions of the vehicle are under control or not, the Supreme Court made this rule.

22.

Emission test for vehicle is made mandatory.Why?

Answer»

Answer:

In the year 2017, the Supreme Court of India mandated a PUC certificate for the renewal of a car INSURANCE policy. In order to make SURE that the vehicle owners undergo an EMISSION TEST to CHECK the emissions of the vehicle are under control or not, the Supreme Court made this rule.

Discussion

23.	A bacak containing water is while in a verticalcircle of radius 75 cm. find max speed ofto of ensure that no water spills out.also find angular speed
Answer» Answer: gsgsgsg 's LUNAR ECLIPSE of the DAY in advance Happy BIRTHDAY Rounak best wishes from the beginning of a new phone number either of them and I don't want you to be in

23.

A bacak containing water is while in a verticalcircle of radius 75 cm. find max speed ofto of ensure that no water spills out.also find angular speed

Answer»

Answer:

gsgsgsg 's LUNAR ECLIPSE of the DAY in advance Happy BIRTHDAY Rounak best wishes from the beginning of a new phone number either of them and I don't want you to be in

Discussion

24.	A ball is thrown vertically upward attains a max height of 45m. The time after which the velocity of the ball become equal to half the velocity of projection?
Answer» ANSWER: HOPE it HELPS you.............

24.

A ball is thrown vertically upward attains a max height of 45m. The time after which the velocity of the ball become equal to half the velocity of projection?

Answer»

ANSWER:

HOPE it HELPS you.............

Discussion

25.	Wilfleys table parles of gang are seperated by which method.
Answer» ANSWER: it seperates by GRAVITATIONAL method atleast THANK

25.

Wilfleys table parles of gang are seperated by which method.

Answer»

ANSWER:

it seperates by GRAVITATIONAL method

atleast THANK

Discussion

26.	The acceleration of a particle moving along x- axis is a= -100x+50. It is released from x=2. Here a and x are in SI units. The speed of the particle at origin will be......
Answer» Answer: $a = 50 - 100x$ $= > <klux>V</klux> \dfrac{dv}{dx} = 50 - 100x$ $= > v \: dv = (50 - 100x)dx$ Integrating on both sides : $= > \int v \: dv = \int \: (50 - 100x)dx$ APPLYING GIVEN limits ( i.e. at X = 2m , the Velocity was 0 , and at x = 0 m , Velocity be v) $= > \int_{0}^{v} v \: dv = \int_{2}^{0} \: (50 - 100x)dx$ $= > \bigg \{ \dfrac{ {v}^{2} }{2} \bigg \}_{0}^{v} = \bigg \{50x - 50 {x}^{2} \bigg \}_{2}^{0}$ $= > \dfrac{ {v}^{2} }{2} = \{0 - (50 \times 2) \} - \{0 - (50 \times {2}^{2}) \}$ $= > \dfrac{ {v}^{2} }{2} = 200 - 100$ $= > \dfrac{ {v}^{2} }{2} = 100$ $= > {v}^{2} = 200$ $= > v = \sqrt{200}$ $= > v = 10 \sqrt{2} \: m {s}^{ - 1}$ So final answer : $\boxed{ \boxed{\sf{ \red{ \large{Velocity_{(at \: x = 0 \: m)} = 10 \sqrt{2} \: m {s}^{ - 1} }}}}}$

26.

The acceleration of a particle moving along x- axis is a= -100x+50. It is released from x=2. Here a and x are in SI units. The speed of the particle at origin will be......

Answer»

Answer:

$a = 50 - 100x$

$= > <klux>V</klux> \dfrac{dv}{dx} = 50 - 100x$

$= > v \: dv = (50 - 100x)dx$

Integrating on both sides :

$= > \int v \: dv = \int \: (50 - 100x)dx$

APPLYING GIVEN limits ( i.e. at X = 2m , the Velocity was 0 , and at x = 0 m , Velocity be v)

$= > \int_{0}^{v} v \: dv = \int_{2}^{0} \: (50 - 100x)dx$

$= > \bigg \{ \dfrac{ {v}^{2} }{2} \bigg \}_{0}^{v} = \bigg \{50x - 50 {x}^{2} \bigg \}_{2}^{0}$

$= > \dfrac{ {v}^{2} }{2} = \{0 - (50 \times 2) \} - \{0 - (50 \times {2}^{2}) \}$

$= > \dfrac{ {v}^{2} }{2} = 200 - 100$

$= > \dfrac{ {v}^{2} }{2} = 100$

$= > {v}^{2} = 200$

$= > v = \sqrt{200}$

$= > v = 10 \sqrt{2} \: m {s}^{ - 1}$

So final answer :

$\boxed{ \boxed{\sf{ \red{ \large{Velocity_{(at \: x = 0 \: m)} = 10 \sqrt{2} \: m {s}^{ - 1} }}}}}$

Discussion

27.	Explain joules temperature law
Answer» Joules LAWS are two: first about heat produced by an electric current and second about how the ENERGY of a gas RELATES to volume PRESSURE and temperature. Joules second law says that the internal energy an ideal gas does not CHANGE if the pressure and volume is changed,but does change when temperature changes. Mark My Answer Brainiest Follow me

27.

Explain joules temperature law

Answer»

Joules LAWS are two: first about heat produced by an electric current and second about how the ENERGY of a gas RELATES to volume PRESSURE and temperature. Joules second law says that the internal energy an ideal gas does not CHANGE if the pressure and volume is changed,but does change when temperature changes.

Mark My Answer Brainiest

Follow me

Discussion

28.	The rat and the elephant will be dropped off from a 20 story building at the same. Who will hit the ground first, the rat or the elephant?
Answer» ANSWER:no one Explanation: They are STILL to be DROPPED.

28.

The rat and the elephant will be dropped off from a 20 story building at the same. Who will hit the ground first, the rat or the elephant?

Answer»

ANSWER:no one

Explanation:

They are STILL to be DROPPED.

Discussion

29.	A rubber eraser 3 cm x 1 cm x 8 cm is clamped at one end with 8 cm edge as vertical. A horizontal force F =2.1 N is applied on the free surface. Shear modulus of rubber 1.4 x 105 Nm 2. Find the horizontal displacement (inmm) of the top face?(A). 1 mm(B).2 mm(C). 3 mm(D). 4 mm
Answer» HELLO FRIEND..!! The ANSWER of u r question is..!! Option.C Thank you..!!

29.

A rubber eraser 3 cm x 1 cm x 8 cm is clamped at one end with 8 cm edge as vertical. A horizontal force F =2.1 N is applied on the free surface. Shear modulus of rubber 1.4 x 105 Nm 2. Find the horizontal displacement (inmm) of the top face?(A). 1 mm(B).2 mm(C). 3 mm(D). 4 mm

Answer»

HELLO FRIEND..!!

The ANSWER of u r question is..!!

Option.C

Thank you..!!

Discussion

30.	Find the value of acceleration due to gravity at a depth R/2 below the earths surface ?A)g B)g/4 C)g/h D)g/2
Answer» B) g/4 This is your ANSWER

30.

Find the value of acceleration due to gravity at a depth R/2 below the earths surface ?A)g B)g/4 C)g/h D)g/2

Answer»

B) g/4

This is your ANSWER

Discussion

31.	If I travel from Mumbai to Pune (150 Km) in 21⁄2 hrs via the Express Highway [2] and return to Mumbai via the old High way (180 km) in 31⁄2 hrs, calculate the average velocity during the entire journey.
Answer» Answer: 0 Explanation: as you RETURNED back to the same place so DISPLACEMENT is zero so the average VELOCITY is zero so Vav = displacement/timetaken

31.

If I travel from Mumbai to Pune (150 Km) in 21⁄2 hrs via the Express Highway [2] and return to Mumbai via the old High way (180 km) in 31⁄2 hrs, calculate the average velocity during the entire journey.

Answer»

Answer:

0

Explanation:

as you RETURNED back to the same place so DISPLACEMENT is zero so the average VELOCITY is zero so Vav = displacement/timetaken

Discussion

32.	The ratio between cross product and dot product of two vectors will be 1 when the angle between them is
Answer» Answer: we KNOW that Cross product= a×b ab cosQ Dot product= a.b ab sinQ. since, (a×b)÷(a.b)=1 therefore, a×b=a.b ab cosQ=ab sinQ cosQ= sinQ we know that sinQ=cos(90-Q) replacing this in PREVIOUS equation, cosQ=cos(90-Q) Q=90-Q 2Q=90 Q=45° therefore ANGLE between the VECTORS should be 45°. Please mark it as BRAINLIEST

32.

The ratio between cross product and dot product of two vectors will be 1 when the angle between them is

Answer»

Answer:

we KNOW that

Cross product=

a×b

ab cosQ

Dot product=

a.b

ab sinQ.

since,

(a×b)÷(a.b)=1

therefore,

a×b=a.b

ab cosQ=ab sinQ

cosQ= sinQ

we know that

sinQ=cos(90-Q)

replacing this in PREVIOUS equation,

cosQ=cos(90-Q)

Q=90-Q

2Q=90

Q=45°

therefore ANGLE between the VECTORS should be 45°.

Please mark it as BRAINLIEST

Discussion

33.	The frequency of a a partial performing 4 cmchanges from 60rpm to 180rpm in 20 seccalculate angular acceleration
Answer» Explanation: GIVEN that convert 60rpm into 1rad/s and convert 180rpm into 3 rad/s thus a is EQUAL to 3rad/s- 1rad/s/20 2/20 1/10 0.1

33.

The frequency of a a partial performing 4 cmchanges from 60rpm to 180rpm in 20 seccalculate angular acceleration

Answer»

Explanation:

GIVEN that

convert 60rpm into 1rad/s

and convert 180rpm into 3 rad/s

thus a is EQUAL to 3rad/s- 1rad/s/20

2/20

1/10

0.1

Discussion

34.	1) An electron is at rest in space with definite energy E. (i.e. rest mass energy). Determinethe shortest time interval after which the electron probability amplitude will be -i?. Whatif we are having a body with mass 50 gm at rest?
Answer» EXPLANATION: REST of MASS is EQUAL to it,s AREA of density

34.

1) An electron is at rest in space with definite energy E. (i.e. rest mass energy). Determinethe shortest time interval after which the electron probability amplitude will be -i?. Whatif we are having a body with mass 50 gm at rest?

Answer»

EXPLANATION:

REST of MASS is EQUAL to it,s AREA of density

Discussion

35.	Mark the directions of the forces that act on it name the force
Answer» Answer: In the THREAD UPWARD tension force. Downwards MG that is GRAVITATIONAL force. Please mark me the brainliest.

35.

Mark the directions of the forces that act on it name the force

Answer»

Answer:

In the THREAD UPWARD tension force.

Downwards MG that is GRAVITATIONAL force.

Please mark me the brainliest.

Discussion

36.	15CM फोकस दूरी के अवतल दर्पण से 60CM पर रखी गई एक वस्तु के प्रतिबिंब की स्थिति का पता लगाएं
Answer» Answer: -20cm 1 by f is equal to 1 by v + 1 by U se f is equal to MINUS 15CM, u is equal to minus 60cm v=-20cm

36.

15CM फोकस दूरी के अवतल दर्पण से 60CM पर रखी गई एक वस्तु के प्रतिबिंब की स्थिति का पता लगाएं

Answer»

Answer: -20cm

1 by f is equal to 1 by v + 1 by U se f is equal to MINUS 15CM, u is equal to minus 60cm

v=-20cm

Discussion

37.	Couple acting on a barmagnet
Answer» A magnetic NEEDLE is acted UPON by TWO FIELDS of induction B1 and B2 RESPECTIVELY having an angle of 600 between them. The magnetic needle makes an angle of 150 with the direction of B1 and comes to equilibrium.

Discussion

38.	A torch bulb is rated at 1.5v,500m a .find the resitivity.?
Answer» EXPLANATION: I = 500^*10^-3 V = 1.5v R = V/I R = 1.5/0.5 R = 3 ohm Please MARK as BRAINLIEST

38.

A torch bulb is rated at 1.5v,500m a .find the resitivity.?

Answer»

EXPLANATION:

I = 500^*10^-3

V = 1.5v

R = V/I

R = 1.5/0.5

R = 3 ohm

Please MARK as BRAINLIEST

Discussion

39.	Factors to take in account when searching for the right career
Answer» ANSWER: JOB security salary transport facility pention other advantages family ease of access nearness understandability atmosphere more than that your WISH about a career passion interest knowledge

39.

Factors to take in account when searching for the right career

Answer»

ANSWER:

JOB security
salary
transport facility
pention
other advantages
family
ease of access
nearness
understandability
atmosphere

more than that

your WISH about a career
passion
interest
knowledge

Discussion

40.	Thermodynamics stability of NO(g). comment
Answer» ANSWER: SORRY i am in a GREAT but i can't answer this QUESTION

40.

Thermodynamics stability of NO(g). comment

Answer»

ANSWER:

SORRY i am in a GREAT but i can't answer this QUESTION

Discussion

41.	The mass of the earth is 6×10^24. The potential energy of a body of mass 50 kg at distance of 6.3× 10^9m from the centre of earth
Answer» Answer: the first thing to do 77is was to make sure that you can do it in your LIFE to GET to your di if you're a WEEK and a few WEEKS 8before to pronounce it and you your DUE 7887be7377udh and pressure them into the

41.

The mass of the earth is 6×10^24. The potential energy of a body of mass 50 kg at distance of 6.3× 10^9m from the centre of earth

Answer»

Answer:

the first thing to do 77is was to make sure that you can do it in your LIFE to GET to your di if you're a WEEK and a few WEEKS 8before to pronounce it and you your DUE 7887be7377udh and pressure them into the

Discussion

42.	why there will be a change in lemon rice or tamarind rice when it is stored in a metallic containers write the reason behind it
Answer» ANSWER: LEMON is acidic in nature....and when acid REACTS with water, it leads to the formation of products....like salt and HYDROGEN.

42.

why there will be a change in lemon rice or tamarind rice when it is stored in a metallic containers write the reason behind it

Answer»

ANSWER:

LEMON is acidic in nature....and when acid REACTS with water, it leads to the formation of products....like salt and HYDROGEN.

Discussion

43.	If A.B = 0 and A x B = 0, if A is not equal to zero then B is
Answer» ANSWER: then B is 0 .... EXPLANATION: THANK you

43.

If A.B = 0 and A x B = 0, if A is not equal to zero then B is

Answer»

ANSWER:

then B is 0 ....

EXPLANATION:

THANK you

Discussion

44.	the density of a substance is 11.34 g/cc at 0 degree celsius then it is heated to 100 degree celsius ,if its linear coefficient is 28 * 10›6 then its density is
Answer» Answer: We will divide the Projectile MOTION into 2 SIMULTANEOUSLY occuring 1D motions. Along X axis : \sf{ \therefore \: x = u \cos( \THETA) \times t}∴x=ucos(θ)×t \sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}⟹x=20cos(60°)×1 \sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}⟹x=20× 2 1 ×1 \sf{ \implies \: x = 10 \: m}⟹x=10m Along Y axis : \sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}∴y=usin(θ)t− 2 1 GT 2 \sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )⟹y=20sin(60°)×1−( 2 1 ×10×1 2 ) \sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}⟹y=20× 2 3 −5 \sf{ \implies \: y =17.32 - 5}⟹y=17.32−5 \sf{ \implies \: y =12.32 \: m}⟹y=12.32m So , coordinate will be : \BOXED{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}} (x,y)=(10,12.32)

44.

the density of a substance is 11.34 g/cc at 0 degree celsius then it is heated to 100 degree celsius ,if its linear coefficient is 28 * 10›6 then its density is

Answer»

Answer:

We will divide the Projectile MOTION into 2 SIMULTANEOUSLY occuring 1D motions.

Along X axis :

\sf{ \therefore \: x = u \cos( \THETA) \times t}∴x=ucos(θ)×t

\sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}⟹x=20cos(60°)×1

\sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}⟹x=20×

2

1

×1

\sf{ \implies \: x = 10 \: m}⟹x=10m

Along Y axis :

\sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}∴y=usin(θ)t−

2

1

GT

2

\sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )⟹y=20sin(60°)×1−(

2

1

×10×1

2

)

\sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}⟹y=20×

2

3

−5

\sf{ \implies \: y =17.32 - 5}⟹y=17.32−5

\sf{ \implies \: y =12.32 \: m}⟹y=12.32m

So , coordinate will be :

\BOXED{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}}

(x,y)=(10,12.32)

Discussion

45.	In complete combustion of fuels leads to formation of ..........(A)Carbon monoxide(B)Carbon dioxide(C)Chlorofluorocarbon(D)Hydrogen sulphide
Answer» ANSWER: a Explanation: a) CARBON MONOXIDE this answer HELPS you

45.

In complete combustion of fuels leads to formation of ..........(A)Carbon monoxide(B)Carbon dioxide(C)Chlorofluorocarbon(D)Hydrogen sulphide

Answer»

ANSWER:

a

Explanation:

a) CARBON MONOXIDE this answer HELPS you

Discussion

46.	The turbine pits at the nigra falls are 50m deep . The average power develop is 5000 HP , the efficiency being 85% . How much water passes through the turbine per min. ?1 HP =746Wg=10 ms^-10
Answer» ANSWER: The turbine PITS at the nigra falls are 50m deep . The average POWER develop is 5000 HP , the efficiency being 85% . How MUCH water passes through the turbine per min. ? 1 HP =746W g=10 ms^-10

46.

The turbine pits at the nigra falls are 50m deep . The average power develop is 5000 HP , the efficiency being 85% . How much water passes through the turbine per min. ?1 HP =746Wg=10 ms^-10

Answer»

ANSWER:

The turbine PITS at the nigra falls are 50m deep . The average POWER develop is 5000 HP , the efficiency being 85% . How MUCH water passes through the turbine per min. ?

1 HP =746W

g=10 ms^-10

Discussion

47.	Write the evidences of chemical reaction
Answer» ANSWER: ⇒Change of odor. ⇒Change of color (for example, silver to reddish-brown when iron rusts). ⇒Change in temperature or ENERGY, such as the production (exothermic) or loss (ENDOTHERMIC) of heat. ⇒Change of composition - paper turning to ash when burned. ⇒Light and/or heat given off. Hope It WOULD Be Helpful!!! Plzz MARK as "Brainliest" THANK YOU!!!

47.

Write the evidences of chemical reaction

Answer»

ANSWER:

⇒Change of odor.

⇒Change of color (for example, silver to reddish-brown when iron rusts).

⇒Change in temperature or ENERGY, such as the production (exothermic) or loss (ENDOTHERMIC) of heat.

⇒Change of composition - paper turning to ash when burned.

⇒Light and/or heat given off.

Hope It WOULD Be Helpful!!!

Plzz MARK as "Brainliest"

THANK YOU!!!

Discussion

48.	The Mass of 2m³ of steel is 15600 kg. Calculate the density of steel in SI unit.
Answer» Answer: $\huge \underline{ \rm \red{hello}}$ Question:- The Mass of 2m³ of steel is 15600 kg. CALCULATE the density of steel in SI UNIT. _________________________________ To FIND :- the density of steel in SI unit. Solution:- We KNOW that , ${ \rm{density}} = \frac{mass}{volume} \\ \\ = \: \frac{15600 \: kg}{ {2m}^{3} } \\ \\ = 7800kg/ {m}^{3}$ Hence, the density of Steel in SI unit is 7800kg/m³.

48.

The Mass of 2m³ of steel is 15600 kg. Calculate the density of steel in SI unit.

Answer»

Answer:

$\huge \underline{ \rm \red{hello}}$

Question:-

The Mass of 2m³ of steel is 15600 kg. CALCULATE the density of steel in SI UNIT.

_________________________________

To FIND :-

the density of steel in SI unit.

Solution:-

We KNOW that ,

${ \rm{density}} = \frac{mass}{volume} \\ \\ = \: \frac{15600 \: kg}{ {2m}^{3} } \\ \\ = 7800kg/ {m}^{3}$

Hence, the density of Steel in SI unit is 7800kg/m³.

Discussion

49.	A car of mass 1000kg moving at velocity 50kmph moves along curve road of radius 15 meter. Find the reaction between car and road?
Answer» Explanation: F = m.a a= centripetal acceleration a=v²/r a=(50×5/18)² / 15 = 12.9 so f = 1000 × 12.9= 12900 N

49.

A car of mass 1000kg moving at velocity 50kmph moves along curve road of radius 15 meter. Find the reaction between car and road?

Answer»

Explanation:

F = m.a

a= centripetal acceleration

a=v²/r

a=(50×5/18)² / 15 = 12.9

so f = 1000 × 12.9= 12900 N

Discussion

50.	Will a person standing 100m away from the car get hit under dry conditions
Answer» ANSWER: No it do not GET *HIT* *under* *DRY* *CONDITIONS*

50.

Will a person standing 100m away from the car get hit under dry conditions

Answer»

ANSWER:

No it do not GET HIT under DRY CONDITIONS

Discussion

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