the density of a substance is 11.34 g/cc at 0 degree celsius then it i

1.	the density of a substance is 11.34 g/cc at 0 degree celsius then it is heated to 100 degree celsius ,if its linear coefficient is 28 * 10›6 then its density is
Answer» Answer: We will divide the Projectile MOTION into 2 SIMULTANEOUSLY occuring 1D motions. Along X axis : \sf{ \therefore \: x = u \cos( \THETA) \times t}∴x=ucos(θ)×t \sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}⟹x=20cos(60°)×1 \sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}⟹x=20× 2 1 ×1 \sf{ \implies \: x = 10 \: m}⟹x=10m Along Y axis : \sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}∴y=usin(θ)t− 2 1 GT 2 \sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )⟹y=20sin(60°)×1−( 2 1 ×10×1 2 ) \sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}⟹y=20× 2 3 −5 \sf{ \implies \: y =17.32 - 5}⟹y=17.32−5 \sf{ \implies \: y =12.32 \: m}⟹y=12.32m So , coordinate will be : \BOXED{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}} (x,y)=(10,12.32)

the density of a substance is 11.34 g/cc at 0 degree celsius then it is heated to 100 degree celsius ,if its linear coefficient is 28 * 10›6 then its density is

Answer»

Answer:

We will divide the Projectile MOTION into 2 SIMULTANEOUSLY occuring 1D motions.

Along X axis :

\sf{ \therefore \: x = u \cos( \THETA) \times t}∴x=ucos(θ)×t

\sf{ \implies \: x = 20 \cos( 60 \degree) \times 1}⟹x=20cos(60°)×1

\sf{ \implies \: x = 20 \times \dfrac{1}{2} \times 1}⟹x=20×

×1

\sf{ \implies \: x = 10 \: m}⟹x=10m

Along Y axis :

\sf{ \therefore \: y = u \sin( \theta) t - \frac{1}{2} g {t}^{2}}∴y=usin(θ)t−

\sf{ \implies \: y = 20 \sin( 60 \degree) \times 1- ( \frac{1}{2} \times 10 \times {1}^{2}} )⟹y=20sin(60°)×1−(

×10×1

)

\sf{ \implies \: y = 20 \times \frac{ \sqrt{3} }{2} - 5}⟹y=20×

−5

\sf{ \implies \: y =17.32 - 5}⟹y=17.32−5

\sf{ \implies \: y =12.32 \: m}⟹y=12.32m

So , coordinate will be :

\BOXED{ \red{ \bold{ \sf{ \huge{(x,y) = (10,12.32)}}}}}

(x,y)=(10,12.32)