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Can u help me find this answer?1)Velocity of sound in the atmosphere of a planet is 500ms^-1.The minimum distance between the source and sound and the obstate to hear the echo,should bea)17mb)20mc)25md)50m |
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Answer» Answer: Given, SPEED of sound = 500m/s Therefore the distance transversed by sound wave in one SECOND = 500m So, the distnace transversed by the sound wave in 1/10 sec =50.0m Since the sound wave has to travel the distance between source nd reflector twice to produce ECHO. So the minimum distance between source nd reflector required to produce echo = 50.0/2 = 25m |
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