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This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A beam of light is allowed to pass through two beakers A and B, containing a true solution and a colloidal solution respectively. What do you observe? Name the phenomenon responsible for your observation ? |
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Answer» Answer: tyndall EFFECT Explanation: when light passes through beaker A, the light can pass through it,i.e,tyndall effect is OCCURED. if it passes through beaker B, the light can't pass through it,i.e,tyndall effect is not occured. tyndall effect MEANS the PASSING of a beam of light through a medium. |
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| 2. |
A man walks 4m North then3m east. The magnitude of displacement of man is |
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Answer» ANSWER: 5m Explanation: |
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| 3. |
Find the avrage speed of the particle in time interval 0 to 2 second |
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Answer» 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2 |
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| 4. |
Liquid lens experiment to find refractive index of a lensusing mercury |
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Answer» Answer: 1 Secondary School
Physics
13 points Liquid lens experiment to FIND refractive index using mercury Ask for details
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Report byJoshimohit903 12.03.2019 Answers Me · Beginner Know the answer? Add it here!  tanmaybhere100
Ace To find the focal length of the convex lens: The plane mirror is placed horizontally on the base of the retort stand with its reflecting surface upwards. The given convex lens is placed over the plane mirror. The pointer is arranged horizontally on the CLAMP of the retort stand, vertically above the lens. Looking from above, the height of the pointer is adjusted such that the inverted image of the pointer is obtained. The height is further adjusted so that the image coincides with tip of the pointer WITHOUT parallax. The image and OBJECT will be of the same SIZE. The distance of the pointer from the top (y1) and bottom (y2) of the lens are measured. The average of these values gives the focal length of the f1 of the convex lens. |
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| 5. |
The volume of 500 g sealed packet is 350 cmcube . Will the packet float or sink in water if the density of water is 1 gm per cm cube? Whar wull be the mass of the water displayed by packet |
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Answer» Answer: |
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| 6. |
Velocity of a train increases uniformly from 20 kilometre per hour to 60 km per hour in fourth are the distance travelled by the train during this period is |
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Answer» Here intial VELOCITY U= 20 km /hr=5.56 m/s final velocity v=60 km/hr=16.67 m/s the train is under UNIFORM accerleration t=0.2 hr=12 minutes=720 secs a=v-u/t=0.0154 m/s² s=ut+(1/2)at²=7994.88 m=7.99488 km.Mark as Brainliest |
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| 7. |
Velocity of a particle is given v=4-3x acceleration of particle when it passes through origin |
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| 8. |
Uniform heavy chain is placed on the table with a part of it hanging over the edge if just begins to slide when this part is one third of its length efficient of friction between the table and the chain is |
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Answer» · It just BEGINS to SLIDE this part is one-third of its LENGTH. Find the coefficient of friction between the table and the CHAIN. |
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| 9. |
Two vectors both equal in magnitude have their resultant equal in magnitude |
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Answer» Answer: TWO VECTORS, both equal in magnitude, have their resultant equal in magnitude of the EITHER. ... Two equal forces have their resultant equal to either, what is the INCLINATION between them |
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| 10. |
Two symmetric double convex lenses, a and b, have the same focal length, but the radii of curvature differ so that ra=0.9rb. If μa=1.63, then μb will be |
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Answer» Answer: Two symmetric double CONVEX LENSES, a and b, have the same focal LENGTH, but the RADII of curvature differ so that ra=0.9rb. |
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| 11. |
Two people push a car for 3 seconds with with combined net force of 200 newtons calculate the impulse provided to the car |
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Answer» Explanation: GIVEN : Given :FORCE= 200N Given :Force= 200Ntime =3 sec Given :Force= 200Ntime =3 secmass=m=1200kg Given :Force= 200Ntime =3 secmass=m=1200kgImpulse = J= ? Given :Force= 200Ntime =3 secmass=m=1200kgImpulse = J= ?FORMULA to be used : IMPULSE = Fx t Given :Force= 200Ntime =3 secmass=m=1200kgImpulse = J= ?Formula to be used : Impulse = Fx t=200 x 3 = 600 Ns Mark as Brainliest |
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| 12. |
Two plates each of area a are placed parallel to each other at a distance d one feet is connected to a battery of emf e and negative is are the other plate is also 8 the charged on the plate is |
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Answer» SEE the ATTACHMENT... |
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| 13. |
Two pendulum having their bob of mass 20 gram and 25 gram compare the time period and frequency |
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Answer» Hete is your answer buddy Explanation: the time of one oscillation or the period (T) by dividing the total time by the number of oscillations you counted. Use your calculated (T) ALONG with the EXACT LENGTH of the pendulum (L) in the above formula to find "g." This is your measured value for "g Mark as Brainliest |
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| 14. |
A force of 20 Newton acts over an area of 4 m square. Find the pressure. |
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Answer» =20×10000/4 |
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| 15. |
What is newtons second law...pls ans to my ques.... |
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Answer» Newton's SECOND law of motion pertains to the BEHAVIOR of objects for which all existing FORCES are not BALANCED. |
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| 16. |
What is newton's third law |
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Answer» If an object exerts a force on a object then that object ALSO exerts force on first one in same way with OPPOSITE DIRECTION |
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| 17. |
!A particle of mass 1 kg is thrown verticallyupward with speed 100 m/s. After 5 sec itexplodes into two parts. One part of mass 400g comes back with speed 25 m/s, what is thespeed of the other part just after explosion?(g=10 m/s2)1) 600 m/s upward 2) 100 m/s upward3) 100 m/s downward 4) 300 m/s upwardat on onola a to |
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Answer» Answer: I will TELL the answer if you SUBSCRIBE to my YOUTUBE channel name Nikeshmehna |
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| 18. |
If everything in the universe attracts everything else,why we dont attracts each other? |
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Answer» because we are HUMAN being |
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| 19. |
Two particle projected from the same point with same speed "v" at angle of projection "alpha" and " beta" strike the horizontal ground at the same point if h1 and h2 are maximum height attained by prijectile , r is the range for both and t1 and t2 are their time of flight respectively then |
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Answer» ............................ |
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| 20. |
Two lines parallel to the same line are parallel to each other is euclid axion or not? |
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Answer» no Explanation: no no no no no no no no no no |
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| 21. |
Two friends see each other when they are 200 m apart and start running toward each other. One runs at 8 ms and the other at 12 ms. How far does cach run before they meet? |
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Answer» Answer:80 and 120 m |
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| 22. |
Two force p and q are acting at a point o the force p= 240 n and q= 200n. If the resultant is equal to 400 |
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| 23. |
Two forces f1=1n and f2=2n act along the lines x=0 and y=0 respectively. The resultant of forces could be |
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| 24. |
Two blocks a and b of masses 1kg and 2kg are placed as shown a force of 5 n |
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Answer» Answer: This is a basic problem based on Newton's LAWS of Motion. Refer the below given pics for the detailed solution. The same problem can be solved by proceeding in slight different manner also i.e. by applying Newton's second law separately on both the blocks; thus getting two equations with two unknowns (acceleration and mutual force). One more thing to note here that while solving the problem the external force of 100N has been assumed to ACT on the 2kg block in Horizontal DIRECTION as it has not been clearly SPECIFIED in the statement of the problem. |
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| 25. |
Time formula when two projectile are projected horizantally with different velocities |
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Answer» Explanation: Component of velocity ALONG the x-axis at any instant t. vx=ux + axt =u + 0 vx=u This means that the horizontal component of velocity does not change throughout the projectile motion. Component of velocity along the y-axis at any instant t. vy=uy + ayt =0 + gt vy=gt The displacement along x-axis at any instant t x=uxt + (1/2) axt2 x=uxt + 0 x=u t 4. The displacement along y-axis at any instant t y= uyt + (1/2) ayt2 y= 0 + (1/2) ayt2 y=1/2gt2 Equation of a trajectory(PATH of a projectile) We KNOW at any instant x = ut t=x/u Also, y= (1/2)gt2 Subsituting for t we get y= (1/2)g(x/u)2 y= (1/2)(g/u2)x2
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| 26. |
3HCI full formplzzzzz tell |
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Answer» 3 Molecules of hydrochloric ACID |
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| 27. |
What is newton's third law of motion ? |
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Answer» NEWTON'S THIRD LAW OF MOTION :- TO EVERY ACTION THERE IS EQUAL AND OPPOSITE REACTION HOPE IT HELPS YOU MATE PLEASE THANKS ME AND MARK BRAINLIST PLEASE #######################################. |
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| 28. |
A simple pendulum of length l has a Bob of mass m. It is released from the horizontal position. The tension in the string at the lowest point is |
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Answer» Answer: Tension in the string at LOWEST point is 3mg Explanation: Length of the pendulum = l Mass of the BOB = m Let the velocity at the lowest position is v The bob is RELEASED from the horizontal position then its POTENTIAL energy will be converted into kinetic energy at the lowest position the CENTRIFUGAL acceleration at the lowest point The tension in the string at the lowest point = Weight of the bob + Tension due to centrifugal force |
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| 29. |
A force of 5 N gives a mass M1, and acceleration of 10 m s -2 and a mass M2, an acceleration of 20 m s-2 ,what acceleration would it give if both the masses were tied together? |
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Answer» Answer: 6.67ms^-2 Explanation: |
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| 30. |
The sum of magnitudes of two forces acting at a point is 18n |
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Answer» Answer: The SUM of magnitude of two forces acting at a point is 18N and the magnitude of the resultant force is 12N. ... The diagonal OC = resultant R which is perpendicular to the s maller force Q . consider the triangle AOC , OA = P, AC = OB = P, and ANGLE AOC =90DEGREE |
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| 31. |
The radius of a circle is 2.12metre .its area according to the rule of significant figure |
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Answer» |
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| 32. |
13. A 500kg boat has an initial speed of 10ms asit passes under a bridge. At that instant a 50 kgman jumps straight down into the boat from thebridge. The speed of the boat after the man andboat attain a common speed is100 |
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Answer» Dear STUDENT, ◆ Answer - v = 100/11 m/s ● EXPLAINATION - # GIVEN - M = 500 kg m = 50 kg u = 10 m/s # Solution - According to law of conservation of MOMENTUM, Pi = Pf Mu = (M+m)v 500 × 10 = (500+50) × v v = 5000 / 550 v = 100/11 m/s v = 9.09 m/s Therefore, speed of the boat after man jumps into it is 100/11 m/s. Thanks dear... |
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| 33. |
A 20V 5watt lamp is used on AC mains of 200 volts, 50√11/pi c.p.s. Calculate the capacitor |
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Answer» Since the current through the lamp would be: I = P/V=50/100=0.5A and since this is a SERIES circuit we know the same amount of current flows throughout the circuit therefore we can say that the total impedance is: Z=V/I=200/0.5=400Ω by Ohm’s law and lamp’s RESISTANCE is: Rlamp=V/I=100/0.5=200Ω by Ohm’s law Through the impedance triangle Xc would be: Z²=Rlamp²+Xc² Xc=√(Z²-Xc²) Xc=√(400²-200²) Xc=√(120000) Xc=346.41Ω and now we can determine C from: Xc=1/2πfC therefore C=1/2πfXc C=1/(2π(50)(346.6)) C=0.000009F or 9µF Hopes this helps. |
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| 34. |
Ultrasonic waves are used in SONAR. what is the principle behind it? |
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Answer» Answer: 1) Sonar is a device used to measure the distance, direction and speed of underwater objects using ultrasonic waves. 2) It consists of a TRANSMITTER and a detector which is installed in a boat or a ship. 3) The transmitter produces and transmits ultrasonic waves. 4) These waves travel through water and after striking the object on the seabed, get reflected back. 5) The detector receives the reflected ultrasonic waves and converts into electric signals. 6) The speed of sound in water the time INTERVAL between the transmission and reception of ultrasound is recorded Principle behind the working of sonar is it uses the echo principle by sending out sound waves underwater or through the human body to locate objects. Hope my answer helps you :) Regards, hema |
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| 35. |
Iv) The magnitude of vector product of twounit vectors making an angle of 60° witheach other is(A) 1(B) 2(C) 3/2 (D) 13/2 |
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Answer» if c = axb c = absinθ sin60° = √3/2 c = 1*1*√3/2 = √3/2 option (D) √3/2 |
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| 36. |
The shifting of a term from one side of an equation to other side is called |
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Answer» it was KNOWN as TRANSPOSITION. hope it was HELPFUL
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| 37. |
The resultant of two equal forces acting at right angles to each other is 1414 dyne. Find the magnitude of either force |
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Answer» Answer: The resultant of the two FORCES acting PERPENDICULAR to each other and being equal will be √2 times the force.So if the resultant is 1414 N or 100√2 then both the forces will come out to be 100 N. The MAGNITUDE of R is ( A^2+A^2)^1/2=A root2. |
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| 38. |
The resistance r is equal to v upon i where v is equal to (100+-5) |
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Answer» 95. answer............ |
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| 39. |
The refractive index of glass for light going from air to glass is 3 by 2 refractive index for light going from glass to air will be |
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| 40. |
If a ball is thrown vertically upward from a building what is the height of the building |
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| 41. |
Ii) For two vectors to be equal, they shouldhave the(A) same magnitude(B) same direction(C) same magnitude and direction(D) same magnitude but opposite directionp |
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Answer» opction C Explanation: vector PROPERTIES =same magnitude and DIRECTION's |
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| 42. |
a body is projected with an initial velocity 20√2 m/s at an angle of 45° with the horizontal then find maximum height, time of ascent and range. |
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Answer» Answer: max HT =20m range=80m time of ascent=2 s Explanation: |
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| 43. |
3. A body is thrown vertically upward with somespeed. If velocity and acceleration of a body athighest point are v and a repsectively, then(1) v = 0, a = 0 (2) v = 0, a = 0(3) v=0, a=0 (4) V60, a = 0 |
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Answer» option 1 Explanation: velocity at highest point is zero therefore ACCELERATION ALSO zero |
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| 44. |
Using a stopwatch how can a student find the period of oscillation more accurately, at least 4 points needed. |
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Answer» Answer: The PERIOD of OSCILLATION of a simple pendulum is equal to 2512.3 measured VALUE of 1 is 20cm to 1mm accuracy. |
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| 45. |
The mass numbers of two nuclei are 64 and 216. the ratio of their radius of nuclei is |
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Answer» ................................. pagla HA ha ha |
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| 46. |
If a vector has zero magnitude is it meaning full to call it as a vector |
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| 47. |
State universal law of gravitation use it to find acceralation due to gravity as height |
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Answer» ...................... |
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| 48. |
TO UNDERSTAND AND REMEMBERANYTHING LONGER, TEACH IT TO SOMEONE.i BOCQ8.**A man of 60 kg weight manages to be at restbetween the two walls by pressing one wall A by hishands and feet and the other wall B by his back(fig.).If each hand and feet he applies a force F onthe wall and the coefficient of friction between thebody and the walls is 0.7. Then F = (a) 105 N(b) 210 N (c) 420 N (d) 35 N. |
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Answer» Answer: (C) 429 N Explanation: Mass of the body, m=60 kg. FRICTION exerted between WALL and body, =0. 7 Second LAW of motion. F=m×a F=60×0.7 therefore, F=420 N. hope it helps u. PLZ mark it as brainlist answer. I'll help u. |
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| 50. |
Draw velocity time graph(a)when a body is moving with uniform acceleration and its initial velocity is not zero .(b)When a body moving with uniform velocity. |
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