1.

A simple pendulum of length l has a Bob of mass m. It is released from the horizontal position. The tension in the string at the lowest point is

Answer»

Answer:

Tension in the string at LOWEST point is 3mg

Explanation:

Length of the pendulum = l

Mass of the BOB = m

Let the velocity at the lowest position is v

The bob is RELEASED from the horizontal position then its POTENTIAL energy will be converted into kinetic energy at the lowest position

mgl=\frac{1}{2}mv^2

\implies v^2=2gl

the CENTRIFUGAL acceleration at the lowest point

=m\frac{v^2}{l}

=m\frac{2gl}{l}

=2mg

The tension in the string at the lowest point

= Weight of the bob + Tension due to centrifugal force

=mg+2mg

=3mg



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