TO UNDERSTAND AND REMEMBERANYTHING LONGER, TEACH IT TO SOMEONE.i BOCQ8

1.	TO UNDERSTAND AND REMEMBERANYTHING LONGER, TEACH IT TO SOMEONE.i BOCQ8.**A man of 60 kg weight manages to be at restbetween the two walls by pressing one wall A by hishands and feet and the other wall B by his back(fig.).If each hand and feet he applies a force F onthe wall and the coefficient of friction between thebody and the walls is 0.7. Then F = (a) 105 N(b) 210 N (c) 420 N (d) 35 N.
Answer» Answer: (C) 429 N Explanation: Mass of the body, m=60 kg. FRICTION exerted between WALL and body, =0. 7 Second LAW of motion. F=m×a F=60×0.7 therefore, F=420 N. hope it helps u. PLZ mark it as brainlist answer. I'll help u.

TO UNDERSTAND AND REMEMBERANYTHING LONGER, TEACH IT TO SOMEONE.i BOCQ8.**A man of 60 kg weight manages to be at restbetween the two walls by pressing one wall A by hishands and feet and the other wall B by his back(fig.).If each hand and feet he applies a force F onthe wall and the coefficient of friction between thebody and the walls is 0.7. Then F = (a) 105 N(b) 210 N (c) 420 N (d) 35 N.

Answer»

Answer:

Explanation:

Mass of the body, m=60 kg.

FRICTION exerted between WALL and body, =0. 7

Second LAW of motion.

F=m×a

F=60×0.7

therefore, F=420 N.

hope it helps u. PLZ mark it as brainlist answer. I'll help u.

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