67486 + Interview Questions in Secondary School in Physics

1.	Proof of converse of Pythagoras theorem with statement.
Answer» $\huge\underline\mathfrak\red{Statement}$ In a triangle, if the square of one side is equal to the sum of square of other two sides then prove that the triangle is right ANGLED triangle. ________________________ $\huge\underline\mathfrak\red{Solution}$ Given : AC² = AB² + BC² To prove : ABC is a right angled triangle. Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR. Proof : In triangle PQR, Angle Q = 90° ( by construction ) Also, PR² = PQ² + QR² ( By using Pythagoras THEOREM )...(1) But, AC² = AB² + BC² ( Given ) Also, AB = PQ and BC = QR ( by construction ) Therefore, AC² = PQ²+ QR²....(2) From eq (1) and (2), PR² = AC² So, PR = AC Now, In ∆ABC and ∆PQR, AB = PQ ( By construction ) BC = QR ( By construction ) AC = PR ( PROVED above ) Hence, ∆ABC is congruent to ∆PQR by SSS criteria. Therefore, Angle B = Angle Q ( By CPCT ) But, Angle Q = 90° ( By construction ) Therefore, Angle B = 90° Thus, ABC is a right angled triangle with Angle B = 90° ____________________ Hence proved!

1.

Proof of converse of Pythagoras theorem with statement.

Answer»

$\huge\underline\mathfrak\red{Statement}$

In a triangle, if the square of one side is equal to the sum of square of other two sides then prove that the triangle is right ANGLED triangle.

________________________

$\huge\underline\mathfrak\red{Solution}$

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

Also,

PR² = PQ² + QR² ( By using Pythagoras THEOREM )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From eq (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( PROVED above )

Hence,

∆ABC is congruent to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

Discussion

2.	9. A body of mass 70 kg, when completely immersed inwater, displaces 20,000 cm3 of water. Find : (i) theweight of body in water and (ii) the relative density ofmaterial of body.Ans. (i) 50 kgf, (ii) 3.5
Answer» Answer: 20000cm^3=20 KG ans no 1 :( 70-20)kg= 50KG

2.

9. A body of mass 70 kg, when completely immersed inwater, displaces 20,000 cm3 of water. Find : (i) theweight of body in water and (ii) the relative density ofmaterial of body.Ans. (i) 50 kgf, (ii) 3.5

Answer»

Answer:

20000cm^3=20 KG

ans no 1 :( 70-20)kg= 50KG

Discussion

3.	Pls give the answer with explaianation instantly I will mark you brainliest
Answer» 1............... .....

3.

Pls give the answer with explaianation instantly I will mark you brainliest

Answer»

1...............

.....

Discussion

4.	Proof of converse of Pythagoras theorem with statement...!!
Answer» $\huge\underline\mathfrak\red{Statement}$ In a triangle, if the square of one side is EQUAL to the sum of square of other two sides then PROVE that the triangle is right angled triangle. ________________________ $\huge\underline\mathfrak\red{Solution}$ Given : AC² = AB² + BC² To prove : ABC is a right angled triangle. Construction : Draw a right angled triangle PQR such that, ANGLE Q = 90°, AB = PQ, BC = QR. Proof : In triangle PQR, Angle Q = 90° ( by construction ) ALSO, PR² = PQ² + QR² ( By USING Pythagoras theorem )...(1) But, AC² = AB² + BC² ( Given ) Also, AB = PQ and BC = QR ( by construction ) Therefore, AC² = PQ²+ QR²....(2) From eq (1) and (2), PR² = AC² So, PR = AC Now, In ∆ABC and ∆PQR, AB = PQ ( By construction ) BC = QR ( By construction ) AC = PR ( Proved above ) Hence, ∆ABC is congruent to ∆PQR by SSS criteria. Therefore, Angle B = Angle Q ( By CPCT ) But, Angle Q = 90° ( By construction ) Therefore, Angle B = 90° Thus, ABC is a right angled triangle with Angle B = 90° ____________________ Hence proved!

4.

Proof of converse of Pythagoras theorem with statement...!!

Answer»

$\huge\underline\mathfrak\red{Statement}$

In a triangle, if the square of one side is EQUAL to the sum of square of other two sides then PROVE that the triangle is right angled triangle.

________________________

$\huge\underline\mathfrak\red{Solution}$

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

Construction : Draw a right angled triangle PQR such that, ANGLE Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

ALSO,

PR² = PQ² + QR² ( By USING Pythagoras theorem )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From eq (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( Proved above )

Hence,

∆ABC is congruent to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

Discussion

5.	The earth and the moon are attracted to each other bygravitational force. Does the earth attract the moon with aforce that is greater or smaller or the same as the forcewith which the moon attracts the earth? Why?
Answer» Answer: The earth attract the moon with the same FORCE as the moon attract the earth . EXPLANATION: We know that each action has an equal and opposite reaction. So if we earth ATTRACTS the moon with force F then the moon is also attracting the earth with force F but with opposite DIRECTION.

5.

The earth and the moon are attracted to each other bygravitational force. Does the earth attract the moon with aforce that is greater or smaller or the same as the forcewith which the moon attracts the earth? Why?

Answer»

Answer:

The earth attract the moon with the same FORCE as the moon attract the earth .

EXPLANATION:

We know that each action has an equal and opposite reaction.

So if we earth ATTRACTS the moon with force F then the moon is also attracting the earth with force F but with opposite DIRECTION.

Discussion

6.	Last question or q no. 20
Answer» ANSWER: i) CONNECT in series ii)connect in parallel. EXPLANATION: i)On CONNECTING in series the R gets divided hence 1/Rf Ω =1/R1 Ω +1/R2 Ω 1/Rf Ω =1/5Ω +1/10Ω = 1/3Ω or Rf =3Ω (MIN) ii) on connecting in Series Rf Ω = R1 Ω + R2 Ω Rf Ω = 5Ω +10 Ω =15Ω (MAX.) *if you liked my explanation please mark my answer brainliest friend*

6.

Last question or q no. 20

Answer»

ANSWER:

i) CONNECT in series

ii)connect in parallel.

EXPLANATION:

i)On CONNECTING in series the R gets divided hence

1/Rf Ω =1/R1 Ω +1/R2 Ω

1/Rf Ω =1/5Ω +1/10Ω

= 1/3Ω

or Rf =3Ω (MIN)

ii) on connecting in Series

Rf Ω = R1 Ω + R2 Ω

Rf Ω = 5Ω +10 Ω

=15Ω (MAX.)

if you liked my explanation please mark my answer brainliest friend

Discussion

7.	What is oscillatory motion 5 lines matter
Answer» Answer: please mark brainliest Oscillatory motion can be TERMED as the repeated motion in which an object repeats the same movement over and over. In the absence of friction, the oscillatory motion would continue forever; but in the real world, the system eventually settles into equilibrium. Oscillatory motion can be found throughout the physical world in different cases from the uranium nucleus oscillation before it fissions to the carbon dioxide molecules oscillating in the UNIVERSE, absorbing and contributing to global warming. BUILDING and bridges undergoes oscillatory motion, sometimes with disastrous results. Even stars oscillates. Waves- from SOUND to OCEAN waves to seismic waves in the solid earth- ultimately involve oscillatory motion.

7.

What is oscillatory motion 5 lines matter

Answer»

Answer:

please mark brainliest

Oscillatory motion can be TERMED as the repeated motion in which an object repeats the same movement over and over. In the absence of friction, the oscillatory motion would continue forever; but in the real world, the system eventually settles into equilibrium. Oscillatory motion can be found throughout the physical world in different cases from the uranium nucleus oscillation before it fissions to the carbon dioxide molecules oscillating in the UNIVERSE, absorbing and contributing to global warming. BUILDING and bridges undergoes oscillatory motion, sometimes with disastrous results. Even stars oscillates. Waves- from SOUND to OCEAN waves to seismic waves in the solid earth- ultimately involve oscillatory motion.

Discussion

8.	Statement and proof of converse of Pythagoras theorem!
Answer» $\huge\underline\mathfrak\red{Statement}$ In a triangle, if the square of one SIDE is EQUAL to the sum of square of other two sides then prove that the triangle is right ANGLED triangle. ________________________ $\huge\underline\mathfrak\red{Solution}$ Given : AC² = AB² + BC² To prove : ABC is a right angled triangle. Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR. Proof : In triangle PQR, Angle Q = 90° ( by construction ) Also, PR² = PQ² + QR² ( By using Pythagoras theorem )...(1) But, AC² = AB² + BC² ( Given ) Also, AB = PQ and BC = QR ( by construction ) Therefore, AC² = PQ²+ QR²....(2) From eq (1) and (2), PR² = AC² So, PR = AC Now, In ∆ABC and ∆PQR, AB = PQ ( By construction ) BC = QR ( By construction ) AC = PR ( Proved above ) Hence, ∆ABC is CONGRUENT to ∆PQR by SSS criteria. Therefore, Angle B = Angle Q ( By CPCT ) But, Angle Q = 90° ( By construction ) Therefore, Angle B = 90° Thus, ABC is a right angled triangle with Angle B = 90° ____________________ Hence proved!

8.

Statement and proof of converse of Pythagoras theorem!

Answer»

$\huge\underline\mathfrak\red{Statement}$

In a triangle, if the square of one SIDE is EQUAL to the sum of square of other two sides then prove that the triangle is right ANGLED triangle.

________________________

$\huge\underline\mathfrak\red{Solution}$

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

Also,

PR² = PQ² + QR² ( By using Pythagoras theorem )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From eq (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( Proved above )

Hence,

∆ABC is CONGRUENT to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

Discussion

9.	Calculate the kinetic energy of an object weighing 600kg moving at a velocity of 30 m/s
Answer» $kinetic \: energy = \frac{1}{2} m {v}^{2}$ K.E.=270000

9.

Calculate the kinetic energy of an object weighing 600kg moving at a velocity of 30 m/s

Answer»

$kinetic \: energy = \frac{1}{2} m {v}^{2}$

K.E.=270000

Discussion

10.	16,17,19,20 question pls
Answer» ANSWER: I cant SEE bro take a GOOD photo.

10.

16,17,19,20 question pls

Answer»

ANSWER:

I cant SEE bro take a GOOD photo.

Discussion

11.	Mass is 100kilogram =x gram how much
Answer» Answer: 100 X 1000 GRAMS = 100000 grams as, as,1 KG = 1000 Grams

11.

Mass is 100kilogram =x gram how much

Answer»

Answer:

100 X 1000 GRAMS = 100000 grams

as,

as,1 KG = 1000 Grams

Discussion

12.	In a household 5 tubelights of 40 W used for 5 hrs and an iron of 500 W for4 hrs per day. Calculate total energy consumed and cost of energy in 30 days@ 4 Rs./kwh.
Answer» EXPLANATION: the cost of total ENERGY consumed in 30 days is 3600 RUPEES.

12.

In a household 5 tubelights of 40 W used for 5 hrs and an iron of 500 W for4 hrs per day. Calculate total energy consumed and cost of energy in 30 days@ 4 Rs./kwh.

Answer»

EXPLANATION:

the cost of total ENERGY consumed in 30 days is 3600 RUPEES.

Discussion

13.	A similarity between whirling stone and a needle of a sewing machineSimilarity between a whirling stone and a needle of a sewing machine
Answer» EXPLANATION: The lengths of steps, arms, hands, or fingers of VARIOUS INDIVIDUALS are unique; accordingly the separation estimated with their assistance isn't constantly solid.

13.

A similarity between whirling stone and a needle of a sewing machineSimilarity between a whirling stone and a needle of a sewing machine

Answer»

EXPLANATION:

The lengths of steps, arms, hands, or fingers of VARIOUS INDIVIDUALS are unique; accordingly the separation estimated with their assistance isn't constantly solid.

Discussion

14.	Пск (017 Substances having sour taste and turns blue litmus red are called(a) Acids(b) Bases(c) Salts(d) Water2. Substances which furnish hydronium ion in the solution are calle(a) Acids(b) Bases(c) Salts(d) Water3. Acid used in eye-wash is:(a) Carbonic acid(b) Acetic acid(©) Benzoic acid(d) Nitric acid4. Acid which is used as a source of vitamin Cis:(a) Citric acid(b) Carbonic acid(c) Boric acid(d) Tartaric acidFill in the blanks:are used to identify the nature of substances.
Answer» Answer: Explanation: 1.(a.).ACIDS..... 2.(a)ACID... 3.(C)BENZOIC acid.. 4.(a)citric acid..

14.

Пск (017 Substances having sour taste and turns blue litmus red are called(a) Acids(b) Bases(c) Salts(d) Water2. Substances which furnish hydronium ion in the solution are calle(a) Acids(b) Bases(c) Salts(d) Water3. Acid used in eye-wash is:(a) Carbonic acid(b) Acetic acid(©) Benzoic acid(d) Nitric acid4. Acid which is used as a source of vitamin Cis:(a) Citric acid(b) Carbonic acid(c) Boric acid(d) Tartaric acidFill in the blanks:are used to identify the nature of substances.

Answer»

Answer:

Explanation:

1.(a.).ACIDS.....

2.(a)ACID...

3.(C)BENZOIC acid..

4.(a)citric acid..

Discussion

15.	Hey plz reply best and get braineist award ok
Answer» ANSWER: EXPLANATION:(C)TAN thita=3/2

15.

Hey plz reply best and get braineist award ok

Answer»

ANSWER:

EXPLANATION:(C)TAN thita=3/2

Discussion

16.	Hello!State and prove the converse of Pythagoras theorem!Thanks!
Answer» REFER to the attachment Hope it HELPS you

16.

Hello!State and prove the converse of Pythagoras theorem!Thanks!

Answer»

REFER to the attachment

Hope it HELPS you

Discussion

17.	An engine draws water from a depth of 10 m with constant speed (at outlet) 2 m/sec at the rate of10 kg per 10 s the power of the engine is (g = 9.8 m/s')?(A) 102 W(B) 50 W(C) 100 W(D) 98 W
Answer» Answer: Option (D) 98 W The power of the engine is 98 W Explanation: Depth h = 10 m Time taken in drawing WATER upto height of 10 m = 10/2 = 5 seconds In 5 seconds the mass of water drawn m = 5kg Total work done = MGH = 5 × 9.8 × 10 = 490 Joule Power is given by P = Work Done/Time = 490/5 = 98 W Hope this helps.

17.

An engine draws water from a depth of 10 m with constant speed (at outlet) 2 m/sec at the rate of10 kg per 10 s the power of the engine is (g = 9.8 m/s')?(A) 102 W(B) 50 W(C) 100 W(D) 98 W

Answer»

Answer:

Option (D) 98 W

The power of the engine is 98 W

Explanation:

Depth h = 10 m

Time taken in drawing WATER upto height of 10 m = 10/2 = 5 seconds

In 5 seconds the mass of water drawn m = 5kg

Total work done = MGH

= 5 × 9.8 × 10

= 490 Joule

Power is given by

P = Work Done/Time

= 490/5

= 98 W

Hope this helps.

Discussion

18.	20 miles 30 south of east50 miles due west40 mile 30 north east30 mile bo south of westfind theresultant?
Answer» Answer: 200 Explanation: 20+30+50+40+30+30is GOING to be A200

18.

20 miles 30 south of east50 miles due west40 mile 30 north east30 mile bo south of westfind theresultant?

Answer»

Answer:

200

Explanation:

20+30+50+40+30+30is GOING to be A200

Discussion

19.	Derive the relationship between mechanical advantage , effort arm and load arm.
Answer» EXPLANATION: Answer refer in Attachment Thank you

19.

Derive the relationship between mechanical advantage , effort arm and load arm.

Answer»

EXPLANATION:

Answer refer in Attachment

Thank you

Discussion

20.	Derive the formula for equivalent resistance when three resistancesare connected in parallel.
Answer» Answer: Add their values (R = R1 + R2 + …) and represent them by a SINGLE resistance. Look at the parallel banches between the nodes and find their equivalent (by ADDING the reciprocals (1/R = 1/R1 + 1/R2 + ….). In a COMPLEX NETWORK you might be left with a few effective resistances in SERIES - if so add them.

20.

Derive the formula for equivalent resistance when three resistancesare connected in parallel.

Answer»

Answer:

Add their values (R = R1 + R2 + …) and represent them by a SINGLE resistance. Look at the parallel banches between the nodes and find their equivalent (by ADDING the reciprocals (1/R = 1/R1 + 1/R2 + ….). In a COMPLEX NETWORK you might be left with a few effective resistances in SERIES - if so add them.

Discussion

21.	From which side the juice flows more faster in the tetra pack
Answer» ANSWER: DEPENDS on the WAY UR HOLDING it..

21.

From which side the juice flows more faster in the tetra pack

Answer»

ANSWER:

DEPENDS on the WAY UR HOLDING it..

Discussion

22.	Explain magnetic field due to a current through a circular loop
Answer» Answer: Magnetic FIELD Pattern due to a circular LOOP carrying current. Each SEGMENT of circular loop carrying current produces magnetic field lines in the same DIRECTION with in the loop. The direction of magnetic field at the centre of circular coil is perpendicular to the PLACE of the coil.

22.

Explain magnetic field due to a current through a circular loop

Answer»

Answer:

Magnetic FIELD Pattern due to a circular LOOP carrying current. Each SEGMENT of circular loop carrying current produces magnetic field lines in the same DIRECTION with in the loop. The direction of magnetic field at the centre of circular coil is perpendicular to the PLACE of the coil.

Discussion

23.	14. What is a lever? State its principle. Pg. 41935. Derive the relationship between mechanical advantage, effort arm and load arm. 16. How are different types of levers classified?
Answer» Answer: 14. A lever is a simple machine. 35. Mechanical advantage is RATIO of load to EFFORT also it is ratio of effort ARM to load arm. Explanation: 16. There are 3 types of lever: Type one has pivot or FULCRUM between load and effort. Type two has load between pivot and effort. Type 3 has effort between pivot and load.

23.

14. What is a lever? State its principle. Pg. 41935. Derive the relationship between mechanical advantage, effort arm and load arm. 16. How are different types of levers classified?

Answer»

Answer:

14. A lever is a simple machine.

35. Mechanical advantage is RATIO of load to EFFORT also it is ratio of effort ARM to load arm.

Explanation:

16. There are 3 types of lever:

Type one has pivot or FULCRUM between load and effort.

Type two has load between pivot and effort.

Type 3 has effort between pivot and load.

Discussion

24.	mention three disadvantages of friction between the parts of a machine.How does a)oiling and b)using ball bearings help reduce friction?
Answer» ANSWER: The main disadvantage of friction is that it PRODUCES HEAT in VARIOUS parts of machines. In this way some useful energy is wasted as heat energy.

24.

mention three disadvantages of friction between the parts of a machine.How does a)oiling and b)using ball bearings help reduce friction?

Answer»

ANSWER:

The main disadvantage of friction is that it PRODUCES HEAT in VARIOUS parts of machines. In this way some useful energy is wasted as heat energy.

Discussion

25.	A ball is dropped from a space ship accelerating in space at a constant rate of100m/s². Give the acceleration of the ball when it is outside the space ship.
Answer» ANSWER: davjehanabad.com Explanation: answer HAI oil is applied to the moving PART of a BODY MOVE

25.

A ball is dropped from a space ship accelerating in space at a constant rate of100m/s². Give the acceleration of the ball when it is outside the space ship.

Answer»

ANSWER:

davjehanabad.com

Explanation:

answer HAI oil is applied to the moving PART of a BODY MOVE

Discussion

26.	Difference between Dispersion and reflection of light in 3 points
Answer» ANSWER: Reflection takes place when the light does not pass into the MATERIAL, but is instead "bounced" off the surface. REFRACTION occurs when the light passes into the material. ... Dispersion occurs when different wavelengths of light are refracted different amounts, separating the light into its CONSTITUENT colors. Explanation:

26.

Difference between Dispersion and reflection of light in 3 points

Answer»

ANSWER:

Reflection takes place when the light does not pass into the MATERIAL, but is instead "bounced" off the surface. REFRACTION occurs when the light passes into the material. ... Dispersion occurs when different wavelengths of light are refracted different amounts, separating the light into its CONSTITUENT colors.

Explanation:

Discussion

27.	One Volt is defined as energy consumption of one joule per electric charge of one coulomb. Is it right definition or not?
Answer» Explanation: ONE volt is defined as a constant current of 1 AMPERE with RESISTANCE of 1 OHM

27.

One Volt is defined as energy consumption of one joule per electric charge of one coulomb. Is it right definition or not?

Answer»

Explanation:

ONE volt is defined as a constant current of 1 AMPERE with RESISTANCE of 1 OHM

Discussion

28.	The resultant of two vectors at an angle 150° is 10units and is perpendicular to one vector. Themagnitude of the smaller vector is(1) 10 units(2) 10√3 units(3) 10√2 units(4) 5√3 units
Answer» ANSWER: Hyy Happy KRISHNA janmastami I HOPE IT HELPS U.

28.

The resultant of two vectors at an angle 150° is 10units and is perpendicular to one vector. Themagnitude of the smaller vector is(1) 10 units(2) 10√3 units(3) 10√2 units(4) 5√3 units

Answer»

ANSWER:

Hyy

Happy KRISHNA janmastami

I HOPE IT HELPS U.

Discussion

29.	Please give the answer of the c part
Answer» ANSWER: maybe there will be rainbow colours or the colour MAGENTA as LIGHT has THREE colours RED grren and blue. blue +red=magenta

29.

Please give the answer of the c part

Answer»

ANSWER:

maybe there will be rainbow colours or the colour MAGENTA as LIGHT has THREE colours RED grren and blue. blue +red=magenta

Discussion

30.	Pls solve 6 and 7 and solve my problem too
Answer» ANSWER: GIVE me some HINT so I can HELP you

30.

Pls solve 6 and 7 and solve my problem too

Answer»

ANSWER:

GIVE me some HINT so I can HELP you

Discussion

31.	Pls ans this with soln
Answer» ANSWER: EXPLANATION:GIVE me some time to solve this QUESTION

31.

Pls ans this with soln

Answer»

ANSWER:

EXPLANATION:GIVE me some time to solve this QUESTION

Discussion

32.	How to calculate avg speed for below attached question
Answer» Answer: EXPLANATION: Average SPEED = sum of speeds /TOTAL TIME taken = 20/10+4=20/14=1.4

32.

How to calculate avg speed for below attached question

Answer»

Answer:

EXPLANATION:

Average SPEED = sum of speeds /TOTAL TIME taken

= 20/10+4=20/14=1.4

Discussion

33.	3. Observe the diagram given below and answer the questions:(A)Torcm(B)10.2 cm(C)1 cm(a) Which wave has the maximum loudness?(b) Name the wave that has the highest pitch.(c) What is the ratio of the wavelengths of A and B?
Answer» ANSWER: where is the DIAGRAM????

33.

3. Observe the diagram given below and answer the questions:(A)Torcm(B)10.2 cm(C)1 cm(a) Which wave has the maximum loudness?(b) Name the wave that has the highest pitch.(c) What is the ratio of the wavelengths of A and B?

Answer»

ANSWER:

where is the DIAGRAM????

Discussion

34.	On the smooth quarter circular surface of theblock, a particle is released from the state ofrest.The coefficient of friction between the block andthe ground is u.The block has mass M andthe particle has mass m.Prove that the normal reaction acting on the particle after it has rotated by anangle o measured with the horizontal, is equal toN = 3mg sineAfter that prove that the friction force needed from the ground to keep the blockin the state of rest isFr = 3mg sino coseThereafter, prove that the normal reaction acting on the block from the groundisNy = Mg + 3mg (sine)?Finally using trigonometry and the condition that requirement must be less thanor equal to the maximum available show that- very difficult>, where K = M/3msum(1+2K)2-17124K(1 +K)
Answer» ANSWER: CHECK UR answer PLS BRAINLIST 9599797118 my whatsaap number

34.

On the smooth quarter circular surface of theblock, a particle is released from the state ofrest.The coefficient of friction between the block andthe ground is u.The block has mass M andthe particle has mass m.Prove that the normal reaction acting on the particle after it has rotated by anangle o measured with the horizontal, is equal toN = 3mg sineAfter that prove that the friction force needed from the ground to keep the blockin the state of rest isFr = 3mg sino coseThereafter, prove that the normal reaction acting on the block from the groundisNy = Mg + 3mg (sine)?Finally using trigonometry and the condition that requirement must be less thanor equal to the maximum available show that- very difficult>, where K = M/3msum(1+2K)2-17124K(1 +K)

Answer»

ANSWER:

CHECK UR answer PLS BRAINLIST 9599797118 my whatsaap number

Discussion

35.	Two particles A and B start from the origiųand travel in opposite directions along the circularpath of radius 5.0 m at constant speed of0.7 m/s and 1.5 m/s respectively. Determine the timewhen they collide and the magnitude of theacceleration of B just before this happens.
Answer» Answer: 14.3 sec Explanation: Total DISTANCE Covered = 2πR = 2 * (22/7) * 5 = 220/7 m Speed of A = 0.7 m/s Speed of B = 1.5 m/s Total Speed = 0.7 + 1.5 = 2.2 m/s Speed = Distance / Time => Time = Distance/Speed Time = (220/7)/(2.2) => Time = 100/7 sec => Time = 14.3 sec

35.

Two particles A and B start from the origiųand travel in opposite directions along the circularpath of radius 5.0 m at constant speed of0.7 m/s and 1.5 m/s respectively. Determine the timewhen they collide and the magnitude of theacceleration of B just before this happens.

Answer»

Answer:

14.3 sec

Explanation:

Total DISTANCE Covered = 2πR

= 2 * (22/7) * 5

= 220/7 m

Speed of A = 0.7 m/s

Speed of B = 1.5 m/s

Total Speed = 0.7 + 1.5 = 2.2 m/s

Speed = Distance / Time

=> Time = Distance/Speed

Time = (220/7)/(2.2)

=> Time = 100/7 sec

=> Time = 14.3 sec

Discussion

36.	Plz explain with step by step
Answer» ANSWER: what?? EXPLANATION: what is your QUESTION

36.

Plz explain with step by step

Answer»

ANSWER:

what??

EXPLANATION:

what is your QUESTION

Discussion

37.	Ectricity8. Calculate the equivalent resistance between points A and B.
Answer» your QUES is INCOMPLETE ....

37.

Ectricity8. Calculate the equivalent resistance between points A and B.

Answer»

your QUES is INCOMPLETE

....

Discussion

38.	A heater is rated as 220 volts, 880 watts. What is the currentdrawn by the heater when connected to a 220 V a.c. mains ? Calculatethe resistance of heater.
Answer» 1/4ohm Explanation: v=ir YAHI AAPKA ANSWER HAI

38.

A heater is rated as 220 volts, 880 watts. What is the currentdrawn by the heater when connected to a 220 V a.c. mains ? Calculatethe resistance of heater.

Answer»

1/4ohm

Explanation:

v=ir YAHI AAPKA ANSWER HAI

Discussion

39.	Answer me this question...
Answer» Which CHAPTER is this and for which CLASS???

39.

Answer me this question...

Answer»

Which CHAPTER is this and for which CLASS???

Discussion

40.	A battery of 12V is connected to a series combination of resistors 3ohm,4ohm,5ohm and 12ohm.how much current would flow through the 12ohm resistor?
Answer» ANSWER: SERIES Rs=R1+R2+R3 3+4+5+12=24 V=IR I=V/R I=24/12 I=2 the CURRENT FLOW is 2A

40.

A battery of 12V is connected to a series combination of resistors 3ohm,4ohm,5ohm and 12ohm.how much current would flow through the 12ohm resistor?

Answer»

ANSWER:

SERIES

Rs=R1+R2+R3

3+4+5+12=24

V=IR

I=V/R

I=24/12

I=2

the CURRENT FLOW is 2A

Discussion

41.	Ectricity8. Calculate the equivalent resistance between points A and B.75+75Ans. 32/3 12.
Answer» ANSWER: 80 Explanation: By ADDING 75+75 so the answer MAY be CORRECT

41.

Ectricity8. Calculate the equivalent resistance between points A and B.75+75Ans. 32/3 12.

Answer»

ANSWER:

80

Explanation:

By ADDING 75+75

so the answer MAY be CORRECT

Discussion

42.	Please explain this in detail
Answer» ANSWER: BOATH are 2 AMP FLOW ......

42.

Please explain this in detail

Answer»

ANSWER:

BOATH are 2 AMP FLOW ......

Discussion

43.	Lightyear is the unit of distance yes or no
Answer» ANSWER: YES okokokokokokkokoko

43.

Lightyear is the unit of distance yes or no

Answer»

ANSWER:

YES okokokokokokkokoko

Discussion

44.	Calculate the resistance of a metal wire of length 2m and area of cross section 1.5510to the power -6, if the resistivity of metal be 2.810to the power -8.
Answer» ANSWER: RESISTANCE ( R ) = 36 × 10-³ Ω ( ohms) Explanation: ★ CURRENT ELECTRICITY ★ ★ GIVEN ; » Length of Wire ( L ) = 2 m » Area of Cross - Section ( A ) = 1.55 × 10^-6 m² » RESISTIVITY ( p ) = 2.8 × 10^-8 ★ RESISTANCE ( R ) = ??? _________________________________________ ———— [ BY USING FORMULA ] ———— [ $r \: = \: p \: ( \: \frac{l}{a} \: )$ ] ★ R = 2.8 × 10^-8 × [ 2 / 155 × 10^-8 ] » R = 2.8 × 10^-8 × [ 2 × 10^8 / 155 ] » R = [ 2.8 × 2 ] / 155 » R = [ 5.6 ] / 155 » R = 0.036 Ω *★ » RESISTANCE ( R ) = 36 × 10-³ Ω « ★* ________________________________________ ANSWER :- HENCE ; RESISTANCE of wire of RESISTIVITY ( p ) is ; *♣ R = 36 × 10-³ Ω ♥*

44.

Calculate the resistance of a metal wire of length 2m and area of cross section 1.5510to the power -6, if the resistivity of metal be 2.810to the power -8.

Answer»

ANSWER:

RESISTANCE ( R ) = 36 × 10-³ Ω ( ohms)

Explanation:

★ CURRENT ELECTRICITY ★

★ GIVEN ;

» Length of Wire ( L ) = 2 m

» Area of Cross - Section ( A ) = 1.55 × 10^-6 m²

» RESISTIVITY ( p ) = 2.8 × 10^-8

★ RESISTANCE ( R ) = ???

_________________________________________

———— [ BY USING FORMULA ] ————

[ $r \: = \: p \: ( \: \frac{l}{a} \: )$ ]

★ R = 2.8 × 10^-8 × [ 2 / 155 × 10^-8 ]

» R = 2.8 × 10^-8 × [ 2 × 10^8 / 155 ]

» R = [ 2.8 × 2 ] / 155

» R = [ 5.6 ] / 155

» R = 0.036 Ω

★ » RESISTANCE ( R ) = 36 × 10-³ Ω « ★

________________________________________

ANSWER :- HENCE ; RESISTANCE of wire of RESISTIVITY ( p ) is ;

♣ R = 36 × 10-³ Ω ♥

Discussion

45.	Hugens theory theory cannot explain Photoelectric effect why
Answer» Explanation: This is because According to the classical WAVE theory of LIGHT, the intensity of the light determines the AMPLITUDE of the wave, and so a greater light intensity should cause the electrons on the metal to oscillate more violently and to be ejected with a greater KINETIC energy.

45.

Hugens theory theory cannot explain Photoelectric effect why

Answer»

Explanation:

This is because According to the classical WAVE theory of LIGHT, the intensity of the light determines the AMPLITUDE of the wave, and so a greater light intensity should cause the electrons on the metal to oscillate more violently and to be ejected with a greater KINETIC energy.

Discussion

46.	The main scale readings of a vernier calipers (1 M.S.D. = 1 mm) having least count 0.01 cm for the internal and external diameters of a hollow tube are 11 mm and 12 mm. The minimum thickness of the tube is _____. (a) 1 mm (b) 0. 1 mm (c) 0.05 mm (d) 0.5 mm
Answer» 0.1mm Hoped U LIKE the ANSWER.

46.

The main scale readings of a vernier calipers (1 M.S.D. = 1 mm) having least count 0.01 cm for the internal and external diameters of a hollow tube are 11 mm and 12 mm. The minimum thickness of the tube is _____. (a) 1 mm (b) 0. 1 mm (c) 0.05 mm (d) 0.5 mm

Answer»

0.1mm

Hoped U LIKE the ANSWER.

Discussion

47.	A bar magnet is made to fall through a long vertical copper tube the speed of the magnet as a function of time is best represented by graph
Answer» Answer: an exponentially increasing graph with decreasing slope to reach a terminal velocity. It will attain a terminal velocity because as the velocity will increase the CHANGE of flux across the IMAGINARY rings will increase at a faster RATE so according to Lenz law the force acting on it will START decreasing the velocity by working against the WEIGHT of the magnet. the acceleration of the magnet will decrease as the velocity increase because the rate of change of velocity is decreasing because the magnetic force is acting opposite to the weight of magnet and hence net force acting on magnet will decrease and hence acceleration. At terminal velocity of the magnet the magnetic force will be equal to the weight of the magnet as *the* *rate* of *change* of *velocity* is *zero* *and* *net* *force* is *also* *zero. It means* *the* *magnetic* *force* is *cancelling* *the* *weight* of *magnet*. MARK AS BRAINLIEST

47.

A bar magnet is made to fall through a long vertical copper tube the speed of the magnet as a function of time is best represented by graph

Answer»

Answer:

an exponentially increasing graph with decreasing slope to reach a terminal velocity.

It will attain a terminal velocity because as the velocity will increase the CHANGE of flux across the IMAGINARY rings will increase at a faster RATE so according to Lenz law the force acting on it will START decreasing the velocity by working against the WEIGHT of the magnet.

the acceleration of the magnet will decrease as the velocity increase because the rate of change of velocity is decreasing because the magnetic force is acting opposite to the weight of magnet and hence net force acting on magnet will decrease and hence acceleration.

At terminal velocity of the magnet the magnetic force will be equal to the weight of the magnet as the rate of change of velocity is zero and net force is also zero. It means the magnetic force is cancelling the weight of magnet.

MARK AS BRAINLIEST

Discussion

48.	Which of the followingthe following vector is perpendicular to the vector A = 2i +31 +42(2) 49 + 37-26(4) i +27 - 2k(1) i+j+k3 - 31+k
Answer» ANSWER: EXPLANATION: MIGHT be SOMETHING but I don't KNOW

48.

Which of the followingthe following vector is perpendicular to the vector A = 2i +31 +42(2) 49 + 37-26(4) i +27 - 2k(1) i+j+k3 - 31+k

Answer»

ANSWER:

EXPLANATION:

MIGHT be SOMETHING but I don't KNOW

Discussion

49.	9. Dimensions of power are
Answer» POWER=work DONE /TIME so, w=ML^2T^-2 and time =T. so, power ==ML^2T^-3...... HOPE it HELPS you

49.

9. Dimensions of power are

Answer»

POWER=work DONE /TIME

so, w=ML^2T^-2

and time =T.

so, power ==ML^2T^-3......

HOPE it HELPS you

Discussion

50.	A body is projected horizontally with speed20 m/s. What will be its spoed after 5 second ?(A) 20 m/s (B) 50 m/s(C)54 m/s(D) 70 m/s
Answer» Answer: 20 m/s will be SPEED of BODY

50.

A body is projected horizontally with speed20 m/s. What will be its spoed after 5 second ?(A) 20 m/s (B) 50 m/s(C)54 m/s(D) 70 m/s

Answer»

Answer:

20 m/s will be SPEED of BODY

Discussion

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