1.

A battery of 12V is connected to a series combination of resistors 3ohm,4ohm,5ohm and 12ohm.how much current would flow through the 12ohm resistor?

Answer»

ANSWER:

SERIES

Rs=R1+R2+R3

3+4+5+12=24

V=IR

I=V/R

I=24/12

I=2

the CURRENT FLOW is 2A



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