67486 + Interview Questions in Secondary School in Physics

1.	Abus is moving with a velocity 10 ms'. A moto cyclist wishes to overtake the bus in 60 s. With what velocity the motorcyclist should chase the bus which
Answer» ANSWER: $3m \: s \\according \: to \:me \: \\$

1.

Abus is moving with a velocity 10 ms'. A moto cyclist wishes to overtake the bus in 60 s. With what velocity the motorcyclist should chase the bus which

Answer»

ANSWER:

$3m \: s \\according \: to \:me \: \\$

Discussion

2.	A capacitor has been charged by a dc source what are the magnitude of conduction and displacement curents when it is fully charged
Answer» ANSWER: $33joule \: \\ according \: to \: me \: \\ next \: you \: can \: see$

2.

A capacitor has been charged by a dc source what are the magnitude of conduction and displacement curents when it is fully charged

Answer»

ANSWER:

$33joule \: \\ according \: to \: me \: \\ next \: you \: can \: see$

Discussion

3.	A box of mass m kg is placed on the rear side of an open truck accelerating at 4m/s. The coefficient of friction
Answer» ANSWER: $92 \: \: is \: the \: cofficient$

3.

A box of mass m kg is placed on the rear side of an open truck accelerating at 4m/s. The coefficient of friction

Answer»

ANSWER:

$92 \: \: is \: the \: cofficient$

Discussion

4.	A bus travels with speed of 54km/h time 2 hours and 32 km/hour time 1 hour what is average speed of bus.
Answer» ANSWER: $\frac{140}{3} \frac{km}{h}$ EXPLANATION: $With \: the \: speed \: 54 \frac{km}{h \: } \: distance \\ travelled \: by \: bus = (54 \times 2)km = 108km \\ \\ With \: the \: speed \: 32 \frac{km}{h } \: distance \: \\ travelled \: by \: bus = (32 \times 1)km = 32km \\ \\ Average \: Speed \: = \frac{total \:distance \: travelled }{total \: time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{(108 + 32)km}{(2 + 1)h} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{140km}{3h} \\ \\ \\ hope \: it \: will \: help \: you..$

4.

A bus travels with speed of 54km/h time 2 hours and 32 km/hour time 1 hour what is average speed of bus.

Answer»

ANSWER:

$\frac{140}{3} \frac{km}{h}$

EXPLANATION:

$With \: the \: speed \: 54 \frac{km}{h \: } \: distance \\ travelled \: by \: bus = (54 \times 2)km = 108km \\ \\ With \: the \: speed \: 32 \frac{km}{h } \: distance \: \\ travelled \: by \: bus = (32 \times 1)km = 32km \\ \\ Average \: Speed \: = \frac{total \:distance \: travelled }{total \: time \: taken} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{(108 + 32)km}{(2 + 1)h} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{140km}{3h} \\ \\ \\ hope \: it \: will \: help \: you..$

Discussion

5.	A boy of mass 50 kg standing on the ground exerts a force of 500 newton
Answer» Answer: Yes. The statement is right. EXPLANATION: The force exerted by the BOY on ground is : mg = 50 * 10 So, mg = 500 N Here, m is the MASS of boy And g is acceleration due to gravity (=10) *Please* mark as brainliest.. *#DREAMChaser*

5.

A boy of mass 50 kg standing on the ground exerts a force of 500 newton

Answer»

Answer:

Yes. The statement is right.

EXPLANATION:

The force exerted by the BOY on ground is : mg = 50 * 10

So, mg = 500 N

Here, m is the MASS of boy

And g is acceleration due to gravity (=10)

Please mark as brainliest..

#DREAMChaser

Discussion

6.	A body of mass m thrown horizontal with velocity v frm top pf a tower
Answer» ANSWER: $didnt \: understand \: your \: question \: please \: follow \: me$

6.

A body of mass m thrown horizontal with velocity v frm top pf a tower

Answer»

ANSWER:

$didnt \: understand \: your \: question \: please \: follow \: me$

Discussion

7.	A body moving with unifirm acceleration travels 84 m in the first 6s
Answer» ANSWER: $please \: put \: full \: question \: \\ \\ please \: follow \: me$

7.

A body moving with unifirm acceleration travels 84 m in the first 6s

Answer»

ANSWER:

$please \: put \: full \: question \: \\ \\ please \: follow \: me$

Discussion

8.	A body moving with uniform acceleration cover s1 in first 4 sec and another s2 in another 4 sec.Find ration between s1 and s2
Answer» Explanation: no change in velocity bcoz ACCELERATION is uniform no change in time T1 and t2 are 4 sec therefore, S1:s2= 1:1 i.e. it seems to be same.

8.

A body moving with uniform acceleration cover s1 in first 4 sec and another s2 in another 4 sec.Find ration between s1 and s2

Answer»

Explanation:

no change in velocity

bcoz ACCELERATION is uniform

no change in time

T1 and t2 are 4 sec

therefore,

S1:s2= 1:1

i.e. it seems to be same.

Discussion

9.	A large reflecting telescope has an objective mirror with
Answer» ANSWER: PLEASE MARK me as BRAINLIST

9.

A large reflecting telescope has an objective mirror with

Answer»

ANSWER:

PLEASE MARK me as BRAINLIST

Discussion

10.	A body moving along a straight line travels one third of the total distance with a speed of 3.0m/s.The remaining distance is covered with a speed of 4.0m/s for half the time and 5.0m/s for the other half of the time.The average speed during the motion is ______________ ?
Answer» ANSWER: the AVG SPEED for the JOURNEY will be 4m/s

10.

A body moving along a straight line travels one third of the total distance with a speed of 3.0m/s.The remaining distance is covered with a speed of 4.0m/s for half the time and 5.0m/s for the other half of the time.The average speed during the motion is ______________ ?

Answer»

ANSWER:

the AVG SPEED for the JOURNEY will be 4m/s

Discussion

11.	What is Converse of Pythagoras theorem and its proof..?
Answer» $\huge\underline\mathfrak\red{Statement}$ In a triangle, if the square of one side is equal to the sum of square of other two sides then prove that the triangle is right angled triangle. ________________________ $\huge\underline\mathfrak\red{Solution}$ Given : AC² = AB² + BC² To prove : ABC is a right angled triangle. Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR. Proof : In triangle PQR, Angle Q = 90° ( by construction ) Also, PR² = PQ² + QR² ( By using PYTHAGORAS theorem )...(1) But, AC² = AB² + BC² ( Given ) Also, AB = PQ and BC = QR ( by construction ) Therefore, AC² = PQ²+ QR²....(2) From eq (1) and (2), PR² = AC² So, PR = AC Now, In ∆ABC and ∆PQR, AB = PQ ( By construction ) BC = QR ( By construction ) AC = PR ( PROVED above ) Hence, ∆ABC is congruent to ∆PQR by SSS criteria. Therefore, Angle B = Angle Q ( By CPCT ) But, Angle Q = 90° ( By construction ) Therefore, Angle B = 90° Thus, ABC is a right angled triangle with Angle B = 90° ____________________ Hence proved!

11.

What is Converse of Pythagoras theorem and its proof..?

Answer»

$\huge\underline\mathfrak\red{Statement}$

In a triangle, if the square of one side is equal to the sum of square of other two sides then prove that the triangle is right angled triangle.

________________________

$\huge\underline\mathfrak\red{Solution}$

Given : AC² = AB² + BC²

To prove : ABC is a right angled triangle.

Construction : Draw a right angled triangle PQR such that, angle Q = 90°, AB = PQ, BC = QR.

Proof : In triangle PQR,

Angle Q = 90° ( by construction )

Also,

PR² = PQ² + QR² ( By using PYTHAGORAS theorem )...(1)

But,

AC² = AB² + BC² ( Given )

Also, AB = PQ and BC = QR ( by construction )

Therefore,

AC² = PQ²+ QR²....(2)

From eq (1) and (2),

PR² = AC²

So, PR = AC

Now,

In ∆ABC and ∆PQR,

AB = PQ ( By construction )

BC = QR ( By construction )

AC = PR ( PROVED above )

Hence,

∆ABC is congruent to ∆PQR by SSS criteria.

Therefore, Angle B = Angle Q ( By CPCT )

But,

Angle Q = 90° ( By construction )

Therefore,

Angle B = 90°

Thus, ABC is a right angled triangle with Angle B = 90°

____________________

Hence proved!

Discussion

12.	What is refraction?
Answer» Refraction is the bending of light it passes from ONE SUBSTANCE to ANOTHER.

12.

What is refraction?

Answer»

Refraction is the bending of light it passes from ONE SUBSTANCE to ANOTHER.

Discussion

13.	Explain how time is measured in ancient time
Answer» Explanation: For thousands of YEARS, devices have been USED to measure and keep track of time. The current sexagesimal system of time MEASUREMENT DATES to approximately 2000 BC from the Sumerians. The Egyptians divided the day into two 12-hour periods, and used large obelisks to track the movement of the sun.

13.

Explain how time is measured in ancient time

Answer»

Explanation:

For thousands of YEARS, devices have been USED to measure and keep track of time. The current sexagesimal system of time MEASUREMENT DATES to approximately 2000 BC from the Sumerians. The Egyptians divided the day into two 12-hour periods, and used large obelisks to track the movement of the sun.

Discussion

14.	16,17,19,20 questions answers pls
Answer» ANSWER Explanation: 16. i) DIAMETER doubled ⇒radius doubled⇒Area quadrupled From volume conservation⇒length BECAME 1/4th R=ρl/A Thus RESISTANCE became 1/16th i.e.,6.25Ω II) l⇒2 l A⇒A/2 ∴R⇒4R=40Ω 19 l⇒l/2 two in parallel combination. i.e, R⇒R/4 20 i)series ii)parallel

14.

16,17,19,20 questions answers pls

Answer»

ANSWER Explanation:

16. i)

DIAMETER doubled ⇒radius doubled⇒Area quadrupled
From volume conservation⇒length BECAME 1/4th
R=ρl/A
Thus RESISTANCE became 1/16th

i.e.,6.25Ω

II)

l⇒2 l
A⇒A/2
∴R⇒4R=40Ω

19

l⇒l/2
two in parallel combination.

i.e, R⇒R/4

20 i)series

ii)parallel

Discussion

15.	State two ways of increasing friction between twosurfaces.
Answer» Answer: 1 . MAKES the VECHILE TYRES flattened 2.the surface in the downwards doesn't SLOPE that slope must have large contact between two surfaces

15.

State two ways of increasing friction between twosurfaces.

Answer»

Answer:

1 . MAKES the VECHILE TYRES flattened

2.the surface in the downwards doesn't SLOPE that slope must have large contact between two surfaces

Discussion

16.	A body is thrown at some angle from the ground the magnitude of change in velocity
Answer» ANSWER: VELOCITY =INITIAL velocity +FINAL velocity / 2

16.

A body is thrown at some angle from the ground the magnitude of change in velocity

Answer»

ANSWER:

VELOCITY =INITIAL velocity +FINAL velocity / 2

Discussion

17.	A body is projected with a velocity of 49m/s and horizontal range of 245 m then time of fl
Answer» ANSWER: HEIGHT if FLIGHT is 14.7m APPROX.

17.

A body is projected with a velocity of 49m/s and horizontal range of 245 m then time of fl

Answer»

ANSWER:

HEIGHT if FLIGHT is 14.7m APPROX.

Discussion

18.	A body is projected along a rough horizontal surface with a velocity 6m/s. If the body comes to rest after travelling 9m then coefficient of sliding friction is
Answer» Answer: Coefficient of sliding friction is 0.204 Explanation: It is GIVEN that, Initial velocity of the body, u = 6 m/s Final velocity, v = 0 (as it comes to rest) Distance, d = 9 m $\mu_s$ We need to FIND the coefficient of sliding friction. Let it is equal to . Frictional force is given by : $F=\mu_s\times N$ $F=\mu_s\times mg$ Also, $ma=\mu_s\times mg$ $\mu_s=\dfrac{a}{g}$ ...............(1) Acceleration, a can be CALCULATED using THIRD equation of motion as : $a=\dfrac{v^2-u^2}{2s}$ $a=\dfrac{-(6\ m/s)^2}{2\times 9\ m}$ $a=-2\ m/s^2$ The minus sign shows that the force is acting in opposite direction of frictional force. Equation (1) BECOMES, $\mu_s=\dfrac{2}{9.8}$ $\mu_s=0.204$ So, the coefficient of sliding friction is 0.204. Hence, this is the required solution.

18.

A body is projected along a rough horizontal surface with a velocity 6m/s. If the body comes to rest after travelling 9m then coefficient of sliding friction is

Answer»

Answer:

Coefficient of sliding friction is 0.204

Explanation:

It is GIVEN that,

Initial velocity of the body, u = 6 m/s

Final velocity, v = 0 (as it comes to rest)

Distance, d = 9 m

$\mu_s$ We need to FIND the coefficient of sliding friction. Let it is equal to . Frictional force is given by :

$F=\mu_s\times N$

$F=\mu_s\times mg$

Also, $ma=\mu_s\times mg$

$\mu_s=\dfrac{a}{g}$ ...............(1)

Acceleration, a can be CALCULATED using THIRD equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{-(6\ m/s)^2}{2\times 9\ m}$

$a=-2\ m/s^2$

The minus sign shows that the force is acting in opposite direction of frictional force.

Equation (1) BECOMES,

$\mu_s=\dfrac{2}{9.8}$

$\mu_s=0.204$

So, the coefficient of sliding friction is 0.204. Hence, this is the required solution.

Discussion

19.	A body is projected horizontally from the top of a tower with a velocity of 10m/s
Answer» ANSWER: PLEASE GIVE FULL STATEMENT

19.

A body is projected horizontally from the top of a tower with a velocity of 10m/s

Answer»

ANSWER:

PLEASE GIVE FULL STATEMENT

Discussion

20.	A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time of fall
Answer» ANSWER: 4 sec Explanation: ACC to the question the answer in a EASY way is PROVIDED . USEFUL mostly for NEET or other objective examinations.. All the best.!!!

20.

A body dropped from the top of a tower covers 7/16 of the total height in the last second of its fall. The time of fall

Answer»

ANSWER:

4 sec

Explanation:

ACC to the question the answer in a EASY way is PROVIDED . USEFUL mostly for NEET or other objective examinations..

All the best.!!!

Discussion

21.	A body is thrown vertically upward with 45 metre per second distance travelled by the body in 5th second is
Answer» ANSWER: 0 or 0.9 Explanation: That MIGHT be the answer ACC to the GIVEN info. All the BEST..!!

21.

A body is thrown vertically upward with 45 metre per second distance travelled by the body in 5th second is

Answer»

ANSWER:

0 or 0.9

Explanation:

That MIGHT be the answer ACC to the GIVEN info.

All the BEST..!!

Discussion

22.	Give some names of " Energys" ?
Answer» Answer: MECHANICAL ENERGY electromagnetic energy kinetic energy potential energy sonic energy thermal energy nuclear energy and GRAVITATIONAL energy

22.

Give some names of " Energys" ?

Answer»

Answer:

MECHANICAL ENERGY

electromagnetic energy

kinetic energy

potential energy

sonic energy

thermal energy

nuclear energy

and GRAVITATIONAL energy

Discussion

23.	A body is projected with an angle of theta with kinetic energy e
Answer» PLEASE Follow me and THANKS my answers as FRIENDS DEAR

23.

A body is projected with an angle of theta with kinetic energy e

Answer»

PLEASE Follow me and THANKS my answers as FRIENDS DEAR

Discussion

24.	A boat goes upstream and comes back in a total time of 7 hours 30 minutes . Find the time
Answer» Answer: 450 MIN Explanation: Time is already given as 7 hrs 30 min You want to convert the time into MINUTES? 7hr + 30 min = [7hr × 60 min / (1HR)] + 30 min = 420 min + 30 min = 450 min

24.

A boat goes upstream and comes back in a total time of 7 hours 30 minutes . Find the time

Answer»

Answer:

450 MIN

Explanation:

Time is already given as 7 hrs 30 min

You want to convert the time into MINUTES?

7hr + 30 min

= [7hr × 60 min / (1HR)] + 30 min

= 420 min + 30 min

= 450 min

Discussion

25.	A body has an initial velocity of 3.0 m/s and has an acceleration of 1m/s^2
Answer» EXPLANATION: PLZ COMPLETE your QUESTION .

25.

A body has an initial velocity of 3.0 m/s and has an acceleration of 1m/s^2

Answer»

EXPLANATION:

PLZ COMPLETE your QUESTION .

Discussion

26.	A boat can travel 36 km upstream in 5 hours the speed of the stream is 2.4 kmph, how much time will the boat take to cover a distance of 78 km downstream? (in hours)
Answer» LET downstream SPEED be Xkmph speed of STREAM = X- UPSTREAM speed 2.4= X - 7.2 X = 9.6kmph speed = Distance/ time time = 78 km /9.6 KMPH time= 8.125 hours

26.

A boat can travel 36 km upstream in 5 hours the speed of the stream is 2.4 kmph, how much time will the boat take to cover a distance of 78 km downstream? (in hours)

Answer»

LET downstream SPEED be Xkmph

speed of STREAM = X- UPSTREAM speed

2.4= X - 7.2

X = 9.6kmph

speed = Distance/ time

time = 78 km /9.6 KMPH

time= 8.125 hours

Discussion

27.	A boat a boat is sent across a river with a velocity 8 km per hour if the resultant velocity of both is 10 kilometre per hour then velocity of the river is
Answer» ANSWER: $5 \: m \: s \: \: is \: your \: answer$

27.

A boat a boat is sent across a river with a velocity 8 km per hour if the resultant velocity of both is 10 kilometre per hour then velocity of the river is

Answer»

ANSWER:

$5 \: m \: s \: \: is \: your \: answer$

Discussion

28.	A boat takes 2 hours to go 8 km and come back in still water lake. Find time taken for going 8km upstream amd coming back with water velocity 4km/hr
Answer» Explanation: Time=distance/velocityVbr= 8km/hVrg=4km/hLet T1 and t2 be the time TAKEN by BOAT to travel in UPSTREAM and DOWNSTREAM respectivelyUpstream=8-4=4Downstream=8+4=12T1=8/4=2hrT2=8/12=2/3Total time=2+2/3=2 hr and 40 mins

28.

A boat takes 2 hours to go 8 km and come back in still water lake. Find time taken for going 8km upstream amd coming back with water velocity 4km/hr

Answer»

Explanation:

Time=distance/velocityVbr= 8km/hVrg=4km/hLet T1 and t2 be the time TAKEN by BOAT to travel in UPSTREAM and DOWNSTREAM respectivelyUpstream=8-4=4Downstream=8+4=12T1=8/4=2hrT2=8/12=2/3Total time=2+2/3=2 hr and 40 mins

Discussion

29.	A block of mass m =2kg is placed in equilibrium on moving planck acceleration with acceleration a=4m/s if coefficient of friction between, is 0.2 the friction force acting on block id
Answer» Answer: 3.924 N Explanation: Given data in the question : MASS of the block, m = 2 kg ACCELERATION of the plank = 4 m/s² coefficient of friction between, μ = 0.2 It is ALSO given that the block is in equilibrium with the plank. Now, the frictional force is given as: f = μN where, N is the normal reaction N = mg g is the acceleration due to the gravity thus, N = 2 × 9.81 = 19.62 Newton hence, the friction force acting on the block is f = 0.2 × 19.62 = 3.924 N

29.

A block of mass m =2kg is placed in equilibrium on moving planck acceleration with acceleration a=4m/s if coefficient of friction between, is 0.2 the friction force acting on block id

Answer»

Answer:

3.924 N

Explanation:

Given data in the question :

MASS of the block, m = 2 kg

ACCELERATION of the plank = 4 m/s²

coefficient of friction between, μ = 0.2

It is ALSO given that the block is in equilibrium with the plank.

Now,

the frictional force is given as:

f = μN

where, N is the normal reaction

N = mg

g is the acceleration due to the gravity

thus,

N = 2 × 9.81 = 19.62 Newton

hence,

the friction force acting on the block is

f = 0.2 × 19.62 = 3.924 N

Discussion

30.	A boat goes 8 km in one hour along the stream and 2 km in one hour against the stream. The speed in km/hr of the stream is
Answer» Answer: A boat can travel with a SPEED of 15 km/hr in still water. If the speed of the stream is 6 km/hr, what is the time taken by the boat to go 69 km DOWNSTREAM? A boat goes 30 km UPSTREAM and 44 km downstream in 10 HOURS. In 13 hours, it can go 40 km upstream and 55 km down-stream.

30.

A boat goes 8 km in one hour along the stream and 2 km in one hour against the stream. The speed in km/hr of the stream is

Answer»

Answer:

A boat can travel with a SPEED of 15 km/hr in still water. If the speed of the stream is 6 km/hr, what is the time taken by the boat to go 69 km DOWNSTREAM? A boat goes 30 km UPSTREAM and 44 km downstream in 10 HOURS. In 13 hours, it can go 40 km upstream and 55 km down-stream.

Discussion

31.	Definition about unit of time 25 lines matter
Answer» Explanation: A unit of time or midst unit is any particular time interval used as a STANDARD way of measuring or expresing DURATION the base unit of time in the international system of units and by extension most of the western world us the second DEFINED as about 9 billion oscillations of the caesium ATOMS

31.

Definition about unit of time 25 lines matter

Answer»

Explanation:

A unit of time or midst unit is any particular time interval used as a STANDARD way of measuring or expresing DURATION the base unit of time in the international system of units and by extension most of the western world us the second DEFINED as about 9 billion oscillations of the caesium ATOMS

Discussion

32.	Illustration 3.24 A bird flies due east through a distance of100 m, then heading due north by a distance of 50 m, it fliesvertically up through a distance of 20 m. Find the position ofthe bird relative to its initial position.
Answer» Answer: $\hat{i}$ $\hat{j}$ $\hat{k}$ the position of the bird RELATIVE to its initial position is 100 + 50 + 20 m Explanation: Given data DISTANCE east = 100 m distance NORTH = 50 m distance vertical = 20 m to find out position of the bird solution we know bird first fly in east than north and then vertical up side so we consider here east is x axis i.e $\hat{i}$ , y is north axis i.e $\hat{j}$ and z is vertical up side i.e $\hat{k}$ we consider bird initial position is o and final position is R so final position are $\vec{R}$ = x $\hat{i}$ + y $\hat{j}$ + z $\hat{k}$ so put here x, y and z $\vec{R}$ = 100 $\hat{i}$ + 50 $\hat{j}$ + 20 $\hat{k}$ $\hat{i}$ $\hat{j}$ $\hat{k}$ so the position of the bird relative to its initial position is 100 + 50 + 20 m

32.

Illustration 3.24 A bird flies due east through a distance of100 m, then heading due north by a distance of 50 m, it fliesvertically up through a distance of 20 m. Find the position ofthe bird relative to its initial position.

Answer»

Answer:

$\hat{i}$ $\hat{j}$ $\hat{k}$ the position of the bird RELATIVE to its initial position is 100 + 50 + 20 m

Explanation:

Given data

DISTANCE east = 100 m

distance NORTH = 50 m

distance vertical = 20 m

to find out

position of the bird

solution

we know bird first fly in east than north and then vertical up side

so we consider here

east is x axis i.e $\hat{i}$ , y is north axis i.e $\hat{j}$ and z is vertical up side i.e $\hat{k}$

we consider bird initial position is o and final position is R

so final position are $\vec{R}$ = x $\hat{i}$ + y $\hat{j}$ + z $\hat{k}$

so put here x, y and z

$\vec{R}$ = 100 $\hat{i}$ + 50 $\hat{j}$ + 20 $\hat{k}$

$\hat{i}$ $\hat{j}$ $\hat{k}$ so the position of the bird relative to its initial position is 100 + 50 + 20 m

Discussion

33.	A satellite is put into a circular orbit 200 km abovethe earth's surface where the acceleration due togravity is 9.2 ms 2. Determine (i) satellite's speed(ii) Time period (time to take one revolution). Theradius of earth is 6400 km.
Answer» EXPLANATION: It is given that, Radius of the Earth, R = 6400 km A satellite is put into a circular orbit 200 km above the earth's surface, r = 200 km Value of acceleration due to GRAVITY, $a=9.2\ m/s^2$ Total DISTANCE, d = R + r d = 6400 km + 200 km = 6600 km $d=66\times 10^5\ m$ 1. The centripetal acceleration acts on the satellite which is given by : $a=\dfrac{v^2}{d}$ $v=\sqrt{ad}$ $v=\sqrt{9.2\ m/s^2\times 66\times 10^5\ m}$ $v=7792.30\ m/s$ 2. The period to taken one revolution is given by : $T=\dfrac{2\pi d}{v}$ $T=\dfrac{2\pi \times 66\times 10^5\ m}{7792.30\ m/s}$ T = 5321.79 seconds or T = 1.47 hours Hence, this is the required solution.

33.

A satellite is put into a circular orbit 200 km abovethe earth's surface where the acceleration due togravity is 9.2 ms 2. Determine (i) satellite's speed(ii) Time period (time to take one revolution). Theradius of earth is 6400 km.

Answer»

EXPLANATION:

It is given that,

Radius of the Earth, R = 6400 km

A satellite is put into a circular orbit 200 km above the earth's surface, r = 200 km

Value of acceleration due to GRAVITY, $a=9.2\ m/s^2$

Total DISTANCE, d = R + r

d = 6400 km + 200 km = 6600 km

$d=66\times 10^5\ m$

1. The centripetal acceleration acts on the satellite which is given by :

$a=\dfrac{v^2}{d}$

$v=\sqrt{ad}$

$v=\sqrt{9.2\ m/s^2\times 66\times 10^5\ m}$

$v=7792.30\ m/s$

2. The period to taken one revolution is given by :

$T=\dfrac{2\pi d}{v}$

$T=\dfrac{2\pi \times 66\times 10^5\ m}{7792.30\ m/s}$

T = 5321.79 seconds

or

T = 1.47 hours

Hence, this is the required solution.

Discussion

34.	What is electric flux
Answer» ANSWER: In electromagnetism, electric flux is the measure of the electric field through a given SURFACE, although an electric field in itself cannot flow. It is a WAY of describing the electric field strength at any DISTANCE from the charge causing the field. hope it helps u

34.

What is electric flux

Answer»

ANSWER:

In electromagnetism, electric flux is the measure of the electric field through a given SURFACE, although an electric field in itself cannot flow. It is a WAY of describing the electric field strength at any DISTANCE from the charge causing the field.

hope it helps u

Discussion

35.	Atch the following:Column ASodium chlorideWaterLime juiceLime waterMethyl orangeLitmusSting of beesTo remove acidityColumn B(a) Natural media(b) Farmic acid(c) Lichen(d) Magnesium hydroxide(e) Salt(f) Acid(g) Indicator(h) Base
Answer» ANSWER: Sodium chloride - (e) Salt Water - (a) NATURAL media Lime juice - (f) Acid Lime water - (h) BASE Methyl orange - (g) INDICATOR Litmus - (c) Lichen Sting of bees - (b) Formic Acid To remove acidity - (d)Magnesium Hydroxide In *Columb* B *2nd* *option* *should* be *Formic* *Acid* *not* Farmic *acid. #DREAM* *CHASER* *Please* mark as brainliest...

35.

Atch the following:Column ASodium chlorideWaterLime juiceLime waterMethyl orangeLitmusSting of beesTo remove acidityColumn B(a) Natural media(b) Farmic acid(c) Lichen(d) Magnesium hydroxide(e) Salt(f) Acid(g) Indicator(h) Base

Answer»

ANSWER:

Sodium chloride - (e) Salt
Water - (a) NATURAL media
Lime juice - (f) Acid
Lime water - (h) BASE
Methyl orange - (g) INDICATOR
Litmus - (c) Lichen
Sting of bees - (b) Formic Acid
To remove acidity - (d)Magnesium Hydroxide

In Columb B 2nd option should be Formic Acid not Farmic acid.

#DREAM CHASER

Please mark as brainliest...

Discussion

36.	A body of mass 50 gms is allowed to fall freely under gravity.calculate its momentum after 5 seconds (g=980 cm power minss 2
Answer» 2.45 kg m /s or 245000 g CM / sec. . Explanation. .p = m v .m = 50 g or 0.05kg Firstly finding velocity. V = u + gt Here u = 0 ( as in case of free fall) V = 9.8 x 5 V = 49m/s Now,... P = 0.05 x 49 P = 2.45 kg m / s. Done dude . I have SOLVED it in SI UNIT you can CONVERT it ACCORDING to the system you want your ans. Ok bye

36.

A body of mass 50 gms is allowed to fall freely under gravity.calculate its momentum after 5 seconds (g=980 cm power minss 2

Answer»

2.45 kg m /s or 245000 g CM / sec.

.

Explanation.

.p = m v

.m = 50 g or 0.05kg

Firstly finding velocity.

V = u + gt

Here u = 0 ( as in case of free fall)

V = 9.8 x 5

V = 49m/s

Now,...

P = 0.05 x 49

P = 2.45 kg m / s.

Done dude .

I have SOLVED it in SI UNIT you can CONVERT it ACCORDING to the system you want your ans.

Ok bye

Discussion

37.	A black disc spin with angular velocity 2w, and a point on a edge moves at velocity v. A white disc spins with angular velocity 4w ,with a point on a edge moving at velocity 4v.
Answer» EXPLANATION: APPLY conservation of angular momentum to determine the angular velocity of a ... Also, the friction is exerted very CLOSE to the pivot point. ... Two illustrations of a spinning ice skater. Using your numbers, T(0)=37.5 lb and the angle and tension for all points are plotted below. ...... For rotational motion, this means that the body spins with constant speed in a straight ...Mark as BRAINLIEST

37.

A black disc spin with angular velocity 2w, and a point on a edge moves at velocity v. A white disc spins with angular velocity 4w ,with a point on a edge moving at velocity 4v.

Answer»

EXPLANATION:

APPLY conservation of angular momentum to determine the angular velocity of a ... Also, the friction is exerted very CLOSE to the pivot point. ... Two illustrations of a spinning ice skater.

Using your numbers, T(0)=37.5 lb and the angle and tension for all points are plotted below. ...... For rotational motion, this means that the body spins with constant speed in a straight ...Mark as BRAINLIEST

Discussion

38.	A block of mass 1 kg starts from rest at x=0 and moves along the x axis under the action of a force f=t where t is time and k = 1 ns/s the distance the block with travel in 6 seconds is? Answer
Answer» Explanation: block of mass 1 kg starts from rest at x = 0 and moves along the x-axis under the action of a force. F = KT, where t is time and k = 1 NS 1. The the DISTANCE from block will be = 2*15=30metres.

38.

A block of mass 1 kg starts from rest at x=0 and moves along the x axis under the action of a force f=t where t is time and k = 1 ns/s the distance the block with travel in 6 seconds is? Answer

Answer»

Explanation:

block of mass 1 kg starts from rest at x = 0 and moves along the x-axis under the action of a force. F = KT, where t is time and k = 1 NS 1.

The the DISTANCE from block will be = 2*15=30metres.

Discussion

39.	A bird is sitting in a wire cage which is hanging from a spring balance if the birds are flying inside the case the reading of the spring balance will
Answer» Answer: Explanation: When the bird is flying in a wire cage, the AIR PRESSED by the wings of the bird will GO out of cage, HENCE the spring balance will record LESS reading.

39.

A bird is sitting in a wire cage which is hanging from a spring balance if the birds are flying inside the case the reading of the spring balance will

Answer»

Answer:

Explanation:

When the bird is flying in a wire cage, the AIR PRESSED by the wings of the bird will GO out of cage, HENCE the spring balance will record LESS reading.

Discussion

40.	A battery of 24 cells, each of emf 1.5 v and internal resistance 20 is to be connected in order to the maio through a 120 resistor. The correct arrangement of cells will be (a) 2 rows of 12 cells connected in parallel (b) 3 rows of 8 cells connected in parallel (c) 4 rows of 6 cells connected in parallel (d) all of these
Answer» Explanation: A battery of 24 cells, each of emf 1.5 v and internal resistance 20 is to be connected in ORDER to the maio through a 120 resistor. The correct ARRANGEMENT of cells will be *4 rows of 6 cells connected in* *parallel.Hope* *this* *would* be helpful.

40.

A battery of 24 cells, each of emf 1.5 v and internal resistance 20 is to be connected in order to the maio through a 120 resistor. The correct arrangement of cells will be (a) 2 rows of 12 cells connected in parallel (b) 3 rows of 8 cells connected in parallel (c) 4 rows of 6 cells connected in parallel (d) all of these

Answer»

Explanation:

A battery of 24 cells, each of emf 1.5 v and internal resistance 20 is to be connected in ORDER to the maio through a 120 resistor. The correct ARRANGEMENT of cells will be 4 rows of 6 cells connected in parallel.Hope this would be helpful.

Discussion

41.	A balloon carrying a stone is moving with uniform speed 5 metre per second vertically upward its stone instant stone is dropped from the balloon and it strikes a ground after 10 seconds of its release the height from which stone was dropped these
Answer» Explanation: When the BALLOON is at a height of 40m, a stone is dropped from it. ... A HOT air balloon is MOVING vertically upwards with a CONSTANT .

41.

A balloon carrying a stone is moving with uniform speed 5 metre per second vertically upward its stone instant stone is dropped from the balloon and it strikes a ground after 10 seconds of its release the height from which stone was dropped these

Answer»

Explanation:

When the BALLOON is at a height of 40m, a stone is dropped from it. ... A HOT air balloon is MOVING vertically upwards with a CONSTANT .

Discussion

42.	A b and c are real number such that ab+bc+ca is 12 find maximum value of a+b+c
Answer» Explanation: maximum value of expression is 4. If the value of b is 9, then the value of 'a' MUST be? If a, b, and C are positive real NUMBERS such that a+b-c/c=a-b+c/b=-a+b+c/a So, the value of a+b+c will be 4. Mark as Brainliest

42.

A b and c are real number such that ab+bc+ca is 12 find maximum value of a+b+c

Answer»

Explanation:

maximum value of expression is 4. If the value of b is 9, then the value of 'a' MUST be? If a, b, and C are positive real NUMBERS such that a+b-c/c=a-b+c/b=-a+b+c/a

So, the value of a+b+c will be 4.

Mark as Brainliest

Discussion

43.	A ball is dropped from a height of 30m and on hitting the ground if it loses 40% of its energy
Answer» Explanation: The potential ENERGY of gravity is directly affected by the height. When the ball is DROPPED from a 10m height, it loses 40% energy THUS affecting the same percentage of height when it bounces BACK. Now 40% of the energy lost means 40% of the height also lost on bouncing back.

43.

A ball is dropped from a height of 30m and on hitting the ground if it loses 40% of its energy

Answer»

Explanation:

The potential ENERGY of gravity is directly affected by the height. When the ball is DROPPED from a 10m height, it loses 40% energy THUS affecting the same percentage of height when it bounces BACK. Now 40% of the energy lost means 40% of the height also lost on bouncing back.

Discussion

44.	A automobile travelling with a speed of 60 km/ hr. Stops within a distance of 20 when the brakes are applied. If the car is going twice as fast le.. 120 km/hr, the
Answer» Answer: from Motion in a Straight LINE, jeemain,physics,class11,unit2,KINEMATICS ... If the car is GOING twice as fast, the stopping distance will be ? (a)20M(b)40m(c)60m(d)80 m.

44.

A automobile travelling with a speed of 60 km/ hr. Stops within a distance of 20 when the brakes are applied. If the car is going twice as fast le.. 120 km/hr, the

Answer»

Answer:

from Motion in a Straight LINE, jeemain,physics,class11,unit2,KINEMATICS ... If the car is GOING twice as fast, the stopping distance will be ? (a)20M(b)40m(c)60m(d)80 m.

Discussion

45.	A capacitor circuit does not allow passing ______component
Answer» Answer: Hey mate... Good noon...♥ A capacitor circuit does not allow passing DC component... Hope it helps..!!! Have a grt day ahead...^_^

45.

A capacitor circuit does not allow passing ______component

Answer»

Answer:

Hey mate...

Good noon...♥

A capacitor circuit does not allow passing DC component...

Hope it helps..!!!

Have a grt day ahead...^_^

Discussion

46.	Absolute stiffness of a prismatic beam with one end fixed is
Answer» Explanation: Absolute stiffness of a prismatic BEAM with ONE END fixed is member stiffness.

46.

Absolute stiffness of a prismatic beam with one end fixed is

Answer»

Explanation:

Absolute stiffness of a prismatic BEAM with ONE END fixed is member stiffness.

Discussion

47.	A body is deforming plastically by self weight meaning
Answer» ANSWER: LATERAL STRESS. it occurs when under the ACTION of longitudinal stress

47.

A body is deforming plastically by self weight meaning

Answer»

ANSWER:

LATERAL STRESS.

it occurs when under the ACTION of longitudinal stress

Discussion

48.	Calculate the potential energy of a stone weighing 2.5kg placed at a hieght of 6 metre
Answer» Explanation: Mass,m = 2.5 kg Height, H = 6m Acceleration due to gravity, G =9.8 m/s^2 Potential ENERGY = mgh = 2.5 × 9.8 × 6 = 147 JOULES

48.

Calculate the potential energy of a stone weighing 2.5kg placed at a hieght of 6 metre

Answer»

Explanation:

Mass,m = 2.5 kg

Height, H = 6m

Acceleration due to gravity, G =9.8 m/s^2

Potential ENERGY = mgh

= 2.5 × 9.8 × 6

= 147 JOULES

Discussion

49.	What is a wind energy farm? how is the total output taken from it?
Answer» ANSWER: Here is your answer Explanation: *wind FARM, also called a wind power STATION or wind power plant, is a GROUP of wind turbines in the same location used to produce electricity.***

49.

What is a wind energy farm? how is the total output taken from it?

Answer»

ANSWER:

Here is your answer

Explanation:

wind FARM, also called a wind power STATION or wind power plant, is a GROUP of wind turbines in the same location used to produce electricity.

Discussion

50.	What is unit of time
Answer» $\huge{\underline{\mathfrak{\purple{Hey, Mate..!!!}}}}$ $\huge{\red{\mathfrak{Answer}}}$ A unit of time or midst unit is any particular time interval, used as a standard way of measuring or expressing duration. The base unit of time in the INTERNATIONAL System of Units, and by extension most of the WESTERN world, is the second, defined as about 9 billion oscillations of the caesium atom. The base unit for time is the second (the other SI units are: metre for length, KILOGRAM for mass, ampere for electric CURRENT, kelvin for temperature, candela for luminous INTENSITY, and mole for the amount of substance). The second can be abbreviated as s or sec.

Discussion

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