1.

Illustration 3.24 A bird flies due east through a distance of100 m, then heading due north by a distance of 50 m, it fliesvertically up through a distance of 20 m. Find the position ofthe bird relative to its initial position.​

Answer»

Answer:

\hat{i}\hat{j}\hat{k}the position of  the bird RELATIVE to its initial position is 100  + 50 + 20   m

Explanation:

Given data

DISTANCE  east  = 100 m

distance NORTH = 50 m

distance vertical = 20 m

to find out

position of  the bird

solution

we know bird first fly in east than north and then vertical up side

so we consider here

east is x axis i.e \hat{i} , y is north axis i.e \hat{j}  and z is vertical up side i.e \hat{k}

we consider bird initial position is o and final position is R

so final position are \vec{R} = x \hat{i}  + y \hat{j} + z  \hat{k}

so put here x, y and z

\vec{R} = 100 \hat{i}  + 50 \hat{j} + 20  \hat{k}

\hat{i}\hat{j}\hat{k}so  the position of  the bird relative to its initial position is 100  + 50 + 20   m



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