A satellite is put into a circular orbit 200 km abovethe earth's surfa

1.	A satellite is put into a circular orbit 200 km abovethe earth's surface where the acceleration due togravity is 9.2 ms 2. Determine (i) satellite's speed(ii) Time period (time to take one revolution). Theradius of earth is 6400 km.
Answer» EXPLANATION: It is given that, Radius of the Earth, R = 6400 km A satellite is put into a circular orbit 200 km above the earth's surface, r = 200 km Value of acceleration due to GRAVITY, $a=9.2\ m/s^2$ Total DISTANCE, d = R + r d = 6400 km + 200 km = 6600 km $d=66\times 10^5\ m$ 1. The centripetal acceleration acts on the satellite which is given by : $a=\dfrac{v^2}{d}$ $v=\sqrt{ad}$ $v=\sqrt{9.2\ m/s^2\times 66\times 10^5\ m}$ $v=7792.30\ m/s$ 2. The period to taken one revolution is given by : $T=\dfrac{2\pi d}{v}$ $T=\dfrac{2\pi \times 66\times 10^5\ m}{7792.30\ m/s}$ T = 5321.79 seconds or T = 1.47 hours Hence, this is the required solution.