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On the smooth quarter circular surface of theblock, a particle is released from the state ofrest.The coefficient of friction between the block andthe ground is u.The block has mass M andthe particle has mass m.Prove that the normal reaction acting on the particle after it has rotated by anangle o measured with the horizontal, is equal toN = 3mg sineAfter that prove that the friction force needed from the ground to keep the blockin the state of rest isFr = 3mg sino coseThereafter, prove that the normal reaction acting on the block from the groundisNy = Mg + 3mg (sine)?Finally using trigonometry and the condition that requirement must be less thanor equal to the maximum available show that- very difficult>, where K = M/3msum(1+2K)2-17124K(1 +K) |
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