67486 + Interview Questions in Secondary School in Physics

1.	A solid cone of vertical height 24 cm has it's C. G at a distance S from it's vertex, along the axis.Wgat is The value of S?
Answer» Answer: g you KNOW if you need anything else from me please Explanation: THANKS for the FIRST TIME

1.

A solid cone of vertical height 24 cm has it's C. G at a distance S from it's vertex, along the axis.Wgat is The value of S?

Answer»

Answer:

g you KNOW if you need anything else from me please

Explanation:

THANKS for the FIRST TIME

Discussion

2.	A blue shark accelerates at a rate of 16m/s2 for a time of 0.8s. During this time it travels adistance of 11.52m. Calculate its initial speed. Please please please please help...
Answer» EXPLANATION: we the NEWTON's SECOND EQUATION $s = ut + 1 \div 2at ^{2}$ a=16 t=0.8 s=11.52 $11.52 = u \times 0.8 + 1 \div 2 \times 16 \times (0.8) {}^{2}$ on CALCULATING you will get Ans 8m/s

2.

A blue shark accelerates at a rate of 16m/s2 for a time of 0.8s. During this time it travels adistance of 11.52m. Calculate its initial speed. Please please please please help...

Answer»

EXPLANATION:

we the NEWTON's SECOND EQUATION

$s = ut + 1 \div 2at ^{2}$

a=16

t=0.8

s=11.52

$11.52 = u \times 0.8 + 1 \div 2 \times 16 \times (0.8) {}^{2}$

on CALCULATING

you will get

Ans 8m/s

Discussion

3.	Observe the graph and calculate the distance traveled and average speed.
Answer» Answer: distance from speed vs time graph is the AREA under the graph therefore here distance is AR(TRIANGLE + rectangle + trapezium +triangle) area of trapezium is 1/2(sum of PARALLEL sides)height ANS = 662.5

3.

Observe the graph and calculate the distance traveled and average speed.

Answer»

Answer:

distance from speed vs time graph is the AREA under the graph

therefore here distance is AR(TRIANGLE + rectangle + trapezium +triangle)

area of trapezium is 1/2(sum of PARALLEL sides)height

ANS = 662.5

Discussion

4.	A monochromatic ray of light travels from one optical medium P of absolute refractive index 2 to another optical medium Q of absolute refractive index 3. Compare the wavelength of light in P and Q
Answer» ANSWER: When a monochromatic ray of light travels from a MEDIUM of refractive index N 1 to a medium of refractive index n 2 (n 2 >n 1 ), SPEED decreases by a factor of n 1 n 2 . Because n 1 (optically RARER medium) on entering denser medium speed decreases.

4.

A monochromatic ray of light travels from one optical medium P of absolute refractive index 2 to another optical medium Q of absolute refractive index 3. Compare the wavelength of light in P and Q

Answer»

ANSWER:

When a monochromatic ray of light travels from a MEDIUM of refractive index N

1

to a medium of refractive index n

2

(n

2

>n

1

), SPEED decreases by a factor of

n

1

n

2

. Because n

1

(optically RARER medium) on entering denser medium speed decreases.

Discussion

5.	The length of a copper wire is tripled by stretching it. Compare it's initial and final resistivity.
Answer» Answer: The resistance of a WIRE is r if the length of the wire is doubled then its resistance will be R′=ρA2L. So, R = 2R'. Hence, If the length of a wire is doubled, then its resistance becomes 2 times Explanation: PLEASE MARK ME AS THE BRAINLIEST

5.

The length of a copper wire is tripled by stretching it. Compare it's initial and final resistivity.

Answer»

Answer:

The resistance of a WIRE is r if the length of the wire is doubled then its resistance will be

R′=ρA2L. So, R = 2R'. Hence, If the length of a wire is doubled, then its resistance becomes 2 times

Explanation:

PLEASE MARK ME AS THE BRAINLIEST

Discussion

6.	IF THE ERROR IN THE MEASUREMENT OFRADIUS OF A SPHERE IS 2% THEN CALCULATE THE ERROR IN DETERMINATION OF VOLUME OF THE SPHERE ???
Answer» Given :- ERROR in the measurement of radius of sphere = 2 % To find :- error in the DETERMINATION of volume of sphere Knowledge required :- Error in case of a measured quantity raised to a power Generally , if Z = Aᵇ then, Δ Z / Z = b ( Δ A / A ) Hence, the rule is STATED as : The relative error in a physical quantity raised to a power b is b times the relative error in the individual quantity. Solution :- As given percentage error in radius , r = 2 % so, ↦ ( Δ r / r ) = 2 % = 0.02 ....eqn (1) Now, Volume of sphere (V) = 4/3 π r³ ( In this formula 4/3 and π are CONSTANT . hence, Error in the volume of sphere only depends on r³ ) So, using the rule for error in case of quantity raised to any power ↦ ( Δ V / V ) = 3 ( Δ r / r ) ↦ ( Δ V / V ) = 3 ( 0.02 ) ↦ ( Δ V / V ) = 0.06 ↦ ( Δ V / V ) = 0.06 Hence, Relative error in the measurement of volume of sphere is 0.06 Converting it to percentage error ↦ ( Δ V / V ) × 100 % = 0.06 × 100 % ↦ percentage error in the volume of sphere = 6 % Hence, The percentage error in the determination of volume of sphere is 6 % .

6.

IF THE ERROR IN THE MEASUREMENT OFRADIUS OF A SPHERE IS 2% THEN CALCULATE THE ERROR IN DETERMINATION OF VOLUME OF THE SPHERE ???

Answer»

Given :-

ERROR in the measurement of radius of sphere = 2 %

To find :-

error in the DETERMINATION of volume of sphere

Knowledge required :-

Error in case of a measured quantity raised to a power

Generally ,

if Z = Aᵇ

then, Δ Z / Z = b ( Δ A / A )

Hence, the rule is STATED as : The relative error in a physical quantity raised to a power b is b times the relative error in the individual quantity.

Solution :-

As given

percentage error in radius , r = 2 %

so,

↦ ( Δ r / r ) = 2 % = 0.02 ....eqn (1)

Now,

Volume of sphere (V) = 4/3 π r³

( In this formula 4/3 and π are CONSTANT . hence, Error in the volume of sphere only depends on r³ )

So, using the rule for error in case of quantity raised to any power

↦ ( Δ V / V ) = 3 ( Δ r / r )

↦ ( Δ V / V ) = 3 ( 0.02 )

↦ ( Δ V / V ) = 0.06

Hence,

Relative error in the measurement of volume of sphere is 0.06

Converting it to percentage error

↦ ( Δ V / V ) × 100 % = 0.06 × 100 %

↦ percentage error in the volume

of sphere = 6 %

Hence,

The percentage error in the determination of volume of sphere is 6 % .

Discussion

7.	A electric motor has an output power of 2400W and is used to raise a ship's anchor. If the tension in the cable is 8KN, at what constant speed is the ancher being raised?
Answer» Answer: 0.3 m/s Explanation: power=FV 2400=8000V V=0.3m/s

7.

A electric motor has an output power of 2400W and is used to raise a ship's anchor. If the tension in the cable is 8KN, at what constant speed is the ancher being raised?

Answer»

Answer:

0.3 m/s

Explanation:

power=FV

2400=8000V

V=0.3m/s

Discussion

8.	A proton moves along the x axis according to the equation T=√x-50t/10.where x is in meter and t is in second.calculate the average velocity of the proton in first 3.0s of its motion
Answer» Given: A PROTON moves along the X axis according to the EQUATION T=√x-50t/10 where x is in meter and t is in second To find: The average velocity of the proton in first 3 s of its motion. Solution: Now we have given the equation as: t = √( x - 50t ) / 10 Now solving this, we get: 10t = √( x - 50t ) Squaring on both sides, we get: 100t^2 = x - 50t 100t^2 + 50t = x Now LET t = 3 seconds, then : x = 100(3)^2 + 50(3) x = 100(9) + 150 x = 900 + 150 x = 1050 Now we know that: average velocity = total displacement / total time Putting the VALUES in it, we get: average velocity = 1050 / 3 = 350 m/s Answer: So the average velocity is 350 m/s.

8.

A proton moves along the x axis according to the equation T=√x-50t/10.where x is in meter and t is in second.calculate the average velocity of the proton in first 3.0s of its motion

Answer»

Given: A PROTON moves along the X axis according to the EQUATION T=√x-50t/10 where x is in meter and t is in second

To find: The average velocity of the proton in first 3 s of its motion.

Solution:

Now we have given the equation as:

t = √( x - 50t ) / 10

Now solving this, we get:

10t = √( x - 50t )

Squaring on both sides, we get:

100t^2 = x - 50t

100t^2 + 50t = x

Now LET t = 3 seconds, then :

x = 100(3)^2 + 50(3)

x = 100(9) + 150

x = 900 + 150

x = 1050

Now we know that:

average velocity = total displacement / total time

Putting the VALUES in it, we get:

average velocity = 1050 / 3 = 350 m/s

Answer:

So the average velocity is 350 m/s.

Discussion

9.	If the time interval between lightning and thunder is 5 seconds then what is the distance of the nearest point of lightning.
Answer» Answer: here, TIME= 5 s speed of SOUND = 332 m/s now, DISTANCE= 5 * 332 = 1660 m Explanation:

9.

If the time interval between lightning and thunder is 5 seconds then what is the distance of the nearest point of lightning.

Answer»

Answer:

here,

TIME= 5 s

speed of SOUND = 332 m/s

now,

DISTANCE= 5 * 332

= 1660 m

Explanation:

Discussion

10.	Give natural phenomenon showing periodic motion
Answer» Moon and all celestial objects revolves in a periodic manner with a definite time PERIOD. There are lot of examples in day to day life that are periodic in NATURE. SEASONS, Weather are all periodic phenomenon of nature and apart from this EVEN the beating of our heart is periodic . ... the time it takes to MAKE a swing

10.

Give natural phenomenon showing periodic motion

Answer»

Moon and all celestial objects revolves in a periodic manner with a definite time PERIOD. There are lot of examples in day to day life that are periodic in NATURE. SEASONS, Weather are all periodic phenomenon of nature and apart from this EVEN the beating of our heart is periodic . ... the time it takes to MAKE a swing

Discussion

11.	A body of mass m is dropped from q height h derive an expression for kinetic energy of the body when it reaches the ground
Answer» Answer: MGH Explanation FORMULA of final velocity when a body is DROPPED from tower of height h is (2gh)*1/2 K $kinetic \: energy \: = \frac{1}{2} m {v}^{2}$ = $= \frac{1}{2} m { \sqrt{2gh} }^{2}$ = Mgh

11.

A body of mass m is dropped from q height h derive an expression for kinetic energy of the body when it reaches the ground

Answer»

Answer:

MGH

Explanation

FORMULA of final velocity when a body is DROPPED from tower of height h is (2gh)*1/2

K

$kinetic \: energy \: = \frac{1}{2} m {v}^{2}$

=

$= \frac{1}{2} m { \sqrt{2gh} }^{2}$

= Mgh

Discussion

12.	Please help me guys to find out solution....
Answer» find the attachment Explanation: HEY MATE here's your ANS Mark me as BRAINLIEST anwer

12.

Please help me guys to find out solution....

Answer»

find the attachment

Explanation:

HEY MATE here's your ANS

Mark me as BRAINLIEST anwer

Discussion

13.	Respective index of water 4upon 3calculate the speed of light in water speed of light in vacuum is 3 into 10 to the power 8 m/s
Answer» HOPE it helps have a NICE DAY

13.

Respective index of water 4upon 3calculate the speed of light in water speed of light in vacuum is 3 into 10 to the power 8 m/s

Answer»

HOPE it helps

have a NICE DAY

Discussion

14.	In blue light the sun flower will appear in which colour?
Answer» White LIGHT consists of all the rays of light. White light consists of all the rays of light.However when there is blue colour light the blue colour will be observed by the RED flower and there will be no REFLECTION of light to the eye of the observer and HENCE the flower will appear dark in colour.

14.

In blue light the sun flower will appear in which colour?

Answer»

White LIGHT consists of all the rays of light.

White light consists of all the rays of light.However when there is blue colour light the blue colour will be observed by the RED flower and there will be no REFLECTION of light to the eye of the observer and HENCE the flower will appear dark in colour.

Discussion

15.	humidity of air does not depend on the amount of moisture present in air( true or false) and what is the reason this is false
Answer» Answer: false Explanation: it is false HUMIDITY MEANS the AMOUNT of water present in AIR

15.

humidity of air does not depend on the amount of moisture present in air( true or false) and what is the reason this is false

Answer»

Answer:

false

Explanation:

it is false HUMIDITY MEANS the AMOUNT of water present in AIR

Discussion

16.	A miroon is 200m0 Radius ofof Cunvature ofis it ?why typeofmirinon
Answer» ┏_________∞◆∞_________┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭ ┗_________∞◆∞_________┛ A mirror having very LARGE radius of curvature generally has a very large FOCAL length too as, Focal length = Radius of curvature/2 F = R/2 = 200/2 = 100m = 10000cm Mirrors with large focal length generally tend to become PLANE mirrors

16.

A miroon is 200m0 Radius ofof Cunvature ofis it ?why typeofmirinon

Answer»

┏_________∞◆∞_________┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗_________∞◆∞_________┛

A mirror having very LARGE radius of curvature generally has a very large FOCAL length too as,

Focal length = Radius of curvature/2

F = R/2 = 200/2 = 100m = 10000cm

Mirrors with large focal length generally tend to become PLANE mirrors

Discussion

17.	Tensioneach strand.18. Give reasons for the following:(a) In a single fixed pulley, the velocity ratio isalways more than the mechanical advantage.(b) The efficiency of a movable pulley is alwaysless than 100%.(c) In case of a block and tackle system, themechanical advantage increases with theincrease in the number of pulleys.(d) The lower block of a block and tackle pulleysystem must be of negligible weight.
Answer» Answer: Explanation:(a) In a single fixed PULLEY, some effort is wasted in OVERCOMING friction between the strings and the grooves of the pulley; so the effort needed is greater than the LOAD and hence the mechanical advantage is less than the velocity ratio. (b) This is because of some effort is wasted in overcoming the friction between the strings and the grooves of the pulley. (c) This is because mechanical advantage is equal to the total number of pulleys in both the blocks. (d) The efficiency depends upon the mass of lower block; THEREFORE efficiency is reduced DUE to the weight of the lower block of pulleys.

17.

Tensioneach strand.18. Give reasons for the following:(a) In a single fixed pulley, the velocity ratio isalways more than the mechanical advantage.(b) The efficiency of a movable pulley is alwaysless than 100%.(c) In case of a block and tackle system, themechanical advantage increases with theincrease in the number of pulleys.(d) The lower block of a block and tackle pulleysystem must be of negligible weight.

Answer»

Answer:

Explanation:(a) In a single fixed PULLEY, some effort is wasted in OVERCOMING friction between the strings and the grooves of the pulley; so the effort needed is greater than the LOAD and hence the mechanical advantage is less than the velocity ratio. (b) This is because of some effort is wasted in overcoming the friction between the strings and the grooves of the pulley. (c) This is because mechanical advantage is equal to the total number of pulleys in both the blocks. (d) The efficiency depends upon the mass of lower block; THEREFORE efficiency is reduced DUE to the weight of the lower block of pulleys.

Discussion

18.	The angle between self cross product is
Answer» Answer: If the CROSS product of TWO vectors is the ZERO vector (i.e. a × b = 0), then either ONE or both of the inputs is the zero vector, (a = 0 or b = 0) or else they are parallel or ANTIPARALLEL (a ∥ b) so that the sine of the angle between them is zero (θ = 0° or θ = 180° and sinθ = 0).

18.

The angle between self cross product is

Answer»

Answer:

If the CROSS product of TWO vectors is the ZERO vector (i.e. a × b = 0), then either ONE or both of the inputs is the zero vector, (a = 0 or b = 0) or else they are parallel or ANTIPARALLEL (a ∥ b) so that the sine of the angle between them is zero (θ = 0° or θ = 180° and sinθ = 0).

Discussion

19.	A metal rod is is heated to a temperature of 200 degree Celsius it is placed in a room at 30 degree Celsius at which temperature the rod will stop radiating heat
Answer» Explanation: If the ROD is at ROOM temperature, the rod reduce it's temperature when we KEEP it in iced water then the rod START to radiate

19.

A metal rod is is heated to a temperature of 200 degree Celsius it is placed in a room at 30 degree Celsius at which temperature the rod will stop radiating heat

Answer»

Explanation:

If the ROD is at ROOM temperature, the rod reduce it's temperature when we KEEP it in iced water

then the rod START to radiate

Discussion

20.	Kindly find the value for resistance.
Answer» ANSWER: SORRY but the PICTURE is not VISIBLE to me.

20.

Kindly find the value for resistance.

Answer»

ANSWER:

SORRY but the PICTURE is not VISIBLE to me.

Discussion

21.	When pressure on water id increased then boiling pointof water as conpared to 100° will be
Answer» Answer: 100 DEGREE CELSIUS is BOILING POINT of WATER

21.

When pressure on water id increased then boiling pointof water as conpared to 100° will be

Answer»

Answer:

100 DEGREE CELSIUS is BOILING POINT of WATER

Discussion

22.	Find the force acted on a body of mass 500 gram moves with an acceleration of 0.7/s^2
Answer» Answer: 0.35 Newtons Explanation: GIVEN : Mass of the body = m = 500 grams = 0.5 kg Acceleration of the body = a = 0.7 m/s² To find : Force ACTING on the body of mass 500 grams which provides an acceleration of 0.7 m/s² Force = Mass×Acceleration Force = 0.5×0.7 Force = 0.35 Newtons The force acting on the body of mass 0.5 kg which provides an acceleration of 0.7 m/s² is EQUAL to 0.35 Newtons More : Acceleration = (v-u) / t First equation of MOTION = v=u+at Second equation of motion = s=ut+½×at² Third equation of motion = v²-u²=2as

22.

Find the force acted on a body of mass 500 gram moves with an acceleration of 0.7/s^2

Answer»

Answer:

0.35 Newtons

Explanation:

GIVEN :

Mass of the body = m = 500 grams = 0.5 kg

Acceleration of the body = a = 0.7 m/s²

To find :

Force ACTING on the body of mass 500 grams which provides an acceleration of 0.7 m/s²

Force = Mass×Acceleration

Force = 0.5×0.7

Force = 0.35 Newtons

The force acting on the body of mass 0.5 kg which provides an acceleration of 0.7 m/s² is EQUAL to 0.35 Newtons

More :

Acceleration = (v-u) / t

First equation of MOTION = v=u+at

Second equation of motion = s=ut+½×at²

Third equation of motion = v²-u²=2as

Discussion

23.	If the incident ray and reflected rays are at right angles to aeach other then the deviation of incident ray
Answer» ${30}^{0}$

23.

If the incident ray and reflected rays are at right angles to aeach other then the deviation of incident ray

Answer»

${30}^{0}$

Discussion

24.	Two cells of emf E1 and E2 are to be compared in a potentiometer (E1 > E2). When the cells are used in series connection, the balancing length obtained is 400 cm. When they are used in series but E2 is connected with reverse polarities, the balancing length obtained is 200 cm. Ratio of emf of cells is
Answer» Explanation: LET the battery EMF be V let the length of potentiometer be l let 2 EMF's be E1 and E2 RATIO of EMF of cells is 1:3 mark me the brainliest and please follow me

24.

Two cells of emf E1 and E2 are to be compared in a potentiometer (E1 > E2). When the cells are used in series connection, the balancing length obtained is 400 cm. When they are used in series but E2 is connected with reverse polarities, the balancing length obtained is 200 cm. Ratio of emf of cells is

Answer»

Explanation:

LET the battery EMF be V

let the length of potentiometer be l

let 2 EMF's be E1 and E2

RATIO of EMF of cells is 1:3

mark me the brainliest and please follow me

Discussion

25.	Subtract the first integer from the second
Answer» ANSWER: what is the question Explanation: can't UNDERSTAND

25.

Subtract the first integer from the second

Answer»

ANSWER:

what is the question

Explanation:

can't UNDERSTAND

Discussion

26.	Phenolphthalein turns in a basic solution
Answer» Phenolapthelin TURNS *PINK* in BASIC SOLUTION.

Discussion

27.	What is ohm's law ? State the formula .......Don't spam please !!
Answer» $\huge\mathscr\red{♡Hello♡}$ $\huge\mathfrak\pink{hello~friends }$ $\text{[math]}$ $\huge{\mathfrak{Ello!♡}}$ •°⭑ $\huge\mathfrak\pink{hello~Good Night }$ $\text{[math]}$ $\huge{\fbox{\fbox{\orange{\mathfrak{Answer\:Given }}}}}$ $\huge\red{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{From\:Above}}}}}}}$ $\text{[math]}$ Ohm's Law : Ohm's Law is a formula used to calculate the relationship between voltage, CURRENT and resistance in an ELECTRICAL circuit. To students of electronics, Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists. Formula : Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists. E = I x R. When spelled out, it means voltage = current x resistance, or volts = amps x OHMS, or V = A x Ω. $\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \$ $❣️☺️Mysteryboy ☺❣️$ $✌️♥️ Hope it's helps u ♥️✌️$ [/tex][/tex] $✌️♥️ Mark as Brainlist Answer ♥️✌️$ [/tex][/tex]

27.

What is ohm's law ? State the formula .......Don't spam please !!

Answer»

$\huge\mathscr\red{♡Hello♡}$

$\huge\mathfrak\pink{hello~friends }$ $\text{[math]}$

$\huge{\mathfrak{Ello!♡}}$ •°⭑

$\huge\mathfrak\pink{hello~Good Night }$ $\text{[math]}$

$\huge{\fbox{\fbox{\orange{\mathfrak{Answer\:Given }}}}}$

$\huge\red{\underbrace{\overbrace{\ulcorner{\mid{\overline{\underline{From\:Above}}}}}}}$

$\text{[math]}$

Ohm's Law :

Ohm's Law is a formula used to calculate the relationship between voltage, CURRENT and resistance in an ELECTRICAL circuit. To students of electronics, Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists.

Formula :

Ohm's Law (E = IR) is as fundamentally important as Einstein's Relativity equation (E = mc²) is to physicists. E = I x R. When spelled out, it means voltage = current x resistance, or volts = amps x OHMS, or V = A x Ω.

$\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \$

$❣️☺️Mysteryboy ☺❣️$

$✌️♥️ Hope it's helps u ♥️✌️$ [/tex][/tex]

$✌️♥️ Mark as Brainlist Answer ♥️✌️$ [/tex][/tex]

Discussion

28.	.The near point of a hypermetropic eye is 70 cm . Calculate the focal length and power of the convex lensused in his spectacles.
Answer» ANSWER: it is ROUND and very USEFUL by is jdjdbdi

28.

.The near point of a hypermetropic eye is 70 cm . Calculate the focal length and power of the convex lensused in his spectacles.

Answer»

ANSWER:

it is ROUND and very USEFUL by is jdjdbdi

Discussion

29.	6 under what condition the coverage speedus equal to the mmagnitude of the waverageveleocoaty
Answer» ANSWER: SRY couldn't UNDERSTAND the QUESTION properlyy

29.

6 under what condition the coverage speedus equal to the mmagnitude of the waverageveleocoaty

Answer»

ANSWER:

SRY couldn't UNDERSTAND the QUESTION properlyy

Discussion

30.	Higher humidity of air is mean_________saturation
Answer» higher HUMIDITY of AIR is MEAN FREQUENTLY Saturation

Discussion

31.	What is the momentum in kg.m/s of a 10 kg car travelling at 20 cm/s [b] 36 km/h
Answer» Answer: Dear Friend Here is your answer 1.. GIVEN MASS = 10 kg i) when speed is 5 m/s then momentum = mv= 10×5 =50 kgm/s ii) Speed = 20 cm/s First of all convert velocity in to m/s which will be 20/100 = 0.2 m/s Using Momentum = mv= 10×0.2 = 2 kg m /s iii) Speed = 36 km/h = 10m/s momentum = 10×10 = 100 kg m/s 2... Change in momentum = m(v-u) = 1500(20-10) = 15000 kgm/s 3.. Mass = 200 gm = 0.2 kg momentum= 0.2× 5= 1 kg m/ s.

31.

What is the momentum in kg.m/s of a 10 kg car travelling at 20 cm/s [b] 36 km/h

Answer»

Answer:

Dear Friend

Here is your answer

1..

GIVEN MASS = 10 kg

i) when speed is 5 m/s then momentum

= mv= 10×5

=50 kgm/s

ii) Speed = 20 cm/s

First of all convert velocity in to m/s

which will be 20/100 = 0.2 m/s

Using Momentum = mv= 10×0.2

= 2 kg m /s

iii) Speed = 36 km/h = 10m/s

momentum = 10×10

= 100 kg m/s

2...

Change in momentum

= m(v-u)

= 1500(20-10)

= 15000 kgm/s

3..

Mass = 200 gm = 0.2 kg

momentum= 0.2× 5= 1 kg m/ s.

Discussion

32.	A Body is moving along the positive X-AXIS with uniform acceleration of 4 m/sec.If velocity at X=0is 10m/sec The time taken by the body to reach a point at X=12 is ?
Answer» EXPLANATION: multiple all the THINGS jegar answer atuu TE fr ohnu 12 naal divided

32.

A Body is moving along the positive X-AXIS with uniform acceleration of 4 m/sec.If velocity at X=0is 10m/sec The time taken by the body to reach a point at X=12 is ?

Answer»

EXPLANATION:

multiple all the THINGS jegar answer atuu TE fr ohnu 12 naal divided

Discussion

33.	Mass is equal to 1.2 kg and volume is 60 cm cube. find the density
Answer» ┏_________∞◆∞_________┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭ ┗_________∞◆∞_________┛ Given that, MASS = m = 1.2kg = 1200g Volume = V = 60cm³ We KNOW that, DENSITY = Mass/Volume ρ = m/V ρ = 1200/60 ρ = 20 g/cm³

33.

Mass is equal to 1.2 kg and volume is 60 cm cube. find the density

Answer»

┏_________∞◆∞_________┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗_________∞◆∞_________┛

Given that,

MASS = m = 1.2kg = 1200g

Volume = V = 60cm³

We KNOW that,

DENSITY = Mass/Volume

ρ = m/V

ρ = 1200/60

ρ = 20 g/cm³

Discussion

34.	The volume of a spherical body is 200 m^(3). Half of the body floats in water.What is the weight of water displaced by the body?
Answer» 100 kg of WATER is DISPLACED Since half of the volume of the sphere is in water means it displaced 100m^3 The MASS of the 100m^3 water is 100 kg because we KNOW the density of water is 1000kg/m^3 Hope this help :D Please MARK me as the brainliest

34.

The volume of a spherical body is 200 m^(3). Half of the body floats in water.What is the weight of water displaced by the body?

Answer»

100 kg of WATER is DISPLACED

Since half of the volume of the sphere is in water means it displaced 100m^3

The MASS of the 100m^3 water is 100 kg

because we KNOW the density of water is 1000kg/m^3

Hope this help :D

Please MARK me as the brainliest

Discussion

35.	Name the force duewhich thethe earth revoled aroundthe sun ?
Answer» The FORCE DUE to which the earth revolves around the SUN is gravitational force.

35.

Name the force duewhich thethe earth revoled aroundthe sun ?

Answer»

The FORCE DUE to which the earth revolves around the SUN is gravitational force.

Discussion

36.	DC shunt motor are used inOptions-(1) Elevator (2) Cranes (3) Both and (4) None
Answer» ANSWER: none Explanation:

36.

DC shunt motor are used inOptions-(1) Elevator (2) Cranes (3) Both and (4) None

Answer»

ANSWER:

none

Explanation:

Discussion

37.	Describe an daily routine activity to demonstrate electrostatic force
Answer» Answer: CERTAIN actions LIKE rubbing or simply by coming close to each other. One such EXAMPLE can be the STICKING of paper pieces to a comb that has been rubbed on one's head. The ELECTROSTATIC energy generated in the comb attracts the paper pieces towards itself.

37.

Describe an daily routine activity to demonstrate electrostatic force

Answer»

Answer:

CERTAIN actions LIKE rubbing or simply by coming close to each other. One such EXAMPLE can be the STICKING of paper pieces to a comb that has been rubbed on one's head. The ELECTROSTATIC energy generated in the comb attracts the paper pieces towards itself.

Discussion

38.	How to find out diffraction for 1st order
Answer» Answer: In spectroscopy: X-ray OPTICS. … is an INTEGER called the order of diffraction, many weak REFLECTIONS can add constructively to produce nearly 100 percent reflection. The BRAGG condition for the reflection of X-rays is SIMILAR to the condition for optical reflection from a diffraction grating.

38.

How to find out diffraction for 1st order

Answer»

Answer:

In spectroscopy: X-ray OPTICS. … is an INTEGER called the order of diffraction, many weak REFLECTIONS can add constructively to produce nearly 100 percent reflection. The BRAGG condition for the reflection of X-rays is SIMILAR to the condition for optical reflection from a diffraction grating.

Discussion

39.	Lab Activity of observing the types of images and measuring the object distance and image distance from the concave mirror
Answer» Answer: AIM: Observing the types of images and measuring the object distance and image distance from the mirror. ... Place the concave mirror on V - stand, a candle and meter scale. KEEP the candle at different LENGTHS from the mirror along the axis and by moving the PAPER find the POSITION where you get the sharp image on paper.

39.

Lab Activity of observing the types of images and measuring the object distance and image distance from the concave mirror

Answer»

Answer:

AIM: Observing the types of images and measuring the object distance and image distance from the mirror. ... Place the concave mirror on V - stand, a candle and meter scale. KEEP the candle at different LENGTHS from the mirror along the axis and by moving the PAPER find the POSITION where you get the sharp image on paper.

Discussion

40.	Does friction produce heat....
Answer» Yes FRICTION can produce ENERGY when the it rubs on the surface. hope it HELPS you ✌️ mark as brainliest plzz....

40.

Does friction produce heat....

Answer»

Yes FRICTION can produce ENERGY when the it rubs on the surface.

hope it HELPS you ✌️

mark as brainliest plzz....

Discussion

41.	One hockey player has a mass of 50 kg was moving with a velocity of 5 metre per second -1 and other player of mass 60 kg moves towards with him with a velocity of 6 metre per second-1 while playing the clyde and get entangled with what velocity and in which direction will they move after collision ignore friction
Answer» ┏_________∞◆∞_________┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭ ┗_________∞◆∞_________┛ Here we have to use the conservation of linear momentum Initial momentum = Final momentum Given that, MASS of first player = 50kg Mass of second player = 60kg Velocity of first player = 5m/s Velocity of second player = -6m/s (Moving in OPPOSITE DIRECTION) From conservation of linear momentum, m₁u₁ + m₂u₂ = MV Since they get ENTANGLED they are considered as a single mass of M and moving with velocity V *505 - 606 = (50+60)V* 250 - 360 = 110V 110V = -110 V = -110/110 V = -1m/s Hence both players will move in the directon of the player moving with 6m/s with a velocity of 1ms

41.

One hockey player has a mass of 50 kg was moving with a velocity of 5 metre per second -1 and other player of mass 60 kg moves towards with him with a velocity of 6 metre per second-1 while playing the clyde and get entangled with what velocity and in which direction will they move after collision ignore friction

Answer»

┏_________∞◆∞_________┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗_________∞◆∞_________┛

Here we have to use the conservation of linear momentum

Initial momentum = Final momentum

Given that,

MASS of first player = 50kg

Mass of second player = 60kg

Velocity of first player = 5m/s

Velocity of second player = -6m/s (Moving in OPPOSITE DIRECTION)

From conservation of linear momentum,

m₁u₁ + m₂u₂ = MV

Since they get ENTANGLED they are considered as a single mass of M and moving with velocity V

50*5 - 60*6 = (50+60)V

250 - 360 = 110V

110V = -110

V = -110/110

V = -1m/s

Hence both players will move in the directon of the player moving with 6m/s with a velocity of 1ms

Discussion

42.	The far point of a myopic person is 175 cm from the eye. What is the nature and power of the lensrequired to correct this problem ?
Answer» Answer: GIVEN: the far point of a myopic person is 75 cmTo find: the FOCAL LENGTH of the lens used to RECTIFY this defectSolution

42.

The far point of a myopic person is 175 cm from the eye. What is the nature and power of the lensrequired to correct this problem ?

Answer»

Answer:

GIVEN: the far point of a myopic person is 75 cmTo find: the FOCAL LENGTH of the lens used to RECTIFY this defectSolution

Discussion

43.	2. A man has to go 100m north, 80m due East and 40m due South to reach a field. What is the distance and displacement.
Answer» Explanation: 1 BrainlyHelper BrainlyHelper 25.05.2018 PHYSICS Secondary School +13 pts Answered A man has to go 50m due north , 40m due east and 20m due SOUTH to reach a field . A) what distance he has to WALK to reah field? B) What is his displacement from his house to the field ? Concept of Physics - 1 , HC VERMA , CHAPTER "Rest and Motion : Kinematics 2 SEE ANSWERS Log in to add comment Answers prmkulk1978 prmkulk1978 Ace Solution: Distance : Distance is the total path COVERED by the man. Distance travelled by man=50m+40m+20m=110m Displacement : Displacement is the shortest path between source [house] and destination [ field]= AB See the figure : Draw Perpendicular BE to AC. BE=CD=40m AE=AC-CE=50-20=30 NOW, DISPLACEMENT AB=√AE²+EB² AB=√30²+40²=50m Angle with horizontal is given by tanθ=30/40=3/4 θ=tan⁻¹[3/4] direction north to east. ∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east. 4.6 143 votes THANKS 205 Comments Report V07926LOVYANSH Ambitious Answer: Explanation: Distance : Distance is the total path covered by the man. Distance travelled by man=50m+40m+20m=110m Displacement : Displacement is the shortest path between source [house] and destination [ field]= AB See the figure : Draw Perpendicular BE to AC. BE=CD=40m AE=AC-CE=50-20=30 NOW, DISPLACEMENT AB=√AE²+EB² AB=√30²+40²=50m Angle with horizontal is given by tanθ=30/40=3/4 θ=tan⁻¹[3/4] direction north to east. ∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east.

43.

2. A man has to go 100m north, 80m due East and 40m due South to reach a field. What is the distance and displacement.

Answer»

Explanation:

1

BrainlyHelper

25.05.2018

PHYSICS

Secondary School

+13 pts

Answered

A man has to go 50m due north , 40m due east and 20m due SOUTH to reach a field . A) what distance he has to WALK to reah field? B) What is his displacement from his house to the field ? Concept of Physics - 1 , HC VERMA , CHAPTER "Rest and Motion : Kinematics

2

SEE ANSWERS

Log in to add comment

Answers

prmkulk1978

prmkulk1978 Ace

Solution:

Distance :

Distance is the total path COVERED by the man.

Distance travelled by man=50m+40m+20m=110m

Displacement :

Displacement is the shortest path between source [house] and destination [ field]= AB

See the figure :

Draw Perpendicular BE to AC.

BE=CD=40m

AE=AC-CE=50-20=30

NOW, DISPLACEMENT AB=√AE²+EB²

AB=√30²+40²=50m

Angle with horizontal is given by tanθ=30/40=3/4

θ=tan⁻¹[3/4] direction north to east.

∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east.

4.6

143 votes

THANKS

205

Comments Report

V07926LOVYANSH Ambitious

Answer:

Explanation:

Distance :

Distance is the total path covered by the man.

Distance travelled by man=50m+40m+20m=110m

Displacement :

Displacement is the shortest path between source [house] and destination [ field]= AB

See the figure :

Draw Perpendicular BE to AC.

BE=CD=40m

AE=AC-CE=50-20=30

NOW, DISPLACEMENT AB=√AE²+EB²

AB=√30²+40²=50m

Angle with horizontal is given by tanθ=30/40=3/4

θ=tan⁻¹[3/4] direction north to east.

∴His displacement from his house to field is 50m , tan⁻¹[3/4] direction north to east.

Discussion

44.	What will be the area of contact of a block weighing 20N, if it can apply a pressure of 2000Pa?
Answer» Answer: Hello my FRIEND Explanation: a. F fric =μ s W=0.4∗20=8N b. SINCE F applied fric F fric =5N c. MINIMUM force required to start the MOTION F=F staticfric =8N d. Minimum force required to start the motion F=F kineticfric =μ k W=0.2∗20=4N e. F>F staticfric motion started. F>F kineticfric hence motion continues. F fric =4N

44.

What will be the area of contact of a block weighing 20N, if it can apply a pressure of 2000Pa?

Answer»

Answer:

Hello my FRIEND

Explanation:

a. F

fric

=μ

s

W=0.4∗20=8N

b. SINCE F

applied

fric

F

fric

=5N

c. MINIMUM force required to start the MOTION F=F

staticfric

=8N

d. Minimum force required to start the motion

F=F

kineticfric

=μ

k

W=0.2∗20=4N

e. F>F

staticfric

motion started.

F>F

kineticfric

hence motion continues.

F

fric

=4N

Discussion

45.	Is this circuit is in series or parallel
Answer» EXPLANATION: PARALLEL COMBINATION I HOPE you will be UNDERSTOOD

45.

Is this circuit is in series or parallel

Answer»

EXPLANATION:

PARALLEL COMBINATION

I HOPE you will be UNDERSTOOD

Discussion

46.	Guys could you please explain about the Cartesian plain of the spherical mirrors full detailthe reward is 20 points for each answer please don't spam it
Answer» Answer: In the case of spherical mirror all signs are taken from POLE of the spherical mirror, which is OFTEN called origin or origin point. ... For example if an image is formed behind the mirror, the distance of image is taken as + (positive) from pole along the principal axis. I hope it helps you plz MARK me as BRAINLIEST

46.

Guys could you please explain about the Cartesian plain of the spherical mirrors full detailthe reward is 20 points for each answer please don't spam it

Answer»

Answer:

In the case of spherical mirror all signs are taken from POLE of the spherical mirror, which is OFTEN called origin or origin point. ... For example if an image is formed behind the mirror, the distance of image is taken as + (positive) from pole along the principal axis.

I hope it helps you

plz MARK me as BRAINLIEST

Discussion

47.	a person is riding a bike at a speed of 15m/s and gently brake over a distance of 50m and come to a complete stop. what is the acceleration during this time.
Answer» Answer: uh dbhw TH SU Unicode ask TV EK ek EN th en EL fine r do g dj 0éé

47.

a person is riding a bike at a speed of 15m/s and gently brake over a distance of 50m and come to a complete stop. what is the acceleration during this time.

Answer»

Answer:

uh dbhw TH SU Unicode ask TV EK ek EN th en EL fine r do g dj 0éé

Discussion

48.	A battery is connected to a variable resistance so that the current in the circuit increases with time as I=1.2 t + 3 then the total charge that will flow in first 5 seconds will be(1) 10C(2) 20C(3) 30 C(4) 40 C
Answer» Explanation: 30 C is CORRECT ANSWER for you

48.

A battery is connected to a variable resistance so that the current in the circuit increases with time as I=1.2 t + 3 then the total charge that will flow in first 5 seconds will be(1) 10C(2) 20C(3) 30 C(4) 40 C

Answer»

Explanation:

30 C is CORRECT ANSWER for you

Discussion

49.	Write the formula for centripetal force acting on a body performing circular motion
Answer» Answer: The FORMULA for Centripetal FORCE acting on a body performing circular motion is, F = (mv^2) / r.......● where, m = mass of the object v = VELOCITY of the object r = radius of circular path. ●●●●●●●●●●●●●●●●●●● Hope it was helpful......

49.

Write the formula for centripetal force acting on a body performing circular motion

Answer»

Answer:

The FORMULA for Centripetal FORCE acting on a body performing circular motion is,

F = (mv^2) / r.......●

where, m = mass of the object

v = VELOCITY of the object

r = radius of circular path.

●●●●●●●●●●●●●●●●●●●

Hope it was helpful......

Discussion

50.	AS YOU CAN SEE THIS WHAT IS GIVEN IN FIGURE..!!SO PLEASE MAKE A FORMULAE ACCORDING TO THIS AS WHAT IT SAYS THAT FORCE IS DIRECTLY PROPOTIONAL TO PRODUCT OF THEIR MASSES AND SQUARE OF INVERSELY PROPORTIONAL TO SQUARE OF DISTANCE BETWEEN THEM...!!so please make a formulae according to this and make derivation please..!!
Answer» Answer: *F = G M1M2 / R^2 Explanation: Let the mass of the two bodies be 'M1' and 'M2' and the distance between them be 'R'** Thus , According to the question , FORCE (F) is directly proportional to (M1M2) ---> 1 ALSO, Force (F) is inversely proportional to (R^2) -----> 2 Thus , On combining 1 and 2 , F = M1M2 / R^2 Note : We cannot use '=' symbol UNLESS we add a proportionality constant Therefore , The proportionality constant becomes 'G' whose value is *6.67 10^-11 Nm^2/kg^2 . 'G' is also known as GRAVITATIONAL Constant Thus , The formula becomes F = G M1M2 / R^2* *Hope it helps*

50.

AS YOU CAN SEE THIS WHAT IS GIVEN IN FIGURE..!!SO PLEASE MAKE A FORMULAE ACCORDING TO THIS AS WHAT IT SAYS THAT FORCE IS DIRECTLY PROPOTIONAL TO PRODUCT OF THEIR MASSES AND SQUARE OF INVERSELY PROPORTIONAL TO SQUARE OF DISTANCE BETWEEN THEM...!!so please make a formulae according to this and make derivation please..!!

Answer»

Answer:

F = G M1*M2 / R^2

Explanation:

Let the mass of the two bodies be 'M1' and 'M2' and the distance between them be 'R'

Thus ,

According to the question ,

FORCE (F) is directly proportional to (M1*M2) ---> 1

ALSO,

Force (F) is inversely proportional to (R^2) -----> 2

Thus ,

On combining 1 and 2 ,

F = M1*M2 / R^2

Note : We cannot use '=' symbol UNLESS we add a proportionality constant

Therefore ,

The proportionality constant becomes 'G' whose value is 6.67 * 10^-11 Nm^2/kg^2 . 'G' is also known as GRAVITATIONAL Constant

Thus ,

The formula becomes F = G M1*M2 / R^2

Hope it helps

Discussion

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