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A proton moves along the x axis according to the equation T=√x-50t/10.where x is in meter and t is in second.calculate the average velocity of the proton in first 3.0s of its motion

Answer»

Given: A PROTON moves along the X axis according to the EQUATION T=√x-50t/10 where x is in meter and t is in second

To find: The average velocity of the proton in first 3 s of its motion.

Solution:

  • Now we have given the equation as:

                  t = √( x - 50t ) / 10

  • Now solving this, we get:

                  10t = √( x - 50t )

  • Squaring on both sides, we get:

                  100t^2 = x - 50t

                  100t^2 + 50t = x

  • Now LET t = 3 seconds, then :

                  x = 100(3)^2 + 50(3)

                  x = 100(9) + 150

                  x = 900 + 150

                  x = 1050

  • Now we know that:

                  average velocity = total displacement / total time

  • Putting the VALUES in it, we get:

                  average velocity = 1050 / 3 = 350 m/s

Answer:

          So the average velocity is 350 m/s.


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