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Two cells of emf E1 and E2 are to be compared in a potentiometer (E1 > E2). When the cells are used in series connection, the balancing length obtained is 400 cm. When they are used in series but E2 is connected with reverse polarities, the balancing length obtained is 200 cm. Ratio of emf of cells is |
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Answer» Explanation: let the length of potentiometer be l let 2 EMF's be E1 and E2 RATIO of EMF of cells is 1:3 mark me the brainliest and please follow me |
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