One hockey player has a mass of 50 kg was moving with a velocity of 5

1.	One hockey player has a mass of 50 kg was moving with a velocity of 5 metre per second -1 and other player of mass 60 kg moves towards with him with a velocity of 6 metre per second-1 while playing the clyde and get entangled with what velocity and in which direction will they move after collision ignore friction
Answer» ┏_________∞◆∞_________┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭ ┗_________∞◆∞_________┛ Here we have to use the conservation of linear momentum Initial momentum = Final momentum Given that, MASS of first player = 50kg Mass of second player = 60kg Velocity of first player = 5m/s Velocity of second player = -6m/s (Moving in OPPOSITE DIRECTION) From conservation of linear momentum, m₁u₁ + m₂u₂ = MV Since they get ENTANGLED they are considered as a single mass of M and moving with velocity V *505 - 606 = (50+60)V* 250 - 360 = 110V 110V = -110 V = -110/110 V = -1m/s Hence both players will move in the directon of the player moving with 6m/s with a velocity of 1ms

One hockey player has a mass of 50 kg was moving with a velocity of 5 metre per second -1 and other player of mass 60 kg moves towards with him with a velocity of 6 metre per second-1 while playing the clyde and get entangled with what velocity and in which direction will they move after collision ignore friction

Answer»

┏_________∞◆∞_________┓

✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗_________∞◆∞_________┛

Here we have to use the conservation of linear momentum

Initial momentum = Final momentum

Given that,

MASS of first player = 50kg

Mass of second player = 60kg

Velocity of first player = 5m/s

Velocity of second player = -6m/s (Moving in OPPOSITE DIRECTION)

From conservation of linear momentum,

m₁u₁ + m₂u₂ = MV

Since they get ENTANGLED they are considered as a single mass of M and moving with velocity V

50*5 - 60*6 = (50+60)V

250 - 360 = 110V

110V = -110

V = -110/110

V = -1m/s

Hence both players will move in the directon of the player moving with 6m/s with a velocity of 1ms