67486 + Interview Questions in Secondary School in Physics

1.	A train accelerates uniformly from 36km/h to 72km/h in 10s. Find the distance travelled
Answer» ANSWER: Given: Initial velocity = 36 km/hr Final Velocity = 72 km/hr Time TAKEN = 10 seconds To find: Distance travelled. Conversion : Convert unit of velocity from km/hr to m/s. 1. 36 km/hr = 36 × 5/18 = 10 m/s 2. 72 km/hr = 72 × 5/18 = 20 m/s Calculation: Acceleration be denoted as "a" $\therefore \: a = \dfrac{v - u}{t}$ $= > a = \dfrac{20 - 10}{10}$ $= > a = 1 \: m {s}^{ - 2}$ Now distance travelled : $\therefore \: s = ut + \frac{1}{2} a {t}^{2} \\ = > s =( 10 \times 10) + ( \dfrac{1}{2} \times 1 \times {10}^{2} ) \\ = > s = 100 + 50 \\ = > s = 150 \: metres$ So final answer : $\boxed{ \red{distance = 150 \: metres}}$ Additional information on velocity: 1. It is a VECTOR quantity. 2. It has both directions and magnitude. 3. It is also called the RATE of CHANGE of Displacement.

1.

A train accelerates uniformly from 36km/h to 72km/h in 10s. Find the distance travelled

Answer»

ANSWER:

Given:

Initial velocity = 36 km/hr

Final Velocity = 72 km/hr

Time TAKEN = 10 seconds

To find:

Distance travelled.

Conversion :

Convert unit of velocity from km/hr to

m/s.

1. 36 km/hr = 36 × 5/18 = 10 m/s

2. 72 km/hr = 72 × 5/18 = 20 m/s

Calculation:

Acceleration be denoted as "a"

$\therefore \: a = \dfrac{v - u}{t}$

$= > a = \dfrac{20 - 10}{10}$

$= > a = 1 \: m {s}^{ - 2}$

Now distance travelled :

$\therefore \: s = ut + \frac{1}{2} a {t}^{2} \\ = > s =( 10 \times 10) + ( \dfrac{1}{2} \times 1 \times {10}^{2} ) \\ = > s = 100 + 50 \\ = > s = 150 \: metres$

So final answer :

$\boxed{ \red{distance = 150 \: metres}}$

Additional information on velocity:

1. It is a VECTOR quantity.

2. It has both directions and magnitude.

3. It is also called the RATE of CHANGE of Displacement.

Discussion

2.	Why it is dangerous to stand in moving boat
Answer» Answer: No,it is not dangerous to STAND up in a moving boat . the shape of a boat's hull helps it either cut through the WATER or plane (SKIP) over top of the water.In both cases the boat is only ABLE to use the rudder/outdrive to steer if the boat is actually moving. I hope this helps you.please MARK me as the brainliest.

2.

Why it is dangerous to stand in moving boat

Answer»

Answer:

No,it is not dangerous to STAND up in a moving boat . the shape of a boat's hull helps it either cut through the WATER or plane (SKIP) over top of the water.In both cases the boat is only ABLE to use the rudder/outdrive to steer if the boat is actually moving.

I hope this helps you.please MARK me as the brainliest.

Discussion

3.	Elizabeth I had anthrophobia what was she afraid ofA) TulipsB) RosesC) SunflowersD) Jasmines
Answer» EXPLANATION: She was AFRAID of PEOPLE Anthro= FEAR of people

3.

Elizabeth I had anthrophobia what was she afraid ofA) TulipsB) RosesC) SunflowersD) Jasmines

Answer»

EXPLANATION:

She was AFRAID of PEOPLE

Anthro= FEAR of people

Discussion

4.	Total energy of the power signal
Answer» ANSWER: The total energy of POWER SIGNAL is INFINITE.

4.

Total energy of the power signal

Answer»

ANSWER:

The total energy of POWER SIGNAL is INFINITE.

Discussion

5.	List all the simple materials used to make a toy aeroplane that can fly
Answer» ANSWER: SIMPLE BRO only some MATERIALS are USED

5.

List all the simple materials used to make a toy aeroplane that can fly

Answer»

ANSWER:

SIMPLE BRO only some MATERIALS are USED

Discussion

6.	Give reasons why it is a must for an aeroplane to (6 reasons)
Answer» ANSWER: hey MATE.....bro........pls complete the question ...U will GET perfect answers. EXPLANATION: follow me give tnx.

6.

Give reasons why it is a must for an aeroplane to (6 reasons)

Answer»

ANSWER:

hey MATE.....bro........pls complete the question ...U will GET perfect answers.

EXPLANATION:

follow me

give tnx.

Discussion

7.	a uniform rod of mass m and length l is hinged at upper end the rod is free to rotate in vertical plane a ball of mass m moving horizontally with velocity v colloides at lower end of rod perpendicularly to it and stick to it the minimum velocity of ball such that combined system just complete the vertical circle will be
Answer» The Minimum velocity of the ball such that combined system just COMPLETE the vertical circle is $2\sqrt{\frac{gl}{3}}$ Explanation: We know that for a rod of mass m and length l is $\frac{1}{3}ml^2$ Initially the angular velocity of the rod is zero If after impact the combined angular velocity of the rod and the ball is $\omega$ Then, Initial Kinetic Energy of the ball $=\frac{1}{2}mv^2$ This will comvert into ROTATIONAL kinetic energy of the system (Rod + Ball) after impact Therefore, the kinetic energy of the system (Rod + Ball) after impact $=\frac{1}{2}I_{Sys}\omega^2$ Where, $I_{Sys}$ is the moment of inertia of rod + ball system $I_{Sys}=\frac{1}{3}ml^2+ml^2$ $\implies I_{Sys}=\frac{4}{3}ml^2$ From the conservation of energy The kinteic energy before the impact and after the impact will be same Hence, $\frac{1}{2}mv^2=\frac{1}{2}I_{Sys}\omega^2$ $\implies mv^2=\frac{4}{3}ml^2\times \omega^2$ $\implies \omega^2=\frac{3v^2}{4l^2}$ $\implies \omega=\sqrt{\frac{3}{4}}\frac{v}{l}$ THUS, the linear velocity of the system $V=\omega\times l$ $\implies V=\sqrt{\frac{3}{4}}v$ For the system to just complete a full circle $V=\sqrt{gl}$ $\implies \sqrt{\frac{3}{4}}v=\sqrt{gl}$ $\implies v^2=\frac{4}{3}gl$ $\implies v=2\sqrt{\frac{gl}{3}}$ Hope this answer is helpful. Know More: SIMILAR question Click Here: brainly.in/question/9258976

7.

a uniform rod of mass m and length l is hinged at upper end the rod is free to rotate in vertical plane a ball of mass m moving horizontally with velocity v colloides at lower end of rod perpendicularly to it and stick to it the minimum velocity of ball such that combined system just complete the vertical circle will be

Answer»

The Minimum velocity of the ball such that combined system just COMPLETE the vertical circle is $2\sqrt{\frac{gl}{3}}$

Explanation:

We know that for a rod of mass m and length l is

$\frac{1}{3}ml^2$

Initially the angular velocity of the rod is zero

If after impact the combined angular velocity of the rod and the ball is $\omega$

Then,

Initial Kinetic Energy of the ball

$=\frac{1}{2}mv^2$

This will comvert into ROTATIONAL kinetic energy of the system (Rod + Ball) after impact

Therefore,

the kinetic energy of the system (Rod + Ball) after impact

$=\frac{1}{2}I_{Sys}\omega^2$

Where, $I_{Sys}$ is the moment of inertia of rod + ball system

$I_{Sys}=\frac{1}{3}ml^2+ml^2$

$\implies I_{Sys}=\frac{4}{3}ml^2$

From the conservation of energy

The kinteic energy before the impact and after the impact will be same

Hence,

$\frac{1}{2}mv^2=\frac{1}{2}I_{Sys}\omega^2$

$\implies mv^2=\frac{4}{3}ml^2\times \omega^2$

$\implies \omega^2=\frac{3v^2}{4l^2}$

$\implies \omega=\sqrt{\frac{3}{4}}\frac{v}{l}$

THUS, the linear velocity of the system

$V=\omega\times l$

$\implies V=\sqrt{\frac{3}{4}}v$

For the system to just complete a full circle

$V=\sqrt{gl}$

$\implies \sqrt{\frac{3}{4}}v=\sqrt{gl}$

$\implies v^2=\frac{4}{3}gl$

$\implies v=2\sqrt{\frac{gl}{3}}$

Hope this answer is helpful.

Know More:

SIMILAR question

Click Here: brainly.in/question/9258976

Discussion

8.	How do We go to the past? it is a very Important question all are waiting for this answer.so please tell me the answer.
Answer» Explanation: Time TRAVEL to the past is theoretically POSSIBLE in certain general relativity spacetime GEOMETRIES that permit traveling faster than the speed of LIGHT, such as COSMIC strings, transversable wormholes, and Alcubierre drive.

8.

How do We go to the past? it is a very Important question all are waiting for this answer.so please tell me the answer.

Answer»

Explanation:

Time TRAVEL to the past is theoretically POSSIBLE in certain general relativity spacetime GEOMETRIES that permit traveling faster than the speed of LIGHT, such as COSMIC strings, transversable wormholes, and Alcubierre drive.

Discussion

9.	Write a third lae of motion
Answer» Answer: hi here is ans Explanation: it states that EVERY ACTION has equal and opposite REACTION

9.

Write a third lae of motion

Answer»

Answer:

hi here is ans

Explanation:

it states that EVERY ACTION has equal and opposite REACTION

Discussion

10.	Mohit while seated on the back desk, is not able to read the text written on the blackboard clearly.(a) Name the defect of vision from which he is suffering.(b) State one likely cause of his eye defect . (c) How can it be corrected.
Answer» ANSWER: The CORRECT answer is MYOPIA.

10.

Mohit while seated on the back desk, is not able to read the text written on the blackboard clearly.(a) Name the defect of vision from which he is suffering.(b) State one likely cause of his eye defect . (c) How can it be corrected.

Answer»

ANSWER:

The CORRECT answer is MYOPIA.

Discussion

11.	What a newland law of octaves
Answer» EXPLANATION: it is the ANSWER........

11.

What a newland law of octaves

Answer»

EXPLANATION:

it is the ANSWER........

Discussion

12.	A body describes a semi circular path of radius 7m in 11s.Find the speed and magnitude of velocity of the body
Answer» ANSWER: speed will be EQUAL to distance by time it means speed=7m/11sec which is equal to 7/11 meter PER SECOND

12.

A body describes a semi circular path of radius 7m in 11s.Find the speed and magnitude of velocity of the body

Answer»

ANSWER:

speed will be EQUAL to distance by time it means

speed=7m/11sec which is equal to 7/11 meter PER SECOND

Discussion

13.	What a dobereiner's triad
Answer» Answer: In the history of the periodic table, Döbereiner's triads were an early attempt to sort the elements into some logical order by their physical PROPERTIES. In 1817, a letter reported Johann Wolfgang Döbereiner's observations of the ALKALINE earths; namely, that STRONTIUM had properties that were intermediate to those of calcium and barium.[1] By 1829, Döbereiner had found other groups of three elements (hence "triads") whose physical properties were similarly related.[2] He also noted that some quantifiable properties of elements (e.g. atomic weight and density) in a triad followed a trend whereby the value of the MIDDLE element in the triad would be exactly or nearly predicted by taking the arithmetic mean of values for that property of the other two elements. please mark it as brainliest

13.

What a dobereiner's triad

Answer»

Answer:

In the history of the periodic table, Döbereiner's triads were an early attempt to sort the elements into some logical order by their physical PROPERTIES. In 1817, a letter reported Johann Wolfgang Döbereiner's observations of the ALKALINE earths; namely, that STRONTIUM had properties that were intermediate to those of calcium and barium.[1] By 1829, Döbereiner had found other groups of three elements (hence "triads") whose physical properties were similarly related.[2] He also noted that some quantifiable properties of elements (e.g. atomic weight and density) in a triad followed a trend whereby the value of the MIDDLE element in the triad would be exactly or nearly predicted by taking the arithmetic mean of values for that property of the other two elements.

please mark it as brainliest

Discussion

14.	2.A physicist works in a laboratory where the magnetic field is21. She wears a necklace enclosing area 0.01 m in such a waythat the plane of the necklace is normal to the field and ishaving a resistance R=0010Because of power failure, thefield decays to 1 Tin time 10 seconds. Then what is the totalheat produced in her necklace ( Teks)(*)10(1) 204(c)30(d)40J
Answer» ANSWER: ) 10 is the CORRECT answer Explanation:* PLEASE mark me as brainliest

14.

2.A physicist works in a laboratory where the magnetic field is21. She wears a necklace enclosing area 0.01 m in such a waythat the plane of the necklace is normal to the field and ishaving a resistance R=0010Because of power failure, thefield decays to 1 Tin time 10 seconds. Then what is the totalheat produced in her necklace ( Teks)(*)10(1) 204(c)30(d)40J

Answer»

ANSWER:

*) 10 is the CORRECT answer

Explanation:

PLEASE mark me as brainliest

Discussion

15.	Hii.....What is meant by Triads ???
Answer» Answer: a group of THREE PEOPLE or THINGS that are CONNECTED with each other.

15.

Hii.....What is meant by Triads ???

Answer»

Answer:

a group of THREE PEOPLE or THINGS that are CONNECTED with each other.

Discussion

16.	X) The number of atoms per unit cell of body centred cube is:(a) 1(6) 2(c) 4(d) 6
Answer» ANSWER: (the answer is (a)1 HOPE this HELPS U

16.

X) The number of atoms per unit cell of body centred cube is:(a) 1(6) 2(c) 4(d) 6

Answer»

ANSWER:

(the answer is

(a)1

HOPE this HELPS U

Discussion

17.	Class 9th \| PHYSICS \| GravitationWhat is the difference between 'G' and 'g'?
Answer» Answer: G is the ACCURATE VALUE of SOMETHING MAY be given in your book and (g) refers to gravity

17.

Class 9th | PHYSICS | GravitationWhat is the difference between 'G' and 'g'?

Answer»

Answer:

G is the ACCURATE VALUE of SOMETHING MAY be given in your book and (g) refers to gravity

Discussion

18.	Why can’t a scale be fixed with the tube of a simple barometer?
Answer» EXPLANATION: A scale cannot be fixed on the TUBE of a simple barometer as the zero of the scale will not always coincide with the surface level of the mercury in the trough. when the atmospheric PRESSURE rises the level of mercury in the trough will decrease and the the barometric HEIGHT will rise and VICE versa.

18.

Why can’t a scale be fixed with the tube of a simple barometer?

Answer»

EXPLANATION:

A scale cannot be fixed on the TUBE of a simple barometer as the zero of the scale will not always coincide with the surface level of the mercury in the trough. when the atmospheric PRESSURE rises the level of mercury in the trough will decrease and the the barometric HEIGHT will rise and VICE versa.

Discussion

19.	9. Two forces F1 and F2 of magnitude 20N and 10 N respectively, are acting on a body of mass 5 kgopposite direction, then acceleration in the body is(a) 23 m/s^2 (b) 3 m/s^2(c) 2 m/s^2 (d) 22 m/s^2
Answer» Question :- → Two forces F1 and F2 of magnitude 20N and 10 N respectively, are acting on a body of MASS 5 kg opposite direction, then acceleration in the body is- Answer :- → Acceleration in body is $\sf\: 2\: \: \frac{m}{s^2}$ → Option (C) is correct . To Find :- → Acceleration in the body Solution :- We have , → $\sf\: F_1 = 20 N$ → $\sf\: F_2 = 10 N$ Now , → Resultant force (F) = $\sf\: F_1 - F_2$ → F = 20 - 10 N → F = 10 N , °•° acceleration (a) = ? ,m = 5 kg HENCE ,we know that → $\sf\: F= m a$ → $\sf\: a= \frac{F}{m}$ → $\sf\: a = \frac{10}{5}$ → $\sf\: a = 2 \: \: \frac{m}{s^2}$ Hence , acceleration in body is $\sf\: 2 \: \: \frac{m}{s^2}$

19.

9. Two forces F1 and F2 of magnitude 20N and 10 N respectively, are acting on a body of mass 5 kgopposite direction, then acceleration in the body is(a) 23 m/s^2 (b) 3 m/s^2(c) 2 m/s^2 (d) 22 m/s^2

Answer»

Question :-

→ Two forces F1 and F2 of magnitude 20N and 10 N respectively, are acting on a body of MASS 5 kg

opposite direction, then acceleration in the body is-

Answer :-

→ Acceleration in body is $\sf\: 2\: \: \frac{m}{s^2}$

→ Option (C) is correct .

To Find :-

→ Acceleration in the body

Solution :-

We have ,

→ $\sf\: F_1 = 20 N$

→ $\sf\: F_2 = 10 N$

Now ,

→ Resultant force (F) = $\sf\: F_1 - F_2$

→ F = 20 - 10 N

→ F = 10 N ,

°•° acceleration (a) = ? ,m = 5 kg

HENCE ,we know that

→ $\sf\: F= m a$

→ $\sf\: a= \frac{F}{m}$

→ $\sf\: a = \frac{10}{5}$

→ $\sf\: a = 2 \: \: \frac{m}{s^2}$

Hence , acceleration in body is $\sf\: 2 \: \: \frac{m}{s^2}$

Discussion

20.	We watch movies as a result of_______.( fill in the blanks ).
Answer» ANSWER: SUCCESS...... EXPLANATION: MARK me as BRAINLIEST....

20.

We watch movies as a result of_______.( fill in the blanks ).

Answer»

ANSWER:

SUCCESS......

EXPLANATION:

MARK me as BRAINLIEST....

Discussion

21.	A body describe a semicircular path of radius 7m in 11s .Find the speed and magnitude of velocity of the body
Answer» ANSWER: RADIUS =7m time= 11s then,distance=22/7= 22m and displacement=2×7=14m • • • SPEED = 22/11= 2 m/sec (speed= distance/time) and VELOCITY=14/11 m/sec(velocity = displacement/time)

21.

A body describe a semicircular path of radius 7m in 11s .Find the speed and magnitude of velocity of the body

Answer»

ANSWER:

RADIUS =7m

time= 11s

then,distance=22/7= 22m

and displacement=2×7=14m

•

• • SPEED = 22/11= 2 m/sec (speed= distance/time)

and VELOCITY=14/11 m/sec(velocity = displacement/time)

Discussion

22.	How much current does an electric lamp draw from a 220 V line, if the resistance of the filament (when hot) is 110 ohm?answer me fastly follow me
Answer» ANSWER: I = 2 A Explanation: We KNOW that, V = IR 220 = I × 110 I = 220 ÷ 110 I = 2 ampere *HOPE* *THIS* *HELPS* *YOU*.......

22.

How much current does an electric lamp draw from a 220 V line, if the resistance of the filament (when hot) is 110 ohm?answer me fastly follow me

Answer»

ANSWER:

I = 2 A

Explanation:

We KNOW that, V = IR

220 = I × 110

I = 220 ÷ 110

I = 2 ampere

HOPE THIS HELPS YOU.......

Discussion

23.	The average distance of the sun from a planet is 4 times in comparision to average distance ofsun from earth. Find the time period of revolution of the planet
Answer» Answer: 8 TIMES the earth. Explanation: the WHOLE DESCRIPTION is in above pic. Hope it will HELP you ! !

23.

The average distance of the sun from a planet is 4 times in comparision to average distance ofsun from earth. Find the time period of revolution of the planet

Answer»

Answer:

8 TIMES the earth.

Explanation:

the WHOLE DESCRIPTION is in above pic.

Hope it will HELP you ! !

Discussion

24.	At what temperature will the reading on the centigrades scale be identical with the reading on the fahrenheit scale?
Answer» ANSWER: TEMPERATURE when both the Celsius and Fahrenheit SCALES are the same is -40 degrees.

24.

At what temperature will the reading on the centigrades scale be identical with the reading on the fahrenheit scale?

Answer»

ANSWER:

TEMPERATURE when both the Celsius and Fahrenheit SCALES are the same is -40 degrees.

Discussion

25.	Which portion of temperature time graph showing heat of ice at -10°c to water at 100°c represents the change of state of heating (a)ab,bc (b)cd,de (c)de,bc (d)ab,cd
Answer» C DE de FRANCE AD BC

Discussion

26.	What amount of heat must be supplied to 2.0 × 10–2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure? (Molecular mass of N2 = 28; R = 8.3 J mol–1 K–1.)
Answer» Answer: Mass of nitrogen, m = 2.0 × 10–2 kg = 20 g Rise in temperature, ΔT = 45°C Molecular mass of N2, M = 28 Universal gas constant, R = 8.3 J mol–1 K–1 Number of moles, n = m/M = (2 × 10-2 × 103) / 28 = 0.714 Molar specific heat at constant pressure for nitrogen, Cp = (7/2)R = (7/2) × 8.3 = 29.05 J mol-1 K-1 The total AMOUNT of heat to be supplied is given by the relation: ΔQ = NCP ΔT = 0.714 × 29.05 × 45 = 933.38 J Therefore, the amount of heat to be supplied is 933.38 J.

26.

What amount of heat must be supplied to 2.0 × 10–2 kg of nitrogen (at room temperature) to raise its temperature by 45 °C at constant pressure? (Molecular mass of N2 = 28; R = 8.3 J mol–1 K–1.)

Answer»

Answer:

Mass of nitrogen, m = 2.0 × 10–2 kg = 20 g

Rise in temperature, ΔT = 45°C

Molecular mass of N2, M = 28

Universal gas constant, R = 8.3 J mol–1 K–1

Number of moles, n = m/M

= (2 × 10-2 × 103) / 28

= 0.714

Molar specific heat at constant pressure for nitrogen, Cp = (7/2)R

= (7/2) × 8.3

= 29.05 J mol-1 K-1

The total AMOUNT of heat to be supplied is given by the relation:

ΔQ = NCP ΔT

= 0.714 × 29.05 × 45

= 933.38 J

Therefore, the amount of heat to be supplied is 933.38 J.

Discussion

27.	What is velocity? It is denoted by which sign?
Answer» ANSWER: Velocity Is speed in DISTANCE in PROPER PROPOTIONAL time. It is Denoted By 'V'

27.

What is velocity? It is denoted by which sign?

Answer»

ANSWER:

Velocity Is speed in DISTANCE in PROPER PROPOTIONAL time. It is Denoted By 'V'

Discussion

28.	moment of inertia of uniform ring about an axis passing through its centre and perpendicular to its plane is MR². find its moment of inertia .i) about its one of the diameter ii) About a tangent drawn on it and parallel to diameter.
Answer» Answer: yes you are right hope this answer HELPED you if it is not CORRECT PLEASE put thanks to me

28.

moment of inertia of uniform ring about an axis passing through its centre and perpendicular to its plane is MR². find its moment of inertia .i) about its one of the diameter ii) About a tangent drawn on it and parallel to diameter.

Answer»

Answer:

yes you are right hope this answer HELPED you

if it is not CORRECT PLEASE put thanks to me

Discussion

29.	What is displacement?
Answer» <P>Explanation: In GEOMETRY, a displacement is a VECTOR whose length is the shortest distance from the INITIAL to the final position of a point P undergoing motion. It quantifies both the distance and direction of the net or total motion along a straight line from the initial position to the final position of the point TRAJECTORY.

29.

What is displacement?

Answer»

<P>Explanation:

In GEOMETRY, a displacement is a VECTOR whose length is the shortest distance from the INITIAL to the final position of a point P undergoing motion. It quantifies both the distance and direction of the net or total motion along a straight line from the initial position to the final position of the point TRAJECTORY.

Discussion

30.	Is charging is a transfer of charge from one object to another?Please tell me friends. Is it right answer?
Answer» Answer: $\huge \purple{hello}$ yes, charging is a transfer of charge from ONE object to another. Explanation: $\orange{example}$ Woolen clothes are CHARGED when they rubbed .Due to this attraction of rubbing they transfer from charge to another object.. MARK as braiieest and gives44 LIKES brother

30.

Is charging is a transfer of charge from one object to another?Please tell me friends. Is it right answer?

Answer»

Answer:

$\huge \purple{hello}$

yes, charging is a transfer of charge from ONE object to another.

Explanation:

$\orange{example}$

Woolen clothes are CHARGED when they rubbed .Due to this attraction of rubbing they transfer from charge to another object..

MARK as braiieest and gives44 LIKES brother

Discussion

31.	A gun of mass 2kg fired a bullet of 20 grms and the velocity after 5 sec of firing is 200m/s.recoil the velocity??plz answer my question in detail and as fast as possible
Answer» Answer: 2 m/ s Explanation: Mass of gun =2 kg Mass of PISTOL =2 g=0.02kg According to law of conservation of MOMENTUM MV= -MV 0.02×200= -2×V V= -0.02×200÷2 V= -2 m/s

31.

A gun of mass 2kg fired a bullet of 20 grms and the velocity after 5 sec of firing is 200m/s.recoil the velocity??plz answer my question in detail and as fast as possible

Answer»

Answer:

2 m/ s

Explanation:

Mass of gun =2 kg

Mass of PISTOL =2 g=0.02kg

According to law of conservation of MOMENTUM MV= -MV

0.02×200= -2×V

V= -0.02×200÷2

V= -2 m/s

Discussion

32.	A geyser heats water flowing at the rate of 3.0 litres per minute from 27 °C to 77 °C. If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 × 104 J/g?
Answer» Answer: Water is flowing at a rate of 3.0 litre/min. The geyser HEATS the water, raising the temperature from 27°C to 77°C. Initial temperature, T1 = 27°C Final temperature, T2 = 77°C ∴Rise in temperature, ΔT = T2 – T1 = 77 – 27 = 50°C Heat of combustion = 4 × 104 J/g Specific heat of water, c = 4.2 J g–1 °C–1 Mass of flowing water, m = 3.0 litre/min = 3000 g/min Total heat used, ΔQ = mc ΔT = 3000 × 4.2 × 50 = 6.3 × 105 J/min ∴ Rate of consumption = 6.3 × 105 / (4 × 104) = 15.75 g/min.

32.

A geyser heats water flowing at the rate of 3.0 litres per minute from 27 °C to 77 °C. If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 × 104 J/g?

Answer»

Answer:

Water is flowing at a rate of 3.0 litre/min.

The geyser HEATS the water, raising the temperature from 27°C to 77°C.

Initial temperature, T1 = 27°C

Final temperature, T2 = 77°C

∴Rise in temperature, ΔT = T2 – T1

= 77 – 27 = 50°C

Heat of combustion = 4 × 104 J/g

Specific heat of water, c = 4.2 J g–1 °C–1

Mass of flowing water, m = 3.0 litre/min = 3000 g/min

Total heat used, ΔQ = mc ΔT

= 3000 × 4.2 × 50

= 6.3 × 105 J/min

∴ Rate of consumption = 6.3 × 105 / (4 × 104) = 15.75 g/min.

Discussion

33.	What are planets? Why are planets seen only in night?
Answer» that a PLANET is a body that ORBITS the Sun, We can see the planets at NIGHT, assuming that the planet of interest is on the night side of the Earth and unobstructed from VIEW. The planets that are visible in the night sky on any particular night look like stars

33.

What are planets? Why are planets seen only in night?

Answer»

that a PLANET is a body that ORBITS the Sun,

We can see the planets at NIGHT, assuming that the planet of interest is on the night side of the Earth and unobstructed from VIEW. The planets that are visible in the night sky on any particular night look like stars

Discussion

34.	Can we fill three electrons in an orbital ? Reason
Answer» Answer: Explanation: YES, it is very much POSSIBLE to FILL an orbit with 3 ELECTRONS, because the MAXIMUM number of electrons that can be obtained in an orbit is 8.

34.

Can we fill three electrons in an orbital ? Reason

Answer»

Answer:

Explanation:

YES, it is very much POSSIBLE to FILL an orbit with 3 ELECTRONS, because the MAXIMUM number of electrons that can be obtained in an orbit is 8.

Discussion

35.	Example on which inertia of a body depends
Answer» Answer:MARK as brainliest and follow plz Explanation: Inertia of a body DEPENDS on its mass. The larger the mass, the larger is the inertia of the body. THEREFORE it is more DIFFICULT to move a body from rest or to STOP the motion of a moving body of larger mass than that of smaller mass.

35.

Example on which inertia of a body depends

Answer»

Answer:MARK as brainliest and follow plz

Explanation: Inertia of a body DEPENDS on its mass. The larger the mass, the larger is the inertia of the body. THEREFORE it is more DIFFICULT to move a body from rest or to STOP the motion of a moving body of larger mass than that of smaller mass.

Discussion

36.	Who was the first DGP
Answer» ANSWER: KANCHAN CHAUDHARY BHATTACHARYA

36.

Who was the first DGP

Answer»

ANSWER:

KANCHAN CHAUDHARY BHATTACHARYA

Discussion

37.	Answers with explanation plz
Answer» ANSWER: III . magnesium v. 4°C ii. zero i.absorption of LIGHT in the EARTH's atmosphere iv.behind the SCREEN

37.

Answers with explanation plz

Answer»

ANSWER:

III . magnesium

v. 4°C

ii. zero

i.absorption of LIGHT in the EARTH's atmosphere

iv.behind the SCREEN

Discussion

38.	What is normal force
Answer» Answer: FORCE is the ENERGY which MOVES ONE object from another place

38.

What is normal force

Answer»

Answer:

FORCE is the ENERGY which MOVES ONE object from another place

Discussion

39.	Let us assume that our galaxy consists of 2.5 × 1011 stars each of one solar mass. How long will a star at a distance of 50,000 ly from the galactic centre take to complete one revolution? Take the diameter of the Milky Way to be 105 ly.
Answer» Answer: Mass of our galaxy Milky Way, M = 2.5 × 1011 solar mass Solar mass = Mass of Sun = 2.0 × 1036 kg Mass of our galaxy, M = 2.5 × 1011 × 2 × 1036 = 5 × 1041 kg Diameter of Milky Way, d = 105 ly Radius of Milky Way, R = 5 × 104 ly 1 ly = 9.46 × 1015 m ∴r = 5 × 104 × 9.46 × 1015 = 4.73 ×1020 m SINCE a star REVOLVES around the galactic centre of the Milky Way, its time period is given by the relation: T = ( 4π2r3 / GM)1/2 = [ (4 × 3.142 × 4.733 × 1060) / (6.67 × 10-11 × 5 × 1041) ]1/2 = (39.48 × 105.82 × 1030 / 33.35 )1/2 = 1.12 × 1016 s 1 year = 365 × 324 × 60 × 60 s 1s = 1 / (365 × 324 × 60 × 60) years ∴ 1.12 × 1016 s = 1.12 × 1016 / (365 × 24 × 60 × 60) = 3.55 × 108 years.

39.

Let us assume that our galaxy consists of 2.5 × 1011 stars each of one solar mass. How long will a star at a distance of 50,000 ly from the galactic centre take to complete one revolution? Take the diameter of the Milky Way to be 105 ly.

Answer»

Answer:

Mass of our galaxy Milky Way, M = 2.5 × 1011 solar mass

Solar mass = Mass of Sun = 2.0 × 1036 kg

Mass of our galaxy, M = 2.5 × 1011 × 2 × 1036 = 5 × 1041 kg

Diameter of Milky Way, d = 105 ly

Radius of Milky Way, R = 5 × 104 ly

1 ly = 9.46 × 1015 m

∴r = 5 × 104 × 9.46 × 1015

= 4.73 ×1020 m

SINCE a star REVOLVES around the galactic centre of the Milky Way, its time period is given by the relation:

T = ( 4π2r3 / GM)1/2

= [ (4 × 3.142 × 4.733 × 1060) / (6.67 × 10-11 × 5 × 1041) ]1/2

= (39.48 × 105.82 × 1030 / 33.35 )1/2

= 1.12 × 1016 s

1 year = 365 × 324 × 60 × 60 s

1s = 1 / (365 × 324 × 60 × 60) years

∴ 1.12 × 1016 s = 1.12 × 1016 / (365 × 24 × 60 × 60) = 3.55 × 108 years.

Discussion

40.	Si unit of amptitude
Answer» Answer: did you want si unit of amplitude is This DISTANCE is known as the amplitude of the WAVE, and is the CHARACTERISTIC height of the wave, above or below the equilibrium POSITION. Normally the symbol A is used to represent the amplitude of a wave. The SI unit of amplitude is the metre (m). I hope it will HELP you

40.

Si unit of amptitude

Answer»

Answer:

did you want si unit of amplitude is

This DISTANCE is known as the amplitude of the WAVE, and is the CHARACTERISTIC height of the wave, above or below the equilibrium POSITION. Normally the symbol A is used to represent the amplitude of a wave. The SI unit of amplitude is the metre (m).

I hope it will HELP you

Discussion

41.	Io, one of the satellites of Jupiter, has an orbital period of 1.769 days and the radius of the orbit is 4.22 × 108 m. Show that the mass of Jupiter is about one-thousandth that of the sun.
Answer» Answer: Orbital period of I0 , TI0 = 1.769 days = 1.769 × 24 × 60 × 60 s Orbital radius of I0 , RI0 = 4.22 × 108 m Satellite I0 is REVOLVING around the Jupiter Mass of the latter is GIVEN by the relation: MJ = 4π2RI03 / GTI02 .....(i) Where, MJ = Mass of Jupiter G = Universal gravitational constant Orbital period of the earth, Te = 365.25 days = 365.25 × 24 × 60 × 60 s Orbital radius of the Earth, Re = 1 AU = 1.496 × 1011 m Mass of sun is given as: Ms = 4π2Re3 / GTe2 ......(ii) ∴ Ms / MJ = (4π2Re3 / GTe2) × (GTI02 / 4π2RI03) = (Re3 × TI02) / (RI03 × TE2) Substituting the values, we GET: = (1.769 × 24 × 60 × 60 / 365.25 × 24 × 60 × 60)2 × (1.496 × 1011 / 4.22 × 108)3 = 1045.04 ∴ Ms / MJ ~ 1000 Ms ~ 1000 × MJ Hence, it can be inferred that the mass of Jupiter is about one-thousandth that of the Sun.

41.

Io, one of the satellites of Jupiter, has an orbital period of 1.769 days and the radius of the orbit is 4.22 × 108 m. Show that the mass of Jupiter is about one-thousandth that of the sun.

Answer»

Answer:

Orbital period of I0 , TI0 = 1.769 days = 1.769 × 24 × 60 × 60 s

Orbital radius of I0 , RI0 = 4.22 × 108 m

Satellite I0 is REVOLVING around the Jupiter

Mass of the latter is GIVEN by the relation:

MJ = 4π2RI03 / GTI02 .....(i)

Where,

MJ = Mass of Jupiter

G = Universal gravitational constant

Orbital period of the earth,

Te = 365.25 days = 365.25 × 24 × 60 × 60 s

Orbital radius of the Earth,

Re = 1 AU = 1.496 × 1011 m

Mass of sun is given as:

Ms = 4π2Re3 / GTe2 ......(ii)

∴ Ms / MJ = (4π2Re3 / GTe2) × (GTI02 / 4π2RI03) = (Re3 × TI02) / (RI03 × TE2)

Substituting the values, we GET:

= (1.769 × 24 × 60 × 60 / 365.25 × 24 × 60 × 60)2 × (1.496 × 1011 / 4.22 × 108)3

= 1045.04

∴ Ms / MJ ~ 1000

Ms ~ 1000 × MJ

Hence, it can be inferred that the mass of Jupiter is about one-thousandth that of the Sun.

Discussion

42.	T=Under root density/s where s is displacment
Answer» ANSWER: t=time & t= √density/ s

42.

T=Under root density/s where s is displacment

Answer»

ANSWER:

t=time

& t= √density/ s

Discussion

43.	Why does the blood oozes out when there is a slight cut on our body
Answer»

Discussion

44.	Rutherford's model could not explain
Answer» Answer:The major drawback of Rutherford EXPERIMENT is that the ORBITAL revolution of the electron is not expected to be stable. According to Rutherford's model, the electrons, while MOVING in their ORBITS, WOULD give up energy. This would make them slow down, gradually and move towards the nucleus. Explanation:

44.

Rutherford's model could not explain

Answer»

Answer:The major drawback of Rutherford EXPERIMENT is that the ORBITAL revolution of the electron is not expected to be stable. According to Rutherford's model, the electrons, while MOVING in their ORBITS, WOULD give up energy. This would make them slow down, gradually and move towards the nucleus.

Explanation:

Discussion

45.	Direction (Q. Nos. 11 and 12)In each of the following questions, a statement of Assertion is given followed by corresponding statement of Reason just below it. Of the statements, mark the correct answer as (a) If both Assertion and Reason are true and Reason is the correct explanation of Assertion. (b) If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion. (c) If Assertion is true, but Reason is false. (d) If Assertion is false, but Reason is true. (e )If both Assertion and Reason are false. 11. Assertion-If two persons walking or running in opposite direction collide with each other, then boih reel hurt.Reason- Every action applies equal reaction 12. Assertion- Epithelial tissues are the protective tissues of animal body. Reason-Squamous epithelium is the thickest among all the epithelial tissues.
Answer» Answer: Answer 11 - (a) Explanation: NEWTON's law states that EVERY action has a EQUAL and opposite reaction hence when two person collide, the SECOND person will apply equal force in the direction opposite to the first person therefore they both will feel hurt.

45.

Direction (Q. Nos. 11 and 12)In each of the following questions, a statement of Assertion is given followed by corresponding statement of Reason just below it. Of the statements, mark the correct answer as (a) If both Assertion and Reason are true and Reason is the correct explanation of Assertion. (b) If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion. (c) If Assertion is true, but Reason is false. (d) If Assertion is false, but Reason is true. (e )If both Assertion and Reason are false. 11. Assertion-If two persons walking or running in opposite direction collide with each other, then boih reel hurt.Reason- Every action applies equal reaction 12. Assertion- Epithelial tissues are the protective tissues of animal body. Reason-Squamous epithelium is the thickest among all the epithelial tissues.

Answer»

Answer:

Answer 11 - (a)

Explanation:

NEWTON's law states that EVERY action has a EQUAL and opposite reaction hence when two person collide, the SECOND person will apply equal force in the direction opposite to the first person therefore they both will feel hurt.

Discussion

46.	What is a force what changes can be produced by a force
Answer» ANSWER: matalan???????......

46.

What is a force what changes can be produced by a force

Answer»

ANSWER:

matalan???????......

Discussion

47.	Why electron can not exist in the nucleus
Answer» Answer: 1.it UNSTABLE the atom. 2.The second reason that electron can not exist inside the NUCLEUS is that EXPERIMENTAL results show that no electron or particle in the atom possess energy greater than 4 MeV. Therefore ,it conformed that electron do not exist inside the nucleus. hope it helps you!

47.

Why electron can not exist in the nucleus

Answer»

Answer:

1.it UNSTABLE the atom.

2.The second reason that electron can not exist inside the NUCLEUS is that EXPERIMENTAL results show that no electron or particle in the atom possess energy greater than 4 MeV. Therefore ,it conformed that electron do not exist inside the nucleus.

hope it helps you!

Discussion

48.	What do you mean by e=mc^2
Answer» ANSWER: HEY! e= mc^2 is the special FORMULA of the the THEORY of special RELATIVITY.

48.

What do you mean by e=mc^2

Answer»

ANSWER:

HEY!

e= mc^2

is the special FORMULA of the the THEORY of special RELATIVITY.

Discussion

49.	Simplify 2/3
Answer» EXPLANATION: I can not UNDERSTAND this QUESTION

49.

Simplify 2/3

Answer»

EXPLANATION:

I can not UNDERSTAND this QUESTION

Discussion

50.	A child sits stationary at one end of a long trolley moving uniformly with a speed V on a smooth horizontal floor. If the child gets up and runs about on the trolley in any manner, what is the speed of the CM of the (trolley + child) system?
Answer» Answer: The child is RUNNING arbitrarily on a trolley moving with velocity V. However, the running of the child will PRODUCE no effect on the velocity of the centre of mass of the trolley. This is because the FORCE due to the boy’s motion is purely internal. Internal forces produce no effect on the motion of the bodies on which they act. Since no external force is involved in the boy–trolley SYSTEM, the boy’s motion will produce no change in the velocity of the centre of mass of the trolley.

50.

A child sits stationary at one end of a long trolley moving uniformly with a speed V on a smooth horizontal floor. If the child gets up and runs about on the trolley in any manner, what is the speed of the CM of the (trolley + child) system?

Answer»

Answer:

The child is RUNNING arbitrarily on a trolley moving with velocity V. However, the running of the child will PRODUCE no effect on the velocity of the centre of mass of the trolley. This is because the FORCE due to the boy’s motion is purely internal. Internal forces produce no effect on the motion of the bodies on which they act. Since no external force is involved in the boy–trolley SYSTEM, the boy’s motion will produce no change in the velocity of the centre of mass of the trolley.

Discussion

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