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A geyser heats water flowing at the rate of 3.0 litres per minute from 27 °C to 77 °C. If the geyser operates on a gas burner, what is the rate of consumption of the fuel if its heat of combustion is 4.0 × 104 J/g? |
Answer» Answer:Water is flowing at a rate of 3.0 litre/min. The geyser HEATS the water, raising the temperature from 27°C to 77°C. Initial temperature, T1 = 27°C Final temperature, T2 = 77°C ∴Rise in temperature, ΔT = T2 – T1 = 77 – 27 = 50°C Heat of combustion = 4 × 104 J/g Specific heat of water, c = 4.2 J g–1 °C–1 Mass of flowing water, m = 3.0 litre/min = 3000 g/min Total heat used, ΔQ = mc ΔT = 3000 × 4.2 × 50 = 6.3 × 105 J/min ∴ Rate of consumption = 6.3 × 105 / (4 × 104) = 15.75 g/min. |
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