This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
if the angular momentum of a planet of mass m,moving around the sun in a circular orbit is L,about the centre of the sun ,the areal velocity is |
|
Answer» vvvv Explanation: gggjhhhhhhhhhhhhhhhbbbhhhhhh |
|
| 2. |
find the de broglie wavelength associated with hydrogen molecule moving with a velocity of 3 kilometre per second. |
Answer» ★☆〖Qบęຮτ ı¨ ø nˇ〗☆★⭐The Dual Nature of Matter⭐=> de-Broglie's Principle states that "All material PARTICLES in motion possess wave characteristics..." => de-Broglie's Relationship can be derived by combining the MASS and energy relationships PROPOSED by Max Planck, and Albert Einstein... E = ∫c²dm = Σc²Δm = mc²E = hν=> The combination of these two yielded the desired result: λ = h/mc=> The above equation is VALID for a Photon(γ⁰) => The same relation can be extended to every particle of this universe, if the speed of light in vacua(c) is REPLACED by the ordinary velocity of the particle:
____________________________________ ________________ (100% Plagiarism-Free ☺️☺️) Hope it helps you! ヅ ✪ Be Brainly ✪ |
|
| 3. |
How to convert kgm³ to gcm³ |
|
Answer» so 1kgm³= 1000gm³ and 1m³= 1000000cm³ so 1kgm³=10⁹cm³ |
|
| 4. |
A body fall from 40m it's velocity after 2s is |
|
Answer» = 40/2 velocity = 20m/s ANSWER |
|
| 5. |
A bird sitting at a height has only potential energy |
| Answer» | |
| 6. |
Anwer in a note book |
|
Answer» ☆If the angle between the INCIDENT ray and MIRROR is 40°.The the angle of incidence will be 50°. ☆Fingers apper blured DUE to persistence of vision. |
|
| 7. |
Explain where and how urin in produced |
|
Answer» Answer: Each nephron CONSISTS of a BALL formed of small BLOOD capillaries, called a glomerulus, and a small tube called a renal tubule. UREA, together with water and other waste substances, forms the urine as it passes through the nephrons and down the renal tubules of the kidney. |
|
| 8. |
Set an hour to Karthik Karthik Kanaka vertical 1.78 he Mata Man City Setu centimetre is stop and get |
|
Answer» what is this I don't UNDERSTAND this QUESTION |
|
| 9. |
Wright in a note book |
|
Answer» Answer: I Ray = reflected Ray so 40 2) our eyes capture as a image over 3000 images are captured to form a maving object thus the over shaking may RESULT slow process 3) the image formed in a plane image APPEARS at the equal distance from the mirror Its right appear to be at left and visa versa it show ONE side closed and opens up the mirroring this known as I side closed mirror 4) I don't remember this CAUSE I suddided it in 8th class 7) |
|
| 10. |
What is banking of road ? Obtain an expression for maximum/minimum safety speed of vehicle moving along a curved horizontal road.? |
|
Answer» Answer: Banking of roads : To avoid risk of skidding as well as to reduce the wear and tear of the car tyres, the road surface at a bend is tilted inwards, i.e., the outer SIDE of road is raised above its inner side. This is called 'banking of roads'. Consider a car taking a left turn along a road of RADIUS r banked at an angle θ for a designed optimum speed V. Let m be the mass of the car. In general, the forces ACTING on the car are: (a) Its weight mg
, acting vertically down (b) The normal reaction of the road N , perpendicular to the road surface (c) The frictional force f s
along the inclined surface of the road. Resolve N and f s
into two perpendicular components Ncosθ vertically up and f s
sinθ vertically down, Nsinθ and f s
cosθ HORIZONTALLY towards the centre of the circular path. If v max
is the maximum safe speed without skidding. r mv max 2
=Nsinθ+f s
cosθ =Nsinθ+μ s
Ncosθ r mv max 2
=N(sinθ+μ s
cosθ)....(1) and Ncosθ=mg+f s
sinθ =mg+μ s
Nsinθ ∴mg=N(cosθ−μ s
sinθ)...(2) Dividing eq. (1) by eq. (2), r.mg mv max 2
= N(cosθ−μ s
sinθ) N(sinθ+μ s
cosθ)
∴ rg v max 2
= cosθ−μ s
sinθ sinθ+μ s
cosθ
= 1−μ s
tanθ tanθ+μ s
∴v max
= 1−μ s
tanθ rg(tanθ+μ s
)
...,.(3) This is the expression for the maximum safe speed on a banked road. At the optimum speed, the friction between the car tyres and the road surface is not called into play. Hence, by setting μ s
=0 in eq. (3), the optimum speed on a banked circular road is v= rgtanθ
...(4) ∴tanθ= rg v 2
or θ=tan −1 ( rg v 2
) From this eq. we see that θ depends upon v,r and g. The angle of banking is independent of the mass of a vehicle negotiating the curve. solution |
|
| 11. |
Example application ofthe principle of thermodynamics |
|
Answer» Answer: Explanation: One of the most IMPORTANT things we can do with heat is to USE it to do work for us. A heat engine does exactly this—it makes use of the properties of thermodynamics to transform heat into work. GASOLINE and diesel engines, jet engines, and steam turbines that generate ELECTRICITY are all examples of heat engines. |
|
| 12. |
Two blocks are connectedBy a string |
| Answer» | |
| 13. |
What is difference between radius of curvature and center of curvature?Explain in detail |
|
Answer» Answer: RADIUS of curvature is the radius of the circle which touches the curve at a GIVEN point and has the same tangent and curvature at that point (the circle is drawn for use only, just to determine the VALUE, a curve has INFINITE Radius of curvature for infinite point(x, y) Radius is the distance between the centre and any other point on the circumference of circle or surface of sphere. In circles you MUST use the term radius. |
|
| 14. |
Find the work done in bringing a charge тАШqтАЩ from perpendicular distance r1 to r2 |
|
Answer» sjsnennwnwnwjwjwkwkwkwkwkwow |
|
| 16. |
Refractive index of water with respect to air an 1•33 and that of diamond is 2•42 |
|
Answer» Explanation: the value 1.33 REPRESENTS the refractive INDEX of water with RESPECT to the air when light enters from air to water. And 2.41 represents the refractive index of diamond with respect to the air when light enters from air to diamond. |
|
| 17. |
Which song is best for black day (minimum 5) |
|
Answer» Explanation: |
|
| 18. |
What is a speed of light ? can anything else mive faster than light ? explain . |
|
Answer» Answer: 1. The BIG Bang itself expanded much faster than the SPEED of light. But this only means that "nothing can go faster than light." Since nothing is just empty space or vacuum, it can EXPAND faster than light speed since no MATERIAL object is breaking the light BARRIER. |
|
| 20. |
an object of 4 cm height is placed 30 cm away from a convex lens of focus length 20cm. and what will be the height of the image. |
|
Answer» Answer: Answer Expert Verified 4.0/5 182 santy2 Ace 6.7K answers 32.9M people helped In this question I am going to USE a scale of 1:5 to DRAW this diagram. When I use this scale: Focal length =20/5=4cm Object HEIGHT =4/5=0.8cm The object distance =30/5 =6cm. From the diagram, the image height is 1.6cm. Which from the scale is : 1.6 × 5=8cm The ratio of image SIZE to object size is : 8:4=2:1 The ratio= 2:1 |
|
| 21. |
Magnification of an image is -2 and an object isplaced at a distance of 20cm from a concavemirror then find the focal length of the mirror |
Answer» Given :In concave mirror, MAGNIFICATION of image = -2 Object distance = - 20cm To find :The focal length of the mirror Solution :Firstly we have to find image distance using magnification formula that is, The Magnification produced by a mirror is equal to the ratio of the image distance to the object distance with a minus sign .i.e.,
where,
by, SUBSTITUTING all the given VALUES in the formula, Now, using mirror formula that is, » A formula which GIVES the relationship between image distance, object distance and focal length of a sperical mirror is known as the mirror formula .i.e.,
where,
now, substituting all the given values, Thus, the focal length of the mirror is 13.3cm |
|
| 22. |
When do you seen objects ? |
Answer» We are able to see because light from an object can move through space and REACH our eyes. Once light reaches our eyes, signals are SENT to our BRAIN, and our brain deciphers the information in order to detect the appearance, location and MOVEMENT of the objects we are SIGHTING at. |
|
| 23. |
The equation of a wave is given by y=5sin(20x-30t) find the amplitude,velocity, propagation constant, angular velocity, frequency and time period of a wave |
|
Answer» Answer: The wave FUNCTION is given by y(x,t)=Asin(kx−ωt+φ) y ( x , t ) = A sin ( k x − ω t + φ ) where k=2π/λ k = 2 π / λ is defined as the wave number, ω=2π/T ω = 2 π / T is the angular FREQUENCY, and φ is the phase SHIFT. |
|
| 24. |
Increase in velocity of sound in air for 1 degree celcius rise in temperature |
|
Answer» it is clear that for 10C increase in TEMPERATURE , VELOCITY increases by 0.61 m/s. |
|
| 25. |
B) What is the dimensional formula of capacitance |
|
Answer» The dimensional formula of force and charge is [M1 L1 T-2] and [I1 T1] respectively. Therefore, the Capacitance is DIMENSIONALLY REPRESENTED as [M-1 L-2 T4 I2]. |
|
| 26. |
32. हाइड्रोजन के एक नमूने पर इलेक्ट्रॉनों की बौछार की जाती है।इलेक्ट्रॉनों को कितने विभवान्तर से त्वरित किया जाना चाहिये(3) n = 4 →n=1कि पाश्चन की पहली रेखा उत्सर्जित हो :-(1) 2.55(2) 0.65V(3) 12.09V(4) 12.75V |
|
Answer» (3) N = 4 → n=1. कि पाश्चन की पहली रेखा उत्सर्जित हो :- (1) 2.55 |
|
| 27. |
How can you measure the length of a curved surface answer in detail |
|
Answer» Answer: take a thread and PLAVE it AROUND the curve then MEASURE the distance of thread with SCALE |
|
| 28. |
What do you mean by uniform and non-uniform motion ? What can be the shape the covered by a moving object to have (a) uniform speed and (b) uniform velocitywhat happened xD |
|
Answer» Answer: The shape of the path covered by a moving object having UNIFORM SPEED and uniform VELOCITY will be a straight LINE. This is because a body has uniform velocity only if it travels in a straight line and moves over equal distances in equal interval of time, no matter how small the time intervals maybe Explanation: what happened xD i don't KNOW XD |
|
| 29. |
Khelo India fitness assignment program manual Rotary for school chains and boards |
|
Answer» HI what did you MEAN by Can you PLZ MARK me as BRAINLIEST plz plz |
|
| 30. |
A source of light moves with a velocity (c÷2)towards the observer,thenthe speed of light is |
|
Answer» The Velocity of light in a vacuum is a UNIVERSAL CONSTANT, independent of the FRAME of REFERENCE. So the velocity of light will be observed as c. |
|
| 31. |
Describe teachers roles on community development |
|
Answer» Answer: Explanation: As the role of the teacher is to educate and guide the students to grow as an INDIVIDUAL, so is it with the community. The community has a duty to educate and guide the people in it. In fact, communities need to have some guidelines for their development in terms of economic growth, infrastructure development, social awareness and human resource development. A good community is always a sign of good education at all levels. What is the role of a teacher in the education system: A teacher is a key member of the education system. Without a good teacher, there can be no good education. The role of a teacher in the education system can be compared to that of a facilitator. It is important for teachers to help students learn by making sure that they have the necessary RESOURCES and environment to do so. Teachers should also make sure that they are AVAILABLE when students need them and should always strive to teach them better so that they are able to succeed in life. Teachers should also be role models for their students by setting an example for them through their behaviour and work ethics. What is the role of a teacher in society: A teacher has a lot of responsibilities in society. The biggest responsibility of any educator is to educate people about how they can help build their community, country and world into better places for all its inhabitants, not just themselves or their family members. The role of teachers as citizens includes participating in debates about important issues AFFECTING communities, contributing ideas about ways to solve problems and making sure that children get enough information on how they can become responsible citizens too one day when they grow up. Teachers also need to educate themselves on issues that may affect them or their students as well as other community members such as discrimination, violence and prejudice against others who may be different from themselves because this will help them understand what their responsibilities are as educators and leaders who will play an important part in SHAPING future generations into better citizens than themselves. |
|
| 32. |
Pure water is cooled to -15C. Some ice is added to it |
|
Answer» the TEMPERATURE of WATER be CHANGE |
|
| 33. |
Object starts from rest and constant acceleration. If it travels 20m in 10s. Then find total displacement in 20s |
|
Answer» Explanation: Distance in 20 seconds s=0∗20+a×20 /2 s=200a --(1) distance travels in first 10 seconds s 1
=0×10+a×102/2s1
=50a --(2) distance travels in NEXT 10 seconds s 2
=s−s1s2
=200a−50a=150a--(3) s 1
s 2
= 50a 150a
=3 |
|
| 34. |
विद्युत चुंबकीय प्रेरण किसे कहते हैं |
|
Answer» किसी चालक को किसी परिवर्ती चुम्बकीय क्षेत्र में रखने पर उस चालक के सिरों के बीच विद्युतवाहक बल उत्पन्न होने को विद्युत्-चुम्बकीय प्रेरण (ELECTROMAGNETIC INDUCTION) कहते हैं। |
|
| 35. |
The ground state electron energy level of lithium is −12.8eV. If the transition to the second energy level requires the absorption of light at a frequency of 7.32×1011kHz, what is the energy of the second energy level? Give your answer in eV, correct to three significant figures and without a unit. |
|
Answer» energy level requires the absorption of light at a frequency of 7.32×1011kHz, what is the energy of the second energy level? Give your ANSWER in eV, correct to three significant figures and without a UNIT. |
|
| 36. |
Complete and please post |
|
Answer» xffyfdfzzyujkkjgcvghvvmkjgg |
|
| 37. |
A truck travelling with a velocity of 30 metre per second come to rest after 10 seconds calculate its acceleration |
|
Answer» Answer: Given Final VELOCITY (v) = 50 m/s Given Final velocity (v) = 50 m/s INITIAL velocity (u) = 30 m/s Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We KNOW v = u + at Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.5 Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520 Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520 Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520 = t or 8 = t Given Final velocity (v) = 50 m/s Initial velocity (u) = 30 m/s Acceleration (a) = 2.5 m/s We know v = u + at∴ 50 = 30 + 2.5 t⇒ 50 - 30 = 2.5 t⇒ 2.520 = t or 8 = t∴ Time TAKEN to ACCELERATE = 8 seconds |
|
| 38. |
What is velocity after collision |
|
Answer» In a collision, the velocity change is ALWAYS COMPUTED by subtracting the initial velocity VALUE from the final velocity value. If an object is moving in ONE DIRECTION before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before. |
|
| 39. |
The gravitational force of attraction of the earth on a 1 kg of brass ball is same as the gravitational force of attraction of 1 kg brass ball on the earth. Explain Why?n the earth. Explain Why? |
|
Answer» the GRAVITATIONAL FORCE of ATTRACTION |
|
| 40. |
When the soil is dry, the earthworms burrow very deep into the soil and do not come to the surface. The average annual rainfall for the area of Kojonup is 550mm. How might the results have been different if there had been very little rain during the six months of the test? |
|
Answer» Answer: Hungarian authors have long been discussing the role of earthworms in improving soil productivity. Earthworm counts in our higher quality soils are similar to those found in soils where more ATTENTION is PAID to earthworm activity. Negative impacts that are independent of farming—such as sustained dry spells in the summer—also affect earthworm counts. Negative impacts that DEFINITELY depend on farming include land use causing soil moisture loss, deep stubble treatment leaving the soil without cover, and ploughing in the summer without subsequent pressing. The climate change is having both positive and negative impacts. Weather patterns are causing losses but adopting climate mitigating tillage are generating benefits. In the trials results so far show that tillage focusing on PRESERVING soil moisture, structure, and organic materials, COVERING the surface in the critical months as well as adequate soil loosening are fundamental pre-requisites for making the soil a favourable habitat for earthworms. |
|
| 41. |
(b) The mass of the sea water in the pool is 2.70 x 105kg.Calculate the density of the sea water. Give your answer to 3 significant figures.density =(c) Calculate the pressure due to the sea water at the bottom of the poolpressure =(d) State a suitable instrument for measuring the dimensions given in Fig. 1.1. |
|
Answer» Answer: Photosynthesis is the PROCESS by which plants PREPARE FOOD with the helps of sunlight, air, water and chlorophyll |
|
| 42. |
At night, we sometimes see more than one shadow of ourselves. give reason |
|
Answer» bhai ff KHELTE ho meri UID 1999004889 challenge me if u are brave. |
|
| 43. |
Difference between sigma and integration |
|
Answer» Answer: Summation- SUM of a SMALL numbers of LARGE quantities. Integration- Sum of a large numbers of small quantities. |
|
| 44. |
The ratio of slit widths, when amplitude of light wave from them have a ratio |
Answer» The SLIT WIDTHS are in the RATIO of 2:1 |
|
| 45. |
Why do we need integration |
|
Answer» Answer: The main reason for organizations to use SYSTEM integration is their need to improve productivity and quality of their OPERATIONS. The goal is to get the organizations various IT systems to “TALK to each other” through the integration, to SPEED up information flows and reduce operational costs for the ORGANIZATION |
|
| 46. |
A force of 100 N acts on a particle of mass 25 kg. find the acceleration of the particle. |
|
Answer» Answer: 4 m/s² Explanation: Ɡiven F=100N m= 25kɡ a=? 100= 25a a = 100/25 = 4 m/s² |
|
| 47. |
DGawain sa Pagkatuto Bilang 1: Buoin ang mga ginulong titik sa loob ngkahon upang mabuo ang konsepto ng gender. Gawin ito sa iyongkuwaderno.TYIEDNTI1 GENDERSOLREE |
|
Answer» Answer: 1. Identity 2.Roles Explanation: SANA makatulong |
|
| 48. |
Define stress and strain and explain it's type |
|
Answer» Answer: Stress is the force acting on the unit area of a material. The effect of stress on a body is named as strain. Stress can deform the body. ... Stress can be categorized into three categories depending upon the direction of the deforming forces acting on the body.Types of Stress There are several types of stress in physics but it is mainly categorized into two forms that are NORMAL Stress and Tangential or Shearing Stress. Some stress types are discussed in the points below. Normal Stress: As the name suggests, Stress is said to be Normal stress when the direction of the deforming force is perpendicular to the cross-sectional area of the body. The length of the wire or the volume of the body CHANGES stress will be at normal. Normal stress can be further classified into two types based on the dimension of force- Longitudinal stress Bulk Stress or Volumetric stress Longitudinal Stress: Consider a cylinder. When two cross-sectional areas of the cylinder are subjected to equal and opposite forces the stress experienced by the cylinder is called longitudinal stress. Longitudinal Stress = Deforming Force / Area of cross-section = F/A As the name suggests, when the body is under longitudinal stress- The deforming force will be acting ALONG the length of the body. Longitudinal stress results in the change in the length of the body. Hence, thereby it affects slight change in diameter. The Longitudinal Stress either stretches the object or compresses the object along its length. Thus, it can be further classified into two types based on the direction of deforming force- Tensile stress Compressive stress Tensile Stress If the deforming force or applied force results in the increase in the object’s length then the resulting stress is termed as tensile stress. For example: When a rod or wire is stretched by pulling it with equal and opposite forces (outwards) at both ends. Compressive Stress If the deforming force or applied force results in the decrease in the object’s length then the resulting stress is termed as compressive stress. For example: When a rod or wire is compressed/squeezed by pushing it with equal and opposite forces (inwards) at both ends. Bulk Stress or Volume Stress When the deforming force or applied force acts from all dimensions resulting in the change of volume of the object then such stress in called volumetric stress or Bulk stress. In short, when the volume of body changes due to the deforming force it is termed as Volume stress. Shearing Stress or Tangential Stress When the direction of the deforming force or external force is parallel to the cross-sectional area, the stress experienced by the object is called shearing stress or tangential stress. This results in the change in the shape of the body. According to the strain definition, it is defined as the amount of deformation experienced by the body in the direction of force applied, divided by initial dimensions of the body. The relation for deformation in terms of length of a solid is given below. ϵ=δlL where, ϵ is the strain due to stress applied δl is the change in length L is the original length of the material. The strain is a dimensionless quantity as it just defines the relative change in shape. Depending on stress application, strain experienced in a body can be of two types. They are: ● Tensile Strain: It is the change in length (or area) of a body due to the application of tensile stress. ● Compressive Strain: It is the change in length (or area) of a body due to the application of compressive strain When we study solids and their mechanical properties, information regarding their elastic properties is most important. These can be obtained by studying the stress-strain RELATIONSHIPS, under different loads, in these materials. hope this answer is helpful for you . |
|
| 49. |
The amunt of work is directly proportional to |
|
Answer» RATE of doing work is DIRECTLY PROPORTIONAL to time TAKEN to do the work. |
|
| 50. |
Rod of length 80 cm and mass3.2kg hp supported horizontally by the two spiring balances C and D .Balance C is 20cm from one end while D 30cm on the other.Find reading of each balance. |
|
Answer» This one's probably about moments. If would be HELPFUL to draw a DIAGRAM to visualize the respective forces acting on the rod. (so you would have BALANCES C and D at each end of the rod, exerting an upward force on the rod. The weight of the rod exerts a downward force on the middle of the rod) To examine the reading on each BALANCE, take the other balance as a pivot. Moment = Force x Distance from pivot For example, if we want to find the reading on Balance D, Balance C is the pivot. 2 forces are acting on the rod - it's weight, and the upward countering force exerted by Balance D. Since the rod is assumed to be in equilibrium, the moments exerted by both forces are the same: Weight x Distance from pivot = Balance D x Distance from pivot The distances from the pivot of the respective forces should be easy to CALCULATE with a diagram. Then repeat the same with balance D |
|