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Object starts from rest and constant acceleration. If it travels 20m in 10s. Then find total displacement in 20s |
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Answer» Explanation: Distance in 20 seconds s=0∗20+a×20 /2 s=200a --(1) distance travels in first 10 seconds s 1
=0×10+a×102/2s1
=50a --(2) distance travels in NEXT 10 seconds s 2
=s−s1s2
=200a−50a=150a--(3) s 1
s 2
= 50a 150a
=3 |
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