1.

Object starts from rest and constant acceleration. If it travels 20m in 10s. Then find total displacement in 20s

Answer»

Explanation:

Distance in 20 seconds

s=0∗20+a×20

2

/2

s=200a --(1)

distance travels in first 10 seconds

s

1

=0×10+a×102/2s1

=50a --(2)

distance travels in NEXT 10 seconds

s

2

=s−s1s2

=200a−50a=150a--(3)

s

1

s

2

=

50a

150a

=3



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