67486 + Interview Questions in Secondary School in Physics

1.	Bus stabbing at a uniform speed of 60 km per Ghanta how much time will it take to travel a distance of 450 km
Answer» SPEED of the bus = 60km/h Distance = 450 KM Time = ? we know that,. time = distance/speed t = 450/60 t = 7.5 HR t = 7 hours and 30 minutes Therefore, the bus takes 7.5 hr to TRAVEL a distance of 450 km.

1.

Bus stabbing at a uniform speed of 60 km per Ghanta how much time will it take to travel a distance of 450 km

Answer»

SPEED of the bus = 60km/h

Distance = 450 KM

Time = ?

we know that,.

time = distance/speed

t = 450/60

t = 7.5 HR

t = 7 hours and 30 minutes

Therefore, the bus takes 7.5 hr to TRAVEL a distance of 450 km.

Discussion

2.	The minimum energy required to remove an elecron is called(a) Stopping potential(b) KE(c) Work function(d)None of these
Answer» $\huge\star\mathfrak\red{{Hey Mate...!!}}$ ● The minimum ENERGY required to REMOVE an electron from VALENCE shell is CALLED ionization energy. ● So None of these is the CORRECT option.

2.

The minimum energy required to remove an elecron is called(a) Stopping potential(b) KE(c) Work function(d)None of these

Answer»

$\huge\star\mathfrak\red{{Hey Mate...!!}}$

● The minimum ENERGY required to REMOVE an electron from VALENCE shell is CALLED ionization energy.

● So None of these is the CORRECT option.

Discussion

3.	Arrange according to the increasing order of volume expansion : solid, liquid and gas
Answer» ANSWER: GAS, LIQUID, solid is the CORRECT answer

3.

Arrange according to the increasing order of volume expansion : solid, liquid and gas

Answer»

ANSWER:

GAS, LIQUID, solid

is the CORRECT answer

Discussion

4.	24.12.75 eV ऊर्जा के फोटॉन का हाइड्रोजन के परमाणु द्वारानिम्न ऊर्जा स्तर में पूर्णत: अवशोषण किया जाता है तो उत्तेजितस्तर की मुख्य क्वाण्टम संख्या का मान होगा :-(1) 1 (2) 3 (3)4 (4) अनन्त
Answer» ANSWER: fragrance and. God was a NICE DAY and so misbehave and just.

4.

24.12.75 eV ऊर्जा के फोटॉन का हाइड्रोजन के परमाणु द्वारानिम्न ऊर्जा स्तर में पूर्णत: अवशोषण किया जाता है तो उत्तेजितस्तर की मुख्य क्वाण्टम संख्या का मान होगा :-(1) 1 (2) 3 (3)4 (4) अनन्त

Answer»

ANSWER:

fragrance and. God was a NICE DAY and so misbehave and just.

Discussion

5.	• ज्याच्या प्रत्येक पृष्ठभागाची वक्रता त्रिज्या 50 सेमीआहे, अशा डबल बहिर्वक्र भिंगाचे नाभीय अंतर कितीअसेल, जर काचेचा वक्रीभवन दर्शक 1.50 असेल ?1) 100 सेमी2) 25 सेमी3) 50 सेमी4) 75 सेमी
Answer» ANSWER: SORRY i don't UNDERSTAND what is your LANGUAGE

5.

• ज्याच्या प्रत्येक पृष्ठभागाची वक्रता त्रिज्या 50 सेमीआहे, अशा डबल बहिर्वक्र भिंगाचे नाभीय अंतर कितीअसेल, जर काचेचा वक्रीभवन दर्शक 1.50 असेल ?1) 100 सेमी2) 25 सेमी3) 50 सेमी4) 75 सेमी

Answer»

ANSWER:

SORRY i don't UNDERSTAND what is your LANGUAGE

Discussion

6.	What is refraction of light? Write two laws of refraction
Answer» The two LAWS followed by a beam of light traversing through two MEDIA are: The incident ray refracted ray, and the normal to the interface of two media at the point of INCIDENCE all lie on the same plane. The RATIO of the sine of the angle of incidence to the sine of the angle of refraction is a constant. Flw_Me!

6.

What is refraction of light? Write two laws of refraction

Answer»

The two LAWS followed by a beam of light traversing through two MEDIA are: The incident ray refracted ray, and the normal to the interface of two media at the point of INCIDENCE all lie on the same plane. The RATIO of the sine of the angle of incidence to the sine of the angle of refraction is a constant.

Flw_Me!

Discussion

7.	Ampere circuit law define
Answer» Answer: Ampere's CIRCUITAL LAW states that line integral of magnetic FIELD forming a closed loop around the current(i) carrying wire, in the PLANE normal to the current, is equal to the μo times the net current passing through the close loop. hope this answer is HELPFUL for you.

7.

Ampere circuit law define

Answer»

Answer:

Ampere's CIRCUITAL LAW states that line integral of magnetic FIELD forming a closed loop around the current(i) carrying wire, in the PLANE normal to the current, is equal to the μo times the net current passing through the close loop.

hope this answer is HELPFUL for you.

Discussion

8.	What is DE broglie's hypothesis? describe the formula for de broglie's wavelength
Answer» Answer: De Broglie's hypothesis of MATTER WAVES postulates that any particle of matter that has linear momentum is ALSO a wave. The WAVELENGTH of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The SPEED of the matter wave is the speed of the particle.

8.

What is DE broglie's hypothesis? describe the formula for de broglie's wavelength

Answer»

Answer:

De Broglie's hypothesis of MATTER WAVES postulates that any particle of matter that has linear momentum is ALSO a wave. The WAVELENGTH of a matter wave associated with a particle is inversely proportional to the magnitude of the particle's linear momentum. The SPEED of the matter wave is the speed of the particle.

Discussion

9.	Who is first scientist
Answer» ANSWER: Aristotle is considered by MANY to be the first scientist. Explanation: hope it HELPS you

9.

Who is first scientist

Answer»

ANSWER:

Aristotle is considered by MANY to be the first scientist.

Explanation:

hope it HELPS you

Discussion

10.	3 differences between Physical and Chemical change
Answer» Answer: A chemical change is a permanent change. A PHYSICAL change affects only physical properties i.e. shape, SIZE, etc. ... Some examples of physical change are freezing of water, melting of wax, BOILING of water, etc. A few examples of chemical change are digestion of FOOD, BURNING of coal, rusting, etc.

10.

3 differences between Physical and Chemical change

Answer»

Answer:

A chemical change is a permanent change. A PHYSICAL change affects only physical properties i.e. shape, SIZE, etc. ... Some examples of physical change are freezing of water, melting of wax, BOILING of water, etc. A few examples of chemical change are digestion of FOOD, BURNING of coal, rusting, etc.

Discussion

11.	State and explain Bernoulli’s theorem. Mention any one application of Bernoulli’s theorem.
Answer» Answer: In 1738, the Swiss scientist Daniel Bernoulli developed a relationship for the flow of fluid through a pipe of varying cross section. He proposed a theorem for the STREAMLINE flow of a liquid based on the law of conservation of energy. Bernoulli’s theorem According to Bernoulli’s theorem, the sum of pressure energy, kinetic energy, and potential energy per unit mass of an incompressible, non-viscous fluid in a streamlined flow remains a constant. Mathematically, This is known as Bernoulli’s equation. Proof: Let us consider a flow of liquid through a pipe AB as shown in Figure 7.33. Let V be the volume of the liquid when it enters A in a time t which is equal to the volume of the liquid leaving B in the same time. Let aA, vA and PA be the area of cross section of the tube, velocity of the liquid and pressure exerted by the liquid at A respectively. Let the force exerted by the liquid at A is FA = PAaA Distance travelled by the liquid in time t is d = vA t Therefore, the work done is W = FAD = PAaAvA t But aAvAt = aAd =V, volume of the liquid entering at A. Thus, the work done is the pressure energy (at A), W = FAd = PAV Since m is the mass of the liquid entering at A in a given time, therefore, pressure energy of the liquid at A is Potential energy of the liquid at A, PEA = mg hA, Due to the flow of liquid, the kinetic energy of the liquid at A, Therefore, the TOTAL energy due to the flow of liquid at A, EA = EPA + KEA + PEA Similarly, let aB, vB, and PB be the area of cross section of the tube, velocity of the liquid, and pressure exerted by the liquid at B. Calculating the total energy at EB, we get From the law of conservation of energy, EA = EB Thus, the above equation can be written as The above equation is the consequence of the conservation of energy which is true until there is no loss of energy due to friction. But in practice, some energy is lost due to friction. This arises due to the fact that in a fluid flow, the layers flowing with different velocities exert frictional forces on each other. This loss of energy is generally converted into heat energy. Therefore, Bernoulli’s RELATION is strictly valid for fluids with zero viscosity or non-viscous liquids. Notice that when the liquid flows through a horizontal pipe, then h = 0 Applications of Bernoulli’s Theorem Blowing off roofs during wind storm In olden days, the roofs of the huts or houses were designed with a slope. One important scientific reason is that as per the Bernoulli’s principle, it will be SAFEGUARDED except roof during storm or cyclone. During cyclonic condition, the roof is blown off without damaging the other parts of the house. In accordance with the Bernoulli’s principle, the high wind blowing over the roof creates a low-pressure P1. The pressure under the roof P2 is greater. Therefore, this pressure difference (P2–P1) creates an up thrust and the roof is blown off.

11.

State and explain Bernoulli’s theorem. Mention any one application of Bernoulli’s theorem.

Answer»

Answer:

In 1738, the Swiss scientist Daniel Bernoulli developed a relationship for the flow of fluid through a pipe of varying cross section. He proposed a theorem for the STREAMLINE flow of a liquid based on the law of conservation of energy.

Bernoulli’s theorem

According to Bernoulli’s theorem, the sum of pressure energy, kinetic energy, and potential energy per unit mass of an incompressible, non-viscous fluid in a streamlined flow remains a constant. Mathematically,

This is known as Bernoulli’s equation.

Proof:

Let us consider a flow of liquid through a pipe AB as shown in Figure 7.33. Let V be the volume of the liquid when it enters A in a time t which is equal to the volume of the liquid leaving B in the same time. Let aA, vA and PA be the area of cross section of the tube, velocity of the liquid and pressure exerted by the liquid at A respectively.

Let the force exerted by the liquid at A is

FA = PAaA

Distance travelled by the liquid in time t is

d = vA t

Therefore, the work done is

W = FAD = PAaAvA t

But aAvAt = aAd =V, volume of the liquid entering at A.

Thus, the work done is the pressure energy (at A),

W = FAd = PAV

Since m is the mass of the liquid entering at A in a given time, therefore, pressure energy of the liquid at A is

Potential energy of the liquid at A,

PEA = mg hA,

Due to the flow of liquid, the kinetic energy of the liquid at A,

Therefore, the TOTAL energy due to the flow of liquid at A, EA = EPA + KEA + PEA

Similarly, let aB, vB, and PB be the area of cross section of the tube, velocity of the liquid, and pressure exerted by the liquid at B. Calculating the total energy at EB, we get

From the law of conservation of energy,

EA = EB

Thus, the above equation can be written as

The above equation is the consequence of the conservation of energy which is true until there is no loss of energy due to friction. But in practice, some energy is lost due to friction. This arises due to the fact that in a fluid flow, the layers flowing with different velocities exert frictional forces on each other. This loss of energy is generally converted into heat energy. Therefore, Bernoulli’s RELATION is strictly valid for fluids with zero viscosity or non-viscous liquids. Notice that when the liquid flows through a horizontal pipe, then h = 0

Applications of Bernoulli’s Theorem

Blowing off roofs during wind storm

In olden days, the roofs of the huts or houses were designed with a slope. One important scientific reason is that as per the Bernoulli’s principle, it will be SAFEGUARDED except roof during storm or cyclone.

During cyclonic condition, the roof is blown off without damaging the other parts of the house. In accordance with the Bernoulli’s principle, the high wind blowing over the roof creates a low-pressure P1. The pressure under the roof P2 is greater. Therefore, this pressure difference (P2–P1) creates an up thrust and the roof is blown off.

Discussion

12.	The equivalent resistance is 4.5 ohm then the value of R in the circuit is
Answer» Answer: EXPLANATION: The two resistances 3 OHM and 3 ohm are in PARALLEL. Equivalent resistance of two resistances connected in parallel is : $\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$ Hence $\frac{1}{R_{eq}}$ = ( $\frac{1}{3} + \frac{1}{3}$ ) = $\frac{2}{3}$ ∴ $R_{eq}$ = $\frac{3}{2}$ ohm = 1.5 ohm As given that equivalent resistance of the whole circuit is 4.5 ohm, ⇒ 1.5 + R = 4.5 ∴ R = 3 ohm Thanks !

12.

The equivalent resistance is 4.5 ohm then the value of R in the circuit is

Answer»

Answer:

EXPLANATION:

The two resistances 3 OHM and 3 ohm are in PARALLEL.

Equivalent resistance of two resistances connected in parallel is :

$\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}$

Hence $\frac{1}{R_{eq}}$ = ( $\frac{1}{3} + \frac{1}{3}$ ) = $\frac{2}{3}$

∴ $R_{eq}$ = $\frac{3}{2}$ ohm = 1.5 ohm

As given that equivalent resistance of the whole circuit is 4.5 ohm,

⇒ 1.5 + R = 4.5

∴ R = 3 ohm

Thanks !

Discussion

13.	In stable Equilibrium
Answer» ANSWER: STABLE equilibrium is the most frequently MET state in THERMODYNAMICS, and most SYSTEMS exist in this state.

13.

In stable Equilibrium

Answer»

ANSWER:

STABLE equilibrium is the most frequently MET state in THERMODYNAMICS, and most SYSTEMS exist in this state.

Discussion

14.	Schrodinger related problems with answer
Answer» Answer: We are having issues USING Desmond on our workstation. SIMULATIONS run fine on one of our gpus ("Gpu0") but CRASH consistently on the other gpu ("gpu1" - which is also set up as the display gpu). Not sure if hardware issue or software/set up problem. I have attached screenshots of errors. Both gpus are visible to schrodinger. Similar issue on both schrodinger 2020-3 and 2019-1. Ubuntu 20.04.1 LTS 2x GeForce RTC 2080 -nvcc RETURNS: nvcc: NVIDIA (R) Cuda compiler driver Copyright (c) 2005-2019 NVIDIA Corporation Built on Sun_Jul_28_19:07:16_PDT_2019 Cuda compilation tools, release 10.1, V10.1.243 Any suggestions to work out if this is a hardware or set-up problem? Thanks,

14.

Schrodinger related problems with answer

Answer»

Answer:

We are having issues USING Desmond on our workstation. SIMULATIONS run fine on one of our gpus ("Gpu0") but CRASH consistently on the other gpu ("gpu1" - which is also set up as the display gpu). Not sure if hardware issue or software/set up problem. I have attached screenshots of errors. Both gpus are visible to schrodinger. Similar issue on both schrodinger 2020-3 and 2019-1.

Ubuntu 20.04.1 LTS

2x GeForce RTC 2080

-nvcc RETURNS:

nvcc: NVIDIA (R) Cuda compiler driver

Built on Sun_Jul_28_19:07:16_PDT_2019

Cuda compilation tools, release 10.1, V10.1.243

Any suggestions to work out if this is a hardware or set-up problem?

Thanks,

Discussion

15.	Y=asin(bt-cx) how can i get the dimension of b
Answer» Answer: judge the equivalent RESISTANCE when the following are connected in parallel a) 1 home and b) 1000000homes Explanation: judge the equivalent resistance when the following are connected in parallel a) 1 home and b) 1000000homes

15.

Y=asin(bt-cx) how can i get the dimension of b

Answer»

Answer:

judge the equivalent RESISTANCE when the following are connected in parallel

a) 1 home and

b) 1000000homes

Explanation:

judge the equivalent resistance when the following are connected in parallel

a) 1 home and

b) 1000000homes

Discussion

16.	Effect of a force on the body depends upon??
Answer» A. Magnitude A. MagnitudeB. Direction A. MagnitudeB. DIRECTIONC. POSITION or LINE of action Flw_Me!

16.

Effect of a force on the body depends upon??

Answer»

A. Magnitude

A. MagnitudeB. Direction

A. MagnitudeB. DIRECTIONC. POSITION or LINE of action

Flw_Me!

Discussion

17.	The Compton shift in wavelength decreases with decrease in(a) Scattering angle(b) a of incident X-rays (c) Both a & b(d) None
Answer» ANSWER: C EXPLANATION:

17.

The Compton shift in wavelength decreases with decrease in(a) Scattering angle(b) a of incident X-rays (c) Both a & b(d) None

Answer»

ANSWER:

C

EXPLANATION:

Discussion

18.	Two identical thin watch glasses are joined together with air inside. The surface B is silvered. A sharp image of object placed on optic axis at 20cm from the lens is formed at distance 10cm from lens. Find the distance of the sharp image from the lens when the space between the glasses is filled with water.
Answer» Answer: Two identical thin watch glasses are joined together with air inside. The surface B is SILVERED. A sharp image of object placed on optic axis at 20CM from the LENS is formed at distance 10cm from lens. Find the distance of the sharp image from the lens when the SPACE between the glasses is FILLED with answer is 12 cm

18.

Two identical thin watch glasses are joined together with air inside. The surface B is silvered. A sharp image of object placed on optic axis at 20cm from the lens is formed at distance 10cm from lens. Find the distance of the sharp image from the lens when the space between the glasses is filled with water.

Answer»

Answer:

Two identical thin watch glasses are joined together with air inside. The surface B is SILVERED. A sharp image of object placed on optic axis at 20CM from the LENS is formed at distance 10cm from lens. Find the distance of the sharp image from the lens when the SPACE between the glasses is FILLED with answer is 12 cm

Discussion

19.	AnsweredJohn drove South 120 km at 60 km/h and then East 150 km at 50 km/h. Determinea) the average speed for the whole journey?b) the magnitude of the average velocity for the whole journey?2
Answer» Explanation: AVERAGE SPEED= TOTAL distance TAKEN/ total time =120+50/2+3 =170/5 =34km/h average VELOCITY= initial+final velocity/2 =60+50/2 =110/2 =55km/h

19.

AnsweredJohn drove South 120 km at 60 km/h and then East 150 km at 50 km/h. Determinea) the average speed for the whole journey?b) the magnitude of the average velocity for the whole journey?2

Answer»

Explanation:

AVERAGE SPEED= TOTAL distance TAKEN/ total time

=120+50/2+3

=170/5

=34km/h

average VELOCITY= initial+final velocity/2

=60+50/2

=110/2

=55km/h

Discussion

20.	Which is not a natural phenomena
Answer» ANSWER: COOKING , HEATING is not a NATURAL PHENOMENA

20.

Which is not a natural phenomena

Answer»

ANSWER:

COOKING , HEATING is not a NATURAL PHENOMENA

Discussion

21.	The units of calorific value is [ ]A) Newton’s/grams B) Newton’s/kgC) kilo joules/kg D) kilo joules/gram
Answer» ANSWER: the UNITS of CALORIFIC VALUE is "KILO joules/kg"

21.

The units of calorific value is [ ]A) Newton’s/grams B) Newton’s/kgC) kilo joules/kg D) kilo joules/gram

Answer»

ANSWER:

the UNITS of CALORIFIC VALUE is "KILO joules/kg"

Discussion

22.	S-ut+1/2at provepls help me I will make you brainliest...
Answer» s= UT + 1/2 at^2 PROVE by INTRIGATION

22.

S-ut+1/2at provepls help me I will make you brainliest...

Answer»

s= UT + 1/2 at^2 PROVE

by INTRIGATION

Discussion

23.	The time of revolution of planet A round the sun is 8 times that of another planet B. The distance of planıfrom the sun is how many times greater than that of the planet B from the sunA. 2B. 3C. 4D. 5
Answer» ANSWER: C) EXPLANATION: i HOPE it is the righte ANSWE

23.

The time of revolution of planet A round the sun is 8 times that of another planet B. The distance of planıfrom the sun is how many times greater than that of the planet B from the sunA. 2B. 3C. 4D. 5

Answer»

ANSWER:

C)

EXPLANATION:

i HOPE it is the righte ANSWE

Discussion

24.	1. Find the audible sound frequency from the following:a) 490 Hz b) 30 KHz c) 10000 Hz d) 10000 KHz e) 12 Hz
Answer» ANSWER is a) 490Hz Explanation: RANGE of AUDIBLE SOUND is 20HZ to 20000Hz 1KHz=1000Hz

24.

1. Find the audible sound frequency from the following:a) 490 Hz b) 30 KHz c) 10000 Hz d) 10000 KHz e) 12 Hz

Answer»

ANSWER is a) 490Hz

Explanation:

RANGE of AUDIBLE SOUND is 20HZ to 20000Hz

1KHz=1000Hz

Discussion

25.	Define virtual image
Answer» In optics, an IMAGE is DEFINED as the collection of focus POINTS of light RAYS coming from an object. A REAL image is the collection of focus points actually made by converging rays, while a virtual image is the collection of focus points made by extensions of diverging rays. ... Such an image will be magnified. Flw_Me!

25.

Define virtual image

Answer»

In optics, an IMAGE is DEFINED as the collection of focus POINTS of light RAYS coming from an object. A REAL image is the collection of focus points actually made by converging rays, while a virtual image is the collection of focus points made by extensions of diverging rays. ... Such an image will be magnified.

Flw_Me!

Discussion

26.	Hello friends. I need your help. Please give me some numerical questions from chapter 'Work, Energy and Power' (ICSE). Not From book.I'll mark brainliest to the toughest question... have a fantastic day ;)
Answer» ANSWER: YES I will MARK U _______

26.

Hello friends. I need your help. Please give me some numerical questions from chapter 'Work, Energy and Power' (ICSE). Not From book.I'll mark brainliest to the toughest question... have a fantastic day ;)

Answer»

ANSWER:

YES

I will MARK U _______

Discussion

27.	Define Time Period of Pendulum
Answer» A pendulum is a weight suspended from a pivot so that it can SWING freely. The time for one complete cycle, a left swing and a right swing, is called the period. The period DEPENDS on the length of the pendulum and ALSO to a slight degree on the AMPLITUDE, the width of the pendulum's swing. Mark me as BRAINLIEST !

27.

Define Time Period of Pendulum

Answer»

A pendulum is a weight suspended from a pivot so that it can SWING freely. The time for one complete cycle, a left swing and a right swing, is called the period. The period DEPENDS on the length of the pendulum and ALSO to a slight degree on the AMPLITUDE, the width of the pendulum's swing.

Mark me as BRAINLIEST !

Discussion

28.	Newton's second law of Motion
Answer» NEWTON's second LAW states that the ACCELERATION of an object is directly related to the net FORCE and inversely related to its mass. Acceleration of an object depends on two things, force and mass. Flw_Me!

28.

Newton's second law of Motion

Answer»

NEWTON's second LAW states that the ACCELERATION of an object is directly related to the net FORCE and inversely related to its mass. Acceleration of an object depends on two things, force and mass.

Flw_Me!

Discussion

29.	Renewable source of energy of Mizoram .
Answer» $\huge\underline\bold\green{♡Answer♡}$ With a view to promote generation of grid-grade power through NON-Conventional Energy Sources in the context of non polluting, RENEWABLE inputs like solar, wind, small HYDEL, biomass and other wastes, the GOVERNMENT of Mizoram has adopted this policy.

29.

Renewable source of energy of Mizoram .

Answer»

$\huge\underline\bold\green{♡Answer♡}$

With a view to promote generation of grid-grade power through NON-Conventional Energy Sources in the context of non polluting, RENEWABLE inputs like solar, wind, small HYDEL, biomass and other wastes, the GOVERNMENT of Mizoram has adopted this policy.

Discussion

30.	What is the number of significant figures in 0.00650
Answer» ANSWER: i THINK 4 lemme KNOW if I'm WRONG

30.

What is the number of significant figures in 0.00650

Answer»

ANSWER:

i THINK 4

lemme KNOW if I'm WRONG

Discussion

31.	Two capacitors of 3microfarad and 6microfarad are connectedseries, their equivalent capacitance is
Answer» ANSWER: I am PRO in FF Ahahahshhshs NOOBDa. KYA Olye kdjdjd

31.

Two capacitors of 3microfarad and 6microfarad are connectedseries, their equivalent capacitance is

Answer»

ANSWER:

I am PRO in FF Ahahahshhshs NOOBDa. KYA Olye

kdjdjd

Discussion

32.	The current flowing through a 5000 Ω resistor is equal to 100 mA. Calculate the potential difference across the resistor
Answer» EXPLANATION: GIVEN: R=5000ohm I=100 mA To Find: V i.e potential difference V=IR (Ohm's law) V=5000*100 V=500000 volts Edit: My answer may be WRONG

32.

The current flowing through a 5000 Ω resistor is equal to 100 mA. Calculate the potential difference across the resistor

Answer»

EXPLANATION:

GIVEN:

R=5000ohm

I=100 mA

To Find:

V i.e potential difference

V=IR (Ohm's law)

V=5000*100

V=500000 volts

Edit: My answer may be WRONG

Discussion

33.	Describe with theory, Searle’s viscometer to find n.
Answer» Answer: shear stress = torque ÷ C1. shear RATE = C2 × angular velocity. shear rate = C2 × angular velocity / gap. VISCOSITY = shear stress / shear rate.

33.

Describe with theory, Searle’s viscometer to find n.

Answer»

Answer:

shear stress = torque ÷ C1. shear RATE = C2 × angular velocity. shear rate = C2 × angular velocity / gap. VISCOSITY = shear stress / shear rate.

Discussion

34.	Conversion of water to ice is a chemical change or a physical change? explain
Answer» Answer: PHYSICAL CHANGE Explanation: It is a physical change because the CHEMICAL composition of WATER i.e H2O does not change

34.

Conversion of water to ice is a chemical change or a physical change? explain

Answer»

Answer:

PHYSICAL CHANGE

Explanation:

It is a physical change because the CHEMICAL composition of WATER i.e H2O does not change

Discussion

35.	(D)रेजिन एवं गोंद कहाँ संचित रहता है ?(A)फ्लोएम में(B)कोटेक्स में(C)छाल में(D) पुराने जाइलम में
Answer» ANSWER: PLEASE TELL FULL QUESTION

35.

(D)रेजिन एवं गोंद कहाँ संचित रहता है ?(A)फ्लोएम में(B)कोटेक्स में(C)छाल में(D) पुराने जाइलम में

Answer»

ANSWER:

PLEASE TELL FULL QUESTION

Discussion

36.	AreAssertion: Resistors connected in series are More effective than those connectedparallel .Reason: Resistance of resistors increasewhen connected in series
Answer» ANSWER: Both ASSERTION and reason are true reason is the correct explanation of assertion hope it helps DROP a thanks and mark as brainliest if U are satisfied

36.

AreAssertion: Resistors connected in series are More effective than those connectedparallel .Reason: Resistance of resistors increasewhen connected in series

Answer»

ANSWER:

Both ASSERTION and reason are true reason is the correct explanation of assertion

hope it helps

DROP a thanks

and mark as brainliest if U are satisfied

Discussion

37.	What do you mean by short circuting of a circuit in short ?
Answer» Answer: an electrical circuit in a DEVICE of lower resistance than that of a NORMAL circuit, especially one resulting from the unintended contact of components and CONSEQUENT accidental DIVERSION of the current. "an office block had been set on fire by an electrical short circuit" Explanation: It will HELP you

37.

What do you mean by short circuting of a circuit in short ?

Answer»

Answer:

an electrical circuit in a DEVICE of lower resistance than that of a NORMAL circuit, especially one resulting from the unintended contact of components and CONSEQUENT accidental DIVERSION of the current.

"an office block had been set on fire by an electrical short circuit"

Explanation:

It will HELP you

Discussion

38.	What is the S.I unit of resistivity?
Answer» ANSWER: ohm-metre Thus, in the metre-kilogram-second SYSTEM, the unit of resistivity is ohm-metre. If LENGTHS are measured in centimetres, resistivity may be EXPRESSED in units of ohm-centimetre. Explanation:

38.

What is the S.I unit of resistivity?

Answer»

ANSWER:

ohm-metre

Thus, in the metre-kilogram-second SYSTEM, the unit of resistivity is ohm-metre. If LENGTHS are measured in centimetres, resistivity may be EXPRESSED in units of ohm-centimetre.

Explanation:

Discussion

39.	Nes: IfIf a wire of resisfance R is melted and recast to halve of its lengthwhat will be the new resistance ofwire ?
Answer» Answer: BECOMES half Explanation: becomes half as R is directly proportional to LENGTH of the WIRE

39.

Nes: IfIf a wire of resisfance R is melted and recast to halve of its lengthwhat will be the new resistance ofwire ?

Answer»

Answer:

BECOMES half

Explanation:

becomes half as R is directly proportional to LENGTH of the WIRE

Discussion

40.	What is Ghost????Is it real?????
Answer» Answer: Don't watch those horror movies and believe about ghosts, they are just the imagination of humans, humans are afraid by the fear of unknown. For example, in older periods, they could have seen a bush move. There are many REASONS for the bush to move, but humans imagined that the dead people come again! !Its Basically" The fear of unknown"sometimes it's also caused due to "Hallucination" Hope you got it Ghosts are real in one's mind only If found HELPFUL MARK it as brainiliest and FOLLOW plz Rip Pulwama MARTYRS

40.

What is Ghost????Is it real?????

Answer»

Answer:

Don't watch those horror movies and believe about ghosts, they are just the imagination of humans, humans are afraid by the fear of unknown. For example, in older periods, they could have seen a bush move. There are many REASONS for the bush to move, but humans imagined that the dead people come again!

!Its Basically" The fear of unknown"sometimes it's also caused due to "Hallucination"

Hope you got it

Ghosts are real in one's mind only

If found HELPFUL MARK it as brainiliest and FOLLOW plz

Rip Pulwama MARTYRS

Discussion

41.	Please I need help I will mark as brainlest answerplease give correct answers
Answer» Answer: 25.Take two test tubes, label them as A and B.Take about 0.5g of sodium CARBONATE in test tube A and 0.5g of sodium hydrogencarbonate in test B.Add about 2ML if dilute HCl to both the test Tubes. Pass the CARBON dioxide gas through CALCIUM hydroxide solution (sodium carbonate +Hcl) so the solution will turn MILKY

41.

Please I need help I will mark as brainlest answerplease give correct answers

Answer»

Answer:

25.Take two test tubes, label them as A and B.Take about 0.5g of sodium CARBONATE in test tube A and 0.5g of sodium hydrogencarbonate in test B.Add about 2ML if dilute HCl to both the test Tubes. Pass the CARBON dioxide gas through CALCIUM hydroxide solution (sodium carbonate +Hcl) so the solution will turn MILKY

Discussion

42.	Derive an expression that relates angularmomentum with the angular velocity of a rigid body.
Answer» EXPLANATION: For a rigid body, the angular momentum (L) is the product of the moment of inertia and the angular velocity: L = Iω. For a point of MASS, angular momentum can be expressed as the product of LINEAR momentum and the radius ( R): L = mvr *hope* it *helps*

42.

Derive an expression that relates angularmomentum with the angular velocity of a rigid body.

Answer»

EXPLANATION:

For a rigid body, the angular momentum (L) is the product of the moment of inertia and the angular velocity: L = Iω. For a point of MASS, angular momentum can be expressed as the product of LINEAR momentum and the radius ( R): L = mvr

hope it helps

Discussion

43.	A car travels stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50km/h.finddisplacement of the car.distance travelled by the car.average speed of the car.
Answer» ANSWER: Displacement is 0 and average speed is 35km/h Explanation: As object travels from A to b and then again from B to A, the object returns to its starting point therefore there is 0 displacement . AVG speed = total distance / total time let us TAKE distance from A to B , D THEREFORE, t1= D/30 t2= D/50 so, D+D/(D/30+D/50) = 35km/h I can't give you the distance until you tell me the time (numeral value)

43.

A car travels stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50km/h.finddisplacement of the car.distance travelled by the car.average speed of the car.

Answer»

ANSWER:

Displacement is 0 and average speed is 35km/h

Explanation:

As object travels from A to b and then again from B to A, the object returns to its starting point therefore there is 0 displacement .

AVG speed = total distance / total time

let us TAKE distance from A to B , D

THEREFORE,

t1= D/30

t2= D/50

so, D+D/(D/30+D/50) = 35km/h

I can't give you the distance until you tell me the time (numeral value)

Discussion

44.	When the current carrying wire will experience maximum and minimum force when it is placed in a uniform magnetic field lines?
Answer» when the wire is PLACED PERPENDICULAR to the magnetic LINES of force.

Discussion

45.	a material having higher mass density may not necessarily have higher optical density.justify the statement with an eample
Answer» ANSWER: Explanation: OPTICAL density :- Optical density is a measure of materials ability to pass light. Optical density is the ratio of speed of light in 2 media. Mass density :- Mass density is mass per unit volume. the mass density of an optically denser medium MAY be lesser than a optically RARER medium. Eg :- the mass density of turpentine is less than that of water, but its optical density is high. Cheers!!!!!!

45.

a material having higher mass density may not necessarily have higher optical density.justify the statement with an eample

Answer»

ANSWER:

Explanation:

OPTICAL density :- Optical density is a measure of materials ability to pass light. Optical density is the ratio of speed of light in 2 media.

Mass density :- Mass density is mass per unit volume.

the mass density of an optically denser medium MAY be lesser than a optically RARER medium.

Eg :- the mass density of turpentine is less than that of water, but its optical density is high.

Cheers!!!!!!

Discussion

46.	How much energy would it take to heat 1 g of brass from 10 to 15o C?
Answer» Answer: A copper wire has a MASS of 165 g. An electric CURRENT runs through the wire for a short time and its temperature rises from 21°C to 39°C. What MINIMUM quantity of energy is converted by the electric current

46.

How much energy would it take to heat 1 g of brass from 10 to 15o C?

Answer»

Answer:

A copper wire has a MASS of 165 g. An electric CURRENT runs through the wire for a short time and its temperature rises from 21°C to 39°C. What MINIMUM quantity of energy is converted by the electric current

Discussion

47.	How many moles of CH4 are contained in 2.408 X10^25 atoms of ch4?Pls koi bana do pls... Chemistry walon se nhi bana
Answer» ANSWER: MOLES of CH4 = (no. of TOTAL ATOMS of CH4) / 6.02310^23 moles of CH4 = (2.40810^25) / 6.023*10^23 moles of CH4 = 39.98 moles

47.

How many moles of CH4 are contained in 2.408 X10^25 atoms of ch4?Pls koi bana do pls... Chemistry walon se nhi bana

Answer»

ANSWER:

MOLES of CH4 = (no. of TOTAL ATOMS of CH4) / 6.023*10^23

moles of CH4 = (2.408*10^25) / 6.023*10^23

moles of CH4 = 39.98 moles

Discussion

48.	Two point charges Qa=8c and Qb=5c are separated by the distance r=10cm what is the magnitude of the force
Answer» AnswEr : From the QUESTION, $\sf Charge_1 = 8 \ C$ $\sf Charge_2 = 5 \ C$ Distance of Separation (r) = 10CM = 10^-1 m ELECTROSTATIC Force between the charges would be GIVEN as : $\huge{\boxed{\boxed{\sf F = \dfrac{1}{4 \pi \epsilon_o} \times \dfrac{Q_a Q_b}{r^2}}}}$ $\sf{Here}\begin{cases} \sf{Q_a,Q_b \longrightarrow Charges } \\ \sf{r \longrightarrow Distance \ Of \ Separation } \\ \sf{\epsilon_o \longrightarrow Permittivity \ Of \ Free \ Space} \end{cases}$ Putting the VALUES, $\longrightarrow \: \sf \: F = 9 \times {10}^{9} \times \dfrac{8 \times 5}{ ({ {10}^{ - 1} )}^{2} } \\ \\ \longrightarrow \: \sf \: F = 40 \times 9 \times {10}^{11} \\ \\ \longrightarrow \: \boxed{ \boxed{ \sf F = 36 \times {10}^{12} \: N}}$ The electrostatic force acting on the charges is of the magnitude 36 × 10¹² N

48.

Two point charges Qa=8c and Qb=5c are separated by the distance r=10cm what is the magnitude of the force

Answer»

AnswEr :

From the QUESTION,

$\sf Charge_1 = 8 \ C$

$\sf Charge_2 = 5 \ C$

Distance of Separation (r) = 10CM = 10^-1 m

ELECTROSTATIC Force between the charges would be GIVEN as :

$\huge{\boxed{\boxed{\sf F = \dfrac{1}{4 \pi \epsilon_o} \times \dfrac{Q_a Q_b}{r^2}}}}$

$\sf{Here}\begin{cases} \sf{Q_a,Q_b \longrightarrow Charges } \\ \sf{r \longrightarrow Distance \ Of \ Separation } \\ \sf{\epsilon_o \longrightarrow Permittivity \ Of \ Free \ Space} \end{cases}$

Putting the VALUES,

$\longrightarrow \: \sf \: F = 9 \times {10}^{9} \times \dfrac{8 \times 5}{ ({ {10}^{ - 1} )}^{2} } \\ \\ \longrightarrow \: \sf \: F = 40 \times 9 \times {10}^{11} \\ \\ \longrightarrow \: \boxed{ \boxed{ \sf F = 36 \times {10}^{12} \: N}}$

The electrostatic force acting on the charges is of the magnitude 36 × 10¹² N

Discussion

49.	an eye has a far point of 5.0m and a normal near point. determine the focal length of the lens used to correct the defect
Answer» ANSWER: jsbwlenke qjqmwnensjn

49.

an eye has a far point of 5.0m and a normal near point. determine the focal length of the lens used to correct the defect

Answer»

ANSWER:

jsbwlenke qjqmwnensjn

Discussion

50.	two small pith balls are 1 cm apart in air and carry charges of 2 into 10 power minus 9 coulomb and minus 6 into 10 power minus 9 coulomb respectively calculate the force of attraction if the balls are dust and then separated by a distance of 1 cm what will the force between them
Answer» Given that, Charge on first ball $q=2\times10^{-9}\ C$ Charge on SECOND ball $q=-6\times10^{-9}\ C$ Distance = 1 cm We need to calculate the force of attraction Using formula of force $F=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q_{1}q_{2}}{r^2}$ Put the value into the formula $F=9\times10^{9}\times\dfrac{2\times10^{-9}\times6\times10^{-9}}{(1\times10^{-2})^2}$ $F=0.00108\ N$ $F=1.08\times10^{-3}\ N$ When these TWO charged pith balls are touched then first the opposite charges are NEUTRALISED and then the SEPARATED charge of $-4\times10^{-9}\ C$ is equally DISTRIBUTED on pith balls. We need to calculate the force of repulsion Using formula of force $F=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q_{1}q_{2}}{r^2}$ Put the value into the formula $F=9\times10^{9}\times\dfrac{2\times10^{-9}\times2\times10^{-9}}{(1\times10^{-2})^2}$ $F=0.00036\ N$ $F=3.6\times10^{-4}\ N$ $1.08\times10^{-3}\ N$ Hence, The force of attraction is $3.6\times10^{-4}\ N$ The force of repulsion is

50.

two small pith balls are 1 cm apart in air and carry charges of 2 into 10 power minus 9 coulomb and minus 6 into 10 power minus 9 coulomb respectively calculate the force of attraction if the balls are dust and then separated by a distance of 1 cm what will the force between them

Answer»

Given that,

Charge on first ball $q=2\times10^{-9}\ C$

Charge on SECOND ball $q=-6\times10^{-9}\ C$

Distance = 1 cm

We need to calculate the force of attraction

Using formula of force

$F=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q_{1}q_{2}}{r^2}$

Put the value into the formula

$F=9\times10^{9}\times\dfrac{2\times10^{-9}\times6\times10^{-9}}{(1\times10^{-2})^2}$

$F=0.00108\ N$

$F=1.08\times10^{-3}\ N$

When these TWO charged pith balls are touched then first the opposite charges are NEUTRALISED and then the SEPARATED charge of $-4\times10^{-9}\ C$ is equally DISTRIBUTED on pith balls.

We need to calculate the force of repulsion

Using formula of force

$F=\dfrac{1}{4\pi\epsilon_{0}}\dfrac{q_{1}q_{2}}{r^2}$

Put the value into the formula

$F=9\times10^{9}\times\dfrac{2\times10^{-9}\times2\times10^{-9}}{(1\times10^{-2})^2}$

$F=0.00036\ N$

$F=3.6\times10^{-4}\ N$

$1.08\times10^{-3}\ N$ Hence, The force of attraction is

$3.6\times10^{-4}\ N$ The force of repulsion is

Discussion

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