1.

Two point charges Qa=8c and Qb=5c are separated by the distance r=10cm what is the magnitude of the force

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AnswEr :

From the QUESTION,

  • \sf Charge_1 = 8 \ C

  • \sf Charge_2 = 5 \ C

  • Distance of Separation (r) = 10CM = 10^-1 m

ELECTROSTATIC Force between the charges would be GIVEN as :

\huge{\boxed{\boxed{\sf F = \dfrac{1}{4 \pi \epsilon_o} \times \dfrac{Q_a Q_b}{r^2}}}}

\sf{Here}\begin{cases} \sf{Q_a,Q_b \longrightarrow Charges } \\ \sf{r \longrightarrow Distance \ Of \ Separation } \\ \sf{\epsilon_o \longrightarrow Permittivity \ Of \ Free \ Space} \end{cases}

Putting the VALUES,

\longrightarrow \: \sf \: F = 9 \times {10}^{9} \times \dfrac{8 \times 5}{ ({ {10}^{ - 1} )}^{2} } \\ \\ \longrightarrow \: \sf \: F = 40 \times 9 \times {10}^{11} \\ \\ \longrightarrow \: \boxed{ \boxed{ \sf F = 36 \times {10}^{12} \: N}}

The electrostatic force acting on the charges is of the magnitude 36 × 10¹² N



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