1.

A car travels stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50km/h.finddisplacement of the car.distance travelled by the car.average speed of the car.​

Answer»

ANSWER:

Displacement is 0 and average speed is 35km/h

Explanation:  

As object travels from A to b and then again from B to A, the object returns to its  starting point therefore there is 0 displacement .

AVG speed = total distance / total time

let us TAKE distance from A to B  , D

THEREFORE,

t1= D/30

t2= D/50

so, D+D/(D/30+D/50) = 35km/h

I can't give you the distance until you tell me the time (numeral value)



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