67486 + Interview Questions in Secondary School in Physics

1.	If we assume that the ground is a flat, the direction of ‘g’
Answer» ANSWER: the DIRECTION of G is ALWAYS DOWNWARDS

1.

If we assume that the ground is a flat, the direction of ‘g’

Answer»

ANSWER:

the DIRECTION of G is ALWAYS DOWNWARDS

Discussion

2.	How to differentiate y=x^√2
Answer» ANSWER: √2x^(√2-1) EXPLANATION: SOLUTION is ATTACHED

2.

How to differentiate y=x^√2

Answer»

ANSWER:

√2x^(√2-1)

EXPLANATION:

SOLUTION is ATTACHED

Discussion

3.	What is the potential energy of a 150 kg diver standing on a diving board that is 10 m high?
Answer» ANSWER: PLEASE SEE the ATTACHMENT

3.

What is the potential energy of a 150 kg diver standing on a diving board that is 10 m high?

Answer»

ANSWER:

PLEASE SEE the ATTACHMENT

Discussion

4.	Hola ❤⏺ A projectile is projected from a point 5m away from the foot of 10 m high tower such that it touches the tower and falls on other sides of it at a distance 15m from foot of tower . calculate :-a) R b) H c) T d) U v) Theta ✒️ Show ur own talent ❌No spam ❌
Answer» Answer: 1. R = 20 m 2. H = 10 m 3. T = 4√5/√g sec. 4. u = 5√g m/s 5. $\theta={\tan}^{-1}2$ Explanation: LET the projectile is projected at an ANGLE $\alpha$ with the horizontal with an initial VELOCITY u. Now, it's given that, It's projected from a point at a distance of 5 m from the foot of a tower which is 10 m high. Also, it just touches the tower and falls to a distance of 15 m from the foot of the tower. Therefore, total horizontal distance COVERED by the projectile = 5 + 15 = 20 m But, we know that, maximum horizontal distance is called range. Therefore, we will get, (1) Range, R = 20 m Also, it just touches the highest point of tower and falls after that. Therefore, maximum height attained is, (2) Maxm. height, H = 10 m Now, we know that, $R = \dfrac{ {u}^{2} \sin(2 \alpha ) }{g}$ Therefore, we will get, $= > \dfrac{2 {u}^{2} \sin( \alpha ) \cos( \alpha ) }{g} = 20 \\ \\ = > \dfrac{2 {u}^{2} { \sin}^{2} \alpha \cos\alpha }{2g \sin( \alpha ) } = \dfrac{20}{2} \\ \\ = > \frac{ {u}^{2} { \sin }^{2} \alpha }{2g} \times \cot( \alpha ) = 5$ But, we know that, $\dfrac{ {u}^{2} { \sin }^{2} \alpha }{2g} = H$ And, H = 10 m Therefore, substituting the values, we get, $= > \cot( \alpha ) = \frac{5}{10} \\ \\ = > \cot( \alpha ) = \frac{1}{2} \\ \\ = > \tan( \alpha ) = 2 \\ \\ = > \alpha = { \tan}^{ - 1} 2$ Therefore, angle at which it is projected, (5) $\bold{\theta={\tan}^{-1}2}$ Now, we know that, $\sin(2 \alpha ) = \dfrac{2 \tan( \alpha ) }{1 + { \tan }^{2} \alpha }$ Substituting the values, we get, $= > \sin(2 \alpha ) = \dfrac{2 \times 2}{1 + {2}^{2} } \\ \\ = > \sin(2 \alpha ) = \dfrac{4}{1 + 4} \\ \\ = > \sin(2 \alpha ) = \dfrac{4}{5}$ Now, we have, $= > \dfrac{ {u}^{2} \sin(2 \alpha ) }{g} = 20 \\ \\ = > {u}^{2} \times \dfrac{4}{5} = 20g \\ \\ = > {u}^{2} = \frac{5 \times 20}{4}g \\ \\ = > {u}^{2} = 25g \\ \\ = > u = 5 \sqrt{g}$ Therefore, the projectile is projected with velocity EQUAL to , (4) u = 5√g m/s. Now, we know that, Time of flight, $t=\dfrac{2u\sin\alpha}{g}$ Therefore, substituting the values, we get, => t = 2u/g × 2/√5 => t = 4u/√5g => t = 4× 5√g/√5g => t = 4√5/√g Hence, we get, (3) T = 4√5/√g

4.

Hola ❤⏺ A projectile is projected from a point 5m away from the foot of 10 m high tower such that it touches the tower and falls on other sides of it at a distance 15m from foot of tower . calculate :-a) R b) H c) T d) U v) Theta ✒️ Show ur own talent ❌No spam ❌

Answer»

Answer:

1. R = 20 m

2. H = 10 m

3. T = 4√5/√g sec.

4. u = 5√g m/s

5. $\theta={\tan}^{-1}2$

Explanation:

LET the projectile is projected at an ANGLE $\alpha$ with the horizontal with an initial VELOCITY u.

Now, it's given that,

It's projected from a point at a distance of 5 m from the foot of a tower which is 10 m high.

Also, it just touches the tower and falls to a distance of 15 m from the foot of the tower.

Therefore, total horizontal distance COVERED by the projectile = 5 + 15 = 20 m

But, we know that, maximum horizontal distance is called range.

Therefore, we will get,

(1) Range, R = 20 m

Also, it just touches the highest point of tower and falls after that.

Therefore, maximum height attained is,

(2) Maxm. height, H = 10 m

Now, we know that,

$R = \dfrac{ {u}^{2} \sin(2 \alpha ) }{g}$

Therefore, we will get,

$= > \dfrac{2 {u}^{2} \sin( \alpha ) \cos( \alpha ) }{g} = 20 \\ \\ = > \dfrac{2 {u}^{2} { \sin}^{2} \alpha \cos\alpha }{2g \sin( \alpha ) } = \dfrac{20}{2} \\ \\ = > \frac{ {u}^{2} { \sin }^{2} \alpha }{2g} \times \cot( \alpha ) = 5$

But, we know that,

$\dfrac{ {u}^{2} { \sin }^{2} \alpha }{2g} = H$

And, H = 10 m

Therefore, substituting the values, we get,

$= > \cot( \alpha ) = \frac{5}{10} \\ \\ = > \cot( \alpha ) = \frac{1}{2} \\ \\ = > \tan( \alpha ) = 2 \\ \\ = > \alpha = { \tan}^{ - 1} 2$

Therefore, angle at which it is projected,

(5) $\bold{\theta={\tan}^{-1}2}$

Now,

we know that,

$\sin(2 \alpha ) = \dfrac{2 \tan( \alpha ) }{1 + { \tan }^{2} \alpha }$

Substituting the values, we get,

$= > \sin(2 \alpha ) = \dfrac{2 \times 2}{1 + {2}^{2} } \\ \\ = > \sin(2 \alpha ) = \dfrac{4}{1 + 4} \\ \\ = > \sin(2 \alpha ) = \dfrac{4}{5}$

Now, we have,

$= > \dfrac{ {u}^{2} \sin(2 \alpha ) }{g} = 20 \\ \\ = > {u}^{2} \times \dfrac{4}{5} = 20g \\ \\ = > {u}^{2} = \frac{5 \times 20}{4}g \\ \\ = > {u}^{2} = 25g \\ \\ = > u = 5 \sqrt{g}$

Therefore, the projectile is projected with velocity EQUAL to ,

(4) u = 5√g m/s.

Now, we know that,

Time of flight, $t=\dfrac{2u\sin\alpha}{g}$

Therefore, substituting the values, we get,

=> t = 2u/g × 2/√5

=> t = 4u/√5g

=> t = 4× 5√g/√5g

=> t = 4√5/√g

Hence, we get,

(3) T = 4√5/√g

Discussion

5.	What is the hardest metal in the world
Answer» ${\huge{\underline{\underline{\mathcal {\red{♡Answer♡}}}}}}$ TUNGSTEN and TITANIUM is the HARDEST METAL in the WORLD. $Thank You❤$ $Mr.Khiladi❤$

5.

What is the hardest metal in the world

Answer»

${\huge{\underline{\underline{\mathcal {\red{♡Answer♡}}}}}}$

TUNGSTEN and TITANIUM is the HARDEST METAL in the WORLD.

$Thank You❤$

$Mr.Khiladi❤$

Discussion

6.	what is the wavelength of a sound wave in air at 20°c with a frequency of 14MHZ? (given V = 3444 m/S)
Answer» Answer: GIVEN, (In air) VELOCITY V=340m/s Frequency f=20,000Hz Wavelegth λ=? V=f.λ λ= F V = 20,000 340 =0.017Hz Also, Given (in WATER) Velocity, V=1480m/s Frequencyf=20,000Hz wavelength, λ=? V=F.λ λ= F V = 20,000 1480 =0.074Hz

6.

what is the wavelength of a sound wave in air at 20°c with a frequency of 14MHZ? (given V = 3444 m/S)

Answer»

Answer:

GIVEN, (In air)

VELOCITY V=340m/s

Frequency f=20,000Hz

Wavelegth λ=?

V=f.λ

λ=

F

V

=

20,000

340

=0.017Hz

Also, Given (in WATER)

Velocity, V=1480m/s

Frequencyf=20,000Hz

wavelength, λ=?

V=F.λ

λ=

F

V

=

20,000

1480

=0.074Hz

Discussion

7.	did you ever use physics to solve any problem in daily life write a daily life event you use physics to solve problem
Answer» Answer: yes i USE physics to solve any problem in DAILY life. We use Physics every day in our home for COOKING,boiling,ETC. Explanation: The teacher in my school has given a project to MAKE an electro magnet. I use physics to make an electro magnet.

7.

did you ever use physics to solve any problem in daily life write a daily life event you use physics to solve problem

Answer»

Answer:

yes i USE physics to solve any problem in DAILY life. We use Physics every day in our home for COOKING,boiling,ETC.

Explanation:

The teacher in my school has given a project to MAKE an electro magnet. I use physics to make an electro magnet.

Discussion

8.	a motor boat speed 20 km per h in still water takes one hour more to go 48 upstream than to return downstream to same spot find the speed of stream
Answer» Answer: The “speed of the given stream” is 4km/hr. Solution: Now let us take the speed of the stream as x Therefore, the speed of BOAT upstream is EQUAL to \frac{48}{20-x} and the speed of the boat downstream is \frac{48}{20+x}. Now as to find the value of the speed of the stream we subtract the speed of downstream from upstream we get: \frac{48}{20-x}-\frac{48}{20+x}=1 48(2 x)=400-x^{2} x^{2}+96 x-400=0 x(x+100)-4(x+100) x=4,-100 Now as we can see that after solving the equation we get two VALUES one is 4 and the other one is -100. Now the value of speed can never be negative therefore x = 4 km/hr is the CORRECT value for the speed of the stream.

8.

a motor boat speed 20 km per h in still water takes one hour more to go 48 upstream than to return downstream to same spot find the speed of stream

Answer»

Answer:

The “speed of the given stream” is 4km/hr.

Solution:

Now let us take the speed of the stream as x

Therefore, the speed of BOAT upstream is EQUAL to \frac{48}{20-x} and the speed of the boat downstream is \frac{48}{20+x}.

Now as to find the value of the speed of the stream we subtract the speed of downstream from upstream we get:

\frac{48}{20-x}-\frac{48}{20+x}=1

48(2 x)=400-x^{2}

x^{2}+96 x-400=0

x(x+100)-4(x+100)

x=4,-100

Now as we can see that after solving the equation we get two VALUES one is 4 and the other one is -100. Now the value of speed can never be negative therefore x = 4 km/hr is the CORRECT value for the speed of the stream.

Discussion

9.	Pls answer this question pls pls pls
Answer» ANSWER: RIA PLS SEND it FULLY we will answer

9.

Pls answer this question pls pls pls

Answer»

ANSWER:

RIA PLS SEND it FULLY we will answer

Discussion

10.	Which state of mattor can be squashedeasily ?
Answer» Answer: Gas Explanation: Because a SOLID cannot CHANGE shape so it cannot. When a solid melts its BECOME a LIQUID

10.

Which state of mattor can be squashedeasily ?

Answer»

Answer:

Gas

Explanation:

Because a SOLID cannot CHANGE shape so it cannot. When a solid melts its BECOME a LIQUID

Discussion

11.	Mecalculate the des isdance of Ikmlong copper wire of radius 1 mm(Resistivity of copper = 1 F2 x 10 8 nm
Answer» Answer: Calculate the RESISTANCE of 1 km long COPPER WIRE of radius 1 mm. Resistivity of the copper is 1.72 × 10–8 ω m. Explanation: calculate the DES isdance of I km long copper wire of radius 1 mm calculate the des isdance of Ikm long copper wire of radius 1 mm (Resistivity of copper = 1 F2 x 10 8 nm $1 + .3$

11.

Mecalculate the des isdance of Ikmlong copper wire of radius 1 mm(Resistivity of copper = 1 F2 x 10 8 nm

Answer»

Answer:

Calculate the RESISTANCE of 1 km long COPPER WIRE of radius 1 mm. Resistivity of the copper is 1.72 × 10–8 ω m.

Explanation:

calculate the DES isdance of I km

long copper wire of radius 1 mm

calculate the des isdance of Ikm

long copper wire of radius 1 mm

(Resistivity of copper = 1 F2 x 10 8 nm

$1 + .3$

Discussion

12.	Write the names of quantities in front of the example-1) A car running on a highway with the speed of 45km/hr towards east.
Answer» ANSWER: SPEED of the car (V) = 45 kmph EXPLANATION: Pl. mark this as 'Brainliest Answer'

12.

Write the names of quantities in front of the example-1) A car running on a highway with the speed of 45km/hr towards east.

Answer»

ANSWER:

SPEED of the car (V) = 45 kmph

EXPLANATION:

Pl. mark this as 'Brainliest Answer'

Discussion

13.	Why PH present in our body
Answer» Answer: HEY mate here is ur answer ☺️☺️❤️❤️ ❤️❤️☺️PH is present in our body to calculate the acid and base level in our blood at which our body function BEST. The human body is built to naturally maintain a healthy balance of acidity and alkalinity.. The lungs and kidneys play a KEY ROLE in this process..... ☺️☺️❤️ Hope it HELPS u mate ❤️❤️☺️ If u like my answer mark it as a brainlist ☺️☺️❤️❤️ Follow me ❤️❤️☺️☺️

13.

Why PH present in our body

Answer»

Answer:

HEY mate here is ur answer ☺️☺️❤️❤️

❤️❤️☺️PH is present in our body to calculate the acid and base level in our blood at which our body function BEST. The human body is built to naturally maintain a healthy balance of acidity and alkalinity.. The lungs and kidneys play a KEY ROLE in this process..... ☺️☺️❤️

Hope it HELPS u mate ❤️❤️☺️

If u like my answer mark it as a brainlist ☺️☺️❤️❤️

Follow me ❤️❤️☺️☺️

Discussion

14.	The take off of boeing 747 is 252km/hr.if it can accelarate at 1.5m/s^2 what should be the minimum length of the runway?
Answer» EXPLANATION: given v=252 KM/hr convert it into m/s so,multiply with 5/18 v=252×5/18 v=70m/s v^2-u^2=2as for any flight INTIAL VELOCITY is zero u=0 70×70=2×3/2×s s=1633.3m s=1.6 km approx

14.

The take off of boeing 747 is 252km/hr.if it can accelarate at 1.5m/s^2 what should be the minimum length of the runway?

Answer»

EXPLANATION:

given v=252 KM/hr

convert it into m/s so,multiply with 5/18

v=252×5/18

v=70m/s

v^2-u^2=2as

for any flight INTIAL VELOCITY is zero

u=0

70×70=2×3/2×s

s=1633.3m

s=1.6 km approx

Discussion

15.	How do you use heat at home
Answer» Answer: FURNACES and HEATERS put heatinto the air to make your homewarmer; air conditioners remove heat to make yourhome cooler. All heating and cooling units burn fuel. Air conditioners use electricity. Most home heating systemsuse gas or fuel oil; other SYSTEMS use electricity.

15.

How do you use heat at home

Answer»

Answer:

FURNACES and HEATERS put heatinto the air to make your homewarmer; air conditioners remove heat to make yourhome cooler. All heating and cooling units burn fuel. Air conditioners use electricity. Most home heating systemsuse gas or fuel oil; other SYSTEMS use electricity.

Discussion

16.	An object is placed at a large distance in front of a concave mirror of radius of curvature 40centimetre.The image will be formed in front of the mirror at a distance of:
Answer» ANSWER: Answer is 20cm Explanation: By the FORMULA F=R/2 = 40/2 = 20

16.

An object is placed at a large distance in front of a concave mirror of radius of curvature 40centimetre.The image will be formed in front of the mirror at a distance of:

Answer»

ANSWER:

Answer is 20cm

Explanation:

By the FORMULA F=R/2

= 40/2 = 20

Discussion

17.	Complete the figure with correct labelling ? Mention the type of mirror in each case.
Answer» ANSWER: A = concave lens B = convex lens Explanation: please make me brainlest and please GIVE me thanks. THANKS

17.

Complete the figure with correct labelling ? Mention the type of mirror in each case.

Answer»

ANSWER:

A = concave lens

B = convex lens

Explanation:

please make me brainlest and please GIVE me thanks.

THANKS

Discussion

18.	A car move from 30km/h and back with 60km/h.find average speed and velocity during the motion
Answer» ANSWER: Average speed : 40km/hr Average velocity : 0 Explanation: Average speed= TOTAL distance covered /total TIME Let the distance from START to end POINT be L km Total time=(L/30)+(L/60)=L/20 Average speed = 2L/(L/20)=40 Average velocity is zero because DISPLACEMENT is zero Hope this answer helped you

18.

A car move from 30km/h and back with 60km/h.find average speed and velocity during the motion

Answer»

ANSWER:

Average speed : 40km/hr

Average velocity : 0

Explanation:

Average speed= TOTAL distance covered /total TIME

Let the distance from START to end POINT be L km

Total time=(L/30)+(L/60)=L/20

Average speed = 2L/(L/20)=40

Average velocity is zero because DISPLACEMENT is zero

Hope this answer helped you

Discussion

19.	the ground orbit energy of atom is -13.6 ev find the K.E and P.E of the electron in the ground state
Answer» EXPLANATION: k.E will be -E = 13.6 AND P.Ewill be -2E = -27.2 HOPEFULLY this answer will HELP

19.

the ground orbit energy of atom is -13.6 ev find the K.E and P.E of the electron in the ground state

Answer»

EXPLANATION:

k.E will be -E = 13.6 AND P.Ewill be -2E = -27.2 HOPEFULLY this answer will HELP

Discussion

20.	Express 8 nC in charge
Answer» Answer: 810^-9 C is the EXPRESSION of 8nC Explanation:* mark it as best answer and if it HELPS also mark thanks.HOPE IT WOULD HELP YOU.

20.

Express 8 nC in charge

Answer»

Answer:

8*10^-9 C is the EXPRESSION of 8nC

Explanation:

mark it as best answer and if it HELPS also mark thanks.HOPE IT WOULD HELP YOU.

Discussion

21.	what is the distance time graph what is the nature of distance time graph for 1st and object moving under uniform motion second and object moving and non uniform motion
Answer» Answer: What is the nature of the distance - 'TIME graphs for UNIFORM and non-uniform motion of an OBJECT? Answer: When the motion is uniform, thedistance time graph is a straight linewith a slope. When the motion is non-uniform, the distance time graph is nota straight line. HOPE IT HELPS *MARK* AS *BRAINLIEST*

21.

what is the distance time graph what is the nature of distance time graph for 1st and object moving under uniform motion second and object moving and non uniform motion

Answer»

Answer:

What is the nature of the distance - 'TIME graphs for UNIFORM and non-uniform motion of an OBJECT?

Answer: When the motion is uniform, thedistance time graph is a straight linewith a slope. When the motion is non-uniform, the distance time graph is nota straight line.

HOPE IT HELPS

MARK AS BRAINLIEST

Discussion

22.	A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it is on the conveyor belt?
Answer» Answer: 80J Explanation: K.E =1/2402*2 =80J

22.

A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it is on the conveyor belt?

Answer»

Answer:

80J

Explanation:

K.E =1/2*40*2*2

=80J

Discussion

23.	Please give me a list of units needed in the chapter of force and motion ... (Like of speed velociti accln etc)
Answer» Answer: speed, ACCELERATION, velocity, NEWTONS, MASS, time (h/m/s), MOMENTUM

23.

Please give me a list of units needed in the chapter of force and motion ... (Like of speed velociti accln etc)

Answer»

Answer:

speed, ACCELERATION, velocity, NEWTONS, MASS, time (h/m/s), MOMENTUM

Discussion

24.	Write the names of quantities in front of example-1) A body moves 7km from his home to the market.
Answer» ANSWER: SCALER QUANTITY because there is no DIRECTION is GIVEN

24.

Write the names of quantities in front of example-1) A body moves 7km from his home to the market.

Answer»

ANSWER:

SCALER QUANTITY because there is no DIRECTION is GIVEN

Discussion

25.	The dimension of mass in terms of energy, velocity, force is
Answer» We have to express the dimension of mass in TERMS of energy $\sf{E,}$ velocity $\sf{v}$ and force $\sf{F.}$ Solution 1:- Let the dimension of mass in terms of energy, velocity and force is as follows, $\longrightarrow\sf{[m]=E^a\,v^b\,F^c\quad\quad\dots(1)}$ Taking dimensions of each, $\longrightarrow\sf{[m]=[E]^a\,[v]^b\,[F]^c}$ $\longrightarrow\sf{M=(ML^2T^{-<klux>2</klux>})^a(LT^{-1})^b(MLT^{-2})^c}$ $\longrightarrow\sf{M^1\,L^0\,T^0=M^{a+c}\,L^{2a+b+c}\,T^{-2a-b-2c}}$ Equating like POWERS, $\longrightarrow\sf{a+c=1}$ $\longrightarrow\sf{2a+b+c=0}$ $\longrightarrow\sf{-2a-b-2c=0}$ By SOLVING them we get, $\longrightarrow\sf{a=1}$ $\longrightarrow\sf{b=-2}$ $\longrightarrow\sf{c=0}$ Hence (1) becomes, $\longrightarrow\sf{\underline{\underline{[m]=E^1\,v^{-2}\,F^0}}}$ Solution 2:- We know that kinetic energy is also an energy and is given by, $\longrightarrow\sf{E=\dfrac{1}{2}mv^2}$ We take the dimensions, $\longrightarrow\sf{[E]=\left[m\right]\left[v\right]^2}$ From this we get the dimension of mass, $\longrightarrow\sf{[m]=\dfrac{\,[E]\,}{\,[v]^2}\,}$ $\longrightarrow\sf{[m]=[E][v]^{-2}}$ Finally, we get, $\longrightarrow\sf{\underline{\underline{[m]=E^1\,v^{-2}\,F^0}}}$

25.

The dimension of mass in terms of energy, velocity, force is

Answer»

We have to express the dimension of mass in TERMS of energy $\sf{E,}$ velocity $\sf{v}$ and force $\sf{F.}$

Solution 1:-

Let the dimension of mass in terms of energy, velocity and force is as follows,

$\longrightarrow\sf{[m]=E^a\,v^b\,F^c\quad\quad\dots(1)}$

Taking dimensions of each,

$\longrightarrow\sf{[m]=[E]^a\,[v]^b\,[F]^c}$

$\longrightarrow\sf{M=(ML^2T^{-<klux>2</klux>})^a(LT^{-1})^b(MLT^{-2})^c}$

$\longrightarrow\sf{M^1\,L^0\,T^0=M^{a+c}\,L^{2a+b+c}\,T^{-2a-b-2c}}$

Equating like POWERS,

$\longrightarrow\sf{a+c=1}$

$\longrightarrow\sf{2a+b+c=0}$

$\longrightarrow\sf{-2a-b-2c=0}$

By SOLVING them we get,

$\longrightarrow\sf{a=1}$

$\longrightarrow\sf{b=-2}$

$\longrightarrow\sf{c=0}$

Hence (1) becomes,

$\longrightarrow\sf{\underline{\underline{[m]=E^1\,v^{-2}\,F^0}}}$

Solution 2:-

We know that kinetic energy is also an energy and is given by,

$\longrightarrow\sf{E=\dfrac{1}{2}mv^2}$

We take the dimensions,

$\longrightarrow\sf{[E]=\left[m\right]\left[v\right]^2}$

From this we get the dimension of mass,

$\longrightarrow\sf{[m]=\dfrac{\,[E]\,}{\,[v]^2}\,}$

$\longrightarrow\sf{[m]=[E][v]^{-2}}$

Finally, we get,

$\longrightarrow\sf{\underline{\underline{[m]=E^1\,v^{-2}\,F^0}}}$

Discussion

26.	Why Brownian motion isn't seen in real solution ?
Answer» ANSWER: Brownian motion is the continuous random movement of SMALL particles suspended in a fluid, which arise from collisions with the fluid MOLECULES. When colloidal solutions are viewed under a powerful ultramicroscope, the colloidal particles appear to be in a state of continuous zig-zag motion all over the field of view. This movement is nothing but a Brownian movement. Brownian movement is observed in COLLOIDS due to the unbalanced bombardment of the particles by the molecules of the dispersion medium. As true solutions or suspensions LACK this property and hence Brownian movement is not observed. Explanation: PLEASE mark as the brainliest answer ❤

26.

Why Brownian motion isn't seen in real solution ?

Answer»

ANSWER:

Brownian motion is the continuous random movement of SMALL particles suspended in a fluid, which arise from collisions with the fluid MOLECULES.

When colloidal solutions are viewed under a powerful ultramicroscope, the colloidal particles appear to be in a state of continuous zig-zag motion all over the field of view.

This movement is nothing but a Brownian movement.

Brownian movement is observed in COLLOIDS due to the unbalanced bombardment of the particles by the molecules of the dispersion medium.

As true solutions or suspensions LACK this property and hence Brownian movement is not observed.

Explanation:

PLEASE mark as the brainliest answer ❤

Discussion

27.	If a glass piece is thrown into water give reason for the same
Answer» EXPLANATION: the GLASS will not FLOAT on WATER it SINK

27.

If a glass piece is thrown into water give reason for the same

Answer»

EXPLANATION:

the GLASS will not FLOAT on WATER it SINK

Discussion

28.	According order 7/6, 4/8, 12/16, 20/4
Answer» Answer: It was the liberal, educated middle CLASS who demanded the end of aristocratic privileges and encouraged NATIONAL unity. e. They were inspired by the doctrine and ideas of liberalism and demanded GOVERNMENT based on the CONSENT, and stood for freedom and

28.

According order 7/6, 4/8, 12/16, 20/4

Answer»

Answer:

It was the liberal, educated middle CLASS who demanded the end of aristocratic privileges and encouraged NATIONAL unity. e. They were inspired by the doctrine and ideas of liberalism and demanded GOVERNMENT based on the CONSENT, and stood for freedom and

Discussion

29.	1Q. Activities:a)How will you prove that air occupy space?b)How will you prove that a liquid has a fixed volume but nofixed shape. It takes the shape of container.
Answer» Answer: 1)TAKE a balloon and blow it up (fill it with AIR, that is, don't explode it.) As the air ENTERS the balloon from your lungs, the air (which is a gas) takes up space in the balloon. The balloon EXPANDS because the air inside needs to take up more space. So that is how you can see that air takes up space.

29.

1Q. Activities:a)How will you prove that air occupy space?b)How will you prove that a liquid has a fixed volume but nofixed shape. It takes the shape of container.

Answer»

Answer:

1)TAKE a balloon and blow it up (fill it with AIR, that is, don't explode it.) As the air ENTERS the balloon from your lungs, the air (which is a gas) takes up space in the balloon. The balloon EXPANDS because the air inside needs to take up more space. So that is how you can see that air takes up space.

Discussion

30.	I got vmc jankapuri branch do I join
Answer» Explanation: WHAT SOMEONE SHOULD DO IF SICK Stay home in another room, away from other people, and use a separate bathroom if available. Restrict contact with pets and other ANIMALS, just like you would around other people. Avoid using public TRANSPORTATION, ride-sharing or taxis. Wear a cloth face cover when around other people (e.g., sharing a room or vehicle) and before entering a health care provider’s office. SEE CDC guidelines. Call a health care provider for medical advice. Older adults and people of any age with serious underlying medical conditions should call a health care provider as soon as symptoms start. Clean and disinfect all surfaces daily and high-touch surfaces frequently throughout the day in your sick room and designated bathroom. High-touch surfaces include phones, remote controls, counters, tabletops, doorknobs, bathroom fixtures, toilets, keyboards, tablets and bedside tables. Follow CDC guidance. Wash your hands often with soap and water for at least 20 SECONDS, especially after being in a public place, or after blowing your nose, coughing or sneezing. If soap and water are not readily available, use a hand sanitizer with at least 60% alcohol. Cover your coughs and sneezes. Use a tissue to cover your nose and mouth, and throw used tissues in a lined trash can. If a tissue isn’t available, cough or sneeze into your elbow — not your hands. Wash your hands immediately. Keep track of symptoms, which may appear two to 14 days after exposure. Drinks a lot of fluids to stay hydrated and rest at home. Follow your health care provider’s instructions.

30.

I got vmc jankapuri branch do I join

Answer»

Explanation:

WHAT SOMEONE SHOULD DO IF SICK

Stay home in another room, away from other people, and use a separate bathroom if available. Restrict contact with pets and other ANIMALS, just like you would around other people. Avoid using public TRANSPORTATION, ride-sharing or taxis.

Wear a cloth face cover when around other people (e.g., sharing a room or vehicle) and before entering a health care provider’s office. SEE CDC guidelines.

Call a health care provider for medical advice. Older adults and people of any age with serious underlying medical conditions should call a health care provider as soon as symptoms start.

Clean and disinfect all surfaces daily and high-touch surfaces frequently throughout the day in your sick room and designated bathroom. High-touch surfaces include phones, remote controls, counters, tabletops, doorknobs, bathroom fixtures, toilets, keyboards, tablets and bedside tables. Follow CDC guidance.

Wash your hands often with soap and water for at least 20 SECONDS, especially after being in a public place, or after blowing your nose, coughing or sneezing. If soap and water are not readily available, use a hand sanitizer with at least 60% alcohol.

Cover your coughs and sneezes. Use a tissue to cover your nose and mouth, and throw used tissues in a lined trash can. If a tissue isn’t available, cough or sneeze into your elbow — not your hands. Wash your hands immediately.

Keep track of symptoms, which may appear two to 14 days after exposure. Drinks a lot of fluids to stay hydrated and rest at home. Follow your health care provider’s instructions.

Discussion

31.	When moon comes between sun and earth
Answer» This AUSPICIOUS OCCASION is CALLED SOLAR ECLIPSE....

31.

When moon comes between sun and earth

Answer»

This AUSPICIOUS OCCASION is CALLED

SOLAR ECLIPSE....

Discussion

32.	a bus travels with the speed of 50 km per hour and return with the speed of 40km per hour find the average speed of bus
Answer» AVERAGE SPEED of BUS is 45km/h

Discussion

33.	When an object 10km from a point to b point then it moves back and travel 3 km. find the distance and displacement ,Explain the question by diagram
Answer» Answer: DISTANCE is =13 km and displacement = 7KM

33.

When an object 10km from a point to b point then it moves back and travel 3 km. find the distance and displacement ,Explain the question by diagram

Answer»

Answer:

DISTANCE is =13 km and displacement = 7KM

Discussion

34.	If a body completes 2 rounds of a circular track of radius7meter then find its distance and displacement
Answer» Answer: Distance is 88m, displacement is 0M Explanation: Distance is the total length TRAVELLED......2 ROUND of the circumference.....so, Distance= 2*2πr =88m As the STARTING and final position is same displacement is 0m... HOPE it helped

34.

If a body completes 2 rounds of a circular track of radius7meter then find its distance and displacement

Answer»

Answer:

Distance is 88m, displacement is 0M

Explanation:

Distance is the total length TRAVELLED......2 ROUND of the circumference.....so,

Distance= 2*2πr

=88m

As the STARTING and final position is same displacement is 0m...

HOPE it helped

Discussion

35.	Two lenses have focal length of 20cm and
Answer» ANSWER: hey PLEASE WRITE WHOLE question thank you please MARK me as brainliest

35.

Two lenses have focal length of 20cm and

Answer»

ANSWER:

hey PLEASE WRITE WHOLE question thank you

please MARK me as brainliest

Discussion

36.	25 multiply 10to the power -2
Answer» ANSWER: $25 \times \sqrt{ - 2 = - 50}$ PLEASE MARK it's BRAINLIEST please ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

36.

25 multiply 10to the power -2

Answer»

ANSWER:

$25 \times \sqrt{ - 2 = - 50}$

PLEASE MARK it's BRAINLIEST please

❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

Discussion

37.	suppose you were lost somewhere in middle of jungle and you have only bar magnet . you already know to reach home you go in East direction. how you find direction ? explain
Answer» Answer: Bar magnet ALWAYS POINT towards North - SOUTH direction. So it can be easy to find EAST or West direction. Hope it HELPS you

37.

suppose you were lost somewhere in middle of jungle and you have only bar magnet . you already know to reach home you go in East direction. how you find direction ? explain

Answer»

Answer:

Bar magnet ALWAYS POINT towards North - SOUTH direction. So it can be easy to find EAST or West direction.

Hope it HELPS you

Discussion

38.	Q) Inertia of rest is the property by virtue of which the body is unable to change by itself:(A) the state of rest only(B) the state of uniform linear motion(C) the direction of motion only(D) the steady state of rest
Answer» ANSWER: STATE of REST only Hope it HELPS

38.

Q) Inertia of rest is the property by virtue of which the body is unable to change by itself:(A) the state of rest only(B) the state of uniform linear motion(C) the direction of motion only(D) the steady state of rest

Answer»

ANSWER:

STATE of REST only

Hope it HELPS

Discussion

39.	A sound wave has a frequency of 3 khz and wavelength of 15cm.How much time will take to travel 2km.
Answer» Answer: 4.4445s Explanation: we KNOW that SPEED of a wave =frequency wavelength speed =3000HZ15/100lamda speed=450m/s time TAKEN by the wave to travel 2km=1/450*2000m =4.4445s

39.

A sound wave has a frequency of 3 khz and wavelength of 15cm.How much time will take to travel 2km.

Answer»

Answer:

4.4445s

Explanation:

we KNOW that SPEED of a wave =frequency *wavelength

speed =3000HZ*15/100lamda

speed=450m/s

time TAKEN by the wave to travel 2km=1/450*2000m

=4.4445s

Discussion

40.	Fill up the blanks correctly
Answer» MOLECULES of a SUBSTANCE are always in a STATE of motion and so they possess kinetic ENERGY.

40.

Fill up the blanks correctly

Answer»

MOLECULES of a SUBSTANCE are always in a STATE of motion and so they possess kinetic ENERGY.

Discussion

41.	An object moves along a circular path of 7 m radius and completes its oneround in 10 sec. Calculate the velocity of the object.
Answer» ANSWER: Zero Explanation: As the initial point and final point are same, the displacement is zero. VELOCITY = Displacement / Time Velocity = 0 / 10 Hence, velocity = 0

41.

An object moves along a circular path of 7 m radius and completes its oneround in 10 sec. Calculate the velocity of the object.

Answer»

ANSWER:

Zero

Explanation:

As the initial point and final point are same, the displacement is zero.

VELOCITY = Displacement / Time

Velocity = 0 / 10

Hence, velocity = 0

Discussion

42.	Calculate the moment if a force of 5.0 N is applied to a spanner of 15 cm long.
Answer» FIRST CHANGE CM INTO M ⊥ Distance = 10cm = 10/100 = 1/10 m Force APPLIED on SPANNER 5 N ∴ MOMENT of force = F ×⊥ distance = 5 × 1/10 = 0.5 nm.

42.

Calculate the moment if a force of 5.0 N is applied to a spanner of 15 cm long.

Answer»

FIRST CHANGE CM INTO M

⊥ Distance = 10cm = 10/100 = 1/10 m Force APPLIED on SPANNER 5 N ∴ MOMENT of force = F ×⊥ distance = 5 × 1/10 = 0.5 nm.

Discussion

43.	why potential energy is considered for the entire system, rather than assigning it to any specific particle ?
Answer» Contrary to most introductory and intermediate TEXTBOOKS, a single, non-interacting particle cannot possess potential energy. Potential energy is a PROPERTY of a system of interacting particles and/or fields. A minimum of two entities is required. It is probably more useful to think of potential energy as interaction energy. The CONCEPT of potential energy (or interaction energy) follows nicely from the concept of system. Suppose you have several interacting particles and/or fields (protons in an electric field for example) in your system. Further suppose there are other charged particles outside your system in the surroundings. The system's potential energy is merely a way of accounting for the mutual pairwise interactions within the system. More precisely, the change in the system's potential energy is the opposite of the work done by these internal interactions. See chapter 6 of Matter & Interactions by Chabay and SHERWOOD (Third edition, Wiley, 2011)

43.

why potential energy is considered for the entire system, rather than assigning it to any specific particle ?

Answer»

Contrary to most introductory and intermediate TEXTBOOKS, a single, non-interacting particle cannot possess potential energy. Potential energy is a PROPERTY of a system of interacting particles and/or fields. A minimum of two entities is required. It is probably more useful to think of potential energy as interaction energy.

The CONCEPT of potential energy (or interaction energy) follows nicely from the concept of system. Suppose you have several interacting particles and/or fields (protons in an electric field for example) in your system. Further suppose there are other charged particles outside your system in the surroundings. The system's potential energy is merely a way of accounting for the mutual pairwise interactions within the system. More precisely, the change in the system's potential energy is the opposite of the work done by these internal interactions. See chapter 6 of Matter & Interactions by Chabay and SHERWOOD (Third edition, Wiley, 2011)

Discussion

44.	1. Why are caterpillar tracks used in battle tanks instead of tyres?
Answer» Heavy tanks have broad chains CALLED caterpillar TRACKS which considerably increase area in contact. The tracks help the tanks to distribute its weight more evenly over a larger SURFACE area than WHEELS can.

Discussion

45.	a car takes 20 seconds to stop after applying brakes what distance that that does it travel during this interval during this interval it if brakes produce a retardation of 0.6 m/s2.
Answer» ACCELERATION a = -6 m/s^2 Time t = 2 s Final VELOCITY v = 0 m/s Let initial velocity be U Let distance be s v = u + at So, 0 = u + (-6)(2) So, u = 12 m/s Now, s = ut + (1/2) at^2 So, s = 12(2) + (1/2)(-6)(2^2) So, s = 24 - 12 So, s = 12 m Thus, distance travelled is 12 m

45.

a car takes 20 seconds to stop after applying brakes what distance that that does it travel during this interval during this interval it if brakes produce a retardation of 0.6 m/s2.

Answer»

ACCELERATION a = -6 m/s^2

Time t = 2 s

Final VELOCITY v = 0 m/s

Let initial velocity be U

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m

Discussion

46.	A wire whose resistance is 80Ω is cut into three pieces of equal lengths which are then arranged in parallel. Calculate the resistance of the combination.
Answer» The RESISTANCE of each PIECE of WIRE will be80/3 When they r added in PARALLELS then 3/80+3/80+3/80=1/R R=80/9 R=8.8ohm

46.

A wire whose resistance is 80Ω is cut into three pieces of equal lengths which are then arranged in parallel. Calculate the resistance of the combination.

Answer»

The RESISTANCE of each PIECE of WIRE will be80/3

When they r added in PARALLELS then

3/80+3/80+3/80=1/R

R=80/9

R=8.8ohm

Discussion

47.	Are the distance always positive or negative
Answer» ANSWER: POSITIVE...................................

47.

Are the distance always positive or negative

Answer»

ANSWER:

POSITIVE...................................

Discussion

48.	If a inclined plane is moving with velocity v. then what is velocity of the block placed on it
Answer» Explanation:when inclined PLANE is moving with velocity V then the velocity of block placed is CONSTANT velocity. Hence here the constant velocity means the block on inclined plane EITHER is in a state of rest or in uniform motion. Answer:constant velocity

48.

If a inclined plane is moving with velocity v. then what is velocity of the block placed on it

Answer»

Explanation:when inclined PLANE is moving with velocity V then the velocity of block placed is CONSTANT velocity. Hence here the constant velocity means the block on inclined plane EITHER is in a state of rest or in uniform motion.

Answer:constant velocity

Discussion

49.	A batsman deflect a ball by an angle of 45 without changing its initial speed which is equal to 54km per hour. What is the impulse imparted to the ball mass of the ball is 0.15 kg
Answer» Given, MASS of ball = 0.15 Kg Initial speed of ball =54km/h = 54×5/18 m/s = 15 m/s Let the ball inclined along path AO . By batsman deflecting path of it along OB. Here, ANGLE AOP = angle POB = 45/2 ° We have to REQUIRE break speed of it in components . We see that horizontal component of VELOCITY ( usin22.5°) remains unchange. Vertical component (ucos22.5°) just reversed. Hence, CHANGE in momentum of the ball = m(v-u) = mucos22.5° -(-mucos22.5°) = 2mucos22.5° = 2 × 0.15 × 15×cos22.5 = 4.16 kgm/s Hence, impulse imparted by ball = Change in linear momentum of the ball = 4.16 kgm/s

49.

A batsman deflect a ball by an angle of 45 without changing its initial speed which is equal to 54km per hour. What is the impulse imparted to the ball mass of the ball is 0.15 kg

Answer»

Given,

MASS of ball = 0.15 Kg

Initial speed of ball =54km/h

= 54×5/18 m/s = 15 m/s

Let the ball inclined along path AO . By batsman deflecting path of it along OB.

Here,

ANGLE AOP = angle POB = 45/2 °

We have to REQUIRE break speed of it in components .

We see that horizontal component of VELOCITY ( usin22.5°) remains unchange.

Vertical component (ucos22.5°) just reversed.

Hence,

CHANGE in momentum of the ball = m(v-u)

= mucos22.5° -(-mucos22.5°)

= 2mucos22.5°

= 2 × 0.15 × 15×cos22.5

= 4.16 kgm/s

Hence, impulse imparted by ball = Change in linear momentum of the ball = 4.16 kgm/s

Discussion

50.	a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is
Answer» ANSWER: A stone projected UPWARDS with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3. The maximum HEIGHT reached by it is 36h/5 Explanation: Two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3 v^2=u^2−2gh ⇒(u/3)^2=(u/2)^2−2gh ⇒5u^2/36 =2gh ⇒u^2/2g=36/5h Maximum height reached by the stone hmax=u^2/2g=36/5h

50.

a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is

Answer»

ANSWER:

A stone projected UPWARDS with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance

'h' with velocities u/2 and u/3. The maximum HEIGHT reached by it is 36h/5

Explanation:

Two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3

v^2=u^2−2gh

⇒(u/3)^2=(u/2)^2−2gh

⇒5u^2/36 =2gh

⇒u^2/2g=36/5h

Maximum height reached by the stone

hmax=u^2/2g=36/5h

Discussion

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