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a car takes 20 seconds to stop after applying brakes what distance that that does it travel during this interval during this interval it if brakes produce a retardation of 0.6 m/s2. |
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Answer» ACCELERATION a = -6 m/s^2 Time t = 2 s Final VELOCITY v = 0 m/s Let initial velocity be U Let distance be s v = u + at So, 0 = u + (-6)(2) So, u = 12 m/s Now, s = ut + (1/2) at^2 So, s = 12(2) + (1/2)(-6)(2^2) So, s = 24 - 12 So, s = 12 m Thus, distance travelled is 12 m |
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