1.

a car takes 20 seconds to stop after applying brakes what distance that that does it travel during this interval during this interval it if brakes produce a retardation of 0.6 m/s2.​

Answer»

ACCELERATION a = -6 m/s^2

Time t = 2 s

Final VELOCITY v = 0 m/s

Let initial velocity be U

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m



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