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The take off of boeing 747 is 252km/hr.if it can accelarate at 1.5m/s^2 what should be the minimum length of the runway? |
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Answer» given v=252 KM/hr convert it into m/s so,multiply with 5/18 v=252×5/18 v=70m/s v^2-u^2=2as for any flight INTIAL VELOCITY is zero u=0 70×70=2×3/2×s s=1633.3m s=1.6 km approx |
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