a stone projected up with velocity u reaches 2 points A and B at dista

1.	a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is
Answer» ANSWER: A stone projected UPWARDS with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3. The maximum HEIGHT reached by it is 36h/5 Explanation: Two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3 v^2=u^2−2gh ⇒(u/3)^2=(u/2)^2−2gh ⇒5u^2/36 =2gh ⇒u^2/2g=36/5h Maximum height reached by the stone hmax=u^2/2g=36/5h

a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is

Answer»

ANSWER:

A stone projected UPWARDS with a velocity 'u' reaches two points 'P' and 'Q' separated by a distance

'h' with velocities u/2 and u/3. The maximum HEIGHT reached by it is 36h/5

Explanation:

Two points 'P' and 'Q' separated by a distance 'h' with velocities u/2 and u/3

v^2=u^2−2gh

⇒(u/3)^2=(u/2)^2−2gh

⇒5u^2/36 =2gh

⇒u^2/2g=36/5h

Maximum height reached by the stone

hmax=u^2/2g=36/5h

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a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is​

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a stone projected up with velocity u reaches 2 points A and B at distance h with velocity u/2 and u/3 then the maximum height reached by it is