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HII

ANSWER:-----

1.)NAPTHALENE BALLS DISAPPEARS IN THE AIR AIR COMPLETELY THIS IS BECAUSE IT GOES UNDER THE PROCESS OF THE SUBLIMATION THAT IS DIRECT CONVERSION OF SOLID INTO GASEOUS STATE AND VICE VERSA.

2.)WE CAN GET THE SMELL OF THE PERFUME EVEN IT IS SEVERAL METRES AWAY THIS US BECAUSE THE PARTICLES OF THE PERFUME GETS INTO THE SPACES PRESENT BETWEEN THE AIR AND ALSO THE KINETIC ENERGY OF THE GAS MOLECULES IS HIGH AND THE RATE OF DIFFUSION IS HIGH.




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1/f = 1/v + 1/u this was my INFERENCE

You can't MAKE because it's NATURAL

Because when we go up due to increase in HIGHT our NOSE start bleeding.
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An object's gravitational POTENTIAL energy is directly proportional to the negative of the product of the first two FACTORS mentioned above (the MASSES), and inversely proportional to the THIRD (the distance).


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Explanation:

DIPLACEMENT in NTH SECOND is GIVEN by

Sn= u+1/2a( 2n-1)

s= 0 + 1/2 ×26× (2×6-1)

s= 143m ans

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IIT JEE QUESTIONS:


Question1:

Select the correct stability order of the conformation /Rotamers/ Rotational isomers of ETHANE Molecule

(a) PARTIALLY Eclipsed > Fully Eclipsed > Anti-staggered > Skew or Gouche

(b) Skew or Gouche > Partially Eclipsed > Fully Eclipsed > Anti-staggered

(c) Anti-staggered > Skew or Gouche > Partially Eclipsed > Fully Eclipsed 

(d) Fully Eclipsed > Anti-staggered > Skew or Gouche > Partially Eclipsed

Solution1:

The isomers which can be produced by the free rotation about single bond are known as conformation /Rotamers/ Rotational isomers and this phenomenon is called as conformational analysis

These isomers can be represented by

1. Sawhorse projection

2. Newman’s projection formula

3. A staggered conformer is more stable than an eclipsed conformer as the latter involves unfavourable energy interactions between atoms.

4. In conformational analysis (energetics study of different rotational conformers or rotamers), structures are represented by *Newman projection * (atoms and bonds are viewed along the axis of rotation).

Hence, the correct answer is (c).

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Question2:

As PER IUPAC nomenclature, the name of the complex [Co (H2O)4(NH3 )2]C13 is 

(a) tetraaquadiaminecobalt (III) chloride

(b) tetraaquadiamminecobalt (III) chloride

(c) diaminetetraaquacobalt (III) chloride

(d) diamminetctraaquacobalt (III) chloride

Solution2:

First of all, the compound has complex positive part [Co(H2O)4(NH3)2]3+ therefore, according to IUPAC conventions, positive part will be named first. Secondly, in writing name of complex, ligands are named first in alphabetical order, IRRESPECTIVE of its charge, hence "ammine" will be written prior to "aqua".

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According to question, due to own weight of CYLINDER , it will float 1/4 of its height in liquid of relative DENSITY of 4.

To make it float in neutral equilibrium, CENTRE of gravity and centre of buoyancy must coincide.
e.g., cylinder upto full height must get immersed.

for free floating weight (W) J buoyancy FORCE {e.g., weight of liquid equal to 1/4th volume of cork.}
the vertical DOWNWARD force exerted by anchoring would be weight of liquid equal to 3/4th volume of cork = 3W

hence, answer is 3W

Tyndall effect is scattering of LIGHT by particles in a very fine suspension or COLLOID . It was named after physicit John Tyndall.

This effect is ALSO KNOWN as Willis tyndall scattering.

when we apply torch light on glass of milk then the PATH of light becomes visible but it is not so in case of water because in milk light is scattered by its very fine particles..

APPLICATIONS

● The concept is determining the streng
th of concentrations

● The headlights of vehicles work on tyndall effect

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I THINK prisim it DISPERSE LIGHT

The MATERIAL is CALLED the CONDUCTOR

❤️❤️hey MATE ❤️❤️

The electronic configuration of sodium can be written as 2, 8, 1. 2, 8, 1 electrons are distributed in the shells K, L, M respectively. THEREFORE, valence electron in sodium is 1 and it needs to lose 1 electron from the OUTERMOST orbit to attain octet. Hence, the valency of sodium is 1.

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Answer : (a) (ϕ2−ϕ1)∈0(ϕ2−ϕ1)∈0

Explanation : Net flux through SURFACE = ϕ2−ϕ1ϕ2−ϕ1

Using gauss's law

ϕ2−ϕ1=qenc∈0ϕ2−ϕ1=qenc∈0

qenc=(ϕ2−ϕ1)∈0.

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Here is UR answer

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Let's take a CONCAVE mirror of focal length ,f and a candle in front of concave mirror.
To observe experiment in case of mirror,
use mirror FORMULA, 1/v + 1/u = 1/f
if mirror is concave,
Take , f => negative , u => negative

now, we observe following information from the experiment with concave mirror on measuring distance of object and images.

1. when candle is PLACED so far from concave mirror[ assume candle is placed at infinity ]
then, image is formed at focus ,F of concave mirror which is real and point SIZED.

2. when candle is placed beyond centre of curvature of concave mirror then, image is formed between focus and centre of curvature of concave mirror which is real and small sized.

3. when candle is placed at centre of curvature, C , image is formed at C which is real and same as that of object.

4. when candle is placed between C and F , image is formed behind C which is enlarged, real and inverted.

5. when candle is placed at focus , F of concave mirror, image is formed at infinity which is highly enlarged , real and inverted.

6. when candle is placed between focus and pole of concave mirror, image is formed behind the mirror which is enlarged , virtual and erect

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# Answer- RECOIL speed = 4.36 m/s.

# Explanation-
You'll already know that momentum is given by formula,
mv = H/λ ...(1)

For emission of photon during TRANSITION from n=5 to n=1, wavelength is given by,
1/λ = R(1/n1^2 - 1/n2^2)
1/λ = 1.097×10^7(1/1^2 - 1/5^2)
λ = 9.48 × 10^-8 m

Putting this in eqn (1)
mv = h/λ
1.6×10^-27 × v = 6.62×10^-34 / 9.48×10^-8
v = 4.36 m/s

Recoil speed of HYDROGEN atom is 4.36 m/s.

(standard values of R,h and m TAKEN)

Hope that helped you...

Because AEROPLANE FLY in AIR and SHADOW is not SEEN in air

USE Kepler 3RD LAW for PLANETARY SYSTEM

Hii FRIEND,
I think you have written incomplete question.I have seen this question in DIFFERENT format.

# Complete question would be-
When a light ray enters a medium with refractive index N2 from a medium with refractive index n1 at curved interface with radius of curvature R is GIVEN by n2/v - n1/u = (n2-n1)/R . Now assume that the surface is plane and rewrite the formula with suitable changes .

# Solution-

For plane surface,

Radius of curvature will be infinity.

Putting this in formula for refraction at curved surface,

n2/v - n1/u = (n2-n1)/∞

n2/v - n1/u = 0

n2/v = n1/u

v/u = n2/n1

n2/n1=v/u

Hence solved n2/n1=v/u for plain surface.

Where is the FIGURE??

Copper wires are COVERED with RUBBER because rubber is an insulator of electricity which MEANS that it does not CONDUCT electricity.

This can't be ANSWERED as the QUESTION is not COMPLETE.plz complete the question FIRST

Use the DOT PRODUCT of the two vectors to get the SCALAR product i.e work.

Work done = F.d =2×10+15×10+6k×10=170+60k j

There should be a LIGHTNING CONDUCTOR in a tall BUILDINGS / 2 the all the switches should be off but that should be given on during lightning NUMBER /3 disconnect all the cables during lightning

The net charge of an isolated system REMAINS constant. The only way to change the net charge of a system is to bring in charge from ELSEWHERE, or remove charge from the system.

Charge can be CREATED and DESTROYED, but only in positive-negative PAIRS.

ANSWER:

Using Fleming's left-hand rule, we can determine the direction of force acting on the proton.

...

DIFFERENCE Between Fleming's Left-Hand and Right-Hand Rule.

Left-Hand Rule Right-Hand Rule

The middle finger represents the direction of the CURRENT The middle finger represents the direction of the induced current

A combination of gears USED to reduce the input speed (as of a marine turbine) to a lower output speed (as of a ship's propeller)

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2 option is correct I 40√3

Kmph, 30 EAST of NORTH as cos 30 is √3/2

Hii FRIEND,

You have given incomplete question.

We ALSO need cross SECTIONAL area of wire to calculate maximum load APPLIED.

Let's calculate maximum stress.

# Solution-

Young MODULUS = stress/strain

strain=1/1000

stress=F/A

stress = strain × young modulus

stress = 1/1000 × 2×10^11

stress = 2×10^8 N/sq.m

F = 2×10^8 × A N.

Maximum stress applied can be 2×10^8 N/sq.m.

Maximum load 2×10^8 × A N.

Hope that cleared your problem...

The wavelength of red light is the longest the light of red colour is scattered least by the AIR MOLECULES of the ATMOSPHERE and therefore a light of red colour can penetrate to a longer DISTANCE

Any of several hydrocarbons having eight carbon atoms CONNECTED by single BONDS. It is commonly ADDED to GASOLINE to prevent knocking from uneven burning of fuel in internal-combustion engines.Octane is the eighth member of the alkane series.
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The principle of a potentiometer is that the potential dropped across a segment of a WIRE of uniform cross-section carrying a constant current is directly PROPORTIONAL to its length. ... Between the END of the wire and any point along it will be a potential proportional to the length of wire to that point.