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100g of ice at 0 degrees celsius is mixed with 100 grams of water at 80 degree Celsius the final temperature of the mixture will be |
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Answer» MASS of ice , m = 100g at 0°C mass of water , m = 100g at 80°C here heat flows through water to ice. so, heat LOST by water to reduce its temperature 0°C = mS∆T = 100g × 1cal/g/°C × (80 - 0) = 8000cal heat gained by ice to melt the ice completely = ML = 100g × 80cal/g = 8000cal here you can see that, heat lost by water to reduce temperature to 0°C is equal heat gained by ice to melt the ice completely. hence, FINAL mixture is water at 0°C . so, temperature of mixture will be 0°C. |
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