If the strain in a wire is not more than 1/1000 and y = 2 × 10^11 the

1.	If the strain in a wire is not more than 1/1000 and y = 2 × 10^11 the maximum weight hung from wire is
Answer» Hii FRIEND, You have given incomplete question. We ALSO need cross SECTIONAL area of wire to calculate maximum load APPLIED. Let's calculate maximum stress. # Solution- Young MODULUS = stress/strain strain=1/1000 stress=F/A stress = strain × young modulus stress = 1/1000 × 2×10^11 stress = 2×10^8 N/sq.m F = 2×10^8 × A N. Maximum stress applied can be 2×10^8 N/sq.m. Maximum load 2×10^8 × A N. Hope that cleared your problem...

If the strain in a wire is not more than 1/1000 and y = 2 × 10^11 the maximum weight hung from wire is

Answer»

Hii FRIEND,

You have given incomplete question.

We ALSO need cross SECTIONAL area of wire to calculate maximum load APPLIED.

Let's calculate maximum stress.

# Solution-

Young MODULUS = stress/strain

strain=1/1000

stress=F/A

stress = strain × young modulus

stress = 1/1000 × 2×10^11

stress = 2×10^8 N/sq.m

F = 2×10^8 × A N.

Maximum stress applied can be 2×10^8 N/sq.m.

Maximum load 2×10^8 × A N.

Hope that cleared your problem...

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If the strain in a wire is not more than 1/1000 and y = 2 × 10^11 the maximum weight hung from wire is

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