This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A liquid of specific gravity 0.8 is flowing in a pipe line with a speed of 2m/s.The K. E per cubic meter of it is |
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Answer» K.E=1/2×mv×vm = 0.8v=2m/s then 1/2×0.8×2×2=1.6 |
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| 2. |
The dimensional formula of density is |
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| 3. |
Please solve this..... |
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Answer» Explanation: → At FIRST FIND the height above the ground at which STONE is STOPPED.H1 max = ut + 1/2gt²H1 = 0 + 1/2×9.8× 5×5H1= 122.5mNow ,It is given in question that srone stopped after 3sec(Vertical direction travelled in 3sec)=H2= 0+1/2×9.8×3×3H2= 44.1mRemaning distance= (122.5-44.1)=78.4mNow,78.4 = ut+1/2×9.8×t²78.4=0+4.9t²t= 4secTotal time taken =[4+3]=7sec✓✓Happy to HELP!:) |
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| 4. |
sab k lia ek question h apne man me koi digit socho usme 5 add karo fr 2 add karo fr usme se 4 minus karo or fr jo digit apne socha usko b minus kardo answer 3 h |
| Answer» HAA EKDUM SHI ANSWER H .... | |
| 5. |
Two stones of masses m and 2m are projected vertically upwards so as to reach the same height. the ratio of kinetic energies of their projection is |
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Answer» k.e=1/2 mv^2=1/2Explanation:the RATIO will be1/2 |
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| 6. |
If density of a planet is double that of the earth and the radius 1.5 times that of the earth, theacceleration due to gravity on the surface of theplanet is(1) 3 times that on the surface of the earth(2) 3 times that on the surface of the earth(3) times that on the surface of the earth(4) 6 times that on the surface of the earth |
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| 7. |
3. A car moving towards north at a speed of 10 m/sturns right within 10 s maintaining the same speed.Average acceleration of the car during this timeinterval is (0) |
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Answer» car turns, ACCELERATION is produced.So, initial velocity due north (U)=10 m/sFinal velocity EAST (V)=10 m/sTime interval (t)=10 sFollowing vectors:- √10²+10²=√200=10√2 m/s=change in velocitySo, acceleration (a)=v-u/t=10√2/10=√2 m/sSo, average acceleration is equal to √2 m/s |
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| 8. |
6 A horizontal force of 1-2 kg is applied on a 1.5 kg block, which rests on a horizontal surface. If thecoefficient of friction is 0-3, find the accelerationproduced in the block.[Ans. 4.9 ms -1 |
| Answer» EXPLANATION:Ctygubjfdhhyh | |
| 9. |
The resultant of two vectors is perpendicular to one of them and has the magnitude 4 m. If the sum ofthe magnitude of two vectors is 8 m then theirrespective magnitude are |
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Answer» lify LET SAYA = Xi => Magnitude of Vector A = XThen resultant Vector C = 4j mPerpendicular to one of vector with magnitude 4mVector B = Vector C - Vector A=> B = 4j - XiMagnitude of B = √(4² + X²)sum of the magnitude of TWO VECTORS is 8m=> X + √(4² + X²) = 8=> √(16 + X²) = 8 - XSquaring both sides16 + X² = 64 + X² - 16X=> 16X = 48=> X = 3Vector A = 3i => Magnitude = 3Vector B = -3i + 4j => Magnitude = √(-3)² + 4² = 5Vector C = 4jMagnitude of two vector = 3 & 5Please mark as brainliest answer |
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| 10. |
2. What are the factors that should be taken into consideration for selecting a source of energy? List any three. |
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Answer» ection of a good source of energy depends on the following FACTORS:It should be POLLUTION free.It should be economical.3.It should be EASILY accessible.It should not be difficult to transport energy from there.It should not PRODUCE RADIOACTIVE waste.It should have a high calorific value. |
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| 11. |
What is uniform velocity? |
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Answer» tion:if a body COVERED equal DISTANCE in equal interval of time in a specified DIRECTION it BUDDY shape to moving with uniform velocity |
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| 13. |
What is the range of reflective index of sodium light through the prism? |
| Answer» TION:The amount of BENDING of a ray of light when it changes mediums DEPENDS on the CHANGE in the index ofrefraction between the two mediums. Sodium chloride has an approximate index ofrefraction if 1.54, which is relatively high compared to other solids. | |
| 14. |
Name some non-SI units of force ? |
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| 15. |
The initial position of an object at rest is given by 3i-8j It moves with constant acceleration and reaches to the position 2i + 4j after 4 s. What is its acceleration? |
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Answer» cceleration is constant, so we use the equation for constant accelerationVf = Vi + aT ⁻⁻⁻⁻⁻⁻⁻⁻⁻ (1)Where Vi is the initial velocity Vf the final velocity a is acceleration T is time takenGiven values are Vi = 3I - 8jVf = 2I + 4jT = 4 SECA = ?Putting these values in equation (1), we get(2i + 4j) = (3i - 8j) + a (4)4 a = (2i + 4j) - (3i - 8j)4 a = (2i - 3i) + (4j + 8j)4 a = -i + 12ja = -1/4 i + 3 j This is the REQUIRED acceleration.Hope it helps. |
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| 16. |
What is friction what are it's causes |
| Answer» FRICTION is opposing FORCE in which a BODY moves. It OPPOSES the movement of a body. | |
| 17. |
In a projectile motion , the range of projectile is given by R= u^2sin2x/g. The value of x for which range becomes maximum is A) 0 B) Π/2 C) Π/3 D) Π/4 |
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Answer» tion:differentiating R w.rt x & equating to 0, we getcos2x = 0 2X = (π/2) x = (π/4) for which RANGE will be MAXIMUM |
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| 18. |
Physical polce mp bane ke liye kya karen |
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Answer» l REQUIREMENTS for Police inspector‘पुलिस बनने के लिए महिलाओ (Female) और पुरुष (Male) दोनों के लिए अलग अलग फिजिकल रिकुवार्मेंट होती है पुलिस में भर्ती होने के लिए इसके साथ ही पुलिस में आरक्षित श्रेणी के लिए भी अलग अलग फिजिकल रिकुवार्मेंटइ आइये जान लेते हैसामान्य वर्ग के लिए फिजिकल रिकुवार्मेंट :पुलिस में भारती के लिए पुरुष की छाती कम से कम 83cm होनी चाहिए बिना फुलाए और फुलाने के बाद छाती कम से कम 87cm तक होना चाहिएपुलिस में भारती के लिए पुरुष का कद कम से कम 165cm होना चाहिएमहिलाओ यानि फीमेल(Female) की लम्बाई यानि हाइट (HEIGHT) 150cm तक होनी चाहिएपुरुष वर्ग को 5KM दोड़ यानि रनिंग करना होगा जिसके आपको 25mint में पूरा करना होगा ये फिजिकल टेस्ट होता है जो पुलिस (Police) बन्ने के लिए आपको क्लियर करना होगामहिलाओ को 2.5km की दोड़ पूरी करनी होगी 15मिनट के अन्दरआरक्षित श्रेणी के लिए फिजिकल रिकुवार्मेंट :आरक्षित श्रेणी के पपुरुष के लिए छाती 81CM होना चाहिए बिना फुलाए और फूलने के बाद छाती (Chest) का साइज़ 85CM तक होना चाहिएआरक्षित वर्ग में पुरुष के लिए हाइट की लम्बाई कम से कम 160cm होना चाहिएमहिलाओ के लम्बाई 145cm होनी चाहिए |
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| 19. |
Explain this questions answer A body is thrown vertically upward reaches back the ground after 6 sTake g - 10 m/s.The maximum height reach by the body is a) 45 mb) 22.5 mc) 20 md) None of theseanswer is option A .give detail explaination |
| Answer» WER is ATTACHED | |
| 20. |
Write about one para sound is produced by a vibrating body |
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Answer» tion:Sound is produced when SOMETHING vibrates. The vibrating body causes the medium (water, air, etc.) around it to vibrate. Vibrations in air are called traveling longitudinal WAVES, which we can HEAR. Sound waves consist of AREAS of high and low pressure called COMPRESSIONS and rarefactions, respectively. |
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| 21. |
Help in question plz plz |
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Answer» 8volts resistance=sum of all the ENERGIES. 2+2+4=8 |
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| 22. |
Solve my question plz..... |
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Answer» ⓡ radius of ELECTRONS Orbit / radius of nucleus .= 10^-10/10^-15= 10^5 then ,radius of Earth's Orbit = 10^5 radius of earth = 10^5 × 7 × 10^8 = 7× 10 ^-13 m ✍️ an atom has GREATER empty space than that of our solar system. ❤.❤ |
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| 23. |
What is electro magnetic prolusion |
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Answer» magnetic PROPULSION (EMP), is the principle of accelerating an object by the utilization of a flowing electrical current and magnetic FIELDS. The electrical current is USED to either create an OPPOSING magnetic field, or to charge a field, which can then be repelled. |
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| 24. |
Plzzz guys answer me |
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Answer» bject is my FAVOURITE SUBJECT but this is very DIFFICULT so I don't ANSWER this QUESTION |
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| 25. |
About sounds produced by the humans in 1para |
| Answer» INFRASOUND and I don't KNOW the EXPLANATION | |
| 26. |
What is meant by source of energy class 10 |
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Answer» RESOURCES something such as oil, COAL, or the sun, which can be used to provide power for light, HEAT, machines, ETC.: alternative/renewable energy source We are committed to the DEVELOPMENT of clean and renewable energy sources. |
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| 27. |
Please help meclass 10 physicsno irrelevant answers please |
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Answer» tion:By increasing the STRENGTH of currentBy increasing the NUMBER of coils.Hope it helpsMark Brainliest and FOLLOW me |
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| 28. |
how can we say that burning of candle chemical changes but the glowing of bulb is a physical changes |
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Answer» owing of bulb is a physical change.When an electric CURRENT is PASSED through the filament of a bulb, the filament starts glowing and the glow stops as soon as the current is cut off. The chemical composition of the tungsten filament does not change on application of current.Burning of candle is both a physical change as well as a chemical change. Candle is MADE up of a solid block of wax with a wick embedded in it.1) Physical ChangeWhen candle is lit, the heat of the flame melts the solid wax to liquid wax. This signifies a physical change from solid state to liquid state.2) Chemical ChangeThe wax acts as a fuel when we light the candle and is basically a chemical substance called carbon. The carbon combines with oxygen to form ANOTHER chemical substance called carbon dioxide. Also the unburnt carbon is deposited as BLACK substance called soot. This signifies a chemical change. |
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| 29. |
Which option from capital letters is correct?? |
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Answer» Hey MATE COMPLETE your question FIRST properly.....where are the options....???hope u understand..... |
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| 30. |
A swimmer is able to swim in a forward direction in a swimming pool only when he is pushing the water in the backward direction.give reasons |
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| 31. |
a 4 kg block A is placed at the top of 8 kg block B which rests on a smooth surface.A just slips on B when a force of 20N is applied on A. The maximum horizontal force F required to make both A and B move together |
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| 32. |
1. If the size of the atom were enlarged to the tip of the sharp pin, how large would the height of the Mount Everest be? |
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Answer» size of the atom were ENLARGED to the tip of the sharp PIN, how large WOULD the height of the Mount EVEREST be ---- ${{10}^{10}}$m |
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| 33. |
When a empty lift is moving down with acceleration of G by 4 metre per second square the tension of the cable is 9000 Newtons when the lift is moving up with an acceleration of G by 3 metre per second square the tension of the cable is?? |
| Answer» HOPE U UNDERSTAND | |
| 34. |
a target is placed symmetrically between 2 guns which are fired simultaneously the muzzle velocity of each gun is 100 m/s and both of them are 500 m away from the target they are fired simultaneously find the difference in the time at which the shells strike the target |
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Answer» e bullet strikes, its HIGH velocity and small frontal cross-section means that it will exert large stresses in any object it hits. This usually results in it penetrating any soft object, such as flesh. The ENERGY is then DISSIPATED in the wound track FORMED by the passage of the bullet. See terminal ballistics for a fuller discussion of these effects.due to the transfer of energy the target BECOMES hotIf this helps so pls mark my answer as brainliest and thank it ........ |
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| 35. |
when two resistors are connected in sereies are connected in series, their effective resistance is 80 Ohm. When they are connected in parallel, their effective resistance is 20 Ohm. What are the values of the two resistances? |
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Answer» and R2 be the two resistances. When they are in PARALLEL, resultant RESISTANCE Rp is given by1/Rp = 1/R1 + 1/R2Rp = R1R2/(R1 + R2)2 = R1R2/(R1 + R2)2(R1 + R2) = R1R2When they are in series effective resistance Rs = R1 + R29 = R1 + R2 ⇒ R2 = 9 - R12 x 9 = R1 R2 = R1 (9 - R1) = 9R1 - R12.18 = 9R1 - R12.R12 - 9R1 + 18 = 0Solve this quadratic equation. You will get R1 = (9 ± √(81 - 4 x 1 x 18))/2 = (9 ± √9)/2 = (9 ± 3)/2R1 = 3 ohm or 6 ohmIf R1 = 3 ohm, R2 = 6 ohm and vice versa. |
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| 36. |
Sulphur is a gas or not |
| Answer» HUR is not a gas.............it is a SOLID............... HELIUM, oxygen, carbon, etc. are GASES | |
| 37. |
Derive the expression for the electric field E at any point inside a spherically symmetric uniform charged distribution applying gauss law |
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Answer» this is the ANSWER of above question.mark as BRAINLIESTS answer.... |
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| 38. |
a body covers first one third of the distance with a velocity of 20m/s, the second one third with a speed of 30m/s and the last one third with a velocity of 40m/s. the average velocity is nearly |
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| 39. |
Derive 3 equations of motion |
| Answer» EXPLANATION:MARK it BRAINLIEST if it HELPS you | |
| 40. |
What method would you suggest to overcome this problem |
| Answer» HEY MATE.........EXPLANATION:for which PROBLEM you are TALKING about? | |
| 41. |
if y=mx+c represents first equation of motion write the unit of the physical quantities represent by y and m |
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Answer» Y is FINAL velocitym is ACCELERATION EXPLANATION:v=u +at |
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| 42. |
Differencebetween mass and weight |
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Answer» tion:There is a basic difference, because MASS is the ACTUAL AMOUNT of material contained in a body and is measured in kg, gm, ETC. Whereas weight is the force exerted by the gravity on that object mg. NOTE that mass is independent of everything but weight is different on the earth, moon, etc... |
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| 43. |
A body covers a distance of 20m in the 7th second and 24m in the 9th second .How much shall it cover in 15th second? |
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Answer» tion:DISTANCE COVERED in 7th second = 20mdistance covered in 9TH second = 24m9-7= 2distance covered in 2 SEC = 4mdistance covered in 15 sec = 36 m |
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| 44. |
Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floorat a constant velocity. What is the frictionforce that will be exerted on the cabinet? |
| Answer» FRICTIONAL FORCE EXERTED on the CABINET can be 200N or less than 200N | |
| 45. |
a car travels a speed of 120 kilometres per hour for 1 hour and highlights for 1/2 hours and then resumes the journey with a speed of 100 kilometres per hour for the next one and half hour find the average speed |
| Answer» DISTANCE = TIME * speedd1 = 120 km d2 = 100 *1.5 = 150 kmAverage speed = TOTAL distance/ total time=270/2.5=108km/h =108 x 5/18 = 30 m/s | |
| 46. |
Umerical Problems The vertical component of a force is 2004The force make an angle of 30° willhorizontal. Find the applied force.[Ans.(400N |
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Answer» 2004-2000=4*30=400N |
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| 47. |
A solution containing 8.6 g L of urea is isotonic with a 5% (W/V) solution of unknown solute. Themolar mass of the solute will be(1) 348.9 g mol! (2) 174.5 g mol(3) 87.3 g moll (4) 34.89 g mol- |
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Answer» (1) 348.9gmol!Explanation:85×5%= |
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| 48. |
Solve this easy qt pzzzzzzzz |
| Answer» ANSWER is 3 MASS, time, VELOCITY I HOPE this answer HELP you | |
| 49. |
Write down the number of significant figures in the following: 0.003 m²,0.1250 gm cm2, 6.4 x 106 m, 1.6 x 10-19C, 9.1 x 10-31 kg.[Ans: 1, 4, 2, 2,2] |
| Answer» 3, 4, 2, 2Explanation:Zero before the decimal point is not a significant figure.Same for the second one. Zero after the decimal point is a significant figure.For counting significant FIGURES of the LAST two, you will neglect the power term and only COUNT the significant figures of the preceding decimal number. | |
| 50. |
The filtration method can't be used to separate sugar and salt mixed in water why |
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Answer» because it is HOMOGENEOUS MIXTURE |
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