3. A car moving towards north at a speed of 10 m/sturns right within 10 s maintaining the same speed.Average acceleration of the car during this timeinterval is (0)

3. A car moving towards north at a speed of 10 m/sturns right within

1.	3. A car moving towards north at a speed of 10 m/sturns right within 10 s maintaining the same speed.Average acceleration of the car during this timeinterval is (0)
Answer» car turns, ACCELERATION is produced.So, initial velocity due north (U)=10 m/sFinal velocity EAST (V)=10 m/sTime interval (t)=10 sFollowing vectors:- √10²+10²=√200=10√2 m/s=change in velocitySo, acceleration (a)=v-u/t=10√2/10=√2 m/sSo, average acceleration is equal to √2 m/s

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3. A car moving towards north at a speed of 10 m/sturns right within 10 s maintaining the same speed.Average acceleration of the car during this timeinterval is (0)​

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3. A car moving towards north at a speed of 10 m/sturns right within 10 s maintaining the same speed.Average acceleration of the car during this timeinterval is (0)