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The initial position of an object at rest is given by 3i-8j It moves with constant acceleration and reaches to the position 2i + 4j after 4 s. What is its acceleration? |
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Answer» cceleration is constant, so we use the equation for constant accelerationVf = Vi + aT ⁻⁻⁻⁻⁻⁻⁻⁻⁻ (1)Where Vi is the initial velocity Vf the final velocity a is acceleration T is time takenGiven values are Vi = 3I - 8jVf = 2I + 4jT = 4 SECA = ?Putting these values in equation (1), we get(2i + 4j) = (3i - 8j) + a (4)4 a = (2i + 4j) - (3i - 8j)4 a = (2i - 3i) + (4j + 8j)4 a = -i + 12ja = -1/4 i + 3 j This is the REQUIRED acceleration.Hope it helps. |
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