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The resultant of two vectors is perpendicular to one of them and has the magnitude 4 m. If the sum ofthe magnitude of two vectors is 8 m then theirrespective magnitude are |
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Answer» lify LET SAYA = Xi => Magnitude of Vector A = XThen resultant Vector C = 4j mPerpendicular to one of vector with magnitude 4mVector B = Vector C - Vector A=> B = 4j - XiMagnitude of B = √(4² + X²)sum of the magnitude of TWO VECTORS is 8m=> X + √(4² + X²) = 8=> √(16 + X²) = 8 - XSquaring both sides16 + X² = 64 + X² - 16X=> 16X = 48=> X = 3Vector A = 3i => Magnitude = 3Vector B = -3i + 4j => Magnitude = √(-3)² + 4² = 5Vector C = 4jMagnitude of two vector = 3 & 5Please mark as brainliest answer |
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