Explore topic-wise InterviewSolutions in Current Affairs.

of BODY after TIME 0.5t is 12M

the ANSWER is OPTION a 7j

activity involving mental or physical effort DONE in order to ACHIEVE a purpose or result.

this is the ANSWER, G / 3 up the PLANE

tion:No, the ACCELERATION due to GRAVITY on the surface of earth is not constant .It VARIES from PLACE to place

A planet has a mass of 6×10^24 kgs.It has a DIAMETER of 12.8 ×10^3 KM or 12.8 ×10^6m.So according to the problem we have to find out the acceleration due to gravity of that planet.Now, we KNOW that gravitational value is CONSTANT, so it is 6.7×10^-11 Nm^2/Kg^2.The formula to find acceleration due to gravity is :g= G × (M/R^2) Where g is the acceleration due to gravity, G is the gravitational constant M is the mass and R is the radius.To find radius, we have to divide the diameter with 2. So R will be (12.8×10^6/2)m = 6.4 × 10^6 m.So,g= 6.7× 10^-11 × [6×10^24/(6.4 × 10^6)^2] = 6.7 × 60/ 6.4× 6.4 = 9.8m/s^2The planet is Earth as its acceleration due to gravity is 9.8m/s^2.

the maximum MEANS more and minimum means LESS some maximum power is more SAFETY 13 and minimum is 3 thank you

udent,◆ Kepler's Laws of planetary motion-Kepler DESCRIBED 3 different laws of planetary motion-(1) Kepler’s Law of Orbits –The Planets move around the sun in ELLIPTICAL orbits with the sun at one focus.(2) Kepler’s Law of Areas –The line joining a planet to the Sun sweeps out equal areas in equal interval of time.(3) Kepler’s Law of PERIODS –The square of the time period of the planet is directly proportional to the CUBE of the semimajor axis of its orbit.Hope this HELPS you...

TVExplanation:CONVERT time into seconds1*3600=3600 seconds250/3600Energy =POWER(W)*time(s)energy=250*3600energy of tv=900,000Jenergy of toaster=power(w)*time(s)enefy of toaster=1200*(10*60)energy of toaster=720,000Whence the tv uses more energy

(a): The circuit diagram has been shown.(b): The current drawn from the ELECTRIC supply = 0.45 A.(c): The total energy consumed by the two lamps = .EXPLANATION:Given:Power RATING of first lamp, = .Power rating of SECOND lamp, = .Voltage supply, = . Assumptions: = current passing through first and second lamps respectively. = current drawn from the electric supply.Part (a):The circuit diagram has been attached below.Part (b):The power consumed by an electrical element is given asTherefore,Using Kirchoff's current law, Part (c):The total power consumed by the two lamps is given byThe power consumed by the lamps is the amount of total electrical energy consumed by the lamps PER unit time.Therefore,For ,

Given u = 0 m/sg = 10 m/s^2h = 20 mNow USING s = ut + 1/2 at^2that is H = ut + 1/2 gt^2Now substitute the value 20 = 0*t + 1/2 * 10 (t)^220 = 5(t)^2(t)^2 = 4t = 2sNow again using V = u + ATV = 0 + 10 * 2 V =20 m/sPlease MARK as brainliest

the moon weight is 300000 more than CRORE and the weight of object is 3000 only compared to Moon and object is different weights and the EARTH weight is more than moon because Earth control total world and surroundings environment so the REASON of earth and moon or object is different Earth is first number of weight the SECOND number of weight is Moon and third number of weight is object

Here's your ANSWEREXPLANATION:u=0 m/sg=9.8m/st=2.5 SECH=?S =ut+1/2 g2S =0 ×2.5×1/2×9.8×2.5×2.5S =0×4.9×2.5×2.5S = 30.625Hope it helps.Have a NICE DAY...

P = 400 w.EXPLANATION:The water from the hose pipe comes out at the SPEED, v = 2 m/sMass per unit length of the pipe = 100 KG/mSo, amount of water that comes out per second = 100 × 2 = 200 kg (SINCE, the water covers 2 m per second and there is 100 kg water per meter).Therefore, Kinetic energy of the water coming out per second is KE = ½ × 200 × 2² = 400 JThis is also the work DONE by the pump per second. So, the power of the pump is, P = 400/1 = 400 W______________________________________________[ANSWER]

tion:t3-6t2+4=3t2-12t (here 4 is CONSTANT so it become 0=9t-12 ( now 12 ALSO become 0 )= 9 ANS.

as there is a short circuit connection between the starting TERMINAL of 2 ohm and ENDING terminal of 6hm so .CURRENT will only flow through the resistance 3ohmi.e., the resultant resistance is 3 ohmstherefore... current through it ....

malatha:)Principles of Electronics is a 2002 book by Colin Simpson designed to accompany the Electronics Technician distance education program and contains a concise and practical overview of the basic principles, including theorems, circuit behavior and problem-solving procedures of Electronic circuits and devices. The textbook REINFORCES concepts with practical "real-world" applications as well as the mathematical solution, allowing readers to more easily relate the academic to the actual.Principles of Electronics presents a broad spectrum of topics, such as atomic structure, Kirchhoff's LAWS, energy, power, introductory circuit analysis techniques, Thevenin's theorem, the maximum power transfer theorem, ELECTRIC circuit analysis, magnetism, resonance, control relays, relay logic, semiconductor diodes, electron current flow, and much more. Smoothly INTEGRATES the flow of material in a nonmathematical format without sacrificing depth of coverage or accuracy to help readers grasp more complex concepts and gain a more thorough understanding of the principles of electronics. Includes many practical applications, problems and examples emphasizing troubleshooting, design, and safety to provide a solid foundation in the field of electronics.Assuming that readers have a basic understanding of algebra and trigonometry, the book provides a thorough treatment of the basic principles, theorems, circuit behavior and problem-solving procedures in modern electronics applications. In one volume, this carefully developed text takes students from basic electricity through dc/ac circuits, semiconductors, operational amplifiers, and digital circuits. The book contains relevant, up-to-date information, giving students the knowledge and problem-solving skills needed to successfully obtain employment in the electronics field.Combining hundreds of examples and practice exercises with more than 1,000 illustrations and photographs ENHANCES Simpson's delivery of this comprehensive approach to the study of electronics principles. Accompanied by one of the discipline's most extensive ancillary multimedia support packages including hundreds of electronics circuit simulation lab projects using CircuitLogix simulation software, Principles of Electronics is a useful resource for electronics education.In addition, it includes features such as:Learning objectives that specify the chapter's goals.Section reviews with answers at the end of each chapter.A comprehensive glossary.Hundreds of examples and end-of-chapter problems that illustrate fundamental concepts.Detailed chapter summaries.Practical Applications section which opens each chapter, presenting real-world problems and solutions.Keep smiling!!!

Explanation:RESISTIVITY : It is defined as the amount of resistance offered by any substance. Its S.I unit is ohm metre.Ohm's law : It states that the potential difference APPLIED across the ends of the CONDUCTOR is DIRECTLY proportional to the current flowing through it           V= IRElectric power : It is rate per unit time with which electricity is transfered in a circuit.

A black HOLE is a REGION of spacetime EXHIBITING gravitational acceleration so strong that nothing—no particles or even electromagnetic radiation such as light—can escape from it. The theory of general relativity predicts that a sufficiently compact MASS can deform spacetime to form a black hole.If you find this answer helpful, PLEASE mark it as brainliest.....Follow Me✓✓

when we USE all appliances in ONE socket.Do not use all appliances in one socket.Due to overloading and MAY be due to DEFECT in appliance.HOPED U LIKE THE ANSWER

1) we USE this to calculate the force or pull of gravity of the planets of the earth and earth included 2) this low also COME in HANDLY when when CALCULATING the trajectory of astronomical BODIES .

1471.5 NExplanation:Given, Now, the given MASS of BODY LYING on the surface , m= 150 kgSo, the FORCE acting on the body is given by, F= m.g                                                                              = 150 x 9.81 N                                                                              = 1471.5 NSo, the force of gravity on a body of mass 150 kg lying on the surface of the EARTH will be 1471.5 N.

4.02×10^-9 NExplanation:TWO OBJECTS say m1 and m2 have masses of 50KG and 120kg respectively.The formula of gravitational force of two objects having DIFFERENT masses m1 and m2 are:F= (G×m1×m2)/r2r is the distance between two objects of masses m1 and m2 respectively.G is the gravitational CONSTANT universally where its value is 6.67×10^-11 N m^2/ kg^2Therefore the force of attraction between two objects having different masses m1 and m2 can be deducted by the above stated formula.F=[ (6.67× 10^-11)×50×120]/10^2 = 4.02× 10^-9 NHence the force of attraction between these two objects are 4.02×10^-9 N.

This indicates that if it is used with a 12 V supply it will expenditure 36 JUL energy/second.

killowatt - HOUR is the COMMERCIAL UNIT of ELECTRIC energyExplanation:

dear•♫•.R1/ R2 = (A1/A2) ^1/3 R = RO A^1/3 = (1/27)^1/3= (1/3^3)^1/3= 1/3

2 nd wala ANSWER HAI bhai or mere ko brainly BANA dena

plzzz GIVE me BRAINLIEST ANS and PLZZZZ follow me

I ain't sure REGARDING the exact temperature but CAMPHOR can EASILY undergo sublimation at normal room temperature ( for me around 20 DEG C). SUBSTANCES which have relatively high vapour pressure readily undergo sublimation.

option aExplanation: because when we turn on LIGHT BATTER of light GIVE ENERGY to it

the third KEPLER law of planetary motion LED newton to establish the inverse SQUARE RULE for gravitational force between two bodies

0.1 m/sExplanation:Mass of the MAN = m1 = 80kg (GIVEN) Mass of bullet = m2 = 20 g = 0.02kg (Given) LET speed of the man be = v1 Speed of the bullet = v2 = 400 m/s (Given) Therefore, ACCORDING to the law of conservation of momentum -m1v1 = m2v2= 80 × v1 = 0.02 × 400v1 = 400 × 0.02/ 80 v1 = 0.1 Therefore, the velocity of the man is 0.1 m/s.

kerples low 0F periods state that the cube of thr mean distance of a planet from the sun is directly proprotional to the squer of time it TAKES to move AROUND the sun.

0kg                  m2= 500 kg u1= 10 m/s                      u2= xv1= 0 m/s                        V2= 0 m/sm1u1 +m2u2 = M1V1 +m2v22000*10 + 500*x = 2000 *0 +500 *020000 + 500x = 0 +0500x = -20000x = -20000/500x = 40 m/sans --  u2= 40 m/s

the ANSWER of your Q. is 0.5 ms^-1.

By using formula v^2=u^2+2aswe can find the answer.here, v=0, s=h, a=g..: u^2+2gh=0.: u^2=-2gh.: h=u^2/g.Don't GET CONFUSED with -ve sign. it indicates DECELERATION.

e RADIUS of nth orbit of hydrogen atom is given by , RN = r ' n^2 ,where,r ' = 5.3 × 10^-11 mfor second excited STATE ,n = 3 r3 = 5.3 × 10 ^-11 × 9 = 4.77 × 10 ^ -10 m

Let the mass of the bodys are MSO the kinetic ENERGY of the 1st BODY is KE1=(1/2)mv^2The kinetic energy of the 2nd body is KE2=(1/2)m(3v)^2 =(9/2)mv^2So the ratio of kinetic energy isKE1:KE2=(1/2):(9/2)=1:9