1.

A particle is moving with velocity v = t3 - 6t2 + 4, where v is in m/s andt is in seconds. At what time will the velocity bemaximum/minimum and what is it equal to?​

Answer»

tion:t3-6t2+4=3t2-12t (here 4 is CONSTANT so it become 0=9t-12 ( now 12 ALSO become 0 )= 9 ANS.



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