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two bodies of equal mass moves with uniform velocity of V and 3V respectively find the ratio of their Kinetic energies |
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Answer» Let the mass of the bodys are MSO the kinetic ENERGY of the 1st BODY is KE1=(1/2)mv^2The kinetic energy of the 2nd body is KE2=(1/2)m(3v)^2 =(9/2)mv^2So the ratio of kinetic energy isKE1:KE2=(1/2):(9/2)=1:9 |
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