a ball is thrown up with some velocity after time t second it is at height h from ground which is given by h=at-1/2bt^2 the dh/dt is zero at t equal to

a ball is thrown up with some velocity after time t second it is at he

1.	a ball is thrown up with some velocity after time t second it is at height h from ground which is given by h=at-1/2bt^2 the dh/dt is zero at t equal to
Answer» EXPLANATION: dh/DT=0d(at-1/2bt^2) /dt = 0 After DIFFERENTIATION a-bt =0 bt=a t=a/b

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a ball is thrown up with some velocity after time t second it is at height h from ground which is given by h=at-1/2bt^2 the dh/dt is zero at t equal to​

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a ball is thrown up with some velocity after time t second it is at height h from ground which is given by h=at-1/2bt^2 the dh/dt is zero at t equal to