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◆ Answer -LAW of dimensional homogeneityExplanation:Hey Dear,● Explaination -PRINCIPLE of dimensional homogeneity STATES that all the terms in a equation MUST be having same DIMENSIONS for the equation to be valid.As dimensions of velocity [L1T-1] are different than that of temperature [K], these two terms can't be added together.Hope that helps you...

then the first train is moving with more speed than the otherExplanation:if the length of the trains is TAKEN as x,the speeds are given by;train₁=x/10train₂=x/15train₁ : train₂= 3x /30: 2x/30x/30 is cancelled on both sidestrain₁ : train₂= 3:2hope it helped and PLS mark as BRAINLIEST:)

two plane mirrors are inclined to each other such that a Ray of light incident on FIRST mirror at Bala to SECOND selected from second second mirror parallel to first minute the ANGLE between them is 2 then the light come into is incident then it back normally to the incident that the normal of incident is EQUAL to normal optiplex and then the zero degree angle is take place

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:We can find the thickness of a one rupee coin by using a SCREW gauge. It can be done in following steps:i) Determine the pitch, the least count and the zero error of the screw gauge.ii) Place the coin between the two studs.iii) Rotate the head until the coin is HELD firmly but not tightly, with the help of the ratchat .iv) Note the reading of the pitch scale crossed by the head scale (PSR) and the head scale division that COINCIDES with the pitch scale AXIS (HSC).Explanation:

Derive the expression for the HEAT produced DUE to a current 'I' flowing for a TIME interval 't' through a resistor 'R' having a potential difference 'V' across its ends. ... So some external energy is required to make the current flow. This energy is provided by the battery.

The law of conservation of momentum states that for two objects COLLIDING in an isolated system, the TOTAL momentum before and after the collision is equal. This is because the momentum LOST by one object is equal to the momentum gained by the other. Conservation of momentum is derived from Newton's LAWS of motion.

Note that the unit vectors in spherical coordinates change with position. For example, for an air parcel at the equator, the meridional unit vector, j→, is parallel to the Earth’s rotation axis, whereas for an air parcel near one of the poles, j→ is nearly perpendicular to the Earth’s rotation axis. In spherical coordinates, the velocity vector and its components are given by: U→=ui→+vj→+wk→u=rcosϕDλDt,      V=rDϕDt,      w=DzDt [10.17] where u, v, and w are the EASTWARD, northward, and upward components of the velocity, respectively. These velocities are derived from the changes in eastward, northward, and upward distances, which are given by: dx=rcosϕdλ=change in eastward distance≅acosϕdλdy=rdϕ=change in northward distance≅adϕdz=dr=change in upward distance Let’s now write the averaged momentum conservation equation [10.16] in component form in spherical coordinates. We will just show you how this conversion is done without actually taking you through all the steps. Note that we need to take the total derivatives of the unit vectors as well as the velocities: DU→Dt=DDt(i→u+j→v+k→w)=i→DuDt+uDi→Dt+j→DvDt+vDj→Dt+k→DwDt+wDk→Dt [10.18] The terms containing derivatives of the unit vectors are called “metric terms.” They depend on the Earth being a sphere. In Cartesian coordinates, they equal zero. Consider just one of these metric terms: Dj→Dt=∂j→∂t+u∂j→∂x+v∂j→∂y+w∂j→∂z=0+u∂j→∂x+v∂j→∂y+0 Since for any location, j→ is constant with time and j→ does not change as a function of altitude, that leaves j→ dependent only on latitude and longitude. Look at ∂j→∂y FIRST. Set y = 0 at the equator, and y = a (Earth’s radius) near the pole. As noted above, at the equator, j→ is parallel to Earth’s rotation axis, but near the pole, it is almost perpendicular to it. Thus the change in j→ GOING from south to north (increasing y) must be pointing down to Earth’s center and so j→ changes by −k→ times a small angular change while y changes by a times the same small angular change. The net result is that: ∂j→∂y=−k→a Using the same approach, we can show that: ∂j→∂x=−tanϕ ai→ The total derivatives of all three unit vectors are: Di→Dt=uacosϕ(j→sinϕ−k→cosϕ)Dj→Dt=−utanϕai→−vak→Dk→Dt=uai→+vaj→ [10.19] Putting this all together: DU→Dt=(DuDt−uvtanϕa+uwa)i→+   (DvDt+u2tanϕa+uwa)j→+   (DwDt−u2+v2a)k→ [10.20] Similar analysis can be done for the other terms in the averaged momentum equation. Coriolis force: −2Ω→×U→=2Ω(vsinϕ−wcosϕ)i→−(2Ωusinϕ)j→+(2Ωucosϕ)k→ [10.21] Gravity: g→=−gk→ [10.22] Pressure Gradient Force (PGF): −1ρ∇→p=−1ρ∂p∂xi→−1ρ∂p∂yj→−1ρ∂p∂zk→ [10.23] Turbulent friction (in the boundary layer only): −Cdh∣∣∣V→∣∣∣V→=−Cdh∣∣∣V→∣∣∣ui→−Cdh∣∣∣V→∣∣∣vj→ [10.24] Adding together all of the forces, the averaged momentum equations in spherical coordinates in the zonal, meridional, and vertical directions are, respectively: DuDt−uvtanϕa+uwa=−1ρ∂p∂x+2Ωv sinϕ−2Ωw cosϕ−Cdh∣∣∣V→∣∣∣uDvDt−u2tanϕa+vwa=−1ρ∂p∂y−2Ωu sinϕ−Cdh∣∣∣V→∣∣∣vDwDt−u2+v2a=−1ρ∂p∂z−g+2Ωu cosϕ

Expression for SINGLE Tone AMPLITUDE Modulated WAVE and draw its frequency spectrum . Single Tone Amplitude MODULATION (AM) DEFINITION .

Thus the angular velocity of the appendages relative to the Space STATION is approximately opposite to the orbital rate. TWO methods are GIVEN for the derivation of the rotational equations of motion. The first method uses D'Alembert's PRINCIPLE whereas the second method is based on the angular MOMENTUM con- cept.

n a conducting solid, an electron will suffer collisions with fixed heavy ions. After collisions, electron will emerge with same speed, but direction CHANGES randomly. If we consider N number of electrons in a given volume, since directons are changed randomly due to collisions, average velocity of N electrons will be zero. This is expressed as begin mathsize 12px style 1 over N sum from i equals 1 to N of v subscript i space equals space 0 end style.................(1) If electrons are accelerated by electric field E, then acceleration is given by, a = -eE/m ..........(2)  Let us consider an ith electron in a group of N electrons at a given time t. Let us assume after a previous collision, speed of this ith electron is vi and there is an elapsed time ti after collision.    Speed Vi of this ith electron at time t is given by,   Vi = vi - (eE/m)ti ...............(3)  Average velocity of electrons at time t is average of all Vi of each electron in the group we have considered. In eqn.(3), average of vi appearing on left side is zero as mentioned in eqn.(1). Collisions of elecrons do not occur at regular INTERVALS but at random time. Let us denote the average time between successive collisions as τ.  Then averaging eqn.(3) over N electrons at any given time t gives us average velocity vd, as given by vd begin mathsize 12px style equals space left parenthesis V subscript i right parenthesis subscript a v e r a g e end subscript space equals space open parentheses v subscript i close parentheses subscript a v e r a g e end subscript minus fraction numerator e E over denominator m end fraction open parentheses t subscript i close parentheses subscript a v e r a g e space end subscript end style begin mathsize 12px style v subscript d space equals space minus space fraction numerator e E over denominator m end fraction tau end style ............................(4) vd is called drift velocity. Due to drift, there will be net transfer of charges across any area perpendicular to Electric field E.  Consider a planar area A, located inside the conductor such that normal to area is parallel to Electric filed E. Then because of drift, in an infinitesimal amount of time Δt, all electrons to the left of the area at distances upto |vd|Δt would have crossed the area. If n is number of free electrons per unit volume in the metal, then there are nΔt|vd|A such electron. Since each electron carry a charge -e, the total charge transported across this area A to the right in time Δt is -neA|vd|Δt.  Flow of charge per unit time across an area A is the magnitude of current I. Then we have, I = neA|vd| ..................(5) by substituting vd from eqn.(4) in eqn.(5),  begin mathsize 12px style I space equals space fraction numerator n e squared over denominator m end fraction tau cross times A open vertical bar E close vertical bar end style  ..............................(6) Current density J is defined as, J = I/A, where I is the current flowing in a cross SECTION area A.  hence eqn.(6) is written as, J = σE,  where conductivity σ is expressed as  begin mathsize 12px style sigma equals fraction numerator n e squared over denominator m end fraction tau end style ----------------------------------------------------- mobility μ is the drift velocity per unit electric field, hence we WRITE, begin mathsize 12px style mu space equals space fraction numerator open vertical bar v subscript d close vertical bar over denominator E end fraction space equals space open vertical bar fraction numerator e tau over denominator m end fraction close vertical bar end style...........(7) In eqn.(7) we used the relation for drift velocity from Eqn.(4).  Potenital difference changes the Electric field, but this change will not affect mobility as per eqn.(7)

:Because these REMAIN CONSTANT.

Explanation:BASED on my understanding of the question,3/5 the total no of students are boys.If the no of girls are 200,find the total no of students,RIGHT? If that is the question,here you go...2/5x=200by dividing 200/2,we get the value of 1/5 the total no of students.1/5x=200/2     =100now MULTIPLY it with 5 to get the total no of students5/5x=1/5x × 5since 1/5x=100,5/5x=100×5        =500you can VERIFY it again if you want.hope it helped and pls mark as brainliest :)

9Explanation:Each BOOK weights=72/9=8g'sIf 72 books=9kg'sIf 80 books=9 KG's

Ask UR question CORRECTLY MATE and with PROPER details

What is acceleration?EXPLANATION:acceleration is the RATE of change of velocity of an object with respect to time. An object's acceleration is the net result of all forces acting on the object, as DESCRIBED by NEWTON's Second Law. The SI unit for acceleration is metre PER second squared.SI unit: m/s2, m·s−2, m s−2(B) 9,8 m/s

relation between electric field and electric potential Deriving electric field from potential. ... In vector calculus NOTATION, the electric field is given by the negative of the gradient of the electric potential, E = −grad V. This expression SPECIFIES how the electric field is calculated at a given point. Since the field is a vector, it has both a direction and magnitude.

vity is usually specified in terms of milliVolt output per THOUSANDTHS of an inch core DISPLACEMENT per Volt of EXCITATION (mV/mil/Volt). Sensitivity varies with excitation frequency, which must also be specified. Sensitivity MOSTLY affects the gain required of the LVDT's signal conditioning ELECTRONICS.

Perpendicular Axis THEOREM. For a PLANAR object, the moment of INERTIA about an axis perpendicular to the plane is the SUM of the moments of inertia of TWO perpendicular axes through the same point in the plane of the object.

onLet’s SAY the distance is x Speed DOWNSTREAM = Speed of Boat + Speed of Stream = 6 kmph + 2 Kmph = 8 kmph Speed Upstream = Speed of Boat - Speed of Stream = 6 kmph - 2 kmph = 4 kmph Time = Distance/Speed Downstream time = x/8 HOURS Upstream time = x/4 hours So for the total journey = x/8 + x/4 = (3/8)x But given total time = 3 hours ==> (3/8) x hours = 3 hours x = 8 km So the distance is 8km and the total distance traveled is 16 km. Good LUCK

What is the angle of projection if the speed of a PROJECTILE when it is at the greatest HEIGHT is the root of 2/5 times its speed at half of the maximum height? A projectile is launched at an angle of 35 degrees from the horizontal and lands 20 seconds LATER at the same height as it was launched.

The exactly HALF-filled and fully filled orbitals have greater stability than other configurations. The reason for their stability are symmetry and exchange energy. (a).Symmetry The half-filled and fully-filled orbitals are more symmetrical than any other configuration and symmetry LEADS to greater stability. (b). Exchange EnergyIn d ORBITAL, the no of empty places when half filled is more when compared to p orbital and obviously is more symmetrical.hope it helped and pleeeease mark as BRAINLIEST:)

The runway orientation is MADE so that LANDING and takeoff are A. Against the wind DIRECTION B. Along the wind direction C. Perpendicular to wind direction D. None of these Answer: OPTION A

a+B=10m/s. ( GIVEN ) a=40m/s. ,. b=? ( Given ) ACCORDING to the QUESTION, 40m/s +b = 10m/s b=40m/s -10m/s  =30 m/s

A heat reservoir at 900 K is BROUGHT into contact with the ambient at 300 K for a SHORT time. During this PERIOD 9000 KJ of heat is lost by the heat reservoir. The total loss in availability due to this process is: a)18000 kJ b)9000 kJ c)6000 kJ d)None of the above Correct answer is option 'D'

s directly PROPORTIONAL to MOMENTUM .Means if we apply force on any body then it PRODUCES momentum.Momentum PRODUCT of MASSES and velocity.

heymate!! welcome to my answerElectricity flows in two ways: EITHER in an alternating current (AC) or in a direct current (DC). Electricity or "current" is nothing but the movement of electrons through a conductor, like a WIRE. The difference between AC and DC lies in the direction in which the electrons flow.hope its CLR to u... PLZ mrk me as BRAINLIST..........

u = 0 m/st = 2sa = 10 m/s²To FIND:-V and sFormula USED:-v = u + atv² - u² = 2asSolution:-v = 0 + 10(2)v = 20 m/s_______________________________20² - 0² = 2×10×s400 = 20 SS = 20m__________________________