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A particle has initial velocity 2icap+3jcap and accelaration -3icap +2jcap what is the magnitude of velocity after 10 sec

Answer» V= U+ atExplanation:u =2î +3J. u=√2²+3² =√13a = -3î+2j. u=√-3²+2² =√13t=10sv= √13 + √13*10 =√13(1+10) =11√13


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