A stone lying at the edge of a road falls down into a river flowing below the road. If he stone takes 2seconds to reach the river, then find(ii) the average speed of the stone at end of the ofthe fall and height of road form the river. take g=10m/s²

A stone lying at the edge of a road falls down into a river flowing

1.	A stone lying at the edge of a road falls down into a river flowing below the road. If he stone takes 2seconds to reach the river, then find(ii) the average speed of the stone at end of the ofthe fall and height of road form the river. take g=10m/s²
Answer» u = 0 m/st = 2sa = 10 m/s²To FIND:-V and sFormula USED:-v = u + atv² - u² = 2asSolution:-v = 0 + 10(2)v = 20 m/s_______________________________20² - 0² = 2×10×s400 = 20 SS = 20m__________________________

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A stone lying at the edge of a road falls down into a river flowing below the road. If he stone takes 2seconds to reach the river, then find(ii) the average speed of the stone at end of the ofthe fall and height of road form the river. take g=10m/s²​

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A stone lying at the edge of a road falls down into a river flowing below the road. If he stone takes 2seconds to reach the river, then find(ii) the average speed of the stone at end of the ofthe fall and height of road form the river. take g=10m/s²